Accessing method inside nested instances - python

I'm trying to update a PyQt label at regular time but since the label is created inside another class instance __init__ I can't figure out how to do on my own.
Here is a simplified version of the code:
from PyQt5.QtCore import QTimer,QSize
from PyQt5.QtWidgets import (QApplication, QMainWindow, QLabel, QTabWidget, QVBoxLayout, QWidget)
import sys
class Main(QMainWindow): #01 THIS IS THE MAIN WINDOW
def __init__(self):
super().__init__()
self.setMinimumSize(QSize(640,480))
self.tabs_widget = Tabs(self)
self.setCentralWidget(self.tabs_widget)
class Tabs(QWidget): #02 SPLIT MAIN WINDOW TO TABS
def __init__(self, parent):
super(QWidget, self).__init__(parent)
self.tabWidget = QTabWidget()
self.tabWidget.addTab(TabOne(), "TabOne")
self.textOne = QLabel("Text One - to be changed")
mainLayout = QVBoxLayout()
mainLayout.addWidget(self.textOne)
mainLayout.addWidget(self.tabWidget)
self.setLayout(mainLayout)
def updateTextOne(self):
self.textOne.setText("Text One - already changed")
class TabOne(QWidget): #03 TAB ONE
def __init__(self):
super().__init__()
mainLayout = QVBoxLayout()
self.textTwo = QLabel("Text Two to be changed")
mainLayout.addWidget(self.textTwo)
self.setLayout(mainLayout)
#THIS IS THE METHOD I WOULD LIKE TO ACCESS!!!
def updateTextTwo(self):
self.textTwo.setText("Text Two - already changed")
if __name__ == "__main__":
app = QApplication(sys.argv)
main = Main()
main.show()
timer = QTimer()
timer.timeout.connect(main.tabs_widget.updateTextOne)
timer.start(2000)
#CAN'T FIGURE OUT HOW TO ACCESS CLASS TabOne > UpdateTextTwo()
# timer = QTimer()
# timer.timeout.connect(main.tabs_widget.tabWidget.)
# timer.start(2000)
sys.exit(app.exec_())
There are two Qlabels, 'textOne' is placed inside Tabs class, I can update it by running updateTextOne() from if __name__ == "__main__":
I can't figure out how to access updateTextTwo() method however, it is located into another class TabOne which instance is created in the previous class Tabs __init__.
Another questions: is there a better way to reach those methods. This is only the beginning of the project but those nested instances already make the project too complex for my programming skills?

Just store it in Tabs() instance here:
self.tabWidget = QTabWidget()
self.tab_one = TabOne()
self.tabWidget.addTab(self.tab_one, "TabOne")
And call:
main.tabs_widget.tab_one.updateTextTwo()

see widget() function:
timer2 = QTimer()
timer2.timeout.connect(main.tabs_widget.tabWidget.widget(0).updateTextTwo)
timer2.start(2000)
(This only works because the widget is already stored in the QTabWidget and you can access it using the widget function. Sanyas solution is the more general solution.)

