I try to send email with amazon SES API docs below, and python return the code 250 meaing OK but my email got a failure message. Could anyone kindly tell me what maybe the problem? thank you
python:
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# https://us-east-2.console.aws.amazon.com/sesv2/home?region=us-east-2#/account
# https://console.aws.amazon.com/iam/home?#/s=SESHomeV4/us-east-2
mail_host = "email-smtp.us-east-2.amazonaws.com"
mail_user = "AKI....T7H"
mail_pass = "BHJ.....iS/x"
sender = 'thelou1s#...com'
receivers = 'thelou1s#...com'
msg = MIMEMultipart()
msg['From'] = sender
msg['To'] = receivers
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))
try:
print("try smtplib.SMTP")
smtp = smtplib.SMTP(mail_host, 587)
smtp.set_debuglevel(True)
print("try connect")
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
# smtpObj.connect(mail_host, 465)
print("try login")
smtp.login(mail_user, mail_pass)
print("try sendmail: " + msg.as_string())
smtp.sendmail(sender, receivers, msg.as_string())
print("Send Success")
smtp.close()
except smtplib.SMTPException:
print("Send Error")
log (Is retcode 250 means success in code side or user side?):
reply: retcode (250); Msg: b'Ok 010f017d8f0f1703-d018f2a9-833e-428e-9010-5e45818e51e4-000000'
data: (250, b'Ok 010f017d8f0f1703-d018f2a9-833e-428e-9010-5e45818e51e4-000000')
Send Success
emails from amazon:
Delivery Status Notification (Failure)
An error occurred while trying to deliver the mail to the following recipients:
thelou1s#...com
here is the email
Just validate your email in amazon console
#!/usr/bin/python
import smtplib
message = """From: Test <test#fromdomain.com>
To: test<test#todomain.com>
Subject: SMTP test
This is test
"""
try:
smtpObj = smtplib.LMTP('exhange.intranet',25)
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except SMTPException:
print "Error: unable to send email"
Hello basiclly im testing open relay server and here is question is there other method to send mail without any authetication than LMTP ?How i can implement this with SMTP which paramter is that ?
Sending a mail with only smtp is getting blocked on exhange easyli, there must be included NOT authetication information for exhange to pass it through.
To use SMTP without authentication, use code like the following:
smtpObj = smtplib.SMTP('exhange.intranet',25)
smtpObj.sendmail(sender, receivers, message)
smtpObj.quit()
I was just wondering if this was the correct way to send a email?
Does everything looks like it should be with a normal email program?
import smtplib
login_Info = ["testemailforthis#gmail.com", "Password"]
receivers = ["testemailforthis#gmail.com"]
message = """From: Me
To: People
Subject: Test email
Hi this is a test email :D"""
try:
email_thing = smtplib.SMTP("smtp.gmail.com", 587)
email_thing.ehlo()
email_thing.starttls()
email.login(login_Info[0], login_Info[1])
email_thing.sendmail(login_Info[0], receivers, message)
email_thing.close()
print("The email was sent!")
except:
print("The email was unable to send!")
I am developing an application using python where I need to send a file through mail. I wrote a program to send the mail but dont know there's something wrong. The code is posted below. Please any one help me with this smtp library. Is there's anything i m missing? And also can someone please tell me what will be the host in smtp! I am using smtp.gmail.com.
Also can any one tell me how can i email a file (.csv file). Thanks for the help!
#!/usr/bin/python
import smtplib
sender = 'someone#yahoo.com'
receivers = ['someone#yahoo.com']
message = """From: From Person <someone#yahoo.com>
To: To Person <someone#yahoo.com>
Subject: SMTP e-mail test
This is a test e-mail message.
"""
try:
smtpObj = smtplib.SMTP('smtp.gmail.com')
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except:
print "Error: unable to send email"
You aren't logging in. There are also a couple reasons you might not make it through including blocking by your ISP, gmail bouncing you if it can't get a reverse DNS on you, etc.
try:
smtpObj = smtplib.SMTP('smtp.gmail.com', 587) # or 465
smtpObj.ehlo()
smtpObj.starttls()
smtpObj.login(account, password)
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except:
print "Error: unable to send email"
I just noticed your request to be able to attach a file. That changes things since now you need to deal with encoding. Still not that tough to follow though I don't think.
import os
import email
import email.encoders
import email.mime.text
import smtplib
# message/email details
my_email = 'myemail#gmail.com'
my_passw = 'asecret!'
recipients = ['jack#gmail.com', 'jill#gmail.com']
subject = 'This is an email'
message = 'This is the body of the email.'
