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Passing variable with POST in django

Hi im trying to pass a name from a form to a view in django using POST. There are no errors in the execution but its passing nothing from the template and dont know if i doing something wrong here. Im starting with django so i can have newbie errors. If u need more information tell me pls.
Views.py
def crear_pdf(request):
empresa_selec = ""
form = EmpModelForm()
if request.method == 'POST':
form = EmpModelForm(data=request.POST)
if form.is_valid():
empresa_selec = form.cleaned_data['nombre']
#"empresa_selec" that's the empty variable
Models.py
class Empresa_modelo(models.Model):
nombre = models.CharField(max_length=100,blank=True,null=True)
Forms.py
class EmpModelForm(forms.ModelForm):
class Meta:
model = Empresa_modelo
fields = ["nombre"]
template.html
<div class="container-fluid">
<form method="POST" enctype="multipart/form-data" action="{% url 'crear_pdf' %}">{% csrf_token %}
<p>Empresa</p>
<input type="text" name="empresa">
<br>
<button type="submit">Subir</button>
</form>
<br>
<a class="btn btn-primary" href="{% url 'crear_pdf' %}">Atras</a>
</div>

You haven't got a field called nombre in your template; you only have empresa.
That's presumably because you don't ouput your EmpModelForm in the template. You don't show your render call in the view, but assuming you pass it as form, you should just do {{ form.as_p }} in the template.

Try using:
<input type="text" name="nombre">
There is no field named empresa.

Had a look at your code,there are a couple of issues.First you are not using the model form defined in your forms.py file in your template. Second you have defined an input text box with the name that you are not referring in your views. Either use the model form or use the same name of your input text box in your views.
def crear_pdf(request):
empresa_selec = ""
form = EmpModelForm()
if request.method == 'POST':
form = EmpModelForm(data=request.POST)
if form.is_valid():
empresa_selec = form.cleaned_data['nombre']
else:
return render(request,"template.html",{"form":form})
And in your template you can edit as such:
<div class="container-fluid">
<form method="POST" enctype="multipart/form-data" action="{% url 'crear_pdf' %}">{% csrf_token %}
{{ form.as_p }}
<br>
<button type="submit">Subir</button>
</form>
<br>
<a class="btn btn-primary" href="{% url 'crear_pdf' %}">Atras</a>
</div>
Hope this helps.

Validate Form Based on Hidden Input's Template Value - Is It Possible?

I have a form that in layman's terms, has a bunch of buttons (that act like checkboxes) with values. Users can select a handful of buttons.
The buttons push their values (via a JQuery function) into a hidden input which I'm using to gather the values.
I would like to make sure that the "values=" attribute of each hidden input isn't null or "" when the user presses the submit form.
Ex: Make sure that the input does NOT equal this:
<input autocomplete="off" id="id_valuePlatform" name="valuePlatform" type="hidden"> or
<input autocomplete="off" id="id_valuePlatform" name="valuePlatform" type="hidden" value="">
Here's the forms.py:
class getGames(forms.Form):
valuePlatform = forms.CharField(required=True, error_messages={'required': 'You need to tell us your platform(s)!'}, widget=forms.HiddenInput(attrs={'autocomplete': 'off'}))
Template:
<form method= "POST" autocomplete="off"> {% csrf_token %}
{{ form.non_field_errors }}
<div class="container">
{% if form.valuePlatform.errors %}
<ol>
{% for error in form.valuePlatform.errors %}
<li><strong>{{ error|escape }}</strong></li>
{% endfor %}
</ol>
{% endif %}
</div>
{{ form.valuePlatform }}
</div>
</div>
</form>
Views.py:
from .forms import getGames
def find(request):
form = getGames()
context = {"form": form}
if form.is_valid():
print form.cleaned_data['valuePlatform']
Is this even possible, or would I have to pass the data to Django via a Ajax POST?

Changed views.py to this, after looking at # Alasdair's examples in the documentation:
from .forms import getGames
def find(request):
form = getGames(request.POST or None)
context = {"form": form}
if request.method == 'POST':
if form.is_valid():
print form.cleaned_data['valuePlatform']

Django/Python: How to pass a variable from a form to a python script with POST method?

