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how do i make my code start at the same point the user was already on once they go through a valueerror exception?

I complete all the steps that I am given by my code and finally it asks 'again (Y or N)'. (I have written an except argument that will prevent someone from ending the code by typing a wrong answer) When they input the wrong answer it starts the user back to the top of the code. I would like it to output what step the user was already on.
CODE:
while True:
try:
choice = int(input("ONLY CHOOSE 1 AS THERE IS NO OTHER CHOICE: "))
assert choice == 1
if choice == (1):
userInp = input("TYPE: ")
words = userInp.split()
start_count = 0
for word in words:
word = word.lower()
if word.startswith("u"):
start_count += 1
print(f"You wrote {len(words)} words.")
print(f"You wrote {start_count} words that start with u.")
again = str(input("Again? (Y or N) "))
again = again.upper()
if again == "Y":
continue
elif again == "N":
break
except AssertionError:
print("Please type a given option.")
except ValueError:
print("Please type a given option.")
EDIT:
So I have made some progress but I have one last problem
CODE:
while True:
try:
choice = int(input("ONLY CHOOSE 1 AS THERE IS NO OTHER CHOICE: "))
assert choice == 1
if choice == (1):
userInp = input("TYPE: ")
words = userInp.split()
start_count = 0
for word in words:
word = word.lower()
if word.startswith("u"):
start_count += 1
print(f"You wrote {len(words)} words.")
print(f"You wrote {start_count} words that start with u.")
while True:
again = input("again? (Y or N)")
if again not in "yYnN":
continue
break
if again == "Y":
continue
elif again == "N":
break
except AssertionError:
print("Please type a given option.")
except ValueError:
print("Please type a given option.")
The problem is that the variable 'again' is not defined when outside of the while loop (outside the while loop that is in the while loop). How do I fix this?

You could create another loop (inside this main loop) where you are asking for input, and have a try block there, so that it loops just the section where the user is giving input until they give correct input.

Python 3 - How to create a code that allows the user to input both letters and numbers when entering their password

I'm very new to python and have been assigned homework where my professor wants us to create a loop for when a user enters their pin (has to be numbers) to log in. The code has to allow only 3 attempts and has to lock out the user for 10 seconds (if PW is wrong) before looping back to allowing them to attempt to login in again.
So far I have been successful in creating a basic code for allowing 3 attempts.
original_pin = 1122
count=0
while count < 3:
secret_pin = int(input('Enter Your Pin: '))
if secret_pin == original_pin:
print('DOOR UNLOCKED!!')
break
else:
print('WRONG PIN!! (TRY AGAIN!)')
count += 1
The issue I'm currently having is that if the user enters a letter, I get this error message (I entered "d") I'm not sure what to change in line 7 so that letters can be accepted as a input.
Traceback (most recent call last):
File "C:/Users/Indias/AppData/Local/Programs/Python/Python39/test.py", line 7, in <module>
secret_pin = int(input('Enter Your Pin: '))
ValueError: invalid literal for int() with base 10: 'd'

You'll have to change two things:
First, you'll need to store the pin as a string instead of an integer. You can do this by surrounding it in either single or double quotes:
original_pin = "1122" # or '1122'
Second, you'll need to remove the int() surrounding input(), because that converts the user's input into an integer.
So if you wanted the pin to be "1122d", the code would look like:
original_pin = "1122d"
count=0
while count < 3:
secret_pin = input('Enter Your Pin: ')
if secret_pin == original_pin:
print('DOOR UNLOCKED!!')
break
else:
print('WRONG PIN!! (TRY AGAIN!)')
count += 1
Edit re: "has to lock out the user for 10 seconds (if PW is wrong)"
You can accomplish this by calling time.sleep(10), which causes the program to wait for 10 seconds before continuing. So the final code with that added looks like:
import time # so we can call time.sleep()
original_pin = "1122d"
count=0
while count < 3:
secret_pin = input('Enter Your Pin: ')
if secret_pin == original_pin:
print('DOOR UNLOCKED!!')
break
else:
print('WRONG PIN!! (TRY AGAIN!)')
count += 1
time.sleep(10) # timeout for 10 seconds