Related

Implement QThread with QProgressBar in PySide (or PyQt) during calculation

I would like to know how to implement QProgressBar, which shows the progress of calculation in main thread.
Please refer to below codes.
import sys
from PySide2.QtWidgets import QApplication, QWidget, QPushButton, QVBoxLayout, QProgressBar
from PySide2.QtCore import QThread
class BarThread(QThread):
# Progress Bar UI Definition
def __init__(self):
QThread.__init__(self)
self.window = QWidget()
self.pgsb = QProgressBar()
self.lay = QVBoxLayout()
self.lay.addWidget(self.pgsb)
self.window.setLayout(self.lay)
self.isRun = False
# Thread Function Definition
def run(self):
self.window.show()
while self.isRun:
self.pgsb.setValue(self.percent)
print(self.percent)
if self.percent == 100:
self.isRun = False
class Tool(QWidget):
# Main UI Definition
def __init__(self):
windowWidth = 300
windowHeight = 300
QWidget.__init__(self)
self.setWindowTitle("Example")
self.resize(windowWidth, windowHeight)
self.bt = QPushButton('Numbering')
self.layout = QVBoxLayout()
self.layout.addWidget(self.bt)
self.setLayout(self.layout)
# Main Function Link Definition
self.bt.clicked.connect(self.numbering)
# Main Function Definition
def numbering(self):
bth = BarThread()
bth.start()
bth.isRun = True
for x in range(0,100000):
bth.percent = x/1000
print(x)
if __name__ == "__main__":
app = QApplication(sys.argv)
widget = Tool()
widget.show()
sys.exit(app.exec_())
You can copy and paste directly onto your python IDE.
(it needs PySide2. It can be installed with 'pip install pyside2' in your prompt).
This code executes simple numbering, however, this doesn't show numbering progress.
How can I solve this problem? Thank you in advance.
P.S. I'm using Windows 10 with PyCharm.
You have at least the following errors:
You must not modify the GUI from another thread, in your case the run method is executed in another thread but you try to modify the value of the QProgressBar, in addition to displaying a widget which is not allowed. If you want to modify the GUI with the information provided in the execution in the secondary thread you must do it through signals since they are thread-safe
The for loop is the blocking task so it must be executed in another thread.
Considering the above, the solution is:
import sys
from PySide2.QtWidgets import (
QApplication,
QWidget,
QPushButton,
QVBoxLayout,
QProgressBar,
)
from PySide2.QtCore import QThread, Signal
class ProgressWidget(QWidget):
def __init__(self, parent=None):
super(ProgressWidget, self).__init__(parent)
self.pgsb = QProgressBar()
lay = QVBoxLayout(self)
lay.addWidget(self.pgsb)
class BarThread(QThread):
progressChanged = Signal(int)
def run(self):
percent = 0
for x in range(0, 100000):
percent = x / 100
self.progressChanged.emit(percent)
class Tool(QWidget):
"""Main UI Definition"""
def __init__(self, parent=None):
super(Tool, self).__init__(parent)
self.setWindowTitle("Example")
self.resize(300, 300)
self.bt = QPushButton("Numbering")
layout = QVBoxLayout(self)
layout.addWidget(self.bt)
# Main Function Link Definition
self.bt.clicked.connect(self.numbering)
self.bar_thread = BarThread(self)
self.progress_widget = ProgressWidget()
self.bar_thread.progressChanged.connect(self.progress_widget.pgsb.setValue)
# Main Function Definition
def numbering(self):
self.bar_thread.start()
self.progress_widget.show()
def closeEvent(self, event):
super(Tool, self).closeEvent(event)
self.bar_thread.quit()
self.bar_thread.wait()
if __name__ == "__main__":
app = QApplication(sys.argv)
widget = Tool()
widget.show()
sys.exit(app.exec_())

How can I get rid of the previous layout and set new Grid Layout in QMainWindow?

I am a newbie with PyQt. I am trying to organize my buttons on a grid layout, but I guess the window has a default layout already. How can I get rid of it and replace it with the new Grid Layout? I have contained the code block relevant with hashes ###, Here is my program:
import sys
from PyQt4 import QtCore, QtGui
from PyQt4.QtGui import QWidget
class MainWindow(QtGui.QMainWindow):
def __init__(self):
QtGui.QWidget.__init__(self)
self.setMinimumSize (800,600) # set minimum size for window
self.setWindowTitle("CoolPlay Kabul") # set window title
self.setWindowIcon(QtGui.QIcon("images/CoolPlay.png"))# set icon for Window
myMenu = self.menuBar()
File_Menu = myMenu.addMenu("&File")
Items_Menu = myMenu.addMenu("&Items")
Playlist_Menu = myMenu.addMenu("&Playlist")
Option_Menu = myMenu.addMenu("&Option")
Exit_Menu = myMenu.addMenu("&Exit")
File_Menu.addAction("New Time")
File_Menu.addAction("Delete Time")
File_Menu.addSeparator()
File_Menu.addAction("Exit")
Items_Menu.addAction("New Item")
Items_Menu.addAction("Delete Item")
Items_Menu.addSeparator()
Items_Menu.addAction("Toggle Segue")
Playlist_Menu.addAction("Clear Playlist")
Playlist_Menu.addAction("Save playlist")
Playlist_Menu.addAction("Load Playlist")
Playlist_Menu.addSeparator()
Playlist_Menu.addAction("Clear 'Played' Indication")
Option_Menu.addAction("Application Setup")
Exit_Menu.addAction("Help")
Exit_Menu.addAction("About")
######################################################
Overall_Layout = QtGui.QGridLayout(self)
self.setLayout(Overall_Layout)
Play_Button = QtGui.QPushButton(QtGui.QIcon("images/PLAY.bmp"), "PLAY",self)
Overall_Layout.addWidget(Play_Button,1,2)
Overall_Layout.addWidget(Play_Button,2,2)
########################################################
self.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
CoolPlay = MainWindow()
CoolPlay.show()
sys.exit(app.exec_())
QMainWindow is a special widget since it already has a preset layout as shown below:
So in this case you should not set a layout to the QMainWindow but to the central widget, but first establish a centralwidget, using the indicated thing we get the following:
######################################################
central_widget = QtGui.QWidget()
self.setCentralWidget(central_widget)
Overall_Layout = QtGui.QGridLayout(central_widget)
Play_Button = QtGui.QPushButton(QtGui.QIcon("images/PLAY.bmp"), "PLAY")
Overall_Layout.addWidget(Play_Button,1,2)
Overall_Layout.addWidget(Play_Button,2,2)
########################################################
On the other hand if you inherit from QMainWindow you must call the QMainWindow constructor, but in code you call QWidget, so you must modify it to:
class MainWindow(QtGui.QMainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
Or
class MainWindow(QtGui.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()

