How can I get more input text in PyQt5 InputDialog? - python

I want get more than one input text from user in PyQt5.QtWidgets QInputDialog ... in this code I can just get one input text box and I want get more input text box when I was clicked the button. See the picture to more information ...
from PyQt5.QtWidgets import (QApplication,QWidget,QPushButton,QLineEdit,QInputDialog,QHBoxLayout)
import sys
class FD(QWidget):
def __init__(self):
super().__init__()
self.mysf()
def mysf(self):
hbox = QHBoxLayout()
self.btn = QPushButton('ClickMe',self)
self.btn.clicked.connect(self.sd)
hbox.addWidget(self.btn)
hbox.addStretch(1)
self.le = QLineEdit(self)
hbox.addWidget(self.le)
self.setLayout(hbox)
self.setWindowTitle("InputDialog")
self.setGeometry(300,300,290,150)
self.show()
def sd(self):
text , ok = QInputDialog.getText(self,'InputDialog','EnterYourName = ')
if ok:
self.le.setText(str(text))
if __name__ == '__main__':
app = QApplication(sys.argv)
F = FD()
sys.exit(app.exec_())

QInputDialog is a convenience class to retrieve a single input from the user.
If you want more fields, use a QDialog.
For example:
class InputDialog(QDialog):
def __init__(self, parent=None):
super().__init__(parent)
self.first = QLineEdit(self)
self.second = QLineEdit(self)
buttonBox = QDialogButtonBox(QDialogButtonBox.Ok | QDialogButtonBox.Cancel, self);
layout = QFormLayout(self)
layout.addRow("First text", self.first)
layout.addRow("Second text", self.second)
layout.addWidget(buttonBox)
buttonBox.accepted.connect(self.accept)
buttonBox.rejected.connect(self.reject)
def getInputs(self):
return (self.first.text(), self.second.text())
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
dialog = InputDialog()
if dialog.exec():
print(dialog.getInputs())
exit(0)

Here's is a general solution, which accepts any number of inputs, based on Dimitry Ernot's answer.
from PyQt5.QtWidgets import QApplication, QLineEdit, QDialogButtonBox, QFormLayout, QDialog
from typing import List
class InputDialog(QDialog):
def __init__(self, labels:List[str], parent=None):
super().__init__(parent)
buttonBox = QDialogButtonBox(QDialogButtonBox.Ok | QDialogButtonBox.Cancel, self)
layout = QFormLayout(self)
self.inputs = []
for lab in labels:
self.inputs.append(QLineEdit(self))
layout.addRow(lab, self.inputs[-1])
layout.addWidget(buttonBox)
buttonBox.accepted.connect(self.accept)
buttonBox.rejected.connect(self.reject)
def getInputs(self):
return tuple(input.text() for input in self.inputs)
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
dialog = InputDialog(labels=["First","Second","Third","Fourth"])
if dialog.exec():
print(dialog.getInputs())
exit(0)

Related

How to create a two or more Color Custom QPushButton in PyQt5?

