how to use curl with -u in python request - python

I am trying to convert a curl request to python request, but i have problem to convert -u .
curl -X POST \
-u "apikey:yourKey" \
--header "Content-Type: audio/wav" \
--data-binary "#path" \
"https://stream-fra.watsonplatform.net/speech-to-text/api/v1/recognize?model=de-DE_BroadbandModel
My solution:
import requests
data = "path"
url = 'https://stream-fra.watsonplatform.net/speech-to-text/api/v1/recognize?model=de-DE_BroadbandModel'
#payload = open("request.json")
headers = {'content-type': 'audio/wav', 'username': "apikey=yourkey" }
r = requests.post(url, headers=headers, data=data)
Edit:
import requests
data = "path"
url = 'https://stream-fra.watsonplatform.net/speech-to-text/api/v1/recognize?model=de-DE_BroadbandModel'
#payload = open("request.json")
headers = {'Content-Type': 'audio/wav'}
#r = requests.post(url, headers=headers, data=data)
print requests.post(url, verify=False, headers=headers, data=data, auth=('apikey', "key"))
now i get
Response [400]
(the curl cmd is working)


Try this
requests.post(url, headers=headers, data=data, auth=(apiKey, yourApiKey))
-u is short for --user which is used for server authentication see here, also look into Basic authentication for requests library.
Edit: You need to read the file (specified in --data-binary "#path") first before passing it in requests.post. I hope this link helps

Related

Post requests in python vs curl

Can someone please suggest the correct syntax for calling the below using python?
curl "https://sometest.api.token" \
-H "Content-Type: application/x-www-form-urlencoded" \
-d "grant_type=client_credentials&client_id={client_id}&client_secret={client_secret}"
My attempt:
import requests
import json
credentials='1111'
secret='2222'
url = 'https://sometest.api.token'
body = {'client_credentials':credentials,'client_secret':secret}
headers = {'Content-type': 'application/x-www-form-urlencoded'}
r = requests.post(url, data=json.dumps(body), headers=headers)

Due to documentation, if you want to send some form-encoded data, you simply pass a dictionary to the data argument.
So you have to try:
import requests
import json
credentials='1111'
secret='2222'
url = 'https://sometest.api.token'
body = {'client_credentials':credentials, 'client_secret':secret}
headers = {'Content-Type': 'application/x-www-form-urlencoded'}
r = requests.post(url, data=body, headers=headers)
And also your parameters in python code are different from parameters in curl, maybe you have to check it.

get 400 bad request after requesting GET in python

Id like to convert this curl command to python script
curl -v -H "Content-Type: application/json" -H "Authorization: Bearer MYTOKEN" https://www.zopim.com/api/v2/chats
I wrote the python script below but I get <Response [400]>and doesn't work.
import requests
url = "https://www.zopim.com/api/v2/chats"
access_token = "MYTOKEN"
response = requests.post(url,
headers={"Content-Type":"application/json;charset=UTF-8",
"Authorization": "Bearer {}".format(access_token)})
print(response)
Any advice will be appreciated.thanks.

You should be using requests.get instead of requests.post, since what you want is a GET request:
import requests
url = "https://www.zopim.com/api/v2/chats"
access_token = "MYTOKEN"
response = requests.get(url,
headers={"Content-Type":"application/json;charset=UTF-8",
"Authorization": "Bearer {}".format(access_token)})
print(response)

How to convert specific CURL request to Python

I have the following Curl request:
curl -v --location --request POST 'http://127.0.0.1:8080/abc' \--header 'Content-Type: application/json' \--data-raw '{data}'
I tried using pycurl and requests command.
Also tried to put headers but it was of no use.
My tried code:
requests = "curl -v --location"
a = "http://127.0.0.1:8080/abc"
headers = {'Content-Type': 'application/json'}
r = requests.post(url=a, headers= headers , params=data)

