tree.put(key, value) insertion - python

So I'm working on an assignment for a data structures class, and one question is to create a put(key, value) method for an AVLTree. I know I have to adding the balancing method, but right now I'm just on the actual insertion. I want the function to work where you can create a tree and type newTree.put(key value) and have it work. Right now I have
class node:
def __init__(self, key, value):
self.key = key
self.value = value
self.left = None
self.right = None
self.height = 0
class AVLTreeMap:
def __init__(self, key, value):
self.root = node(key, value)
#inserting new key-value pair, NEED TO ADD BALANCING ABILITY
def put(self, key, value, height=0):
if(key < self.root.key):
if(self.root.left == None):
self.root.left = node(key, value)
self.root.left.height = height+1
else:
self.root = self.root.left
self.put(key, value, height+1)
else:
if(self.root.right == None):
self.root.right = node(key, value)
self.root.right.height = height+1
else:
self.root = self.root.right
self.put(key, value, height+1)
However, the recursive aspect of put just discounts the root, and creates a new tree of just one parent and that node as one child. Is this the right way to go about this, or is there an easier way? Also, if I do it this way, how do you recurse left and right in this method?

Related

Calculating no. of nodes in a Binary Tree in O(1)?

I am taking Data Structures and Algorithm course from Jovian. Currently on Binary Tress, but I am stuck on one question where we need to calculate no. of nodes in O(1) time.
Firstly here's how the final class TreeMap looks like:
class TreeMap:
def __init__(self):
self.root = None
def __setitem__(self, key, value):
node = find(self.root, key)
if not node:
self.root = insert(self.root, key, value)
self.root = balance_tree(self.root)
else:
update(self.root, key, value)
def __getitem__(self, key):
node = find(self.root, key)
return node.value if node else None
def __iter__(self):
return (x for x in list_all(self.root))
def __len__(self):
return size(self.root)
def display(self):
return display_keys(self.root):
Currently, it's calculating no. of nodes with the recursion method. I think we just need a counter and increment every time a node is created and we also have a hint to modify the BSTNode class. So this is how I did it:
class BSTNode:
counter = 0
def __init__(self, key, value=None):
self.key = key
self.value = value
self.left = None
self.right = None
self.parent = None
BSTNode.counter += 1
But I don't know how do I implement or use the counter in __len__ function in class TreeMap. Any help would be much appreciated.
Here is the link to Jovian Lesson: https://jovian.ai/learn/data-structures-and-algorithms-in-python/lesson/lesson-2-binary-search-trees-traversals-and-balancing

Understanding variable share between recursion

I was doing this leetcode question:(https://leetcode.com/problems/binary-tree-inorder-traversal/) in which I came up with this solution:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def inorderTraversal(self, root: TreeNode) -> List[int]:
if root is None:
return None
result = []
if root.left is None and root.right is None:
result.append(root.val)
return result
return self.traverse(root,result)
def traverse(self,node,result):
if node is None:
return result
result = self.traverse(node.left,result)
result.append(node.val)
result = self.traverse(node.right,result)
return result
However I found out I actually don't need to store the results of recursion call in the variable and I can simply do this:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def inorderTraversal(self, root: TreeNode) -> List[int]:
if root is None:
return None
result = []
if root.left is None and root.right is None:
result.append(root.val)
return result
return self.traverse(root,result)
def traverse(self,node,result):
if node is None:
return result
self.traverse(node.left,result)
result.append(node.val)
self.traverse(node.right,result)
return result
My understanding was that in each recursion call, we are passing a reference to the result variable, not copying the result variable, so what is happening is that when the recursion call gets to the left most node, it appends the value and returns to its parent node, and since we had pass by reference, the result variable in parent node already has the leftmost node added to it, so it just adds the parent node to it and keep continuing on the recursion.
Is my understanding correct or is there something else going on?
Thanks
Yes, your understanding is right.
Note: you are sharing the same code in both boxes.