How to Create a Custom Button with two or More color text and as well as in With double or single underline(in a particular letter)? I tried my level best. But the Blank button (no text) only appears.
import sys
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
class MyButton(QPushButton):
def __init__ (self, mytext,parent=None):
super(MyButton,self).__init__()
self.mytext = mytext
def paintEvent(self, event):
document = QTextDocument()
document.setDocumentMargin(0)
document.setHtml(mytext)
mypixmap=QPixmap(document.size().tosize())
mypixmap.fill(Qt.transparent)
painter = QPainter(mypixmap)
document.drawContents(painter)
painter.end()
class CustomButton(QWidget):
def __init__(self):
super().__init__()
self.setWindowTitle("Grid layout Example")
self.setGeometry(100,100,400,400)
self.widget()
self.show()
def widget(self):
self.btn_sample = MyButton(QIcon("<h2><i>My sample</i> <font color=red>Button!</font></h2>"))
self.btn_sample.resize(20,20)
self.layout = QVBoxLayout()
self.layout.addWidget(self.btn_sample)
self.setLayout(self.layout)
def main():
app = QApplication(sys.argv)
mainwindow = CustomButton()
mainwindow.show()
sys.exit(app.exec_())
if __name__ == "__main__":
main()
import sys
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
class MyButton(QPushButton):
def __init__(self, Text, parent = None):
super(MyButton, self).__init__()
mydocument = QTextDocument()
mydocument.setDocumentMargin(0)
mydocument.setHtml(Text)
mypixmap = QPixmap(mydocument.size().toSize())
mypixmap.fill(Qt.transparent)
mypainter = QPainter(mypixmap)
mydocument.drawContents(mypainter)
mypainter.end()
myicon = QIcon(mypixmap)
self.setIcon(myicon)
self.setIconSize(mypixmap.size())
class mainwindow(QWidget):
def __init__(self , parent = None):
super(mainwindow, self).__init__()
self.setupgui()
def setupgui(self):
self.resize(800,600)
self.setWindowTitle('Custom Button With two Color Text')
newLayout = QHBoxLayout()
self.dashboard = MyButton("<h2><i>Dash Board</i> <font color=red>Qt!</font></h2>",self)
self.transcation = MyButton('<font color="red"><u>T</u></font><font color="black">ranscation</font>',self)
newLayout.addWidget(self.dashboard)
newLayout.addWidget(self.transcation)
self.setLayout(newLayout)
self.show()
def main():
app = QApplication(sys.argv)
ex = mainwindow()
sys.exit(app.exec_())
if __name__ == '__main__':
main()

How do I programmatically change the parent of a layout

I want to be able to move a layout to another layout based on a user input. I have the following code which does not appear to work for me. If I switch lines 31 and 34 so that they operate on the widget rather than the layout then I get the expected behaviour but I am hoping to operate on all widgets within a layout by just moving the layout.
import sys
from PyQt5.QtWidgets import QPushButton, QWidget, QHBoxLayout, QLabel, QApplication, QVBoxLayout
class b(QWidget):
def __init__(self, name):
super(b, self).__init__()
self.layout = QVBoxLayout(self)
lbl_1 = QLabel(name)
self.layout.addWidget(lbl_1)
class a(QWidget):
def __init__(self):
super(a, self).__init__()
self.layout = QHBoxLayout(self)
self.widget_1 = b('widget 1')
self.widget_2 = b('widget 2')
self.layout.addWidget(self.widget_1)
self.layout.addWidget(self.widget_2)
self.button_layout = QHBoxLayout()
self.move_layout = QPushButton('Move to other layout')
self.move_layout.clicked.connect(lambda: self.move_button())
self.button_layout.addWidget(self.move_layout)
self.widget = 'widget_2'
self.widget_2.layout.addLayout(self.button_layout)
def move_button(self):
if self.widget == 'widget_2':
self.widget_1.layout.addLayout(self.button_layout)
self.widget = 'widget_1'
else:
self.widget_2.layout.addLayout(self.button_layout)
self.widget = 'widget_2'
print('moved widget to {}'.format(self.widget))
if __name__ == '__main__':
app = QApplication(sys.argv)
window = a()
window.show()
sys.exit(app.exec_())
Edit: to clarify, In the example above, the layout I want to move (self.button_layout) is a child layout of self.widget_2.layout. When I click the pushbutton, I want the self.button_layout to be set as a child layout of self.widget_1.layout. Essentially it will do what the code below does but using addLayout instead of addWidget.
import sys
from PyQt5.QtWidgets import QPushButton, QWidget, QHBoxLayout, QLabel, QApplication, QVBoxLayout
class b(QWidget):
def __init__(self, name):
super(b, self).__init__()
self.layout = QVBoxLayout(self)
lbl_1 = QLabel(name)
self.layout.addWidget(lbl_1)
class a(QWidget):
def __init__(self):
super(a, self).__init__()
self.layout = QHBoxLayout(self)
self.widget_1 = b('widget 1')
self.widget_2 = b('widget 2')
self.layout.addWidget(self.widget_1)
self.layout.addWidget(self.widget_2)
self.button_layout = QHBoxLayout()
self.move_layout = QPushButton('Move to other layout')
self.move_layout.clicked.connect(lambda: self.move_button())
self.button_layout.addWidget(self.move_layout)
self.widget = 'widget_2'
self.widget_2.layout.addLayout(self.button_layout)
def move_button(self):
if self.widget == 'widget_2':
self.widget_1.layout.addWidget(self.move_layout)
self.widget = 'widget_1'
else:
self.widget_2.layout.addWidget(self.move_layout)
self.widget = 'widget_2'
print('moved widget to {}'.format(self.widget))
if __name__ == '__main__':
app = QApplication(sys.argv)
window = a()
window.show()
sys.exit(app.exec_())
The problem is that if a layout has a parent then it cannot be changed as the error message indicates:
QLayout::addChildLayout: layout "" already has a parent
One possible solution is to remove the parent:
def move_button(self):
self.button_layout.setParent(None)
if self.widget == "widget_2":
self.widget_1.layout.addLayout(self.button_layout)
self.widget = "widget_1"
else:
self.widget_2.layout.addLayout(self.button_layout)
self.widget = "widget_2"
print("moved widget to {}".format(self.widget))
Another alternative is to place the layout in a QWidget that is the container and that place it in the required layout:
class a(QWidget):
def __init__(self):
super(a, self).__init__()
layout = QHBoxLayout(self)
self.widget_1 = b("widget 1")
self.widget_2 = b("widget 2")
layout.addWidget(self.widget_1)
layout.addWidget(self.widget_2)
self.container = QWidget()
container_layout = QHBoxLayout(self.container)
button = QPushButton("Move to other layout")
button.clicked.connect(self.move_button)
container_layout.addWidget(button)
self.widget = "widget_1"
self.move_button()
def move_button(self):
if self.widget == "widget_2":
self.widget_1.layout.addWidget(self.container)
self.widget = "widget_1"
else:
self.widget_2.layout.addWidget(self.container)
self.widget = "widget_2"
print("moved widget to {}".format(self.widget))

