I have this code:
import pandas as pd
import numpy as np
from geopandas import GeoDataFrame
import geopandas
from shapely.geometry import LineString, Point
import matplotlib.pyplot as plt
import contextily
''' Do Something'''
df = start_stop_df.drop('track', axis=1)
crs = {'init': 'epsg:4326'}
gdf = GeoDataFrame(df, crs=crs, geometry=geometry)
ax = gdf.plot()
contextily.add_basemap(ax)
ax.set_axis_off()
plt.show()
Basically, this generates a background map that is in Singapore. However, when I run it, I get the following error: HTTPError: Tile URL resulted in a 404 error. Double-check your tile url:http://tile.stamen.com/terrain/29/268436843/268435436.png
However, it still produces this image:
How can I change the Tile URL? I would still like to have the map of Singapore as the base layer.
EDIT:
Also tried including this argument to add_basemap:
url ='https://www.openstreetmap.org/#map=12/1.3332/103.7987'
Which produced this error:
OSError: cannot identify image file <_io.BytesIO object at 0x000001CC3CC4BC50>
First make sure that your GeoDataframe is in Web Mercator projection (epsg=3857). Once your Geodataframe is correctly georeferenced, you can achieve this by Geopandas reprojection:
df = df.to_crs(epsg=3857)
Once you have this done, you easily choose any of the supported map styles. A full list can be found in contextily.sources module, at the time of writing:
### Tile provider sources ###
ST_TONER = 'http://tile.stamen.com/toner/tileZ/tileX/tileY.png'
ST_TONER_HYBRID = 'http://tile.stamen.com/toner-hybrid/tileZ/tileX/tileY.png'
ST_TONER_LABELS = 'http://tile.stamen.com/toner-labels/tileZ/tileX/tileY.png'
ST_TONER_LINES = 'http://tile.stamen.com/toner-lines/tileZ/tileX/tileY.png'
ST_TONER_BACKGROUND = 'http://tile.stamen.com/toner-background/tileZ/tileX/tileY.png'
ST_TONER_LITE = 'http://tile.stamen.com/toner-lite/tileZ/tileX/tileY.png'
ST_TERRAIN = 'http://tile.stamen.com/terrain/tileZ/tileX/tileY.png'
ST_TERRAIN_LABELS = 'http://tile.stamen.com/terrain-labels/tileZ/tileX/tileY.png'
ST_TERRAIN_LINES = 'http://tile.stamen.com/terrain-lines/tileZ/tileX/tileY.png'
ST_TERRAIN_BACKGROUND = 'http://tile.stamen.com/terrain-background/tileZ/tileX/tileY.png'
ST_WATERCOLOR = 'http://tile.stamen.com/watercolor/tileZ/tileX/tileY.png'
# OpenStreetMap as an alternative
OSM_A = 'http://a.tile.openstreetmap.org/tileZ/tileX/tileY.png'
OSM_B = 'http://b.tile.openstreetmap.org/tileZ/tileX/tileY.png'
OSM_C = 'http://c.tile.openstreetmap.org/tileZ/tileX/tileY.png'
Keep in mind that you should not be adding actual x,y,z tile numbers in your tile URL (like you did in your "EDIT" example). ctx will take care of all this.
You can find a working copy-pastable example and further info at GeoPandas docs.
import contextily as ctx
# Dataframe you want to plot
gdf = GeoDataFrame(df, crs= {"init": "epsg:4326"}) # Create a georeferenced dataframe
gdf = gdf.to_crs(epsg=3857) # reproject it in Web mercator
ax = gdf.plot()
# choose any of the supported maps from ctx.sources
ctx.add_basemap(ax, url=ctx.sources.ST_TERRAIN)
ax.set_axis_off()
plt.show()
Contextily's default crs is epsg:3857. However, your data-frame is in different CRS. Use the following,refer the manual here:
ctx.add_basemap(ax, crs='epsg:4326', source=ctx.providers.Stamen.TonerLite)
Please, refer to this link for using different sources such as Stamen.Toner, Stamen.Terrain etc. (Stamen.Terrain is used as default).
