Hi I am working with date time and timezone in Python. My code is working perfectly. Only this is not showing the correct day of week in Indian time zone. If I run this code from my local machine all is ok. But if I host the code in other time zone it is not showing correct day of week in Indian time zone. My code is given below.
import pytz
import datetime
start_time = '09:15'
end_time = '15:45'
ist = pytz.timezone('Asia/Kolkata')
ind_time = datetime.datetime.now(pytz.timezone("Asia/Kolkata")).strftime('%H:%M')
print(ind_time)
current_time = datetime.datetime.now().strftime('%H:%M')
print(current_time)
day_of_week = datetime.datetime.today().weekday()
print(day_of_week)
if ind_time > start_time and ind_time < end_time and day_of_week <5:
print("Hallo World")
if ind_time > end_time:
pass # to return nothing
Can anyone help me to correct this code?
You probably intended to do:
day_of_week = ind_time.weekday()
print(day_of_week)
schedule.wednesday.at("13:15").do(job)
With this code I can run fuction on wednesday 13:15. But I want to make action like, "run function next day morning '10:00' " How can do this?
Wrap job to return schedule.CancelJob such that it runs only once. Then schedule it to run every day at 10:00.
def job_once():
job()
return schedule.CancelJob
schedule.every().day.at('10:00').do(job_once)
Caveat: if the current time is before 10:00, then the job will run this day at 10:00. There's no way to define an initial delay in the schedule library - but we could get the name of the next day and schedule on this day.
import datetime
tomorrow = (datetime.datetime.now() + datetime.timedelta(days=1)).strftime('%A').lower()
getattr(schedule.every(), tomorrow).at('10:00').do(job_once)
Python contains a simple library called sched:
import sched, time
def functionYouWantToRun():
...
s = sched.scheduler(time.localtime, time.sleep)
s.enterabs(time.strptime('[three character day] [three character month] [day of month] [time (hh:mm:ss)] [year]')
s.run()
def job_that_executes_once():
# Do some work that only needs to happen once...
return schedule.CancelJob
if __name__ == "__main__":
from datetime import datetime, timedelta
import schedule
schedule.every().day.at("10:00").do(job_that_executes_once)
I was going to go with time offset, but then realised the above is easier. That will run it the next day.
If you need to run several days in the future, then you are back to datetime offsets:
x=datetime.today()
y = x.replace(day=x.day, hour=10, minute=0, second=0, microsecond=0) +
timedelta(days=1)
yDay = y.strftime('%A')
How can I run a function in Python, at a given time?
For example:
run_it_at(func, '2012-07-17 15:50:00')
and it will run the function func at 2012-07-17 15:50:00.
I tried the sched.scheduler, but it didn't start my function.
import time as time_module
scheduler = sched.scheduler(time_module.time, time_module.sleep)
t = time_module.strptime('2012-07-17 15:50:00', '%Y-%m-%d %H:%M:%S')
t = time_module.mktime(t)
scheduler_e = scheduler.enterabs(t, 1, self.update, ())
What can I do?
Reading the docs from http://docs.python.org/py3k/library/sched.html:
Going from that we need to work out a delay (in seconds)...
from datetime import datetime
now = datetime.now()
Then use datetime.strptime to parse '2012-07-17 15:50:00' (I'll leave the format string to you)
# I'm just creating a datetime in 3 hours... (you'd use output from above)
from datetime import timedelta
run_at = now + timedelta(hours=3)
delay = (run_at - now).total_seconds()
You can then use delay to pass into a threading.Timer instance, eg:
threading.Timer(delay, self.update).start()
Take a look at the Advanced Python Scheduler, APScheduler: http://packages.python.org/APScheduler/index.html
They have an example for just this usecase:
http://packages.python.org/APScheduler/dateschedule.html
from datetime import date
from apscheduler.scheduler import Scheduler
# Start the scheduler
sched = Scheduler()
sched.start()
# Define the function that is to be executed
def my_job(text):
print text
# The job will be executed on November 6th, 2009
exec_date = date(2009, 11, 6)
# Store the job in a variable in case we want to cancel it
job = sched.add_date_job(my_job, exec_date, ['text'])
Might be worth installing this library: https://pypi.python.org/pypi/schedule, basically helps do everything you just described. Here's an example:
import schedule
import time
def job():
print("I'm working...")
schedule.every(10).minutes.do(job)
schedule.every().hour.do(job)
schedule.every().day.at("10:30").do(job)
schedule.every().monday.do(job)
schedule.every().wednesday.at("13:15").do(job)
while True:
schedule.run_pending()
time.sleep(1)
Here's an update to stephenbez' answer for version 3.5 of APScheduler using Python 2.7:
import os, time
from apscheduler.schedulers.background import BackgroundScheduler
from datetime import datetime, timedelta
def tick(text):
print(text + '! The time is: %s' % datetime.now())
scheduler = BackgroundScheduler()
dd = datetime.now() + timedelta(seconds=3)
scheduler.add_job(tick, 'date',run_date=dd, args=['TICK'])
dd = datetime.now() + timedelta(seconds=6)
scheduler.add_job(tick, 'date',run_date=dd, kwargs={'text':'TOCK'})
scheduler.start()
print('Press Ctrl+{0} to exit'.format('Break' if os.name == 'nt' else 'C'))
try:
# This is here to simulate application activity (which keeps the main thread alive).
while True:
time.sleep(2)
except (KeyboardInterrupt, SystemExit):
# Not strictly necessary if daemonic mode is enabled but should be done if possible
scheduler.shutdown()
I've confirmed the code in the opening post works, just lacking scheduler.run(). Tested and it runs the scheduled event. So that is another valid answer.