Remove the 'int(' on line 7, it's telling your program to only accept integers, and not accept letters, so you're throwing an error. That error is just telling you that letters aren't integers essentially.
original_pin = "1122d" #added a 'd' and made the variable a string!
count=0
while count < 3:
secret_pin = input('Enter Your Pin: ') #removed 'int'
if secret_pin == original_pin:
print('DOOR UNLOCKED!!')
break
else:
print('WRONG PIN!! (TRY AGAIN!)')
count += 1

Use error handling when inputting data as a user can any input the code may throw error and crash
original_pin = 1122
count=0
while count < 3:
try:
secret_pin = (input('Enter Your Pin: '))
except ValueError:
print("Enter Digits only")
finally:
if secret_pin == str(original_pin):
print('DOOR UNLOCKED!!')
break
else:
print('WRONG PIN!! (TRY AGAIN!)')
count += 1

don't convert your input into an integer. You can still do the same comparative statement with two strings, like you currently are with two integers.
pin_pass = input("Put pin in")
correct = "1234"
count = 0
if pin_pass == correct:
print("Correct")
else:
count += 1
print("Wrong")

original_pin = 1122
count = 0
while count < 3:
secret_pin = input("Enter Your Pin: ")#remove int
try:
secret_pin = int(secret_pin)#convert input to int
except:
print("Enter Integer Value")#if not then print reason
"""Checking if secret_pin is int. and secret_pin == original_pin"""
if isinstance(secret_pin, int) and secret_pin == original_pin:
print("DOOR UNLOCKED!!")
break
else:
print("WRONG PIN!! (TRY AGAIN!)")
count += 1

Completing a Startup Menu in Function - Python

I'm trying to finish writing this function that contains five different options and uses a While loop to allow the user to enter in their choice with the entry '5' exiting the loop. Below is the code I have so far, I'm having trouble completing the menu part within the def_main function. I keep getting an error after else:
break
Any input would be appreciated. Thank you for reading.
def main():
menuOption = 0
while 1 == 1:
print("1. Expanded Sum\n2. Reverse Expanded Sum\n3. Reverse Integer\n4. Product Table\n5. Exit\n")
menuOption = int(input("Enter correct menu option: "))
while menuOption<1 or menuOption>5:
print("Incorrect menu option!!")
menuOption = int(input("Enter correct menu option: "))
if menuOption == 5:
return
while 1 == 1:
num = int(input("Enter positive Integer: "))
if num <= 0:
print("You have entered negative integer or zero.")
continue
else:
break
if menuOption == 1:
printSum(num, int(False))
elif menuOption == 2:
printSum(num, int(True))
elif menuOption == 3:
print(str(reverseInt(num)))
elif menuOption == 4:
printProductTable(num)
if __name__ == "__main__": main()
def printSum(n, reverse):
s = sum(range(n+1))
if reverse:
print('+'.join(str(i) for i in range(1, n+1)) + ' = ' + str(s))
else:
print('+'.join(str(i) for i in range(n, 0, -1)) + ' = ' + str(s))
def reverse_int(n):
Reverse = 0
while(n > 0):
Reminder = n %10
Reverse = (Reverse *10) + Reminder
n = n //10
print(Reverse)
def printProductTable(n):
for row in range(1,n+1):
print(*("{:3}".format(row*col) for col in range(1, n+1)))

What is the error you are getting at the break?
It looks like your spacing might be off in the continue, I assume your else goes to the if at the top of the statement, but your continue does not match with it.

Rather than doing while 1==1 you can write while True. And also you have already checked while menuOption<1 or menuOption>5. So if your menuOption is a negative number it already falls into this condition as, say, -2 < 1.
And also seems like your code is not formatted. Means, continue is just above the else. It will generate the error. Re-formate your code. Give proper indentation.

How do i make it so that when the user enters a number to check if it's odd or even and then the code asks the user to input 1 or 2 again

print ("[1] Identify, [2] quit")
user = int(input())
while (user) == 1:
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))
if (user) == 2:
quit()
The code is firstly asking the user to input 1 or 2, the code will then ask the user to input a number and then the code will say if the number is odd or even but I'm trying to make it so that after the user has input the number to check if it's odd or even, it then asks to enter 1 or 2 again.