why pyqt5 GUI will be freeze when I use infinite while loop? [duplicate]

I write a program to that send and recive data from serial, but I have a problem, I want to create a function "connect()" or a class, and when I press a button, the function is executed, but if I create this function in "MainWindow" class, variable "ser" from "TestThread" class become uninitialized, can you help me?
import sys
import serial
from PyQt5.QtWidgets import QMainWindow, QApplication
from PyQt5.QtCore import QThread, pyqtSignal
from PyQt5.uic import loadUi
ser = serial.Serial('/dev/tty.usbmodem14201', 9600, timeout=1)
class TestThread(QThread):
serialUpdate = pyqtSignal(str)
def run(self):
while ser.is_open:
QThread.sleep(1)
value = ser.readline().decode('ascii')
self.serialUpdate.emit(value)
ser.flush()
class MainWindow(QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
loadUi('/Users/bogdanvesa/P2A_GUI/mainwindow.ui', self)
self.thread = TestThread(self)
self.thread.serialUpdate.connect(self.handleSerialUpdate)
self.connect_btn.clicked.connect(self.connectSer)
self.lcd_EBtn.clicked.connect(self.startThread)
def startThread(self):
self.thread.start()
def handleSerialUpdate(self, value):
print(value)
self.lcd_lineEdit.setText(value)
def main():
app = QApplication(sys.argv)
form = MainWindow()
form.show()
sys.exit(app.exec_())
if __name__ == "__main__":
main()
Instead of using pySerial + thread it is better to use QSerialPort that is made to live with the Qt event-loop:
from PyQt5 import QtCore, QtWidgets, QtSerialPort
class Widget(QtWidgets.QWidget):
def __init__(self, parent=None):
super(Widget, self).__init__(parent)
self.message_le = QtWidgets.QLineEdit()
self.send_btn = QtWidgets.QPushButton(
text="Send",
clicked=self.send
)
self.output_te = QtWidgets.QTextEdit(readOnly=True)
self.button = QtWidgets.QPushButton(
text="Connect",
checkable=True,
toggled=self.on_toggled
)
lay = QtWidgets.QVBoxLayout(self)
hlay = QtWidgets.QHBoxLayout()
hlay.addWidget(self.message_le)
hlay.addWidget(self.send_btn)
lay.addLayout(hlay)
lay.addWidget(self.output_te)
lay.addWidget(self.button)
self.serial = QtSerialPort.QSerialPort(
'/dev/tty.usbmodem14201',
baudRate=QtSerialPort.QSerialPort.Baud9600,
readyRead=self.receive
)
#QtCore.pyqtSlot()
def receive(self):
while self.serial.canReadLine():
text = self.serial.readLine().data().decode()
text = text.rstrip('\r\n')
self.output_te.append(text)
#QtCore.pyqtSlot()
def send(self):
self.serial.write(self.message_le.text().encode())
#QtCore.pyqtSlot(bool)
def on_toggled(self, checked):
self.button.setText("Disconnect" if checked else "Connect")
if checked:
if not self.serial.isOpen():
if not self.serial.open(QtCore.QIODevice.ReadWrite):
self.button.setChecked(False)
else:
self.serial.close()
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
w = Widget()
w.show()
sys.exit(app.exec_())
I have used the above code redesigned, so it has a mainwindow with a menubar and a statusbar. I also added the QSerialPortInfo class. This version will find active ports and display them on the status bar.
I only tested this on rpi 4 and Windows 10.
import sys
from PyQt5 import QtCore, QtWidgets, QtSerialPort
