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Finding XPath without using inspecting element?

I am making an automation for download data from a weather institution.
The issue is that in my effort to make it more independent I am trying to make Selenium to Tab keys to a certain spot, so the Browser focus can "Walk" to the download button. When I call the click() function it doesn't do anything. So I tried to Extract the XPath with the function get_attribute("xpath") but it returns None. How I can extract the XPath?
I am going to paste the issue down here:
Bandera=driver.find_element_by_xpath('/html/body/div[2]/div[2]/div/div[3]/div/div/div/div[1]/div/div/div[2]/div/table/tbody/tr[1]/td[1]/div/input')
Bandera.click()
Bandera.click()
## So Here i just select and dis-select a checkbox just to be near the Download button.
actions = ActionChains(driver)
actions.send_keys(Keys.TAB * 1 )
actions.perform()
#Here i just tabed to the button
Accion=driver.switch_to.active_element
#Maybe, here is when i lost the focus of the button?
Descarga_Actual=Accion.get_attribute("xpath")
Thank you and sorry to borrow your time.

To make a click on hover I would use the following sequence:
your_dropdown_locator.click()
dropdown_option = driver.find_element_by_xpath("dropdown option locator")
actions = ActionChains(driver)
actions.move_to_element(dropdown_option)
actions.click().perform()
But, this is the approach that is usually used for dropdowns.
You use: driver.find_element_by_xpath('/html/body/div[2]/div[2]/div/div[3]/div/div/div/div[1]/div/div/div[2]/div/table/tbody/tr[1]/td[1]/div/input') This is the main problem of your code.
If you pasted html code of this dropdown (or button you need to click), people would help you to find a better locator. XPath/CSS must be unique. In your case the locator is very bad.
Also, I see no sense making Bandera.click() two times.
In your case, as I understand, you just need to click the button. So the locator is your main problem.
You need to find the correct locator, to wait till the button is clickable and then to click it.
Another problem in what you are trying to do:
get_attribute("xpath") looks like incorrect expectation of how get_attribute function works. Check at least here what this function means Python Selenium: Find object attributes using xpath

Youtube google popup - selenium

The popup
Trying to automate a YouTube search as I'm learning python automation, however I've come across a problem. I can't figure out how to automate clicking the "I agree" on the popup, hoping someone can send a solution

You can find the element using xpath and click on it with the click() method: https://pythonspot.com/selenium-click-button/

To switch to the iframe popup
driver.switch_to.frame("iframe")
//("iframe" for this specific example, otherwise put id of the iframe there)
driver.find_element_by_xpath('//*[#id="introAgreeButton"]/span/span').click()
To switch back to main frame
driver.switch_to.default_content()

browser.switch_to_default_content()
browser.switch_to.frame(browser.find_elements_by_tag_name('iframe')[0])
browser.implicitly_wait(1)
browser.find_element_by_id('introAgreeButton').click()
browser.switch_to.default_content()
I'm using 'browser' instead of 'driver' here.

How to press multiple buttons on a webpage without knowing the id or xpath with Selenium (Python)

I'm trying to automate the logging in and unfollowing of people on the website Depop. I am having a bit of trouble clicking all of the 'unfollow' buttons. Each of the buttons have a different ID and Class and the only similarities between them is this HTML code:
<span> Following <span>
Is there any way to click every button with this HTMl code?
I have already tried finding the XPath of all the buttons but because there are so many of them, it would be difficult to find the XPath of every single button. I have also tried to find the class of the follow buttons but they are all different. There are no similarities in the css selectors.
I have tried doing something like this but to no success.
driver.get_attribute('<span> Following </span>').click()
For optimum results, the program would go through the page, unfollowing everyone that is currently being followed.