How to return value from the QWidget

I have a widget that ends with pressing OK button. I want that the widget returns a value to the main program (which is in simple example below the obtained value increased by 1). How can I do this?
Also, is there any more elegant way to show the same QWidget with the different title?
MWE:
import sys
from PyQt5 import QtGui, QtCore, QtWidgets
class MainWindow(QtWidgets.QWidget):
def __init__(self,val):
self.val=val
super(MainWindow, self).__init__()
self.initUI()
def initUI(self):
self.End= QtWidgets.QPushButton('OK', self)
self.End.clicked.connect(self.end)
MainLayout = QtWidgets.QVBoxLayout()
MainLayout.addWidget(self.End)
self.setLayout(MainLayout)
self.setWindowTitle(str(self.val))
self.show()
def end(self):
# return self.val+1
self.close()
def main():
app = QtWidgets.QApplication(sys.argv)
for i in range(10):
ex = MainWindow(i)
ex.show()
res = app.exec_()
print(res)
sys.exit()
if __name__ == '__main__':
main()
If you want to use a widget to get some value after some processing, the correct thing is to use QDialog, that prevents any other window from opening if you use exec_():
import sys
from PyQt5 import QtCore, QtGui, QtWidgets
class Dialog(QtWidgets.QDialog):
def __init__(self, val, parent=None):
super(Dialog, self).__init__(parent)
self.val = val
self.initUI()
def initUI(self):
endButton = QtWidgets.QPushButton('OK')
endButton.clicked.connect(self.on_clicked)
lay = QtWidgets.QVBoxLayout(self)
lay.addWidget(endButton)
self.setWindowTitle(str(self.val))
#QtCore.pyqtSlot()
def on_clicked(self):
self.val += 1
self.accept()
def main():
app = QtWidgets.QApplication(sys.argv)
for i in range(10):
ex = Dialog(i)
ex.setAttribute(QtCore.Qt.WA_DeleteOnClose)
if ex.exec_() == QtWidgets.QDialog.Accepted:
print(ex.val)
if __name__ == '__main__':
main()
It is unclear what exactly your intention is with this code. If val is supposed to be a counter for the number of MainWindow instances, then you must declare it as a static:
class MainWindow(QtWidgets.QWidget):
val = 0
def __init__(self):
super(MainWindow, self).__init__()
MainWindow.val += 1
self.initUI()
def initUI(self):
# ...
self.setWindowTitle(str(MainWindow.val))
# ...
def main():
# ...
for i in range(10):
ex = MainWindow()
# ...
# ...
There is nothing wrong in calling QWidget::setWindowTitle() so I don't see a problem here.
If you really want to have it as a non-static class member and each MainWindow uses it as some sort of ID, you can easily call the value right after the ex.show():
def main():
app = QtWidgets.QApplication(sys.argv)
for i in range(10):
ex = MainWindow()
ex.show()
print(MainWindow.val)
res = app.exec_()
print(res)
sys.exit()
Just because you close a widget doesn't mean you have destroyed it so calling the values stored inside the object is not an issue.
However it appears you are not familiar what QApplication::exec() is intended for. It runs the main loop of the given application and returns the exit status (you can set it when calling exit() as the parameter passed to that function). If you simply want to get the value of val upon closing a widget you can simply override the closeEvent handler and emit a signal. Create a QObject instance and connect each MainWindow instance's custom close signal to a slot and do with the value whatever you want to.