from PyQt5.QtWidgets import QApplication, QMainWindow ,QWidget ,QToolBar ,QHBoxLayout, QAction ,QStatusBar ,QLineEdit ,QPushButton ,QTextEdit , QVBoxLayout
from PyQt5.QtCore import Qt , pyqtSignal
from PyQt5.QtSerialPort import QSerialPortInfo
class AddComport(QMainWindow):
porttnavn = pyqtSignal(str)
def __init__(self, parent , menu):
super().__init__(parent)
menuComporte = menu.addMenu("Comporte")
info_list = QSerialPortInfo()
serial_list = info_list.availablePorts()
serial_ports = [port.portName() for port in serial_list]
if(len(serial_ports)> 0):
antalporte = len(serial_ports)
antal = 0
while antal < antalporte:
button_action = QAction(serial_ports[antal], self)
txt = serial_ports[antal]
portinfo = QSerialPortInfo(txt)
buttoninfotxt = " Ingen informationer"
if portinfo.hasProductIdentifier():
buttoninfotxt = ("Produkt specifikation = " + str(portinfo.vendorIdentifier()))
if portinfo.hasVendorIdentifier():
buttoninfotxt = buttoninfotxt + (" Fremstillers id = "+ str(portinfo.productIdentifier()))
button_action = QAction( txt , self)
button_action.setStatusTip( buttoninfotxt)
button_action.triggered.connect(lambda checked, txt = txt: self.valgAfComportClick(txt))
menuComporte.addAction(button_action)
antal = antal +1
else:
print("Ingen com porte fundet")
def valgAfComportClick(self , port):
self.porttnavn.emit(port)
def closeEvent(self, event):
self.close()
class MainWindow(QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
portname = "None"
self.setStatusBar(QStatusBar(self))
menu = self.menuBar()
comfinder = AddComport(self , menu)
comfinder.porttnavn.connect(self.valgAfComport)
self.setWindowTitle("Serial port display / send")
self.message_le = QLineEdit()
self.send_btn = QPushButton(
text="Send",
clicked=self.send
)
self.output_te = QTextEdit(readOnly=True)
self.button = QPushButton(
text="Connect",
checkable=True,
toggled=self.on_toggled
)
lay = QVBoxLayout(self)
hlay = QHBoxLayout()
hlay.addWidget(self.message_le)
hlay.addWidget(self.send_btn)
lay.addLayout(hlay)
lay.addWidget(self.output_te)
lay.addWidget(self.button)
widget = QWidget()
widget.setLayout(lay)
self.setCentralWidget(widget)
self.serial = QtSerialPort.QSerialPort(
portname,
baudRate=QtSerialPort.QSerialPort.Baud9600,
readyRead=self.receive)
#QtCore.pyqtSlot()
def receive(self):
while self.serial.canReadLine():
text = self.serial.readLine().data().decode()
text = text.rstrip('\r\n')
self.output_te.append(text)
#QtCore.pyqtSlot()
def send(self):
self.serial.write(self.message_le.text().encode())
#QtCore.pyqtSlot(bool)
def on_toggled(self, checked):
self.button.setText("Disconnect" if checked else "Connect")
if checked:
if not self.serial.isOpen():
self.serial.open(QtCore.QIODevice.ReadWrite)
if not self.serial.isOpen():
self.button.setChecked(False)
else:
self.button.setChecked(False)
else:
self.serial.close()
def valgAfComport(self , nyport):
seropen = False
if self.serial.isOpen():
seropen = True
self.serial.close()
self.serial.setPortName(nyport)
if seropen:
self.serial.open(QtCore.QIODevice.ReadWrite)
if not self.serial.isOpen():
self.button.setChecked(False)
print(nyport)
def closeEvent(self, event):
self.serial.close()
print("Comport lukket")
# print(comporttxt)
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
w = MainWindow()
w.show()
sys.exit(app.exec_())

