This question already has answers here:
Display a decimal in scientific notation
(13 answers)
Closed 3 years ago.
I have this:
print('bionumbers:',bionumbers)
which outputs:
bionumbers: 9381343483.4
How can I output this value in exponent notation?
Using Python3 format syntax :
print(f'bionumbers: {bionumbers:e}')
Related
This question already has answers here:
Convert string (in scientific notation) to float
(4 answers)
Closed 9 months ago.
How can I parse a character string that represents a scientific number into a numeric number?
>>> float('5e-04')
0.0005
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
how to format float number in python? [duplicate]
(3 answers)
variable number of digit in format string
(3 answers)
Closed 1 year ago.
I'm reading this textbook called "Practical Statistics for Data Scientists" and this :.3f keeps getting used in almost every f-string. What does :.3f mean? My guess is it has something to do with floating point numbers.
Example:
{house_lm_factor.intercept_:.3f}
This is show you how many number are printing:
>>> import math
>>> flt = math.pi
>>> f'{flt:.3f}'
'3.142'
>>> f'{flt:.5f}'
'3.14159'
>>> f'{flt:.10f}'
'3.1415926536'
This question already has answers here:
How do I use a decimal step value for range()?
(34 answers)
Closed 3 years ago.
How do I iterate through floating point numbers in python?
for i in range(1,10,0.001):
print(i)
TypeError: 'float' object cannot be interpreted as an integer
One option:
for i in range(1000,10000):
print(i/1000)
This question already has answers here:
Why does the division get rounded to an integer? [duplicate]
(13 answers)
Closed 5 years ago.
lets say I have a list a and a variable b = 1/len(a) but when I display the value of b it gives me 0
Because of integer divided by integer.
Try b=1.0/len(a)
This question already has answers here:
Convert binary to ASCII and vice versa
(8 answers)
Closed 6 years ago.
x = "01100001"
How do i convert this string into ASCII
Expected Result:
print(x.somefunction())
Output: a
Use following one liner
x = chr(int('010101010',2))
will work.