I want to open 'text' botton but I can't open it.
How can I do?
from selenium import webdriver
import time
driver = webdriver.Chrome(path)
driver.get("https://www.pdfescape.com/account/unregistered/")
time.sleep(0.5)
elem = driver.find_element_by_id("dStartNew").click()
time.sleep(0.5)
elem = driver.find_element_by_id("PdfNew_input_pc").click()
driver.find_element_by_css_selector("[value=\"2\"]").click()
#time.sleep(0.5)
elem = driver.find_element_by_id("PdfNew_input_ps").click()
driver.find_element_by_css_selector("[value=\"a4\"]").click()
#time.sleep(0.5)
driver.find_element_by_xpath('//*[#id="PdfNew_form"]/input[1]').click()
time.sleep(0.5)
driver.find_elements_by_class_name('Add-Text').click()
Problem code : driver.find_elements_by_class_name('Add-Text').click()
The element you wanted to click has no class name - it has the title "Add Text", also you are using find_elements instead of find_element which changes the result type.
So you could select it with:
driver.find_element_by_css_selector('a[title=\"Add Text\"]').click()
Also please let me add another improvement:
driver.find_element_by_xpath('//*[#id="PdfNew_form"]/input[1]').click()
could be much more stable (for the case of page changes) written as:
driver.find_element_by_css_selector('input[type=\"submit\"]').click()
driver.find_elements_by_class_name('Add-Text'),click()
Above code should return a list of elements and you can not click on list of elements
This element is not present in the DOM
To click we use '.' instead of ','
Related
In selenium python code i can click to WebElement (e.g post_raw.click())
Can I identify WebElement link (which will be clicked) with help of selenium methods?
I know about driver.current_url but I am lookink for link before click. I was looking in documentation, but don't find solution https://www.selenium.dev/selenium/docs/api/py/webdriver_remote/selenium.webdriver.remote.webelement.html
My code example:
from selenium import webdriver
# login to facebook code
driver.get("https://touch.facebook.com/dota2")
posts_raw = driver.find_elements_by_xpath("//article")
post_raw = posts_raw[0]
print(type(post_raw)) # <class 'selenium.webdriver.remote.webelement.WebElement'>
post_raw.click() # how can I get post_raw link (which was clicked in this line)
I want function like this:
def get_url_from_WebElement(web_elem: WebElement) -> str:
You can try get href from xpath.
Example :
I want to get link form "question" so i add .get_attribute("href") to find_element
question_link = driver.find_element(By.XPATH, "/html/body/div[3]/div[2]/div/div[1]/div[3]/div[3]/h2[1]/a[1]").get_attribute("href")
if we print it we get :
https://stackoverflow.com/questions/71371250/selenium-get-object-url
Let's say I have a webelement and I want to use that webelement to get the a tag. This does not get the element clicked which is just the middle of the web_element generally.
def get_url_from_WebElement(web_element):
try:
elem=web_element.find_element(BY.XPATH,".//a").get_attribute("href")
return elem
except:
return ''
Do you mean:
def get_url_from_webelement(xpath):
the_url = driver.find_element(By.XPATH, "\"" + xpath + "\"").get_attribute("href")
return the_url
There are two pop-ups: One that asks if you live in California and the second one looks like this:
Here is my code:
The second pop-up doesn't show up every time and when it doesn't the function works. When it does I get an element not interactable error and I don't know why. Here is the inspector for the second pop-up close-btn.
test_data = ['Los Angeles','San Ramon']
base_url = "https://www.hunterdouglas.com/locator"
def pop_up_one(base_url):
driver.get(base_url)
try:
submit_btn = WebDriverWait(driver,5).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"[aria-label='No, I am not a California resident']")))
submit_btn.click()
time.sleep(5)
url = driver.current_url
submit_btn = WebDriverWait(driver,5).until(EC.presence_of_element_located((By.XPATH, "//*[contains(#class,'icon')]")))
print(submit_btn.text)
#submit_btn.click()
except Exception as t:
url = driver.current_url
print(t)
return url
else:
url = driver.current_url
print("second pop_up clicked")
return url
I have tried selecting by the aria-label, class_name, xpath, etc. the way I have it now shows that there is a selenium web element when I print just the element but it doesn't let me click it for some reason. Any direction appreciated. Thanks!