I'm getting this error when submit:
CSRF verification failed. Request aborted.
I've got this far following the documentation, but I don't fully understand it and it's definitely wrong. I just want to take a query word from my search box(form) and pass it to a python script as an argument. I'm new to Django and getting stuck on the easiest things.
In models.py:
class QueryForm(forms.Form):
query = forms.CharField(label='query',max_length=100)
I added this line to my urls.py
url(r'^results/$', 'tweemo.views.results'),
On my homepage where my search box is I have this code for my form:
<form action="/home/results/" method="post">
<label for="query">Search:</label>
<input id="query" type="text" name="query" value="{{ current_query }}">
<input type="submit" value="ok">
</form>
In views.py I added these two functions:
def get_query(request):
if request.method == 'POST':
form = QueryForm(request.POST)
if form.isvalid():
return HttpResponseRedirect('/thanks/')
else:
form = QueryForm()
return render(request, 'results.html', {'form': form})
def results(request):
return render_to_response('results.html',{'here':TwitterStream.objects.all() })
MY results.html contains just this:
<form action="/home/results/" method="post">
{% csrf_token %}
{{ form }}
<input type="submit" value="Submit"/>
</form>

You must just add the {% csrf_token %} tag inside EVERY <form></form> tag which has method to be post in your template.
So the below markup should be corrected:
<form action="/home/results/" method="post">
{% csrf_token %}
<label for="query">Search:</label>
<input id="query" type="text" name="query" value="{{ current_query }}">
<input type="submit" value="ok">
</form>

Well the problem is that you are not passing the csrf token to the form , you need to pass the csrf token to the render function in order for it to be applied in the form . To accomplish this you need to associate the csrf token to the request.
def get_query(request):
if request.method == 'POST':
form = QueryForm(request.POST)
if form.isvalid():
return HttpResponseRedirect('/thanks/')
else:
form = QueryForm()
args = {}
args.update(csrf(request))
args['form'] = form
return render_to_response('results.html', args)
def results(request):
return render_to_response('results.html',{'here':TwitterStream.objects.all() })

Django form will not validate

I am working with Django forms and for some reason, this form will not validate! It submits alright, or at least the runserver shows an http post response with code 200 (ok). For some reason though, my form will not pass the is_valid test!
views.py:
def new_show(request):
if request.method == 'POST':
img_form = ImageForm(request.POST, request.FILES)
show_form = NewShowForm(request.POST)
if show_form.is_valid():
new_Show = Show()
new_Show.title=show_form.cleaned_data['title']
new_Show.body=show_form.cleaned_data['body']
new_Show.pub_date=timezone.now()
new_Show.location=show_form.cleaned_data['location']
new_Show.time=show_form.cleaned_data['time']
new_Show.save()
if img_form.is_valid():
image=Image(image=request.FILES['imageFile'])
new_Show.image_set.add(image)
return HttpResponseRedirect(reverse('shows'))
else:
return HttpResponseRedirect(reverse('shows'))
else:
show_form = NewShowForm()
img_form = ImageForm()
return render_to_response(
'shows/new_show.html',
{'show_form': show_form, 'img_form': img_form},
context_instance=RequestContext(request)
)
Here is my template snippet:
<form action="{% url "new_show" %}" method="post" enctype="multipart/form-data">
{% csrf_token %}
<p>{{ show_form.non_field_errors }}</p>
<p>
<label for="title">Title:</label>
<input type="text" name="title"/>
</p>
<p>
<label for="body">Body:</label>
<textarea type="text" name="body"> </textarea>
</p>
<p>
<label for="location">Location:</label>
<input type="text" name="location"/>
</p>
<p>
<label for="time">Date:</label>
<input type="text" id="time" maxlength="25" size="25" name="time"><img src="{{ STATIC_URL }}../../static/cal.gif" width="16" height="16" border="0" alt="Pick a date">
</p>
<!-- Upload Form. Note enctype attribute! -->
{% csrf_token %}
<p>{{ img_form.non_field_errors }}</p>
<p>{{ img_form.imageFile.label_tag }}</p>
<p>
{{ img_form.imageFile.errors }}
{{ img_form.imageFile }}
</p>
<p><input type="submit" value="Add Upcoming Show"></input></p>
</form>
Here is my form Class:
class NewShowForm(forms.Form):
title=forms.CharField()
body=forms.CharField(widget=forms.TextArea)
location=forms.CharField()
time=forms.DateTimeField(required=True)
class ImageForm(forms.Form):
imageFile = forms.FileField(required=False, label='Select an Image')
Please help me!

If new_Show is a model, why not create a ModelForm instead of forms.Form?
So, instead of
class NewShowForm(forms.Form):
title=forms.CharField()
body=forms.CharField(widget=forms.TextArea)
location=forms.CharField()
time=forms.DateTimeField(required=True)
class ImageForm(forms.Form):
imageFile = forms.FileField(required=False, label='Select an Image')
why not using,
from django.forms import ModelForm
class NewShowForm(ModelForm):
class Meta:
model = NewShow
class ImageForm(ModelForm):
class Meta:
model = Image
?
Using ModelForm will ensure that form validation meets that of model. Moreover, it can cut off your code (especially line 6 to 11).

It will help to add these two lines to your view before if is_valid() to see the errors it's giving:
if request.method == 'POST':
img_form = ImageForm(request.POST, request.FILES)
show_form = NewShowForm(request.POST)
print(form.is_valid())
print(form.errors)
if show_form.is_valid():
You can paste the errors here and we can see what's the issue

Since you've put 2 Django forms together under one HTML form tag, when you submit the form on the front-end you're sending an extra field through request.POST that your NewShowForm doesn't have. If you combine both forms into a single Django form, you should be able to get this to work.

