I'm learning python, and I'm trying with a set of exercises, but I'm stuck on the next one:
inp_1 = input('your score between 0.0 and 1.0')
try:
score = float(inp_1)
if 0.9 <= score <= 1.0:
print ("A") elif score >= 0.8:
print ("B") elif score >= 0.7:
print ("C") elif score >= 0.6:
print ("D") elif score < 0.6:
print ("Your grade is an F")
else:
print ('your score is more than 1.0')
except:
print ('invalid input, please try with a number')
but I'm get the next message error:
IndentationError: unindent does not match any outer indentation level on line 7 elif score >= 0.8: ^ in main.py
The indentation (= number of tabs / spaces in front of each line) is important in python. The code you posted isn't indented properly. A correct indentation would look like this:
inp_1 = input('your score between 0.0 and 1.0')
try:
score = float(inp_1)
if 0.9 <= score <= 1.0:
print ("A")
elif score >= 0.8:
print ("B")
elif score >= 0.7:
print ("C")
elif score >= 0.6:
print ("D")
elif score < 0.6:
print ("Your grade is an F")
else:
print ('your score is more than 1.0')
except:
print ('invalid input, please try with a number')
The first line is always un-indented. When starting a block (e.g. try:, if:, elif:, ...), all following lines that belong within this block are indented with 4 spaces more than the opening line. "Closing" a block is done by writing the next statement with less indentation.
Another example:
if False:
print(1)
print(2)
# prints nothing because both print statements are part of the if condition
if False:
print(1)
print(2)
# prints 2 because the `print(2)` statement is not part of the if condition
Does this answer your question?
Your indentations should be like this:
inp_1 = input('your score between 0.0 and 1.0')
try:
score = float(inp_1)
if 0.9 <= score <= 1.0:
print ("A")
elif score >= 0.8:
print ("B")
elif score >= 0.7:
print ("C")
elif score >= 0.6:
print ("D")
elif score < 0.6:
print ("Your grade is an F")
else:
print ('your score is more than 1.0')
except:
print ('invalid input, please try with a number')
I think you didn't understand indentations fully. This isn't like any other languages. You need to make indentations correctly.
Hope it will help you 😃
Related
So my professor for python assigned an exercise which was to create a program to accept a user input or "score" and create an if else loop with an if else nested loop inside the first loop to check if the score is greater than or equal to 80. If that's satisfied, print a statement saying "you passed." and if the score is equal to 90 or more, then it should say"you got an A." and if the score is below an 80, it should say "you failed."
so far, this is the code I was able to come up with. And it runs up until the score entered is anything equal to or more than 90.
userScore = int(input('enter score:\n'))
if userScore < 80:
userScore = int(input('you failed. Try again:\n'))
if userScore == 80 or userScore > 80:
print(f'good job, you got a B.')
elif userScore >= 90:
print('you got an A')
else:
print('enter a differnt score')
as per your question your code should be :
score = int(input("Please enter your score: "))
if score >= 80:
print("You passed.")
if score >= 90:
print("You got an A.")
else:
print("You failed.")
while(1):
score = int(input("Please enter your score: "))
if score >= 80:
print("You passed.")
if score >= 90:
print("You got an A.")
break
else:
print("You failed.")
while(1):
score = int(input("Please enter your score pal: "))
if score >= 80:
print("You passed the exam.")
if score >= 90:
print("You got an A in the exam.")
break
else:
print("You failed the exam.")
score = input("What is your score? ")
if score == str(100):
print('Perfect!')
elif score <= str(range(95, 99)):
print('Great!')
elif score <= str(range(90, 95)):
print('Good')
else:
print('Fail')
It works when I type 95 to 100, but it doesn't work when I type other numbers.
Use ints to compare numbers, not strings:
score = int(input("What is your score? "))
if score == 100:
print('Perfect!')
elif score in range(95, 100): # This 100 catches the 99 case
print('Great!')
elif score in range(90, 95):
print('Good')
else:
print('Fail')
I am trying to write a program for this assignment:
Write a program to prompt for a score between 0.0 and 1.0. If the score is out of range, print an error. If the score is between 0.0 and 1.0, print a grade using the following table:
Score Grade
>= 0.9 A
>= 0.8 B
>= 0.7 C
>= 0.6 D
< 0.6 F
If the user enters a value out of range, print a suitable error message and exit.