There are 41 elements on that page matching the //*[contains(#class,'icon')] XPath locator. At least the first element is not visible and not clickable, so when you trying to click this submit_btn element this gives element not interactable error.
In case this element is not always appearing you should use logic clicking element only in case the element appeared.
With the correct, unique locator you code can be something like this:
submit_btn = WebDriverWait(driver,5).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"[aria-label='No, I am not a California resident']")))
submit_btn.click()
time.sleep(5)
url = driver.current_url
submit_btn = driver.find_elements_by_xpath('button[aria-label="Close"]')
if(submit_btn):
submit_btn[0].click()
Here I'm using find_elements_by_xpath, this returns a list of web elements. In case element was not found it will be an empty list, it is interpreted as Boolean False in Python.
In case the element is found we will click on the first element in the returned list which will obviously the desired element.
UPD
See the correct locator used here.
It can also be in XPath syntax as //button[#aria-label="Close"]
I have been wondering how I could see when I am at the last page on an amazon listing. I have tried to get at the last page number on the bottom of the screen with nothing working, so I tried a different approach. To see if the 'Next' button can still be clicked. Here is what i have so far, any ideas on why it wont go to the next page?
from selenium.webdriver.chrome.webdriver import WebDriver
from selenium import webdriver
import time
def next():
giveawayPage = 1
currentPageURL = 'https://www.amazon.com/ga/giveaways?pageId=' + str(giveawayPage)
while True:
try:
nextButton = driver.find_element_by_xpath('//*[#id="giveawayListingPagination"]/ul/li[7]')
except:
nextPageStatus = 'false'
print('false')
else:
nextpageStatus = 'true'
giveawayPage = giveawayPage + 1
driver.get(currentPageURL)
if (nextPageStatus == 'false'):
break
if __name__ == '__main__':
driver = webdriver.Chrome('./chromedriver')
driver.get('https://www.amazon.com/ga/giveaways?pageId=1')
next()
The reason this doesn't work is because if you go to the last page of an Amazon Giveaway, the element that you're selecting is still there, it's just not clickable. On most pages, the element looks like:
<li class="a-last">...</li>
On the last page, it looks instead like:
<li class="a-disabled a-last">...</li>
So rather than checking if the element exists, it might be better to check if the element has the class 'a-disabled'.
the li for Next button is always exist, there are several ways to check if it last page:
check if the li has multiple class or not only a-last but also has class a-disabled
//li[#class="a-last"]
check if the <a> element exist in the li
//*[#id="giveawayListingPagination"]/ul/li[7]/a
My program is throwing an error message "Stale element reference: element is not attached to the page document". When I looked at the previous posts (such as Python Selenium stale element fix),, I found that I am not updating the url after calling click function. I updated the url. However, it didn't fix the issue. Could anyone point out where am I making mistake please? Here is my code:
chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("--disable-infobars")
driver = webdriver.Chrome(chrome_options=chrome_options,executable_path="path of driver here")
driver.get("https://stackoverflow.com/users/37181/alex-gaynor?tab=topactivity")
if driver.find_elements_by_xpath("//a[#class='grid--cell fc-white js-notice-close']"):
driver.find_element_by_xpath("//a[#class='grid--cell fc-white js-notice-close']").click()
inner_tabs = driver.find_elements_by_xpath("//div[#class='tabs']//a")
for inner_tab in inner_tabs:
if inner_tab.text == "answers":
inner_tab.click()
time.sleep(3)
driver.get(driver.current_url)
continue
if inner_tab.text == "questions":
inner_tab.click()
time.sleep(3)
driver.get(driver.current_url)
continue
driver.quit()
when you open new URL by clicking link or driver.get() it will create new document element so old element (inner_tab) will invalidate. to solve, first collect all URL then open in loop.
urls_to_visit = []
for inner_tab in inner_tabs:
if inner_tab.text in ["questions", "answers"]:
urls_to_visit.append(inner_tab.get_attribute("href"))
for url in urls_to_visit:
driver.get(url)
time.sleep(3)
This is one of the most frustrating errors you can get with Selenium.