How can I build multiple submit buttons django form?

I have form with one input for email and two submit buttons to subscribe and unsubscribe from newsletter:
<form action="" method="post">
{{ form_newsletter }}
<input type="submit" name="newsletter_sub" value="Subscribe" />
<input type="submit" name="newsletter_unsub" value="Unsubscribe" />
</form>
I have also class form:
class NewsletterForm(forms.ModelForm):
class Meta:
model = Newsletter
fields = ('email',)
I must write my own clean_email method and I need to know by which button was form submited. But the value of submit buttons aren't in self.cleaned_data dictionary.
Could I get values of buttons otherwise?

Eg:
if 'newsletter_sub' in request.POST:
# do subscribe
elif 'newsletter_unsub' in request.POST:
# do unsubscribe

You can use self.data in the clean_email method to access the POST data before validation. It should contain a key called newsletter_sub or newsletter_unsub depending on which button was pressed.
# in the context of a django.forms form
def clean(self):
if 'newsletter_sub' in self.data:
# do subscribe
elif 'newsletter_unsub' in self.data:
# do unsubscribe

You can also do like this,
<form method='POST'>
{{form1.as_p}}
<button type="submit" name="btnform1">Save Changes</button>
</form>
<form method='POST'>
{{form2.as_p}}
<button type="submit" name="btnform2">Save Changes</button>
</form>
CODE
if request.method=='POST' and 'btnform1' in request.POST:
do something...
if request.method=='POST' and 'btnform2' in request.POST:
do something...

one url to the same view!
like so!
urls.py
url(r'^$', views.landing.as_view(), name = 'landing'),
views.py
class landing(View):
template_name = '/home.html'
form_class1 = forms.pynamehere1
form_class2 = forms.pynamehere2
def get(self, request):
form1 = self.form_class1(None)
form2 = self.form_class2(None)
return render(request, self.template_name, { 'register':form1, 'login':form2,})
def post(self, request):
if request.method=='POST' and 'htmlsubmitbutton1' in request.POST:
## do what ever you want to do for first function ####
if request.method=='POST' and 'htmlsubmitbutton2' in request.POST:
## do what ever you want to do for second function ####
## return def post###
return render(request, self.template_name, {'form':form,})
/home.html
<!-- #### form 1 #### -->
<form action="" method="POST" >
{% csrf_token %}
{{ register.as_p }}
<button type="submit" name="htmlsubmitbutton1">Login</button>
</form>
<!--#### form 2 #### -->
<form action="" method="POST" >
{% csrf_token %}
{{ login.as_p }}
<button type="submit" name="htmlsubmitbutton2">Login</button>
</form>

It's an old question now, nevertheless I had the same issue and found a solution that works for me: I wrote MultiRedirectMixin.
from django.http import HttpResponseRedirect
class MultiRedirectMixin(object):
"""
A mixin that supports submit-specific success redirection.
Either specify one success_url, or provide dict with names of
submit actions given in template as keys
Example:
In template:
<input type="submit" name="create_new" value="Create"/>
<input type="submit" name="delete" value="Delete"/>
View:
MyMultiSubmitView(MultiRedirectMixin, forms.FormView):
success_urls = {"create_new": reverse_lazy('create'),
"delete": reverse_lazy('delete')}
"""
success_urls = {}
def form_valid(self, form):
""" Form is valid: Pick the url and redirect.
"""
for name in self.success_urls:
if name in form.data:
self.success_url = self.success_urls[name]
break
return HttpResponseRedirect(self.get_success_url())
def get_success_url(self):
"""
Returns the supplied success URL.
"""
if self.success_url:
# Forcing possible reverse_lazy evaluation
url = force_text(self.success_url)
else:
raise ImproperlyConfigured(
_("No URL to redirect to. Provide a success_url."))
return url

I know this is old, but some of the answers are, to say the least, brief, and they do not address a common case where the form is not a django form.
This solution was inspired by this blog post. It relies on using a view class that is derived from django.views.generic.edit.FormMixin, e.g. CreateView, UpdateView or DeleteView. These provide the get_success_url method which exposes the button name in request
html
<html>
<body>
<form method="post">
<div>
<label> <input type="radio" name="select-type" value="A">Type A</label>
</div>
<div>
<label> <input type="radio" name="select-type" value="B">Type B</label>
</div>
<div>
<input type="submit" value="Use selected">
</div>
<div>
<input type="submit" name="no-selection" value="None of the above">
</div>
</form>
</body>
</html>
views.py
from django.views.generic import UpdateView
class GetType(UpdateView):
def get(self, request):
return render(request, 'get_type.html', {})
def post(self, request):
button = self.get_success_url()
print(button)
def get_success_url(self):
if 'no-selection' in self.request.POST:
return 'none selected'
return ''