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Output without "print()" in SublimeText

Is there a way/plug-in to enable output without "print()" in SublimeText?
For example,
a = 1 + 2
print (a)
Output:
3
Wanted:
a = 1 + 2
a
Output:
3
P.s. I also tried below:

I am pretty sure that the answer is no. You can rename the print function to make it less noticable like this:
_ = print
a = 2
_(a)
Output is 2
Alternatively:
As a few people mentioned in the comments, what you are likely looking for is a repl, which you can get by simply running python command directly in your terminal.
like this:
$ python
that should take you to an interactive environment that gives you real time results for the python code you input. Below is an example...
>>> a = 1 + 2
>>> a
3
>>> a + 25
28
>>> a
3
>>> a = a + 25
>>> a
28

Running R script in Python

I am running a simple R script in python using the following code.
import rpy2.robjects as robjects
r=robjects.r
output = r.source("sample.R")
Now when I print the output
print (output)
I am getting script's last variable only as an output and not all the variable (which I was not expecting. Also I was thinking if I call c or data, the results will be printed as such but python isn't identifying these variables coded in R). I am not sure how to call all these variables.
I am writing very simple code in R script just for testing. My R script looks like:
a <- 1
b <- 3
c <- a + b
data = 1:20
now on calling the script and printing the results I am getting these the following at output. I am not sure what's happening.
$value
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
$visible
[1] FALSE
I am not sure how to exactly print variable as it is from R to python. Please guide me to it. Your help will be appreciated.
Regards

Your variable output will only store the output from the source file, which is exactly what you get, id est the last variable. But all the variables actually live somewhere, in an R environment, which you can get with robjects.globalenv.
Knowing that you can easily retrieve the value for each variable that you created in R:
import rpy2.robjects as robjects
robjects.r.source("sample.R")
print(robjects.globalenv["a"])
print(robjects.globalenv["b"])
print(robjects.globalenv["c"])
print(robjects.globalenv["data"])

ValueError: math domain error While Using Logarithms

I am currently working on a code to find a value C which I will then compare against other parameters. However, whenever I try to run my code I receive this error: ValueError: math domain error. I am unsure why I am receiving this error, though I think it's how I setup my equation. Maybe there is a better way to write it. This is my code:
import os
import math
path = "C:\Users\Documents\Research_Papers"
uH2 =5
uHe = 3
eH2 = 2
eHe = 6
R = ((uH2*eH2)/(uHe*eHe))
kH2=[]
kHe=[]
print(os.getcwd()) # see where you are
os.chdir(path) # use a raw string so the backslashes are ok
print(os.getcwd()) # convince yourself that you're in the right place
print(os.listdir(path)) # make sure the file is in here
myfile=open("hcl#hfs.dat.txt","r")
lines=myfile.readlines()
for x in lines:
kH2.append(x.split(' ')[1])
kHe.append(x.split(' ')[0])
myfile.close()
print kH2
print kHe
g = len(kH2)
f = len(kHe)
print g
print f
for n in range(0,7):
C = (((math.log(float(kH2[n]),10)))-(math.log(float(kHe[n]),10)))/math.log(R,10)
print C
It then returns this line saying that there is a domain error.
C = (((math.log(float(kH2[n]),10)))-(math.log(float(kHe[n]),10)))/math.log(R,10)
ValueError: math domain error
Also, for the text file, I am just using a random list of 6 numbers for now as I am trying to get my code working before I put the real list of numbers in. The numbers I am using are:
5 10 4 2
6 20 1 2
7 30 4 2
8 40 3 2
9 23 1 2
4 13 6 2

Try to check if the value inside the log is positive as non-positive value to a log function is a domain error.
Hope this helps.

how to get result from many list in same line in python

I have three list:
alist=[1,2,3,4,5]
blist=['a','b','c','d','e']
clist=['#','#','$','&','*']
I want my output in this format:
1 2 3 4 5
a b c d e
# # $ & *
I am able to print in correct format but when i am having list with many elements it's actually printing like this:
1 2 3 4 5 6 ..........................................................................
................................................................................
a b c d e ............................................................................
......................................................................................
# # $ & * .............................................................................
.......................................................................................
but I want my output like this:
12345....................................................................
abcde...................................................................
##$&*...................................................................
............................................................... {this line is from alist}
................................................................ {this line is from blist}
................................................................ {this line is from clist}