I recommend to try it like this:
for tab in ['answers', 'questions']:
js = "window.tab = [...document.querySelectorAll('div.tabs > a')].filter(a => a.innerText === '" + tab + "')[0]"
driver.execute_script(js)
driver.execute_script("if(window.tab) window.tab.click()")
time.sleep(3)
print(driver.current_url)
By selecting inside of the browser context you can avoid the stale references.
Note: I particularly deal with this website
How can I use selenium with Python to get the reviews on this page to sort by 'Most recent'?
What I tried was:
driver.find_element_by_id('sort-order-dropdown').send_keys('Most recent')
from this didn't cause any error but didn't work.
Then I tried
from selenium.webdriver.support.ui import Select
select = Select(driver.find_element_by_id('sort-order-dropdown'))
select.select_by_value('recent')
select.select_by_visible_text('Most recent')
select.select_by_index(1)
I've got: Message: Element <select id="sort-order-dropdown" class="a-native-dropdown" name=""> is not clickable at point (66.18333435058594,843.7999877929688) because another element <span class="a-dropdown-prompt"> obscures it
This one
element = driver.find_element_by_id('sort-order-dropdown')
element.click()
li = driver.find_elements_by_css_selector('#sort-order-dropdown > option:nth-child(2)')
li.click()
from this caused the same error msg
This one from this caused the same error also
Select(driver.find_element_by_id('sort-order-dropdown')).select_by_value('recent').click()
So, I'm curious to know if there is any way that I can select the reviews to sort from the most recent first.
Thank you
This worked for me using Java:
#Test
public void amazonTest() throws InterruptedException {
String URL = "https://www.amazon.com/Harry-Potter-Slytherin-Wall-Banner/product-reviews/B01GVT5KR6/ref=cm_cr_dp_d_show_all_top?ie=UTF8&reviewerType=all_reviews";
String menuSelector = ".a-dropdown-prompt";
String menuItemSelector = ".a-dropdown-common .a-dropdown-item";
driver.get(URL);
Thread.sleep(2000);
WebElement menu = driver.findElement(By.cssSelector(menuSelector));
menu.click();
List<WebElement> menuItem = driver.findElements(By.cssSelector(menuItemSelector));
menuItem.get(1).click();
}
You can reuse the element names and follow a similar path using Python.
The key points here are:
Click on the menu itself
Click on the second menu item
It is a better practice not to hard-code the item number but actually read the item names and select the correct one so it works even if the menu changes. This is just a note for future improvement.
EDIT
This is how the same can be done in Python.
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
URL = "https://www.amazon.com/Harry-Potter-Slytherin-Wall-Banner/product-reviews/B01GVT5KR6/ref=cm_cr_dp_d_show_all_top?ie=UTF8&reviewerType=all_reviews";
menuSelector = ".a-dropdown-prompt";
menuItemSelector = ".a-dropdown-common .a-dropdown-item";
driver = webdriver.Chrome()
driver.get(URL)
elem = driver.find_element_by_css_selector(menuSelector)
elem.click()
time.sleep(1)
elemItems = []
elemItems = driver.find_elements_by_css_selector(menuItemSelector)
elemItems[1].click()
time.sleep(5)
driver.close()
Just to keep in mind, css selectors are a better alternative to xpath as they are much faster, more robust and easier to read and change.
This is the simplified version of what I did to get the reviews sorted from the most recent ones. As "Eugene S" said above, the key point is to click on the button itself and select/click the desired item from the list. However, my Python code use XPath instead of selector.
# click on "Top rated" button
driver.find_element_by_xpath('//*[#id="a-autoid-4-announce"]').click()
# this one select the "Most recent"
driver.find_element_by_xpath('//*[#id="sort-order-dropdown_1"]').click()