But it doesn't print the sentence.
try:
inp = raw_input("Enter Score: ")
score = float(inp)
except:
print "Please enter a score number between 0.0 and 1.0"
quit()
if score >= 0.9 :
print "A"
elif score >= 0.8 :
print "B"
elif score >= 0.7 :
print "C"
elif score >= 0.6 :
print "D"
elif score < 0.6 :
print "F"
else:
print "Your score number is not in the 0 - 1 range."
score = input("Enter Score: ")
scor = float(score)
if 0.0 < scor > 1.0:
print("error")
elif scor >= 0.9:
print("A")
elif scor >= 0.8:
print("B")
elif scor >= 0.7:
print("C")
elif scor >= 0.6:
print("D")
elif scor < 0.6:
print("F")
You should raise the exception to get it printed. Here is the code changes that you are looking for.
try:
inp = raw_input("Enter Score: ")
score = float(inp)
if score > 1.0 or score < 0
raise
except:
print "Please enter a score number between 0.0 and 1.0"
quit()
if score >= 0.9 :
print "A"
elif score >= 0.8 :
print "B"
elif score >= 0.7 :
print "C"
elif score >= 0.6 :
print "D"
elif score < 0.6 :
print "F"
else:
#your logic
Hope this was helpful.
Pavan, your code doesn't pass the exam, because you accept values which are higher than 1.0 or smaller than 0.0 which is incorrect.
Add a check somewhere which validates that the score is between 0.0 and 1.0.
So like I highlighted in the comment section please make the modifications to your if statement like below:
try:
inp = raw_input("Enter Score: ")
score = float(inp)
except:
print "Please enter a score number between 0.0 and 1.0"
quit()
# change your if statement here:
if score > 1.0 or score < 0.0:
print "Your score number is not in the 0 - 1 range."
elif score >= 0.9 :
print "A"
elif score >= 0.8 :
print "B"
elif score >= 0.7 :
print "C"
elif score >= 0.6 :
print "D"
elif score < 0.6 :
print "F"
EDIT: First of all the if branch checks for an out of bound score which is a value above 1.0 and below 0.0, then prints an error message.
If the score is within limits than the other elif blocks check to value of the score as in the original post.
inp = input("Enter score between 0.0 and 1.0:")
score = float(inp)
if score >= 0.9 and score <= 1.0:
print("A")
if score >= 0.8 and score < 0.9:
print("B")
if score >= 0.7 and score < 0.8:
print("C")
if score >= 0.6 and score < 0.7:
print("D")
if score >= 0.0 and score <0.6:
print("F")
elif score > 1.0:
print("Error, please enter score between 0.0 and 1.0")
quit()
scr=(input("Enter the Score: "))
try:
scr=float(scr)
if scr>=0.0 and scr<=1.0:
if scr >= 0.9:
print("A")
elif scr >= 0.8:
print("B")
elif scr >= 0.7:
print("C")
elif scr >= 0.6:
print("D")
elif scr<0.6:
print("F")
else:
print("Out Of range")
except:
print("Try a number")
Explanation:
scr is the score which will take float as input ranging from 0.0 to 1.0. If the score is less than 0.0 or greater than 1.0 then it prints "Out of Range". If entered input is not float/ int then it will print "Try a Number".
inp = input("Enter a Score between 0.0 and 1.0")
score = float(inp)
if score >= 0.9 and score <=1.0:
print ('A')
elif score >= 0.8 and score <0.9:
print ('B')
elif score >= 0.7 and score <0.8:
print ('C')
elif score >= 0.6 and score <0.7:
print ('D')
elif score >= 0.0 and score <0.6:
print ('F')
elif score > 1.0 or score < 0.0:
print ("Error, the score should be in the range between 0.0 and 1.0")
quit()
I am working on a python lettering assignment.
90 or above is an A and so on and so on for the rest of the letter grades; but when a value is inputted as a negative number, I need the code to do nothing other than display an error.
This is what i tried so far:
#Design a Python program to assign grade to 10 students
#For each student, the program first asks for the user to enter a positive number
#A if the score is greater than or equal to 90
#B if the score is greater than or equal to 80 but less than 90
#C if the score is greater than or equal to 70 but less than 80
#D if the score is greater than or equal to 60 but less than 70
#F is the score is less than 60
#Ihen the program dispalys the letter grade for this student.
#Use while loop to repeat the above grade process for 10 students.
keep_going = 'y'
while keep_going == "y":
num = float(input("Enter a number: "))
if num >= 90:
print("You have an A")
elif num >= 80:
print("You have an 3")
elif num >= 70:
print("You have an C")
elif num >= 60:
print("You have an D")
elif (num < 60 and <= 0:
print ("You have an F")
else:
print("lnvalid Test Score.")