file_name = 'C:\\temp\\test.txt'
# build the message
msg = email.MIMEMultipart.MIMEMultipart()
msg['From'] = my_email
msg['To'] = ', '.join(recipients)
msg['Date'] = email.Utils.formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(email.MIMEText.MIMEText(message))
# build the attachment
att = email.MIMEBase.MIMEBase('application', 'octet-stream')
att.set_payload(open(file_name, 'rb').read())
email.Encoders.encode_base64(att)
att.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(file_name))
msg.attach(att)
# send the message
srv = smtplib.SMTP('smtp.gmail.com', 587)
srv.ehlo()
srv.starttls()
srv.login(my_email, my_passw)
srv.sendmail(my_email, recipients, msg.as_string())
I am successfully able to send email using the smtplib module. But when the emial is sent, it does not include the subject in the email sent.
import smtplib
SERVER = <localhost>
FROM = <from-address>
TO = [<to-addres>]
SUBJECT = "Hello!"
message = "Test"
TEXT = "This message was sent with Python's smtplib."
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
How should I write "server.sendmail" to include the SUBJECT as well in the email sent.
If I use, server.sendmail(FROM, TO, message, SUBJECT), it gives error about "smtplib.SMTPSenderRefused"
Attach it as a header:
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
and then:
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
Also consider using standard Python module email - it will help you a lot while composing emails. Using it would look like this:
from email.message import EmailMessage
msg = EmailMessage()
msg['Subject'] = SUBJECT
msg['From'] = FROM
msg['To'] = TO
msg.set_content(TEXT)
server.send_message(msg)
This will work with Gmail and Python 3.6+ using the new "EmailMessage" object:
import smtplib
from email.message import EmailMessage
msg = EmailMessage()
msg.set_content('This is my message')
msg['Subject'] = 'Subject'
msg['From'] = "me#gmail.com"
msg['To'] = "you#gmail.com"
# Send the message via our own SMTP server.
server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
server.login("me#gmail.com", "password")
server.send_message(msg)
server.quit()
try this:
import smtplib
from email.mime.multipart import MIMEMultipart
msg = MIMEMultipart()
msg['From'] = 'sender_address'
msg['To'] = 'reciver_address'
msg['Subject'] = 'your_subject'
server = smtplib.SMTP('localhost')
server.sendmail('from_addr','to_addr',msg.as_string())
You should probably modify your code to something like this:
from smtplib import SMTP as smtp
from email.mime.text import MIMEText as text
s = smtp(server)
s.login(<mail-user>, <mail-pass>)
m = text(message)
m['Subject'] = 'Hello!'
m['From'] = <from-address>
m['To'] = <to-address>
s.sendmail(<from-address>, <to-address>, m.as_string())
Obviously, the <> variables need to be actual string values, or valid variables, I just filled them in as place holders. This works for me when sending messages with subjects.
See the note at the bottom of smtplib's documentation:
In general, you will want to use the email package’s features to construct an email message, which you can then convert to a string and send via sendmail(); see email: Examples.
Here's the link to the examples section of email's documentation, which indeed shows the creation of a message with a subject line. https://docs.python.org/3/library/email.examples.html
It appears that smtplib doesn't support subject addition directly and expects the msg to already be formatted with a subject, etc. That's where the email module comes in.
import smtplib
# creates SMTP session
List item
s = smtplib.SMTP('smtp.gmail.com', 587)
# start TLS for security
s.starttls()
# Authentication
s.login("login mail ID", "password")
# message to be sent
SUBJECT = "Subject"
TEXT = "Message body"
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
# sending the mail
s.sendmail("from", "to", message)
# terminating the session
s.quit()
I think you have to include it in the message:
import smtplib
message = """From: From Person <from#fromdomain.com>
To: To Person <to#todomain.com>
MIME-Version: 1.0
Content-type: text/html
Subject: SMTP HTML e-mail test
This is an e-mail message to be sent in HTML format
<b>This is HTML message.</b>
<h1>This is headline.</h1>
"""
try:
smtpObj = smtplib.SMTP('localhost')
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except SMTPException:
print "Error: unable to send email"
code from: http://www.tutorialspoint.com/python/python_sending_email.htm
In case of wrapping it in a function, this should work as a template.
def send_email(login, password, destinations, subject, message):
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server.login(login, password)
message = 'Subject: {}\n\n{}'.format(subject, message)
for destination in destinations:
print("Sending email to:", destination)
server.sendmail(login, destinations, message)
server.quit()
try this out :
from = "myemail#site.com"
to= "someemail#site.com"
subject = "Hello there!"
body = "Have a good day."
message = "Subject:" + subject + "\n" + body
server.sendmail(from, , message)
server.quit()