Also, you can cast your data frame to EPSG:3857 by using df.to_crs(). In this case, you should skip crs argument inside ctx.add_basemap() function.
im too new to add a comment but I wanted to point out to those saying in the comments that they get a 404 error. Check you capitaliations, etc. Stamen's urls are specifc on this. For instance there is not an all caps call. It is only capitalize the first letter. For example:
ctx.add_basemap(ax=ax,url=ctx.providers.Stamen.Toner, zoom=10)
Related
I have a shapefile (will be called source-file hereafter), which I need to clip by a multi-polygon shapefile so that I can have a clipped shapefile for each polygon. I tried the geopandas, though I am able to clip the source-file by individually clipping the it by selecting the polygons separately from the multi-polygon shapefile, but when I try to loop over the polygons to automate the clipping process I get the following error:
Error:
TypeError: 'mask' should be GeoDataFrame, GeoSeries or(Multi)Polygon, got <class 'tuple'>
Code:
import geopandas as gpd
source = ('source-shapefile.shp')
mask = ('mask_shapefile.shp')
sourcefile = gpd.read_file(source)
maskfile = gpd.read_file(mask)
for row in maskfile.iterrows():
gpd.clip(sourcefile, row)
Two points
https://geopandas.org/en/stable/docs/reference/api/geopandas.clip.html mask can be a GeoDataFrame hence no need for looping
https://pandas.pydata.org/docs/reference/api/pandas.DataFrame.iterrows.html yields a tuple of the index value and named tuple of row. Hence your error is the fact your are passing this tuple to clip()
Have constructed an example. It is far simpler to clip using a GeoDataFrame as the mask.
import geopandas as gpd
import pandas as pd
# lets build a mask for use in clip, multipolygons and polygons
maskfile = gpd.read_file(gpd.datasets.get_path("naturalearth_lowres"))
maskfile = maskfile.loc[maskfile["continent"].eq("Europe") & maskfile["name"].ne("Russia")].pipe(
lambda d: d.assign(gdp_grp=pd.cut(d["gdp_md_est"], bins=4, labels=list("abcd")))
).dissolve("gdp_grp").reset_index()
sourcefile = gpd.read_file(gpd.datasets.get_path("naturalearth_lowres"))
# now clip, no looping needed
gpd.clip(sourcefile, maskfile)
Finally, after 5 hours of research, I am now able clip the shapefile by a multi-polygon shapefile and save the clipped polygons separately with their respective names. Following code may be dirty
but it works.
code:
import geopandas as gpd
import pandas as pd
import os, sys
source = ('source-shapefile.shp')
mask = ('mask_shapefile.shp')
outpath = ('/outpath')
sourcefile = gpd.read_file(source)
maskfile = gpd.read_file(mask)
clipshape = maskfile.explode()
clipshape.set_index('CATCH_NAME', inplace=True) # CATCH_NAME is attribute column name
for index, row in clipshape['geometry'].iteritems():
clipped = gpd.clip(sourcefile, row)
clipped.to_file(os.path.join(outpath, f'{index}.shp'))
I am trying to load in a shapefile with the use of geopandas. I have read the file in, but when I go to add the layer to the ipyleaflet map, an error comes up that says 'GeoDataFrame' object has no attribute 'model_id'.
I have tried many files and it just will not read with the geodataframe.
from ipyleaflet import Map, basemaps
fire_was = gpd.read_file('fire_wa.shp')
#add map
center = [47.409824923593575,-120.43401014843751]zoom = 7
m = Map(basemap=basemaps.OpenStreetMap.Mapnik, center=center, zoom=zoom)
m.add_layer(fire_was)
m
Any ideas?
I figured it out. The example I had seen did not show the below but checked more of the documentation of ipyleaflet. You must use GeoData to load the geodataframe.
from ipyleaflet import Map, GeoData, basemaps, LayersControl
fire_was = gpd.read_file('fire_wa.shp') firewa = GeoData(geo_dataframe = fire_was)
m = Map(center =(47.409824923593575,-120.43401014843751), zoom =7,basemap= basemaps.Esri.WorldTopoMap)
m.add_layer(firewa)
m
The task is to make an adress popularity map for Moscow. Basically, it should look like this:
https://nbviewer.jupyter.org/github/python-visualization/folium/blob/master/examples/GeoJSON_and_choropleth.ipynb
For my map I use public geojson: http://gis-lab.info/qa/moscow-atd.html
The only data I have - points coordinates and there's no information about the district they belong to.
