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Is there a method for displaying a folder onscreen?

I am creating a program in Python that requires the user to place images into an Input folder, and then take images out of an Output folder. As this will become an application, the Input and Output folders will be very difficult to navigate to, being buried in the app's contents.
I am looking for a way to open folders onscreen so that a user can add or remove their own files from these folders, without knowing the exact location of the folders they are interacting with.
I am thoroughly stumped on this problem, and I appreciate all of your time.
Thank you very much.
*Edit: I am working on MacOS

If the program is intended for use on windows, it seems like you could use the solution here, where you could open explorer as a sub process and then open the path to the file.
For example
import subprocess
subprocess.Popen(r'explorer /select, FilePath')
You could also use os, and os.startfile(FilePath).

Listing files in a sub folder using Glob

I saw this answer - How can I search sub-folders using glob.glob module in Python? but I didn't understand what os.walk() was doing (I read the docs but it didn't quite make sense).
I'm really new to pathing and still trying to make sense of it.
I have a script that lives in - /users/name/Desktop/folder/ and I want to access some files in /users/name/Desktop/folder/subfolder/*.html
I tried glob.glob('/users/name/Desktop/folder/subfolder/*.html') but it returned an empty list. I realize this is what the previous person did and it didn't work (I was just hoping that glob had been updated!)
Any thoughts on how to do this?

Without any further information it's hard to say what the issue is. I tested your syntax, it works fine for me. Are you sure the extension is .html not .htm in your /users/name/Desktop/folder/subfolder/ directory?
Also, to further troubleshoot you can check what python can see in you directory by running:
os.listdir('/users/name/Desktop/folder/subfolder/')
This should get you started.

Python/Django: how to get files fastest (based on path and name)

My website users can upload image files, which then need to be found whenever they are to be displayed on a page (using src = ""). Currently, I put all images into one directory. What if there are many files - is it slow to find the right file? Are they indexed? Should I create subdirectories instead?
I use Python/Django. Everything is on webfaction.

The access time for an individual file are not affected by the quantity of files in the same directory.
running ls -l on a directory with more files in it will take longer of course. Same as viewing that directory in the file browser. Of course it might be easier to work with these images if you store them in a subdirectory defined by the user's name. But that just depends on what you are going to doing with them. There is no technical reason to do so.
Think about it like this. The full path to the image file (/srv/site/images/my_pony.jpg) is the actual address of the file. Your web server process looks there, and returns any data it finds or a 404 if there is nothing. What it doesn't do is list all the files in /srv/site/images and look through that list to see if it contains an item called my_pony.jpg.

If only for organizational purposes, and to help with system maintenance you should create subdirectories. Otherwise, there is very little chance you'll run into the maximum number of files that a directory can hold.
There is negligible performance implication for the web. For other applications though (file listing, ftp, backup, etc.) there may be consequences, but only if you reach a very large number of files.

Searching script in Python

im trying to make a script which search some file in whole computer similar to Search in windows. I want to do it without any libraries.
I started with setting dir to begginng of disk and then checking how much dirs i have - i want to make a function that will search for new dirs in current dir so at the end ill have list of all dirs in disk. But when i try to found all files ending with ".txt", i get error message WindowsError5 Acces Denied. What am i doing wrong? Thanks
import os
os.chdir("\\.")
dir = os.listdir()
dirs = []
for x in dir:
if os.path.isdir(x):
dirs.append(x)
for y in dirs:
o = os.listdir(y)
for p in o:
if p.endswith(".txt"):
print(p)
input()

First, if you want to walk a directory tree, use os.walk instead of trying to build it yourself. And if you're trying to learn how something like os.walk works, the source code should be right there in os.py.
Second, you probably don't have access to your entire filesystem unless you run as Administrator, so you're going to get a bunch of Access Denied errors as you try to step through the directories you don't have access to. You have to use try/catch to deal with these errors in whatever way you find appropriate (e.g., print the error and move on to the next directory)
Third, this whole idea is probably misguided. Windows Desktop Search does not actually search your whole tree, it keeps a database and searches that, which is much faster (and also allows users to search into paths they couldn't reach directly—for example, you might have access to /Users/foo, but not to /Users, which means WDS can show you files in /Users/foo but your script cannot).
Fourth, this whole thing is much easier to do with the POSIX 'find' tool or… I forget the name, but there's a DOS-derived tool that also comes with Windows that does the same thing but not as flexibly. Either way, it's a one-liner shell/batch command instead of dozens of lines of Python.
Finally, the way you've written this, it's going to search the current drive, not all drives, which probably isn't what you want, is it?

You've hit a directory that you don't have permission to look in. So what. Catch the exception and continue the search.

howoto fix working directory is always home? (python)

This is my first question.
My python script opens and reads from a present text file using the following simple funct:
open("config.ini", "r")
As this is a relative path it is supposed to work because config.ini is placed in the same directory like the script is when it is launched, that should be the current working dir.
In fact this works perfectly on all of my 3 linux boxes, but I have one user who demands support because he gets an error while opening config.ini. The error raises because
os.path.exists("config.ini")
returns false even if the file is there!
Trying to fix this problem we found out that the only way to make it work is to place config.ini in his home directory despite the supposed working directory is another.
Also, if my script tries to create a file in the present working directory, the file is always created in his home dir instead, and so I think that for some reason his working dir is always home!
How can I troubleshoot this problem? Maybe I could introduce absolute paths, but I am afraid that os.getcwd() would return the homedir instead of the correct one.
Should I maybe suggest this user to fix his machine in some way?
Sorry for this long question but english is not my first language and I am a beginner in coding, so have some difficulties to explain.
Thank you very much in advance! =)

Could it be that the user is executing your script from his home directory?
I.e. suppose the script is in:
/home/user/test/foo/foo.py
But the user calls it thus:
/home/user> python test/foo/foo.py
In this case, the "current directory" the script sees is /home/user.
What you can do is find out the directory the script itself resides in by calling this function:
import os
def script_dir():
return os.path.dirname(os.path.realpath(__file__))
It will always return the directory in which the script lives, not the current directory which may be different. You can then store your configuration file there safely.

Along the same lines as Eli Bendersky's suggestion, you might want to try:
os.path.exists(os.path.join(sys.path[0],"config.ini"))
since sys.path[0] should always be the directory in which the script resides.