Here is the logic.
unfollows = driver.find_elements_by_xpath("//span[normalize-space(.)='Following']")
for btn in unfollows:
btn.click()
If you get staleElement exception with the above approach then you have to follow the following approach.
while len(driver.find_elements_by_xpath("//span[normalize-space(.)='Following']"))>0:
btn = driver.find_element_by_xpath("(//span[normalize-space(.)='Following'])[1]")
btn.location_once_scrolled_into_view
driver.execute_script("arguments[0].click();",btn)

Python Selenium Click Next Button

I need to click the "next" button on the following page:
https://www.amazon.com/gp/goldbox/ref=gbps_ftr_s-4_bedf_wht_29726380?gb_f_deals1=dealStates:AVAILABLE%252CWAITLIST%252CWAITLISTFULL%252CEXPIRED%252CSOLDOUT%252CUPCOMING,includedAccessTypes:,sortOrder:BY_SCORE,enforcedCategories:2972638011&pf_rd_p=afc45143-5c9c-4b30-8d5c-d838e760bedf&pf_rd_s=slot-4&pf_rd_t=701&pf_rd_i=gb_main&pf_rd_m=ATVPDKIKX0DER&pf_rd_r=60XTK6YDM9WEAFXB6519&ie=UTF8
I have the following code that will not find xpath element for the "next button":
browser.find_element_by_xpath("//ul[#class='a-pagination']/li[#class='a-last']/a").click() # Click on next button
I have also tried this variation:
browser.find_element_by_xpath("//div[#id='pagination-next-6885645543374035']/ul/li[#class='a-last']/a")
I also tried directly copying the xpath from the inspector. Neither of these three options work.
Thanks in advance for your help.

The issue is Amazon attaches a numerical ending onto the ID that is different each time the page loads. Finally found a way to select it using xpath:
browser.find_element_by_xpath("//span[#class='a-declarative']/div[2]/ul/li[#class='a-last']/a")

Selenium Python: Census ACS Data- unable to select Download button in window

I am attempting to scrape the Census website for ACS data. I have scripted the whole processes using Selenium except the very last click. I am using Python. I need to click a download button that is in a window that pops when the data is zipped and ready, but I can't seem to identify this button. It also seems that the button might change names based on when it was last run, for example, yui-gen2, yui-gen3, etc so I am thinking I might need to account for this someone. Although I normally only see yui-gen2.
Also, the tag seems to be in a "span" which might be adding to my difficulty honing in on the button I need to click.
Please help if you can shed any light on this for me.
code snippet:
#Refine search results to get tables
driver.find_element_by_id("prodautocomplete").send_keys("S0101")
time.sleep(2)
driver.find_element_by_id("prodsubmit").click()
driver.implicitly_wait(100)
time.sleep(2)
driver.find_element_by_id("check_all_btn_above").click()
driver.implicitly_wait(100)
time.sleep(2)
driver.find_element_by_id("dnld_btn_above").click()
driver.implicitly_wait(100)
driver.find_element_by_id("yui-gen0-button").click()
time.sleep(10)
driver.implicitly_wait(100)
driver.find_element_by_id("yui-gen2-button").click()
enter image description here
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Instead of using the element id, which as you pointed out varies, you can use XPath as Nogoseke mentioned or CSS Selector. Be careful to not make the XPath/selector too specific or reliant on changing values, in this case the element id. Rather than using the id in XPath, try expressing the XPath in terms of the DOM structure (tags):
//*/div/div/div/span/span/span/button[contains(text(),'Download')]
TIL you can validate your XPath by using the search function, rather than by running it in Selenium. I right-clicked the webpage, "inspect element", ctrl+f, and typed in the above XPath to validate that it is the Download button.
For posterity, if the above XPath is too specific, i.e. it is reliant on too many levels of the DOM structure, you can do something shorter, like
//*button[contains(text(),'Download')]
although, this may not be specific enough and may require an additional field, since there may be multiple buttons on the page with the 'Download' text.

Given the HTML you provided, you should be able to use
driver.find_element_by_id("yui-gen2-button")
I know you said you tried it but you didn't say if it works at all or what error message you are getting. If that never works, you likely have an IFRAME that you need to switch to.
If it works sometimes but not consistently due to changing ID, you can use something like
driver.find_element_by_xpath("//button[.='Download']")

On the code inspection view on Chrome you can right click on the item you want to find and copy the xpath. You can they find your element by xpath on Selenium.