Querying from sql with dynamic model name and fields in Django - python

I'm new in Django and struggling with some dynamic solutions. I am trying to make an application that user can create table from UI and import data into this table from flat file and then user can be able to browse that data by clicking url(for example, if user create a table for employee, then user should be able to have a url like this for employee : localhost/employee). I will work on import part later but for now, i am trying to find a solution to browse data. And below query is almost do this. But i am not able to use alias instead of column names. Is there any way to build something like that dynamic?
def employee(request):
entries = Employee.objects.annotate(First Name=F('FirstName')). only('FirstName','Email')
print(entries)
return render_to_response('employee.html',{'employees': serializers.serialize("json",entries, fields=('First Name','Email'))})
Above query give me below result. I have only email information here. So there is no First Name because annotate is not working.
[{"model": "client.employee", "pk": 1, "fields": {"Email":"employe1#gmail.com"}}]

As per this ticket, django does not allow serializing non-model fields. So, you need to override the serailizer, so you can try like this:
Write the custom serializer(which will override original json serializer) in a separate file i.e custom_serializer.py
# custom_serializer.py
from django.core.serializers.json import Serializer
class CustomSerializer(Serializer):
def end_object(self, obj):
for field in self.selected_fields:
if field == 'pk' or field=='id': # primary key field
continue
elif field in self._current.keys():
continue
else:
try:
self._current[field] = getattr(obj, field)
except AttributeError:
pass
super(CustomSerializer, self).end_object(obj)
inside the views, import that CustomSerializer and use it. for example
# inside views.py
from .custom_serializer import CustomSerializer
def employee(request):
...
json_data = CustomSerializer().serialize(
entries
fields = (
'First_Name',
'email'
)

Related

How to attach a python file to each row(i.e. each data entry) in database formed using Django?

Ive used default django superuser to create an admin and created a DB using it. But now in that i want to add a python script to each data entry i.e. row. How do i do this???
Nothing special. Used basic Django.
There doesn't seem to be anything particularly complex here. You're just asking if you can use a field on the model to choose something; of course you can.
For instance:
# actions.py
def thing1(obj):
# do something with obj
def thing2(obj):
# do something else with obj
# models.py
from . import actions
ACTIONS = {
"do_thing_1": actions.thing1,
"do_thing_2": actions.thing2,
}
ACTION_CHOICES = [(action, action) for action in ACTIONS]
class MyModel(models.Model):
action = models.CharField(max_length=20, choices=ACTION_CHOICES)
def do_action(self):
return ACTIONS[self.action](self)

Update multiple fields on Google NDB entity

Working with Google App Engine for Python, I am trying to create and then update an ndb entity. To update a single property, you can just access the property using a dot, e.g.
post.body = body
But I would like to know if there is a simple way to update multiple fields within an ndb entity. The following code:
class Create(Handler):
def post(self):
## code to get params
post = Post(author = author,
title = title,
body = body)
post.put()
class Update(Handler):
def post(self, post_id):
post = post.get_by_id(int(post_id))
fields = ['author', 'title', 'body']
data = get_params(self.request, fields)
for field in fields:
post[field] = data[field]
post.put()
The "Create" handler works fine, but the "Update" handler results in:
TypeError: 'Post' object does not support item assignment
So it seems I would need to access the properties using a dot, but that is not going to work when I have a list of properties I want to access.
Can someone provide an alternative way to update multiple properties of an NDB entity after it has been created?
You should use setattr.
for field in fields:
setattr(post, field, data[field])
(Note that GAE objects do actually provide a hidden way of updating them via a dict, but you should use the public interface.)
You can use the populate method:
post.populate(**data)