Change QLabelText as QLineEdit text changes

There is this QLineEdit with setText is set to a predefined value and there is a QDialog with QLabel in it which is supposed to show whatever is in the QLineEdit. The code below shows the situation.
import sys
import os
import datetime
from PySide2.QtWidgets import *
from PySide2 import *
now = datetime.datetime.now()
now_str = now.strftime("%H.%M.%S,%d/%m/%y")
default_text = (str("Sugar_" + now_str))
class MainWindow(QWidget):
def __init__(self):
super(MainWindow, self).__init__()
self.resize(600, 500)
btn = QPushButton("show dialog")
mw_layout = QVBoxLayout()
mw_layout.addWidget(btn)
self.setLayout(mw_layout)
btn.clicked.connect(show_d)
class dialog(QDialog):
def __init__(self):
super(dialog, self).__init__()
self.resize(400, 350)
title = QLineEdit()
title.setText(default_text)
show_title = QPushButton("Show title")
cancel = QPushButton("Cancel")
d_layout = QVBoxLayout()
d_layout.addWidget(title)
d_layout.addWidget(show_title)
d_layout.addWidget(cancel)
self.setLayout(d_layout)
t = title.text()
title_dialog = QDialog()
label = QLabel()
label.setText("The title is " + title.text())
ok = QPushButton("OK!")
t_layout = QVBoxLayout()
t_layout.addWidget(label)
t_layout.addWidget(ok)
title_dialog.setLayout(t_layout)
def show_t():
title_dialog.exec_()
title_dialog.setModal(True)
def close_t():
title_dialog.accept()
show_title.clicked.connect(show_t)
ok.clicked.connect(close_t)
cancel.clicked.connect(self.close_d)
def close_d(self):
self.reject()
def show_d():
d = dialog()
d.exec_()
d.setModal(True)
if __name__ == '__main__':
app = QApplication(sys.argv)
MainWindow = MainWindow()
MainWindow.show()
sys.exit(app.exec_())
But this doesn't work like I expected it to. The QLabel text just show the default text even when the text in QLineEdit is changed.
The console also shows the following error;
qt.xkb.compose: failed to create compose table.
I think there is something's obviously wrong but I can't seem to find what.
Any help appreciated.
You must update the text before a certain event, for example an instant before displaying the dialog:
class dialog(QDialog):
def __init__(self):
super(dialog, self).__init__()
self.resize(400, 350)
self.title_lineedit = QLineEdit(default_text)
show_title = QPushButton("Show title")
cancel = QPushButton("Cancel")
d_layout = QVBoxLayout(self)
d_layout.addWidget(self.title_lineedit)
d_layout.addWidget(show_title)
d_layout.addWidget(cancel)
self.title_dialog = QDialog()
self._title_label = QLabel()
ok = QPushButton("OK!")
t_layout = QVBoxLayout(self.title_dialog)
t_layout.addWidget(self._title_label)
t_layout.addWidget(ok)
show_title.clicked.connect(self.on_clicked)
ok.clicked.connect(self.title_dialog.reject)
cancel.clicked.connect(self.reject)
self.update_label()
def update_label(self):
self._title_label.setText("The title is " + self.title_lineedit.text())
def on_clicked(self):
self.update_label()
self.title_dialog.exec_()