Try the following:
term_width = 80
all_lists = (alist, blist, clist)
length = max(map(len, all_lists))
for offset in xrange(0, length, term_width):
print '\n'.join(''.join(map(str, l[offset:offset+term_width])) for l in all_lists)
This assumes terminal width is 80 characters, which is the default. You might want to detect it's actual width with curses library or something based on it.
Either way, to adapt to any output width you only need to change term_width value and the code will use it.
It also assumes all elements are 1-character long. If it's not the case, please clarify.
If you need to detect terminal width, you may find some solutions here: How to get Linux console window width in Python

Convert Scientific Notation to Float

Encountered a problem whereby my JSON data gets printed as a scientific notation instead of a float.
import urllib2
import json
import sys
url = 'https://bittrex.com/api/v1.1/public/getmarketsummary?market=btc-quid'
json_obj = urllib2.urlopen(url)
QUID_data = json.load(json_obj)
QUID_MarketName_Trex = QUID_data["result"][0]["MarketName"][4:9]
QUID_Last_Trex = QUID_data["result"][0]["Last"]
QUID_High_Trex = QUID_data["result"][0]["High"]
QUID_Low_Trex = QUID_data["result"][0]["Low"]
QUID_Volume_Trex = QUID_data["result"][0]["Volume"]
QUID_BaseVolume_Trex = QUID_data["result"][0]["BaseVolume"]
QUID_TimeStamp_Trex = QUID_data["result"][0]["TimeStamp"]
QUID_Bid_Trex = QUID_data["result"][0]["Bid"]
QUID_Ask_Trex = QUID_data["result"][0]["Ask"]
QUID_OpenBuyOrders_Trex = QUID_data["result"][0]["OpenBuyOrders"]
QUID_OpenSellOrders_Trex = QUID_data["result"][0]["OpenSellOrders"]
QUID_PrevDay_Trex = QUID_data["result"][0]["PrevDay"]
QUID_Created_Trex = QUID_data["result"][0]["Created"]
QUID_Change_Trex = ((QUID_Last_Trex - QUID_PrevDay_Trex)/ QUID_PrevDay_Trex)*100
QUID_Change_Var = str(QUID_Change_Trex)
QUID_Change_Final = QUID_Change_Var[0:5] + '%'
print QUID_Last_Trex
It prints the following value; 1.357e-05.
I need this to be a float with 8 chars behind the decimal (0.00001370)
As you can see here --> http://i.imgur.com/FCVM1UN.jpg, my GUI displays the first row correct (using the exact same code).

You are looking at the default str() formatting of floating point numbers, where scientific notation is used for sufficiently small or large numbers.
You don't need to convert this, the value itself is a proper float. If you need to display this in a different format, format it explicitly:
>>> print(0.00001357)
1.357e-05
>>> print(format(0.00001357, 'f'))
0.000014
>>> print(format(0.00001357, '.8f'))
0.00001357
Here the f format always uses fixed point notation for the value. The default precision is 6 digits; the .8 instructs the f formatter to show 8 digits instead.
In Python 3, the default string format is essentially the same as format(fpvalue, '.16g'); the g format uses either a scientific or fixed point presentation depending on the exponent of the number. Python 2 used '.12g'.

You can use print formatting:
x = 1.357e-05
print('%f' % x)
Edit:
print('%.08f' % x)

There are some approaches:
#1 float(...) + optionally round() or .format()
x = float(1.357e-05)
round(x, 6)
"{:.8f}".format(x)
#2 with decimal class
import decimal
tmp = decimal.Decimal('1.357e-05')
print('[0]', tmp)
# [0] 0.00001357
tmp = decimal.Decimal(1.357e-05)
print('[1]', tmp)
# [1] 0.0000135700000000000005188384444299032338676624931395053863525390625
decimal.getcontext().prec = 6
tmp = decimal.getcontext().create_decimal(1.357e-05)
print('[2]', tmp)
# [2] 0.0000135700
#3 with .rstrip(...)
x = ("%.17f" % n).rstrip('0').rstrip('.')
Note: there are counterparts to %f:
%f shows standard notation
%e shows scientific notation
%g shows default (scientific if 5 or more zeroes)