You need to put your first two lines inside the loop. Here's one way to do it:
while True:
print("[1] Identify, [2] Quit")
user = int(input())
if user == 1:
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is even".format(num))
else:
print("{0} is odd".format(num))
elif user == 2:
break
quit()

The best way to do it would be to put it all inside a while loop and exit if 2 is entered:
while True:
user = int(input("[1] Identify, [2] quit "))
if user==1:
num = int(input("Enter a number: "))
if not num%2:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))
else:quit()

Not decrypting what I have encrypted [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I am having an issue with my decryption algorithm. It outputs to a text file a huge list of repeated ((((( and other things. What's wrong with my code, and how can I fix it? I think it has something to do with the last function of the decrypting process. But I am not sure.
import sys
import os.path
def convertToNum(ch):
alpha ='''abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890`~!##$%^&()-_=+[]{}\\|;:\'",./<>?\n\t '''
index = alpha.find(ch)
return index
def Matrix(text):
evenChars = []
oddChars = []
index = 0
for ch in text:
if index % 2 == 0:
#this is an even character
evenChars.append(convertToNum(ch))
else: #this is an odd character
oddChars.append(convertToNum(ch))
index += 1
masterList = []
if (evenChars >(oddChars)):
oddChars.append(convertToNum(" "))
for i in range(len(evenChars)):
masterList.append([evenChars[i],oddChars[i]])
return masterList
def getMatrices(text):
print("A list of integers acts as a key. Each value is stored in a,b,c,d. Please enter the values for: ")
a = int(input("\nA :"))
b = int(input("B :"))
c = int(input("C :"))
d = int(input("D :"))
if (a*d) - (c*b) == 1:
print("Valid Key\n")
elif (a*d) - (c*b) ==-1:
print("Valid Key\n")
else:
print("Invalid Key")
sys.exit()
indList = Matrix(text)
encryptList = []
for nestList in indList:
x = nestList[0]
y = nestList[1]
encryptList.append(x*a + y*c)
encryptList.append(x*b + y*d)
return encryptList
def backtoText(text):
print("A list of integers acts as a key. Each value is stored in a,b,c,d. If you have already entered a key to encrypt, please use the same key. Please enter the values for: ")
a = int(input("\nA :"))
b = int(input("B :"))
c = int(input("C :"))
d = int(input("D :"))
if (a*d) - (c*b) == 1:
print("Valid Key\n")
elif (a*d) - (c*b) ==-1:
print("Valid Key\n")
else:
print("Invalid Key")
sys.exit()
keyA = ((a*d) - (c*b)) * (d)
keyB = ((a*d) - (c*b)) * (-b)
keyC = ((a*d) - (c*b)) * (-c)
keyD = ((a*d) - (c*b)) * (a)
print(keyA,keyB,keyC,keyD)
evenNums=[]
oddNums=[]
index = 0
for ch in text: #ch takes the place of the next characer in plain text
if index % 2 == 0:
evenNums.append(ch)
else:
oddNums.append(ch)
index += 1
decrypted= []
if (evenNums >(oddNums)):
oddNums.append(" ")
for i in range(len(evenNums)):
decrypted.append([evenNums[i],oddNums[i]])
indList = decrypted
decryptList = []
for nestList in indList:
x = nestList[0]
y = nestList[1]
decryptList.append(x*keyA + y*keyC)
decryptList.append(x*keyB + y*keyD)
return decryptList
def outPutString(text):
alpha = '''abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890`~!##$%^&*()-_=+[]{}\\|;:\'",./<>?\n\t '''
finalString =''
text = backtoText(text)
for ch in text:
finalString += alpha[ch]
return finalString
def main():
print("What would you like to do?: ")
answer = input("1) Encrypt File\n2) Decrypt File\n\n")
if answer == '1':
fileName = input("Please enter a filename to encrypt : ")
if not os.path.isfile(fileName):
print("Invalid Entry. Computer will self destruct in 10 seconds\n\n")
sys.exit()
plaintext_file = open(fileName)
text = ""
for line in plaintext_file.readlines():
text += line + "\n"
plaintext_file.close()
name =input("Please enter the file name that you want to save the encrypted file as : ")
if os.path.isfile(name) == False:
matrices = getMatrices(text)
for value in matrices:
encrypted_file.write(str(value) + "\n")
encrypted_file.close()
encrypted_file.write(str(getMatrices(text)))
encrypted_file.close()
elif os.path.isfile(name) == True:
answer2 = input("The file already exists. Would you like to overwrite it? >> Type y/n >> ")
if answer2 == 'y':
encrypted_file = open(name,'w')
encrypted_file.write(str(getMatrices(text)))
encrypted_file.close()
elif answer == 'n':
print("Thank you for wasting time :D \n\n")
sys.exit()
else:
print("Invalid response. It's not hard to put y or n.\n\n")
sys.exit()
elif answer == '2':
fileName = input("Please enter a filename to decrypt : ")
if not os.path.isfile(fileName):
print("Invalid Entry. Computer will self destruct in 10 seconds\n\n")
sys.exit()
Encrypted_file = open(fileName)
text = []
for line in Encrypted_file.readlines():
text.append(line)
Encrypted_file.close()
name = input("Please enter the file name that you want to save the decrypted text saved as : ")
if os.path.isfile(name) == False:
Decrypted_file = open(name,'w')
Decrypted_file.write(str(outPutString(text)))
Decrypted_file.close()
elif os.path.isfile(name) == True:
answer2 = input("The file already exists. Would you like to overwrite it? >> Type y/n >> ")
if answer2 == 'y':
Decrypted_file = open(name,'w')
Decrypted_file.write(str(outPutString(text)))
Decrypted_file.close()
elif answer == 'n':
print("Thank you for wasting time :D \n\n")
sys.exit()
else:
print("Invalid response. It's not hard to put y or n.\n\n")
sys.exit()
else:
print("Invalid Entry. The program will terminate")
sys.exit()
main()

