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HTML parsing with BeautifulSoup in Python unknown error

I know that this code works for other websites that end in .com
However I noticed that the code doesn't work if I try to parse websites that end in .kr
Can somebody help to find why this is happening and an alternate solution to parse these types of websites?
Following is my code.
import requests
from bs4 import BeautifulSoup
URL = 'https://everytime.kr/#nN4K1XC0weHnnM9VB5Qe'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
results = soup.find(id='container')
print(results)
The URL here is a link to my timetable. I need to parse this website so that I can easily collect the information for the subjects and data relevant to the subject (duration, location, professor's name, etc.).
Thanks

Website is serving dynamic content and you get an empty response back - you may use selenium.
Example
from selenium import webdriver
from bs4 import BeautifulSoup
import time
driver = webdriver.Chrome(executable_path=r'C:\Program Files\ChromeDriver\chromedriver.exe')
url = 'https://everytime.kr/#nN4K1XC0weHnnM9VB5Qe'
driver.get(url)
time.sleep(5)
soup = BeautifulSoup(driver.page_source, 'html.parser')
results = soup.find(id='container')
print(results)
driver.close()

Using Python to receive specific URLs from a webpage (Multireddit lists)

I'm trying to run some statistical analysis on topic-based multireddits. Rather than collecting each individual subreddit by hand, I have found websites that collect these subreddits (Example, Example 2).
These sites unfortunately do not have the ability to download the list of subreddits into plaintext that can be used in a dictionary. Is there a specific method I could use to scrape these sites to only receive back the URL of each attached hyperlink on the webpage?
Thanks!
Edit: Here's my current code
Here's my current code, which runs, but returns every URL.
import requests
from bs4 import BeautifulSoup
import pandas as pd
url = "https://snoopsnoo.com/subreddits/travel/"
page = requests.get(url)
data = page.text
soup = BeautifulSoup(data)
links = []
for link in soup.find_all('a'):
reddit = link.get('href')
links.append(reddit)
df = pd.DataFrame(links, columns=['string_values'])
df.to_csv('travel.csv')

Yes there is such a method. If you are using Python, a widely used library is Beautifulsoup. This library parses the HTML directly, so no webdriver is necessary or running a webbrowser in the background like with selenium. You can install it with: pip install bs4.
For your first example site:
import urllib
from bs4 import BeautifulSoup
# Load the url
url = "https://snoopsnoo.com/subreddits/travel/"
html = urllib.request.urlopen(url).read()
# Create the parser object
soup = BeautifulSoup(html)
# Find all panel headings
panels = soup.find_all(class_="panel-heading big")
# Find the <a>-elements and exctract the link
links = [elem.find('a')['href'] for elem in panels]
print(links)
Here I checked the contents of the page to locate the panel elements by class and then extracted the <a>-elements and its href-attribute.

This code will grab all of the titles.
from selenium import webdriver
firefox_options = webdriver.FirefoxOptions()
#firefox_options.add_argument('--headless')
driver = webdriver.Firefox(executable_path='geckodriver.exe', firefox_options=firefox_options)
driver.get("https://snoopsnoo.com/subreddits/travel/")
for i in range(3):
wds = driver.find_elements_by_class_name('title')
for wd in wds:
print(wd.text)
driver.find_element_by_xpath('/html/body/div/div[2]/div[1]/ul/li/a').click
print('next page')
driver.close()
Change 3 to how many pages you want in for i in range(3): Uncomment firefox_options.add_argument('--headless') to use headless mode