Python PyQt4: Single child window

I have a simple PyQt4 example.
When run, it displays a QMainWindow with a button.
If you click the button, then a second QMainWindow is created.
If you click it again, you get 2 second windows.
What is an elegant and simple way to prevent more than 1 second window in this example?
import sys
from PyQt4.QtGui import *
class win2(QMainWindow):
def __init__(self, parent=None):
QMainWindow.__init__(self,parent)
layout = QVBoxLayout()
label = QLabel(self)
label.setText('This is win2')
layout.addWidget(label)
self.adjustSize()
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
layout = QVBoxLayout()
button1 = QPushButton("win2", self)
layout.addWidget(button1)
button1.clicked.connect(self.showwin2)
def showwin2(self):
w2 = win2(self)
w2.show()
if __name__ == '__main__':
app = QApplication(sys.argv)
mainWin = MainWindow()
mainWin.show()
sys.exit(app.exec_())
Your Function creates a new instance of the class win2 each time the button is pressed. To Supress this behavior only call the show and raise_ functions instead of creating a new instance.
I would create the class as follows, and only use the button to 'show' the window. Tested and works as intended. Also consider using self when assigning your variables so they can be accessed throughout the class instance.
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
layout = QVBoxLayout()
button1 = QPushButton("win2", self)
layout.addWidget(button1)
button1.clicked.connect(self.showwin2)
self.w2 = win2(self)
def showwin2(self):
self.w2.show()
self.w2.raise_()

