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I am requesting someone to tell me a program that asks a user to input only 9 digits. Number 0 not at start but having 9 digits.
How can I limit the number of digits?
For example:
Num=int(input('please Enter a Number'))
if num?!
Please help me soon.
If i got this right this should work:
a=input()
if len(a)==9 and a[0] != '0' and a.isdigit():
#if you want it to be integer
a=int(a)
do something
Hope it helps.
Well if I understood correctly you need a program that asks the user to enter exactly 9 digits. In that case it's pretty simple.
i = input("Enter a nine digit number: ")
if len(i) != 9:
print("You must enter 9 digits!")
quit()
if not i.isdigit():
print("Your input must be a number!")
quit()
# num is a 9 digit integer
# i is a 9 digit string
num = int(i)
You can do this.
num = input('Please enter a number')
if not num[0] == "0" and len(num) == 9 and num.isdigit():
# You can print a message or cast the num into an integer here
# like this: input_number = int(num)
print(True)
else:
print(False)
So what's happening here is that the program will accept the user input and evaluate if the first digit is NOT 0 AND that the length is exactly 9 characters.
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I wrote this code snippet:
lowestNumber = int(input("\nWhat would you like your lowest number to be?"))
highestNumber = int(input("What would you like your highest number to be?"))
number = random.randint(lowestNumber, highestNumber)
tries = 0
while tries < 10:
guess = int(input(f'\nEnter a number between', lowestNumber))
if guess == number:
print("You guessed correctly! The number was", number)
break
elif guess < number:
print("Too low!")
elif guess > number:
print("Too high!")
tries += 1
SyntaxError: bad input on line 22 in main.py.
Line 22 was guess = int(input(f'\nEnter a number between', lowestNumber)).
I searched it up on google and got nothing, I pasted it into OpenAI's code fixing and it also didn't help.
How can I fix this error?
When you wrote
guess = int(input(f'\nEnter a number between', lowestNumber))
it passed both the string and lowestNumber into the input function. However, you probably wanted to write something like Enter a number between (lowestNumber) and (highestNumber). To do this, you would have to write
guess = int(input(f'\nEnter a number between {lowestNumber} and {highestNumber}. '))
In my example, it passes in one object, the string, which contains lowestNumber and highestNumber in it. In your example, it passes in two objects, the string and lowestNumber.
The formatting you did in the input functions works in print statements, so the print statements are correct, but the input function is not.
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The real problem is there:
write a program that takes a string as input and prints “Binary Number” if the string contains only 0s or 1s. Otherwise, print “Not a Binary Number”.
You can iterate every character of the input and verify it is a zero or a one. The all function can be used for this iteration and check.
Also require that the string has at least one character:
def isBinary(string):
return all(ch in "01" for ch in string) and string != ''
Example use:
string = input("Enter a binary number: ")
if isBinary(string):
print("Thank you!")
else:
print("That is not a binary number.")
It is easy.
def is_binary(string_to_check:str):
for x in string_to_check: #loop though all letter
if x in ('0','1'):
continue #yep the letter is binary thingy
else:
return False #no
return True #yep the string is binary
Next time check google before ask.
def check_if_binary(string) :
p = set(string)
s = {'0', '1'}
if s == p or p == {'0'} or p == {'1'}:
print("Binary Number")
else :
print("Not a Binary Number")
string = str(input ("Enter the sting : "))
check_if_binary(string)
References: https://www.geeksforgeeks.org/python-check-if-a-given-string-is-binary-string-or-not/
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I want a program that sums the even numbers of a bigger number using while function.
Exemple :
Number is : 12345
Print : 6 (2+4)
This is what i wrote so far:
num = int(input("Introduce a non negative number: "))
if num % 2 == 0:
sum += num
print("sum")
I can't stress this enough
When doing school assignments, the whole idea with assignments is to teach you concepts, not solutions. There's a reason why you were given this assignment, asking others to solve it for you - is not the way to go.
Go back to your teacher, and ask for help if something is unclear. But because others start posting solutions I might as well just keep mine here.
Skipping the conversion to an early integer, will allow you to iterate over it as a string, and grab one number a a time.
num = input("Introduce a non negative number: ")
total = 0
for i in num:
if int(i) % 2 == 0:
total += int(i)
print("sum:", total)
You can then use your original logic, with some minor modifications.
Since for whatever reason, you're only allowed to use while and not for, you'd have to just adapt a bit.
num = input("Introduce a non negative number: ")
total = 0
i = 0
while i < len(num):
if int(num[i]) % 2 == 0:
total += int(num[i])
i += 1
print("sum:", total)
While I'm at it, after reading my code again. I am quite sure that a while loop here is the least pretty solution to this problem. But from a teaching standpoint there might be some benefit here. But I'd recommend going with the for loop if at all possible.
Try this one:
# split the number to list of digits
digits_list = list(input("Introduce a non negative number: "))
total = 0
# loop over the digits list and pick a digit till the list is empty
while digits_list:
digit = digits_list.pop()
if int(digit) % 2 == 0:
total += int(digit)
print(total)
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It's my 2nd week in programming in Python and have never programmed anything before. appreciate step by step.
I don't know where to start.
try:
count = 0
while True:
user = int(input('Insert Number: '))
count += user
if user == 0:
break
print(count)
except ValueError:
print('Please Insert Numbers Only!')
Here a start, use a while loop for the input. I'll leave the summation part for you unless you need further help:
cc = int(input("Enter an integer to sum. Press 0 to to end and start the summation:"))
while cc != 0:
cc = int(input("Enter an integer to sum. Press 0 to to end and start the summation:"))
def is_int(num):
try:
return int(num)
except:
return False
total = 0
while True:
in_user = is_int(input("input integer: "))
if in_user is not False:
total += in_user
if in_user is 0:
break
print(total)
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I have 2 questions about my code. Why the program doesn't go in the second if statement. How can I end the loop?
from random import *
SecretNumber=randint(1,5)
Guess=int(input("Please enter Guess: "))
NumberofGuesses=1
SecretNumber=0
while Guess != SecretNumber:
NumberofGuesses=NumberofGuesses+1
if Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
if Guess==SecretNumber:
print("Number of Guesses: {0}".format(NumberofGuesses))
Your second if is outside the while loop, so it won't get hit until you guesss the secret number. The loop never ends because you never read another guess.
You also have a problem that you are overriding your random secret number with zero.
You need something like:
import random
SecretNumber=random.randint(1,5)
NumberofGuesses=0
while true:
Guess=int(input("Please enter Guess: "))
NumberofGuesses += 1
if Guess == SecretNumber:
break # Got it!
elif Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
print("Number of Guesses: {0}".format(NumberofGuesses))
It's because you're setting SecretNumber to 0. Remove it and it should work.