Well this was a fun one!
in def convertToNum(ch): the alpha does not equal the alpha in def outPutString(text): (missing an *) causing (in my case) tabs instead of spaces and a ? to appear at the end of my decrypted string. I would recommend using a global variable to prevent things like this happening in the future.
Your encryption algorithm worked great and didn't need any adjustment. There were some incompatible variable types in the decryption phase but I managed to get everything to work and have included the working code (my comments marked with ##) I hope this helped.
Edit: As Eric points out in the comments, if (evenNum>(oddNum)) is probably not doing what you want it to do. According to the python docs:
Sequence objects may be compared to other objects with the same sequence type. The comparison uses lexicographical ordering: first the first two items are compared, and if they differ this determines the outcome of the comparison; if they are equal, the next two items are compared, and so on, until either sequence is exhausted.
I Assume you want to compare the lengths of the two arrays to make sure they are equal. If this is the case then you would want to use if (len(evenNum)>len(oddNum))
import sys
import os.path
def convertToNum(ch):
alpha ='''abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890`~!##$%^&*()-_=+[]{}\\|;:\'",./<>?\n\t ''' #you forgot your asterix
index = alpha.find(ch)
return index
def Matrix(text):
evenChars = []
oddChars = []
index = 0
for ch in text:
if index % 2 == 0:
#this is an even character
evenChars.append(convertToNum(ch))
else: #this is an odd character
oddChars.append(convertToNum(ch))
index += 1
masterList = []
if (len(evenChars) >len(oddChars)): ## comparing lengths instead of contents
oddChars.append(convertToNum(" "))
for i in range(len(evenChars)):
masterList.append([evenChars[i],oddChars[i]])
return masterList
def getMatrices(text):
print("A list of integers acts as a key. Each value is stored in a,b,c,d. Please enter the values for: ")
a = int(input("\nA :"))
b = int(input("B :"))
c = int(input("C :"))
d = int(input("D :"))
if (a*d) - (c*b) == 1:
print("Valid Key\n")
elif (a*d) - (c*b) ==-1:
print("Valid Key\n")
else:
print("Invalid Key")
sys.exit()
indList = Matrix(text)
encryptList = []
for nestList in indList:
x = nestList[0]
y = nestList[1]
encryptList.append(x*a + y*c)
encryptList.append(x*b + y*d)
return encryptList
def backtoText(text):
print("A list of integers acts as a key. Each value is stored in a,b,c,d. If you have already entered a key to encrypt, please use the same key. Please enter the values for: ")
a = int(input("\nA :"))
b = int(input("B :"))
c = int(input("C :"))
d = int(input("D :"))
if (a*d) - (c*b) == 1:
print("Valid Key\n")
elif (a*d) - (c*b) ==-1:
print("Valid Key\n")
else:
print("Invalid Key")
sys.exit()
keyA = ((a*d) - (c*b)) * (d)
keyB = ((a*d) - (c*b)) * (-b)
keyC = ((a*d) - (c*b)) * (-c)
keyD = ((a*d) - (c*b)) * (a)
print(keyA,keyB,keyC,keyD)
evenNums=[]
oddNums=[]
index = 0
newText = text[0].strip('[ ]') ## these two lines convert the string to an array
textArray = newText.split(',')
for ch in textArray: ## changed text to textArray(see above) #ch takes the place of the next characer in plain text