Links from BeautifulSoup without href or <a>

I am trying to create a bot that scrapes all the image links from a site and store them somewhere else so I can download the images after.
from selenium import webdriver
import time
from bs4 import BeautifulSoup as bs
import requests
url = 'https://www.artstation.com/artwork?sorting=trending'
page = requests.get(url)
driver = webdriver.Chrome()
driver.get(url)
time.sleep(3)
soup = bs(driver.page_source, 'html.parser')
gallery = soup.find_all(class_="image-src")
data = gallery[0]
for x in range(len(gallery)):
print("TAG:", sep="\n")
print(gallery[x], sep="\n")
if page.status_code == 200:
print("Request OK")
This returns all the links tags i wanted but I can't find a way to remove the html or copy only the links to a new list. Here is an example of the tag i get:
<div class="image-src" image-src="https://cdnb.artstation.com/p/assets/images/images/012/269/255/20180810092820/smaller_square/vince-rizzi-batman-n52-p1-a.jpg?1533911301" ng-if="::!project.hide_as_adult"></div>
So, how do i get only the links within the gallery[] list?
What i want to do after is to take this links and edit the /smaller-square/ directory to /large/, which is the one that has the high resolution image.

The page loads it's data through AJAX, so through network inspector we see, where the call is made. This snippet will obtain all the image links found on page 1, sorted by trending:
import requests
import json
url = 'https://www.artstation.com/projects.json?page=1&sorting=trending'
page = requests.get(url)
json_data = json.loads(page.text)
for data in json_data['data']:
print(data['cover']['medium_image_url'])
Prints:
https://cdna.artstation.com/p/assets/images/images/012/272/796/medium/ben-zhang-brigitte-hero-concept.jpg?1533921480
https://cdna.artstation.com/p/assets/covers/images/012/279/572/medium/ham-sung-choul-braveking-140823-1-3-s3-mini.jpg?1533959982
https://cdnb.artstation.com/p/assets/covers/images/012/275/963/medium/michael-vicente-orb-gem-thumb.jpg?1533933774
https://cdnb.artstation.com/p/assets/images/images/012/275/635/medium/michael-kutsche-piglet-by-michael-kutsche.jpg?1533932387
https://cdna.artstation.com/p/assets/images/images/012/273/384/medium/ben-zhang-unnamed.jpg?1533923353
https://cdnb.artstation.com/p/assets/covers/images/012/273/083/medium/michael-vicente-orb-guardian-thumb.jpg?1533922229
... and so on.
If you print the variable json_data, you will see other information the page sends (like icon image url, total_count, data about the author etc.)

You can access the attributes using key-value.
Ex:
from bs4 import BeautifulSoup
s = '''<div class="image-src" image-src="https://cdnb.artstation.com/p/assets/images/images/012/269/255/20180810092820/smaller_square/vince-rizzi-batman-n52-p1-a.jpg?1533911301" ng-if="::!project.hide_as_adult"></div>'''
soup = BeautifulSoup(s, "html.parser")
print(soup.find("div", class_="image-src")["image-src"])
#or
print(soup.find("div", class_="image-src").attrs['image-src'])
Output:
https://cdnb.artstation.com/p/assets/images/images/012/269/255/20180810092820/smaller_square/vince-rizzi-batman-n52-p1-a.jpg?1533911301

Scraping all links using Python BeautifulSoup/lxml

http://www.snapdeal.com/
I was trying to scrape all links from this site and when I do, I get an unexpected result. I figured out that this is happening because of javascript.
under "See All categories" Tab you will find all major product categories. If you hover the mouse over any category it will expand the categories. I want those links from each major categories.
url = 'http://www.snapdeal.com/'
data = urllib2.urlopen(url)
page = BeautifulSoup(data)
#print data
for link in page.findAll('a'):
l = link.get('href')
print l
But, this gave me a different result than what I expected (I turned off javascript and looked at the page source and output was from this source)
I just want to finds all sub links from each major category. any suggestions will be appreciated.

This is happening just because you are letting BeautifulSoup chose its own best parser , and you might not have installed lxml .
The best option is to use html.parser to parse the url .
from bs4 import BeautifulSoup
import urllib2
url = 'http://www.snapdeal.com/'
data = urllib2.urlopen(url).read()
page = BeautifulSoup(data,'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print l
This worked for me .Make sure to install dependencies .