pyqt auto connect signal

I want use the autoconnection feature. I am using this example:
http://www.eurion.net/python-snippets/snippet/Connecting%20signals%20and%20slots.html
it works, but I want to create my own signals and own slots, the example using built in signals.
for example, here are a custom signal with a custom slot, but don't works:
import sys
from PyQt4 import QtGui, QtCore
class SignalsAndSlots(QtGui.QWidget):
testSignal = QtCore.pyqtSignal(str,name='testSignal')
def __init__(self):
QtGui.QMainWindow.__init__(self)
self.setObjectName('testObject')
self.label = QtGui.QLabel(self)
QtCore.QMetaObject.connectSlotsByName(self)
self.emitSignal()
def emitSignal(self):
self.testSignal.emit('message')
#QtCore.pyqtSlot(str,name='on_testObject_testSignal')
def autoSlot(self,msg):
self.label.setText(msg)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
gui = SignalsAndSlots()
gui.show()
app.exec_()
Thanks a lot
Ber is right. This what the pyqt documentation says:
QMetaObject.connectSlotsByName searches recursively for all child objects of the given object [...]
Here is a simple example with custom signals :
import sys
from PyQt4 import QtGui, QtCore
class CustomButton(QtGui.QPushButton):
custom_clicked = QtCore.pyqtSignal(str, name='customClicked')
def mousePressEvent(self, event):
self.custom_clicked.emit("Clicked!")
class SignalsAndSlots(QtGui.QWidget):
def __init__(self):
QtGui.QMainWindow.__init__(self)
layout = QtGui.QHBoxLayout(self)
self.custom_button = CustomButton("Press Me", self)
self.custom_button.setObjectName('customButton')
self.label = QtGui.QLabel("Nothing...", parent=self)
layout.addWidget(self.custom_button)
layout.addWidget(self.label)
QtCore.QMetaObject.connectSlotsByName(self)
#QtCore.pyqtSlot(str, name='on_customButton_customClicked')
def autoSlot(self, msg):
self.label.setText(msg)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
gui = SignalsAndSlots()
gui.show()
app.exec_()
But I think you should consider not using the object names. New-style signal connection is way neater. Here is the same application :
import sys
from PyQt4 import QtGui, QtCore
class CustomButton(QtGui.QPushButton):
custom_clicked = QtCore.pyqtSignal(str)
def mousePressEvent(self, event):
self.custom_clicked.emit("Clicked!")
class SignalsAndSlots(QtGui.QWidget):
def __init__(self):
QtGui.QMainWindow.__init__(self)
layout = QtGui.QHBoxLayout(self)
self.custom_button = CustomButton("Press Me", self)
self.custom_button.setObjectName('customButton')
self.label = QtGui.QLabel("Nothing...", parent=self)
layout.addWidget(self.custom_button)
layout.addWidget(self.label)
self.custom_button.custom_clicked.connect(self.on_clicked)
def on_clicked(self, msg):
self.label.setText(msg)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
gui = SignalsAndSlots()
gui.show()
app.exec_()
I investigated a bit into the doc. of QtCore.QMetaObject.connectSlotsByName().
For this, I made an MCVE to collect things not working vs. things working:
#!/usr/bin/python3
import sys
from PyQt5.QtCore import QT_VERSION_STR
from PyQt5.QtCore import QMetaObject, pyqtSlot
from PyQt5.QtWidgets import QApplication, QMainWindow, QVBoxLayout, QPushButton, QWidget
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
# build GUI
qMain = QWidget()
qVBox = QVBoxLayout()
qBtnPreview1 = QPushButton("Preview 1")
qBtnPreview1.setObjectName("preview1")
qVBox.addWidget(qBtnPreview1)
qBtnPreview2 = QPushButton("Preview 2")
qBtnPreview2.setObjectName("preview2")
qVBox.addWidget(qBtnPreview2)
qBtnPreview3 = QPushButton("Preview 3")
qBtnPreview3.setObjectName("preview3")
qVBox.addWidget(qBtnPreview3)
qBtnPreview4 = QPushButton("Preview 4")
qBtnPreview4.setObjectName("preview4")
qVBox.addWidget(qBtnPreview4)
qBtnPreview5 = QPushButton("Preview 5")
qBtnPreview5.setObjectName("preview5")
qVBox.addWidget(qBtnPreview5)
qBtnPreview6 = QPushButton("Preview 6")
qBtnPreview6.setObjectName("preview6")
qVBox.addWidget(qBtnPreview6)
qMain.setLayout(qVBox)
self.setCentralWidget(qMain)
# install signal handlers
qBtnPreview1.clicked.connect(lambda: print("preview1 clicked."))
qBtnPreview2.clicked.connect(lambda: print("preview2 clicked."))
qBtnPreview3.clicked.connect(lambda: print("preview3 clicked."))
qBtnPreview4.clicked.connect(lambda: print("preview4 clicked."))
qBtnPreview5.clicked.connect(lambda: print("preview5 clicked."))
qBtnPreview6.clicked.connect(lambda: print("preview6 clicked."))
QMetaObject.connectSlotsByName(self)
#pyqtSlot()
def preview1(self):
print("MainWindow.preview1() called.")
#pyqtSlot()
def preview2_clicked(self):
print("MainWindow.preview2_clicked() called.")
#pyqtSlot()
def on_preview3(self):
print("MainWindow.on_preview3() called.")
#pyqtSlot()
def on_preview4_clicked(self):
print("MainWindow.on_preview4_clicked() called.")
#pyqtSlot(name='on_preview5_clicked')
def preview5_clicked(self):
print("MainWindow.preview5_clicked() called.")
def on_preview6_clicked(self):
print("MainWindow.on_preview6_clicked() called.")
if __name__ == '__main__':
print("Qt Version: {}".format(QT_VERSION_STR))
app = QApplication(sys.argv)
# build GUI
qWinMain = MainWindow()
qWinMain.show()
# runtime loop
sys.exit(app.exec_())
Output:
$ ./testQMetaObjectConnectSlotsByName.py
Qt Version: 5.9.3
After clicking each of the six buttons once, I got:
preview1 clicked.
preview2 clicked.
preview3 clicked.
preview4 clicked.
MainWindow.on_preview4_clicked() called.
preview5 clicked.
MainWindow.preview5_clicked() called.
preview6 clicked.
MainWindow.on_preview6_clicked() called.
MainWindow.on_preview6_clicked() called.
Observations:
MainWindow.preview1(), MainWindow.preview2_clicked(), MainWindow.on_preview3() were not connected. They don't follow the required convention of QtCore.QMetaObject.connectSlotsByName().
MainWindow.on_preview4_clicked() is connected by name – properly following the required name convention.
MainWindow.preview5_clicked() is connected as well – by giving the required name by #pyqtSlot(name='on_preview5_clicked').
MainWindow.on_preview6_clicked() is connected as well – even without marking it as slot explicitly. (However, it is called twice for any reason which might be undesirable.)
Explicit connections work in any case and appear more robust to me.
Further readings:
QMetaObject::connectSlotsByName() (Qt5 C++ doc.)
Connecting Slots By Name (PyQt5 doc.)
PyQt5.QtCore.pyqtSlot() (PyQt5 doc.).
Actually, this was my answer to another question (SO: How to display two images in each Qlabel PyQt5) until I realized that QtCore.QMetaObject.connectSlotsByName() unlikely plays a role in that question.
So, I moved it here where it may be more appropriate even although the question is a bit aged.

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