I am attempting to get the Keys in a dictionary
My current method of doing this is using a for loop to iterate through the dictionary. The value of each key is unknown as they are randomly generated.
Dictionary Format for _GENOME[xx][yy].WEIGHTS is {(0,0) : 2, (1,3) : 3}
for i in _GENOME[xx][yy].WEIGHTS:
print(xx,yy,_GENOME[xx][yy].WEIGHTS[i])
I understand my solution will need to use the .index() function. However i can't find a way to implement this into my system.
My hope is to print out each variable of the key tuple separately.
Does this help?
for key, value in d.items():
print (("Key - (#1:%s, #2:%s), value - %s ") %(key[0], key[1], value))
where d is whatever dictionary object you have (_GENOME[xx][yy].WEIGHTS ?)
Related
dict = {"Pond":"A Lake",
"Lake":"A Pond",
"Book":"Bunch of Pages",
"Chaddi":"The Undies"
}
for key in dict:
print(f"{Key}:{dict[key]}")
You incorrectly capitalized the letter k. You wrote Key. Use key.
If d is your dictionary (you should not use dict as the name of your dictionary):
for key in d:
print(f"{key}:{d[key]}")
Someone has already solved your mistake.
Here I did other alternative solutions, and more understandable.
for key, value in dict.items():
print(key,":",value)
A few things. First you simply misspelled the word key, as answered by #oda. Fix that capital k in the print function and your code will work.
Second, don't call a dictionary dict, since dict is already a function in python:
d = dict()
creates a new empty dictionary.
If you create a variable named dict you'll overshadow the dict function and you'll probably get some error sooner or later.
In a nutshell, I want to replace the Key from a Dictionary with the value of another Dictionary that has the same Key as the first dict.
The output I'm expecting is the following:
{'Sneakers-Viewed Product-(not set)' : 2}
Thanks in advance!
You can easily do this in one step:
dictionary[new_key] = dictionary.pop(old_key)
I have a list of dicts ('sortings') that I am trying to iterate through to access a values in one specific key of each dict. My code keeps saying that there is a key error for the desired value in the dict. If I print inside the for loop, it prints with the values entered but once I exit the for loop it says there is a key error.
for i in range(sort_len):
sentence = sortings[i]['content']
containing_messages.append(sentence)
print(containing_messages)
This is an answer for my understanding of the question. I would require the given input and expected output to provide a better answer.
list_of_dicts = [{'keya':'value1_1','keyb':'value2_1','keyc':'value3_1'},
{'keya':'value1_2','keyb':'value2_2','keyc':'value3_2'},
{'keya':'value1_3','keyb':'value2_3','keyc':'value3_3'}]
list_of_key_values = [my_dict['keyb'] for my_dict in list_of_dicts]
print list_of_key_values
I have created a python dictionary with a structure like :-
mydict = {'2018-08' : [32124,4234,23,2323,32423,342342],
'2018-07' : [13123,23424,2,3,4343,4232,2342],
'2018-06' : [1231,12,12313,12331,3123131313,434546,232]}
I want to check if any value in the values of key '2018-08' match with any values of other keys. is there a short way to write this?
You can simply loop over your expected values of mydict, and then for each of them check if its present in any of the values of the dictionary
You can use the idiom if item in list to check if item item is present in the list list
expected_values = mydict['2018-08']
found = False
for expected in expected_values:
for key in mydict:
if expected in mydict[key]:
found = True
break
Take into account that is a brute force algorithm and it may not be the optimal solution for larger dictionaries
The question is vague, so I am assuming that you want the values in the target month (e.g. 2018-08) that are contained somewhere within the other months.
Sets are much faster for testing membership compared to list iteration.
target = '2018-08'
s = set()
for k, v in mydict.iteritems():
if k != target:
s.update(v)
matches = set(mydict[target]) & s
Can use itertools.chain to create a long list
import itertools
for key,value in mydict.items():
temp_dict = mydict.copy()
temp_dict.pop(key)
big_value_list=list(itertools.chain(*temp_dict.values()))
print(key, set(value) & set(big_value_list))
Dry run by changing your provided inputs
mydict = {'2018-08' : [32124,4234,23,2323,32423,342342],
'2018-07' : [13123,23424,2,3,4343,4232,2342],
'2018-06' : [1231,12,12313,12331,3123131313,434546,232,342342,2342]}
Output:
('2018-08', set([342342]))
('2018-07', set([2342]))
('2018-06', set([342342, 2342]))
I have 2 dict, one original and one for mapping the original one's key to another value simultaneously,for instance:
original dict:
built_dict={'China':{'deportivo-cuenca-u20':{'danny':'test1'}},
'Germany':{'ajax-amsterdam-youth':{'lance':'test2'}}}
mapping dict:
club_team_dict={'deportivo-cuenca-u20':'deportivo','ajax-amsterdam-youth':'ajax'}
It works well if I use the following code to change the key of the nested dict of original dict,like
def club2team(built_dict,club_team_dict):
for row in built_dict:
# print test_dict[row]
for sub_row in built_dict[row]:
for key in club_team_dict:
# the key of club_team_dict must be a subset of test_dict,or you have to check it and then replace it
if sub_row==key:
built_dict[row][club_team_dict[sub_row]] = built_dict[row].pop(sub_row)
return built_dict
and the result:
{'Germany': {'ajax': {'lance': 'test2'}}, 'China': {'deportivo': {'danny': 'test1'}}}
so far so good, however if I have a dict with multiple key mapping to the same key,for example,my original dict is like
built_dict={'China':{'deportivo-cuenca-u20':{'danny':'test1'}},
'Germany':{'ajax-amsterdam-youth':{'lance':'test2'},
'ajax-amsterdam':{'tony':'test3'}}}
and the mapping dict with more then 1 key mapping to the same value,like:
club_team_dict={'deportivo-cuenca-u20':'deportivo',
'ajax-amsterdam-youth':'ajax',
'ajax-amsterdam':'ajax'}
as you can see, both 'ajax-amsterdam-youth'and 'ajax-amsterdam-youth' are mapping to 'ajax',and the trouble is when I use the same code to execute it, the original dict's size has been changed during the iteration
RuntimeError: dictionary changed size during iteration
I want to get a result with nested list for the same key like this
{'Germany': {'ajax':[{'lance': 'test2'},
{'tony' : 'test3'}]}},
'China': {'deportivo': [{'danny': 'test1'}]}}
Well I have found a solution for this,the code:
def club2team(built_dict,club_team_dict):
for row in built_dict:
# print test_dict[row]
for sub_row in built_dict[row].keys():
for key in club_team_dict:
# the key of club_team_dict must be a subset of test_dict,or you have to check it and then replace it
if sub_row==key:
# built_dict[row][club_team_dict[sub_row]] = built_dict[row].pop(sub_row)
built_dict[row].setdefault(club_team_dict[sub_row],[]).append(built_dict[row].pop(sub_row))
return built_dict
pay attention to the for sub_row in built_dict[row].keys(): and setdefault() method, I used to believe that in python 2.7, the default iteration for dict is just iterate the keys(), however, this time it proves it's a little different, maybe you have better solution, please show me and it will be appreciate,thank you