I thinks you should try another library such as selenium , it provide a web driver for you and this is the advantage of this library ,for my self I couldn't handle javascripts with bs4.

Categories Menu is the url you are looking for. Many websites generate the content dynamically using XHR(XMLHTTPRequest).
In order to examine the components of a website get familiar with Firebug add-on in Firefox or Developer Tools(inbuilt addon) in Chrome. You can check the XHR used in website under the network tab in aforementioned add-ons.

Use a web scraping tool such as scrapy or mechanize
In mechanize, to get all the links in the snapdeal homepage,
br=Browser()
br.open("http://www.snapdeal.com")
for link in browser.links():
print link.name
print link.url

I have been looking into a way to scrape links from webpages that are only rendered in an actual browser but wanted the results to be run using a headless browser.
I was able to achieve this using phantomJS, selenium and beautiful soup
#!/usr/bin/python
import bs4
import requests
from selenium import webdriver
driver = webdriver.PhantomJS('phantomjs')
url = 'http://www.snapdeal.com/'
browser = driver.get(url)
content = driver.page_source
soup = bs4.BeautifulSoup(content)
links = [a.attrs.get('href') for a in soup.find_all('a')]
for paths in links:
print paths
driver.close()

The following examples will work for both HTTP and HTTPS. I'm writing this answer to show how this can be used in both Python 2 and Python 3.
Python 2
This is inspired by this answer.
from bs4 import BeautifulSoup
import urllib2
url = 'https://stackoverflow.com'
data = urllib2.urlopen(url).read()
page = BeautifulSoup(data,'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print l
Python 3
from bs4 import BeautifulSoup
from urllib.request import urlopen
import ssl
# to open up HTTPS URLs
gcontext = ssl.SSLContext()
# You can give any URL here. I have given the Stack Overflow homepage
url = 'https://stackoverflow.com'
data = urlopen(url, context=gcontext).read()
page = BeautifulSoup(data, 'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print(l)
Other Languages
For other languages, please see this answer.

Getting Different Results For Web Scraping

I was trying to do web scraping and was using the following code :
import mechanize
from bs4 import BeautifulSoup
url = "http://www.thehindu.com/archive/web/2010/06/19/"
br = mechanize.Browser()
htmltext = br.open(url).read()
link_dictionary = {}
soup = BeautifulSoup(htmltext)
for tag_li in soup.findAll('li', attrs={"data-section":"Chennai"}):
for link in tag_li.findAll('a'):
link_dictionary[link.string] = link.get('href')
print link_dictionary[link.string]
urlnew = link_dictionary[link.string]
brnew = mechanize.Browser()
htmltextnew = brnew.open(urlnew).read()
articletext = ""
soupnew = BeautifulSoup(htmltextnew)
for tag in soupnew.findAll('p'):
articletext += tag.text
print articletext
I was unable to get any printed values by using this. But on using attrs={"data-section":"Business"} instead of attrs={"data-section":"Chennai"} I was able to get the desired output. Can someone help me?

READ THE TERMS OF SERVICES OF THE WEBSITE BEFORE SCRAPING
If you are using firebug or inspect element in Chrome, you might see some contents that will not be seen if you are using Mechanize or Urllib2.
For example, when you view the source code of the page sent out by you. (Right click view source in Chrome). and search for data-section tag, you won't see any tags which chennai, I am not 100% sure but I will say those contents need to be populated by Javascript ..etc. which requires the functionality of a browser.
If I were you, I will use selenium to open up the page and then get the source page from there, then the HTML collected in that way will be more like what you see in a browser.
Cited here
from selenium import webdriver
from bs4 import BeautifulSoup
import time
driver = webdriver.Firefox()
driver.get("URL GOES HERE")
# I noticed there is an ad here, sleep til page fully loaded.
time.sleep(10)
soup = BeautifulSoup(driver.page_source)
print len(soup.findAll(...}))
# or you can work directly in selenium
...
driver.close()
And the output for me is 8