Django Rest Framework - Read nested data, write integer

So far I'm extremely happy with Django Rest Framework, which is why I alsmost can't believe there's such a large omission in the codebase. Hopefully someone knows of a way how to support this:
class PinSerializer(serializers.ModelSerializer):
item = ItemSerializer(read_only=True, source='item')
item = serializers.IntegerSerializer(write_only=True)
class Meta:
model = Pin
with the goal
The goal here is to read:
{pin: item: {name: 'a', url: 'b'}}
but to write using an id
{pin: item: 10}
An alternative would be to use two serializers, but that looks like a really ugly solution:
django rest framework model serializers - read nested, write flat
Django lets you access the Item on your Pin with the item attribute, but actually stores the relationship as item_id. You can use this strategy in your serializer to get around the fact that a Python object cannot have two attributes with the same name (a problem you would encounter in your code).
The best way to do this is to use a PrimaryKeyRelatedField with a source argument. This will ensure proper validation gets done, converting "item_id": <id> to "item": <instance> during field validation (immediately before the serializer's validate call). This allows you to manipulate the full object during validate, create, and update methods. Your final code would be:
class PinSerializer(serializers.ModelSerializer):
item = ItemSerializer(read_only=True)
item_id = serializers.PrimaryKeyRelatedField(write_only=True,
source='item',
queryset=Item.objects.all())
class Meta:
model = Pin
fields = ('id', 'item', 'item_id',)
Note 1: I also removed source='item' on the read-field as that was redundant.
Note 2: I actually find it rather unintuitive that Django Rest is set up such that a Pin serializer without an Item serializer specified returns the item_id as "item": <id> and not "item_id": <id>, but that is beside the point.
This method can even be used with forward and reverse "Many" relationships. For example, you can use an array of pin_ids to set all the Pins on an Item with the following code:
class ItemSerializer(serializers.ModelSerializer):
pins = PinSerializer(many=True, read_only=True)
pin_ids = serializers.PrimaryKeyRelatedField(many=True,
write_only=True,
source='pins',
queryset=Pin.objects.all())
class Meta:
model = Item
fields = ('id', 'pins', 'pin_ids',)
Another strategy that I previously recommended is to use an IntegerField to directly set the item_id. Assuming you are using a OneToOneField or ForeignKey to relate your Pin to your Item, you can set item_id to an integer without using the item field at all. This weakens the validation and can result in DB-level errors from constraints being violated. If you want to skip the validation DB call, have a specific need for the ID instead of the object in your validate/create/update code, or need simultaneously writable fields with the same source, this may be better, but I wouldn't recommend anymore. The full line would be:
item_id = serializers.IntegerField(write_only=True)
If you are using DRF 3.0 you can implement the new to_internal_value method to override the item field to change it to a PrimaryKeyRelatedField to allow the flat writes. The to_internal_value takes unvalidated incoming data as input and should return the validated data that will be made available as serializer.validated_data. See the docs: http://www.django-rest-framework.org/api-guide/serializers/#to_internal_valueself-data
So in your case it would be:
class ItemSerializer(ModelSerializer):
class Meta:
model = Item
class PinSerializer(ModelSerializer):
item = ItemSerializer()
# override the nested item field to PrimareKeyRelatedField on writes
def to_internal_value(self, data):
self.fields['item'] = serializers.PrimaryKeyRelatedField(queryset=Item.objects.all())
return super(PinSerializer, self).to_internal_value(data)
class Meta:
model = Pin
Two things to note: The browsable web api will still think that writes will be nested. I'm not sure how to fix that but I only using the web interface for debug so not a big deal. Also, after you write the item returned will have flat item instead of the nested one. To fix that you can add this code to force the reads to use the Item serializer always.
def to_representation(self, obj):
self.fields['item'] = ItemSerializer()
return super(PinSerializer, self).to_representation(obj)
I got the idea from this from Anton Dmitrievsky's answer here: DRF: Simple foreign key assignment with nested serializers?
You can create a Customized Serializer Field (http://www.django-rest-framework.org/api-guide/fields)
The example took from the link:
class ColourField(serializers.WritableField):
"""
Color objects are serialized into "rgb(#, #, #)" notation.
"""
def to_native(self, obj):
return "rgb(%d, %d, %d)" % (obj.red, obj.green, obj.blue)
def from_native(self, data):
data = data.strip('rgb(').rstrip(')')
red, green, blue = [int(col) for col in data.split(',')]
return Color(red, green, blue)
Then use this field in your serializer class.
I create a Field type that tries to solve the problem of the Data Save requests with its ForeignKey in Integer, and the requests to read data with nested data
This is the class:
class NestedRelatedField(serializers.PrimaryKeyRelatedField):
"""
Model identical to PrimaryKeyRelatedField but its
representation will be nested and its input will
be a primary key.
"""
def __init__(self, **kwargs):
self.pk_field = kwargs.pop('pk_field', None)
self.model = kwargs.pop('model', None)
self.serializer_class = kwargs.pop('serializer_class', None)
super().__init__(**kwargs)
def to_representation(self, data):
pk = super(NestedRelatedField, self).to_representation(data)
try:
return self.serializer_class(self.model.objects.get(pk=pk)).data
except self.model.DoesNotExist:
return None
def to_internal_value(self, data):
return serializers.PrimaryKeyRelatedField.to_internal_value(self, data)
And so it would be used:
class PostModelSerializer(serializers.ModelSerializer):
message = NestedRelatedField(
queryset=MessagePrefix.objects.all(),
model=MessagePrefix,
serializer_class=MessagePrefixModelSerializer
)
I hope this helps you.