Will the memory reference of the Node object be same in both cases?

class Node:
def __init__(self, key, value):
self.key = key
self.value = value
self.prev = None
self.next = None
Consider this as the Node(DLL) Structure, I have following two implementations of a function that I care to use:
1.
def put(self, key, value):
"""
:type key: int
:type value: int
:rtype: void
"""
if key not in self.hashmap:
self.hashmap[key] = Node(key, value)
self.add(hashmap[key])
2.
self.hashmap[key] = Node(key, value)
self.add(Node(key, value))
In both the cases, I am trying to add the Node value to the class structure. In (1), I am quite sure that the value of hashmap[key] which is Node(key, value) will be added.
My hunch tells me that in case (2), a new object will be created and added rather than the same object that's created in line self.hashmap[key] = Node(key, value).
Is my hunch correct? Why or why not?

default argument in recursive class method of python

Inside a recursive class function, how do i use a class member as default argument?
I am currently using following snippet that works (python 3). height is recursive class function. Default argument that i want to use for node is self._root. In order to achieve this, i do something like following but thats a very round about way where i have to define another function height_tree. Is there a more direct approach?
# following code works #
class BTree:
def __init__(self, node=None):
self._root = node
def height_tree(self):
return self.height(self._root)
def height(self, node):
if node is not None:
height = max(self.height(node.get_left()), self.height(node.get_right())) + 1
else:
height = 0
return height
I want to do something like following but it obviously doesn't works !
def height(self, node=self._root)
# code from above follows
I however cannot use alternate trick of assigning root to node when node is None since that is one of the end condition in recursion
def height(self, node)
if node is None:
node = self._root
# this will conflict with logic in code block above#
Are there any recommended ways to handle such a situation?
You can use a sentinel object:
sentinel = object()
def height(self, node=sentinel)
if node is sentinel:
node = self._root
...
Since such object would have a unique memory address, it would never be identical to any other object (including None).
You can always create arbitrary sentinels:
SENTINEL = object()
class BTree:
def __init__(self, node=None):
self._root = node
def height_tree(self):
return self.height(self._root)
def height(self, node=SENTINEL):
if node is SENTINEL:
node = self._root
elif node is not None:
height = max(self.height(node.get_left()), self.height(node.get_right())) + 1
else:
height = 0
return height

Python object instantiation

I am very new to python and need some help with instantiating an object. The python interpreter is giving me trouble when instantiating an object of a class I defined. There are two classes, BTNode and BST (which are stored in files bst_node.py and bst.py respectively):
# file: bst_node.py
class BTNode:
"""a binary search tree node implementation"""
def ___init___(self, value):
self.value = value
self.left is None
self.right is None
self.parent is None
def ___init___(self, value, left, right, parent):
"""set the parameters to corresponding class members"""
self.value = value
self.left = left
self.right = right
self.parent = parent
def is_leaf(self):
"""check whether this node is a leaf"""
if self.left.value is None and self.right.value is None:
return True
return False
# file: bst.py
from bst_node import *
class BST:
"""a binary search tree implementation"""
def ___init___(self, value):
self.root = BTNode(value)
def insert(self, curRoot, newValue):
if curRoot.is_leaf():
if newValue < curRoot.value:
newNode = BTNode(newValue, None, None, curRoot)
curRoot.left = newNode
else:
newNode = BTNode(newValue, None, None, curRoot)
curRoot.right = newNode
else:
if newValue < curRoot.value:
self.insert(curRoot.left, newValue)
else:
self.insert(curRoot.right, newValue)
So, in the interpreter I do:
import bst as b
t1 = b.BST(8)
and I get an error which says that this constructor takes no arguments
The constructor clearly takes an argument value so what is going wrong here? How can I fix this error?
Thanks, all help is greatly appreciated!
The first issue is that you called your functions ___init___ instead of __init__. All of the 'special methods' use two underscores.
A second issue in this code is that in BTNode you redefined __init__. You can't overload functions in python. When you reclare __init__ you effectively deleted the first constructor.
A third issue is your usage of is. is is an operator that checks whether two objects are exactly the same and returns True or False. In the constructor, you have a few self.left is None is examining the value of self.left (which wasn't declared yet), and examining whether or not it is None. To set it, use = as follows:self.left = None
To fix the second and third issue you should use default argument values. For example:
def __init__(self, value, left=None, right=None, parent=None):
In addition to the number of underscores problem, you should replace
def ___init___(self, value):
self.value = value
self.left is None
self.right is None
self.parent is None
def ___init___(self, value, left, right, parent):
"""set the parameters to corresponding class members"""
self.value = value
self.left = left
self.right = right
self.parent = parent
with
def __init__(self, value, left=None, right=None, parent=None):
"""set the parameters to corresponding class members"""
self.value = value
self.left = left
self.right = right
self.parent = parent
Because as #Moshe points out, you can't overload functions, you should use default arguments insted.
Changing ___init___ to __init__ should fix it. (2 underscores vs 3)

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