if index % 2 == 0:
evenNums.append(int(ch)) ## converting string number to int for later operations
else:
oddNums.append(int(ch))
index += 1
decrypted= []
if (len(evenNums) >len(oddNums)): ## comparing lengths instead of arrays
oddNums.append(" ")
for i in range(len(evenNums)):
decrypted.append([evenNums[i],oddNums[i]])
indList = decrypted
decryptList = []
for nestList in indList:
x = nestList[0]
y = nestList[1]
decryptList.append(x*keyA + y*keyC)
decryptList.append(x*keyB + y*keyD)
return decryptList
def outPutString(text):
alpha = '''abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890`~!##$%^&*()-_=+[]{}\\|;:\'",./<>?\n\t '''
finalString =''
text = backtoText(text)
for ch in text:
finalString += alpha[ch]
print(finalString)
return finalString
def main():
print("What would you like to do?: ")
answer = input("1) Encrypt File\n2) Decrypt File\n\n")
if answer == '1':
fileName = input("Please enter a filename to encrypt : ")
if not os.path.isfile(fileName):
print("Invalid Entry. Computer will self destruct in 10 seconds\n\n")
sys.exit()
plaintext_file = open(fileName)
text = ""
for line in plaintext_file.readlines():
text += line ##+ "\n" ##you don't need to add a new line as '\n' is already included at the end of every line.
plaintext_file.close()
name =input("Please enter the file name that you want to save the encrypted file as : ")
if os.path.isfile(name) == False:
##matrices = getMatrices(text)
##for value in matrices:
##encrypted_file.write(str(value) + "\n")
##encrypted_file.close()
## I added the line below(and removed lines above) to be consistent with your later usage
encrypted_file = open(name,'w')
encrypted_file.write(str(getMatrices(text)))
encrypted_file.close()
elif os.path.isfile(name) == True:
answer2 = input("The file already exists. Would you like to overwrite it? >> Type y/n >> ")
if answer2 == 'y':
encrypted_file = open(name,'w')
encrypted_file.write(str(getMatrices(text)))
encrypted_file.close()
elif answer == 'n':
print("Thank you for wasting time :D \n\n")
sys.exit()
else:
print("Invalid response. It's not hard to put y or n.\n\n")
sys.exit()
elif answer == '2':
fileName = input("Please enter a filename to decrypt : ")
if not os.path.isfile(fileName):
print("Invalid Entry. Computer will self destruct in 10 seconds\n\n")
sys.exit()
Encrypted_file = open(fileName)
text = []
for line in Encrypted_file.readlines():
text.append(line)
Encrypted_file.close()
name = input("Please enter the file name that you want to save the decrypted text saved as : ")
if os.path.isfile(name) == False:
Decrypted_file = open(name,'w')
Decrypted_file.write(str(outPutString(text)))
Decrypted_file.close()
elif os.path.isfile(name) == True:
answer2 = input("The file already exists. Would you like to overwrite it? >> Type y/n >> ")
if answer2 == 'y':
Decrypted_file = open(name,'w')
Decrypted_file.write(str(outPutString(text)))
Decrypted_file.close()
elif answer == 'n':
print("Thank you for wasting time :D \n\n")
sys.exit()
else:
print("Invalid response. It's not hard to put y or n.\n\n")
sys.exit()
else:
print("Invalid Entry. The program will terminate")
sys.exit()
main()