Question 1:
Do I have to manually calculate for each disctrict if the point belongs to it, or there is more effective way to do this?
Question 2:
If there is no way to do this easier, then, how can I get all the coordinates for each disctrict from the geojson file (link above)?
import pandas as pd
import numpy as np
import geopandas as gpd
from shapely.geometry import Point
Reading in the Moscow area shape file with geopandas
districts = gpd.read_file('mo-shape/mo.shp')
Construct a mock user dataset
moscow = [55.7, 37.6]
data = (
np.random.normal(size=(100, 2)) *
np.array([[.25, .25]]) +
np.array([moscow])
)
my_df = pd.DataFrame(data, columns=['lat', 'lon'])
my_df['pop'] = np.random.randint(500, 100000, size=len(data))
Create Point objects from the user data
geom = [Point(x, y) for x,y in zip(my_df['lon'], my_df['lat'])]
# and a geopandas dataframe using the same crs from the shape file
my_gdf = gpd.GeoDataFrame(my_df, geometry=geom)
my_gdf.crs = districts.crs
Then the join using default value of 'inner'
gpd.sjoin(districts, my_gdf, op='contains')
Thanks to #BobHaffner, I tried to solve the problem using geopandas.
Here are my steps:
I download a shape-files for Moscow using this link click
From a list of tuples containing x and y (latitude and logitude) coordinates I create list of Points (docs)
Assuming that in the dataframe from the first link I have polygons I can write a simple loop for checking if the Point is inside this polygon. For details read this.
I am trying to set the crs of a geopandas object as described here.
The example file can be downloaded from here
import geopandas as gdp
df = pd.read_pickle('myShp.pickle')
I upload the screenshot to show the values of the coordinates
then if I try to change the crs the values of the polygon don't change
tmp = gpd.GeoDataFrame(df, geometry='geometry')
tmp.crs = {'init' :'epsg:32618'}
I show again the screenshot
If I try:
import geopandas as gdp
df = pd.read_pickle('myShp.pickle')
df = gpd.GeoDataFrame(df, geometry='geometry')
dfNew=df.to_crs(epsg=32618)
I get:
ValueError: Cannot transform naive geometries. Please set a crs on the object first.
Setting the crs like:
gdf.crs = {'init' :'epsg:32618'}
does not transform your data, it only sets the CRS (it basically says: "my data is represented in this CRS"). In most cases, the CRS is already set while reading the data with geopandas.read_file (if your file has CRS information). So you only need the above when your data has no CRS information yet.
If you actually want to convert the coordinates to a different CRS, you can use the to_crs method:
gdf_new = gdf.to_crs(epsg=32618)
See https://geopandas.readthedocs.io/en/latest/projections.html
super late answer, but it's:
tmp.set_crs(...)
Use this to define whatever coordinate system the data is in, i.e. 'telling the computer what coordinate system we started in'
Then;
tmp.to_crs(...)
Use this to change to your new preferred crs.
I have created a geoDataFrame using, and would like to create a Folium Map, plotting the population eat for each country. Do I have to create the Json file, or I can directly use the geoDataFrame file?
import folium
import fiona
import geopandas as gpd
world = fiona.open(gpd.datasets.get_path('naturalearth_lowres'))
world = gpd.GeoDataFrame.from_features([feature for feature in world])
world = world[(world.pop_est > 0) & (world.name != "Antarctica")]
I used folium.map and geojson function, but it failed to create correct JSON files.
Thanks for the help!
The m.cholopleth() code in #joris's answer is now deprecated. The following code produces the same result using the new folium.Chloropleth() function:
m = folium.Map()
folium.Choropleth(world, data=world,
key_on='feature.properties.name',
columns=['name', 'pop_est'],
fill_color='YlOrBr').add_to(m)
folium.LayerControl().add_to(m)
m
In recent releases of folium, you don't need to convert the GeoDataFrame to geojson, but you can pass it directly. Connecting the population column to color the polygons is still somewhat tricky to get correct:
m = folium.Map()
m.choropleth(world, data=world, key_on='feature.properties.name',
columns=['name', 'pop_est'], fill_color='YlOrBr')
m