Returning extended fields in JSON

I have two tabels(Ingredient_Step and Ingredient) in on relation as you can see below:
Models.Py
class Ingredient_Step(models.Model):
ingredient = models.ForeignKey(Ingredient)
Step = models.ForeignKey(Step)
def __unicode__(self):
return u'{}'.format(self.Step)
class Ingredient(models.Model):
IngredientName = models.CharField(max_length=200,unique=True)
Picture = models.ImageField(upload_to='Ingredient')
def __unicode__(self):
return u'{}'.format(self.IngredientName)
In a function, i need serialize a JSON object from a query that returns from "Ingredient_step", but I need send the field "IngredientName", who comes from "Ingredient" table.
I try using "ingredient__IngredientName" but it fails.
Views.Py:
def IngredientByStep(request):
if request.is_ajax() and request.GET and 'id_Step' in request.GET:
if request.GET["id_Step"] != '':
IngStp = Ingredient_Step.objects.filter(Step =request.GET["id_Step"])
return JSONResponse(serializers.serialize('json', IngStp, fields=('pk','ingredient__IngredientName')))
How i can call extends field from a relation?
Thanks
This "feature" of Django (and many ORM's like SQLAlchemy) are called Lazy Loading, meaning data is only loaded from related models if you specifically ask for them. In this case, build your IngStp as a list of results, and make sure to access the property for each result before serializing.
Here's an example of how to do that: Django: Include related models in JSON string?

Where's the primary key of the object I want to update in django using modelform?

I'm using modelform in django to insert and update objects in my database, but when I try to update I cannot see the primary key/id of the object being updated:
My model:
class Category(models.Model):
name = models.CharField(max_length=20, db_index = True)
and my form:
class CategoryForm(ModelForm):
class Meta:
model = Category
fields = ['name']
and in my template I got:
{% csrf_token %}
{{ category_form.as_p }}
In my view I do
cat = Category.objects.get(pk = cat_id)
data['category_form'] = CategoryForm(instance = cat)
and pass the data to my template, which renders the form ok, but the id of the object I about to update is nowhere in the html source. How can the code then now what object to update?
I feel stupid asking this since it should be pretty basic, but I've followed all the tutorials and looked thru the django docs, googled and search this site without luck.
Thanks in advance.
Where is cat_id coming from in your view? I guess you receive it in url, like so:
url( r'categories/(\d+)/edit/', your_view, {} ),
in urls.py somewhere. Now in your view you can read it from appropriate view function argument:
def your_view( request, cat_id ):
Now you can obtain object with proper id, which you do here:
cat = Category.objects.get(pk = cat_id)
...and instantiate ModelForm passing it cat object if you want to edit existing object, or don't pass it, if you want an empty form for object creation.
The explanation for this can be found in the django docs here: http://docs.djangoproject.com/en/dev/topics/forms/modelforms/#the-save-method
While trying to update already saved entity you must provide an instance parameter when you recreate the form. Otherwise django will try to insert a new entity.
foo_form = FooForm(request.POST, instance=foo)
The primary key is an attribute called "id" on your instance object "cat". The form itself, and in your example represented by "cat_id". The Model form should takes care to track the primary key - all you should need to do is pass the resulting "request.POST" data back into CategoryForm, valid the data with is_valid() and then save it.
i.e.
form_with_post = CategoryForm(request.POST)
if form_with_post.is_valid():
form_with_post.save()
else:
... return the form_with_post through the context to display the errors
The ID doesn't need to be in the HTML, because you've passed the instance into the form object when you instantiate it. Django simply updates that instance when you do form.save().

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