Original screenshot
I see three problems, all in the same line:
elif (num < 60 and <= 0:
Syntax: num < 60 and <= 0 is not a valid expression; should be num < 60 and num <= 0
Logic: num <= 0 is not what you want, it should be num >= 0
Syntax: you missed a closing bracket ).
If you change those, it should work.
grade = int(input("Enter Score:"))
print "FFFFFDCBAA"[grade//10] if grade >= 0 else "ERROR!!!!"
you just have to change your elif for below 60.
keep_going = 'y'
while keep_going == "y":
num = float(input("Enter a number: "))
if num >= 90:
print("You have an A")
elif num >= 80:
print("You have an 3")
elif num >= 70:
print("You have an C")
elif num >= 60:
print("You have an D")
elif 60 > num >= 0:
print ("You have an F")
else:
print("lnvalid Test Score.")
I am trying to solve this grade input program. I need to input the grades between 0.6 to 1.0 and assign them a letter value. I can only use the if else method as we haven't gotten to the other methods yet in class...
score = raw_input("Enter Score Grade:")
sco = int(float(score))
if score < 0.60:
print "Your grade is an F"
elif score >= 0.6:
print "grade d"
elif score >= 0.7:
print "grade c"
elif score >= 0.8:
print "grade b"
elif score >= 0.9:
print "grade a"
else:
print "wrong score"`
You don't have to go highest to lowest score, you can also do this:
score = float(raw_input("Enter Score Grade:"))
if score < 0.60:
print "Your grade is an F"
elif score < 0.7:
print "grade d"
elif score < 0.8:
print "grade c"
elif score < 0.9:
print "grade b"
elif score <= 1.0:
print "grade a"
else:
print "wrong score"
If you do decide to check from highest to lowest, being consistent is a good practice. You can check your failing grade last:
score = float(raw_input("Enter Score Grade:"))
if score > 1:
print "wrong score"
elif score >= 0.9:
print "grade a"
elif score >= 0.8:
print "grade b"
elif score >= 0.7:
print "grade c"
elif score >= 0.6:
print "grade d"
else:
print "Your grade is an F"
As a reusable function :
def grade(score):
if score > 1:
return "wrong score"
if score >= 0.9:
return "grade a"
if score >= 0.8:
return "grade b"
if score >= 0.7:
return "grade c"
if score >= 0.6:
return "grade d"
return "Your grade is an F"
score = float(raw_input("Enter Score Grade:"))
print grade(score)
You should start from the largest grade first:
as you see 0.92 > 0.6 and also 0.92 > 0.9
But according to yout logic, it will satisfy the first if and will never reach last if.
Do something like this:
score = raw_input("Enter Score Grade:")
sco = int(float(score))
if score < 0.60:
print ("Your grade is an F")
elif score >= 0.9:
print ("grade a")
elif score >= 0.8:
print ("grade b")
elif score >= 0.7:
print ("grade c")
elif score >= 0.6:
print ("grade d")
else:
print ("wrong score")
You need to go from high grade to low grade. You need to change sco = int(float(score)) to score = float(score). It is not required to change it to int as you are comparing float
score = raw_input('Enter the Score')
score = float(score)
if score >= 0.9:
grade = 'A'
elif score >= 0.8:
grade = 'B'
elif score >= 0.7:
grade = 'C'
elif score >= 0.6:
grade = 'D'
else:
grade = 'F'
print 'Your Grade : ' + grade
You have to take not of the first condition. If the first condition is equal to 0.9, it will equate to false and give the grade of 'B'. Also, it will be wise to convert the input to int first
score = int(raw_input('Enter the Score'))
score = float(score)
if score > 0.9:
grade = 'A'
elif score >= 0.8:
grade = 'B'
elif score >= 0.7:
grade = 'C'
elif score >= 0.6:
grade = 'D'
else:
grade = 'F'
print 'Your Grade : ' + grade
It is therefore advisable to use the greater than or equal to so as to handle the situation when it is equal to the upper value(ie 0.9).
score = int(raw_input('Enter the Score'))
score = float(score)
if score >= 0.9:
grade = 'A'
elif score >= 0.8:
grade = 'B'
elif score >= 0.7:
grade = 'C'
elif score >= 0.6:
grade = 'D'
else:
grade = 'F'
print 'Your Grade : ' + grade