Is this works?
https://curl.trillworks.com/
import requests
headers = {
'Content-Type': 'application/json',
}
data = '{data}'
response = requests.post('http://127.0.0.1:8080/abc',
headers=headers,
data=data)

Format python PATCH request from curl command

I have a curl command I can run from my local machine that works, but transferring it to a python script is giving me difficulties. Here's the curl command that works:
curl -X PATCH "http://localhost:9999/pins/1" -H "Content-Type: application/json" -d "{"state": "on"}"
And here is what I have so far as a python request:
import requests
url = 'http://localhost:9999/pins/1'
payload = {'state':'on'}
head = {'Content-Type':'application/json'}
r = requests.patch(url, payload, headers=head)
But I am receiving a 400 response. Any direction?
Also, if I format it as
r = requests.patch(url, data=payload)
I get a 500 response code. Also should be noted: I can run a simple get request easily by running something like
r = requests.get(url)

import requests
url = 'http://localhost:9999/pins/1'
payload = {'state':'on'}
head = {'Content-Type':'application/json'}
r = requests.patch(url, json=payload)
change this r = requests.patch(url, data=payload) to r = requests.patch(url, json=payload)

Try the following to make sure that your payload is valid json.
import requests
import json
url = 'http://localhost:9999/pins/1'
payload = {'state':'on'}
head = {'Content-Type':'application/json'}
r = requests.patch(url, data=json.dumps(payload), headers=head)

Working fine when hitting using Curl but Bad Request 400 when using python requests

import requests
import json
import numpy as np
payload = {'query':json.dumps({
"per_page":12,
"sort":None,
"scroll_id":None,
"session_id":None,
"q":"diapers",
"shingle_active":False,
"location":"110005",
"types":["allopathy","brand","sku","udp"],
"country":"",
"is_query_suggestion_applicable":False,
"debug":False,
"filters":None,
"source_fields":["count"],
"query_filters":None,
"is_all":True
})}
headers = {'Content-Type': 'application/json'}
url = 'https://kjhghfjdslsls'
r = requests.post(url, params=payload, headers=headers)
print(r.text)
This gives error :
{"errors":[{"message":"Parameter per_page is required"}],"is_success":false,"status_code":400}
Though when using the below curl request it is working fine & returning required output-->
curl --location --request POST 'http://khjfhdksl' \
--header 'Content-Type: application/json' \
--header 'Content-Type: application/json' \
--data-raw '{
"sort":null,
"per_page":12,
"scroll_id":null,
"session_id":null,
"q":"diapers",
"shingle_active":false,
"location":"110005",
"types":["allopathy","brand","sku","udp"],
"country":"",
"is_query_suggestion_applicable":false,
"debug":false,
"filters":null,
"source_fields":["count"],
"query_filters":null,
"is_all":true
}'

You have a top-level key query in the payload for the python version. And you are passing the payload as params (query params)
Try removing that:
import requests
import json
import numpy as np
payload = json.dumps({
"per_page":12,
"sort":None,
"scroll_id":None,
"session_id":None,
"q":"diapers",
"shingle_active":False,
"location":"110005",
"types":["allopathy","brand","sku","udp"],
"country":"",
"is_query_suggestion_applicable":False,
"debug":False,
"filters":None,
"facets":[{"field":"sku.brand.raw","name":"brand","type":"facet","range":None},{"field":"product_form","name":"product_form","type":"facet","range":None},{"field":"rx_required","name":"rx_required","type":"facet","range":None},{"field":"uses","name":"uses","type":"facet","range":None},{"field":"age","name":"age","type":"facet","range":None},{"field":"recommended","name":"recommended","type":"facet","range":None}],
"source_fields":["count"],
"query_filters":None,
"is_all":True
})
headers = {'Content-Type': 'application/json'}
url = 'https://search-stag123api.example.com/search-new/search/v1/search/lambda'
r = requests.post(url, data=payload, headers=headers)
print(r.text)

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