show text after enter key pressed

I want show text after enter key pressed
from PyQt5.QtWidgets import QWidget, QApplication, QPlainTextEdit, QVBoxLayout, QLabel
from PyQt5.QtCore import Qt
import sys
class PlainTextEdit(QPlainTextEdit):
def __init__(self, parent):
super().__init__(parent=parent)
close_window = ClosingWindow()
vbox = QVBoxLayout()
self.close_window.setLayout(vbox)
def keyPressEvent(self, QKeyEvent):
if QKeyEvent.key() == Qt.Key_Enter:
self.close_window.label_display.setText("Enter key pressed")
class ClosingWindow(QWidget):
def __init__(self):
super().__init__()
plainText = PlainTextEdit(self)
self.initUI()
def initUI(self):
vbox = QVBoxLayout()
label_display = QLabel("Text Here")
self.setLayout(vbox)
self.setWindowTitle("Message Box")
self.setGeometry(200, 200, 500, 300)
self.show()
if __name__ == "__main__":
app = QApplication(sys.argv)
close_win = ClosingWindow()
sys.exit(app.exec_())
Your code has the following errors:
You are creating an infinite loop: You are creating a PlainTextEdit within a ClosingWindow, and in that PlainTextEdit you are creating another ClosingWindow, and in that other ClosingWindow you are creating a PlainTextEdit, etc. Every time you use the constructor of a class you are creating a different object, so the "close_window" created in PlainTextEdit is different from the "close_win".
Each class must have a single responsibility (1), in your case the responsibility of PlainTextEdit is to notify that it was pressed enter, and in that case you must use a signal.
The enter key on the keyboard does not correspond to Qt::Key_Enter but Qt::Key_Return, it only corresponds to Qt::Key_Return on the keypad.
It is not necessary to create a layout in PlainTextEdit.
Considering the above, the solution is:
from PyQt5 import QtCore, QtWidgets
class PlainTextEdit(QtWidgets.QPlainTextEdit):
sendTextSignal = QtCore.pyqtSignal(str)
def keyPressEvent(self, event):
if event.key() in (QtCore.Qt.Key_Enter, QtCore.Qt.Key_Return):
self.sendTextSignal.emit("Enter key pressed")
else:
self.sendTextSignal.emit("Not Enter key pressed")
super().keyPressEvent(event)
class ClosingWindow(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
plainText = PlainTextEdit()
label_display = QtWidgets.QLabel("Text Here")
plainText.sendTextSignal.connect(label_display.setText)
vbox = QtWidgets.QVBoxLayout(self)
vbox.addWidget(plainText)
vbox.addWidget(label_display)
self.setWindowTitle("Message Box")
self.setGeometry(200, 200, 500, 300)
self.show()
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
close_win = ClosingWindow()
sys.exit(app.exec_())
(1) Single responsibility principle

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