>>> import sched
>>> import time as time_module
>>> def myfunc(): print("Working")
...
>>> scheduler = sched.scheduler(time_module.time, time_module.sleep)
>>> t = time_module.strptime('2020-01-11 13:36:00', '%Y-%m-%d %H:%M:%S')
>>> t = time_module.mktime(t)
>>> scheduler_e = scheduler.enterabs(t, 1, myfunc, ())
>>> scheduler.run()
Working
>>>
I ran into the same issue: I could not get absolute time events registered with sched.enterabs to be recognized by sched.run. sched.enter worked for me if I calculated a delay, but is awkward to use since I want jobs to run at specific times of day in particular time zones.
In my case, I found that the issue was that the default timefunc in the sched.scheduler initializer is not time.time (as in the example), but rather is time.monotonic. time.monotonic does not make any sense for "absolute" time schedules as, from the docs, "The reference point of the returned value is undefined, so that only the difference between the results of consecutive calls is valid."
The solution for me was to initialize the scheduler as
scheduler = sched.scheduler(time.time, time.sleep)
It is unclear whether your time_module.time is actually time.time or time.monotonic, but it works fine when I initialize it properly.
dateSTR = datetime.datetime.now().strftime("%H:%M:%S" )
if dateSTR == ("20:32:10"):
#do function
print(dateSTR)
else:
# do something useful till this time
time.sleep(1)
pass
Just looking for a Time of Day / Date event trigger:
as long as the date "string" is tied to an updated "time" string, it works as a simple TOD function. You can extend the string out to a date and time.
whether its lexicographical ordering or chronological order comparison,
as long as the string represents a point in time, the string will too.
someone kindly offered this link:
String Comparison Technique Used by Python
had a really hard time getting these answers to work how i needed it to,
but i got this working and its accurate to .01 seconds
from apscheduler.schedulers.background import BackgroundScheduler
sched = BackgroundScheduler()
sched.start()
def myjob():
print('job 1 done at: ' + str(dt.now())[:-3])
dt = datetime.datetime
Future = dt.now() + datetime.timedelta(milliseconds=2000)
job = sched.add_job(myjob, 'date', run_date=Future)
tested accuracy of timing with this code:
at first i did 2 second and 5 second delay, but wanted to test it with a more accurate measurement so i tried again with 2.55 second delay and 5.55 second delay
dt = datetime.datetime
Future = dt.now() + datetime.timedelta(milliseconds=2550)
Future2 = dt.now() + datetime.timedelta(milliseconds=5550)
def myjob1():
print('job 1 done at: ' + str(dt.now())[:-3])
def myjob2():
print('job 2 done at: ' + str(dt.now())[:-3])
print(' current time: ' + str(dt.now())[:-3])
print(' do job 1 at: ' + str(Future)[:-3] + '''
do job 2 at: ''' + str(Future2)[:-3])
job = sched.add_job(myjob1, 'date', run_date=Future)
job2 = sched.add_job(myjob2, 'date', run_date=Future2)
and got these results:
current time: 2020-12-10 19:50:44.632
do job 1 at: 2020-12-10 19:50:47.182
do job 2 at: 2020-12-10 19:50:50.182
job 1 done at: 2020-12-10 19:50:47.184
job 2 done at: 2020-12-10 19:50:50.183
accurate to .002 of a second with 1 test
but i did run a lot of tests and accuracy ranged from .002 to .011
never going under the 2.55 or 5.55 second delay
#everytime you print action_now it will check your current time and tell you should be done
import datetime
current_time = datetime.datetime.now()
current_time.hour
schedule = {
'8':'prep',
'9':'Note review',
'10':'code',
'11':'15 min teabreak ',
'12':'code',
'13':'Lunch Break',
'14':'Test',
'15':'Talk',
'16':'30 min for code ',
'17':'Free',
'18':'Help ',
'19':'watever',
'20':'watever',
'21':'watever',
'22':'watever'
}
action_now = schedule[str(current_time.hour)]
Well, I am making this program which will click a link sent on zoom and close zoom at the end of meeting
This is the code
import pyautogui
import time
import pause
import datetime
import schedule
YEAR = 2020
MONTH = 11
DATE = 6
HOUR = 10
MINUTES = 1
SECONDS = 00
now = datetime.datetime.now()
EndTime = now.replace(hour=HOUR, minute=MINUTES, second=SECONDS, microsecond=0)
JustBefore= now.replace(hour=HOUR, minute=MINUTES-1, second=SECONDS, microsecond=0)
def leave_the_meeting():
pyautogui.click(1198, 1072)
time.sleep(3)
pyautogui.click(1443, 998)
time.sleep(1)
pyautogui.click(1398, 933)
def click_the_attendance_link():
pyautogui.click(1665, 674)
time.sleep(9)
I want click_the_attendance_link() to keep functioning over and over again until JustBefore and then stop.
and then I want leave_the_meeting() to start functioning for just one time at EndTime.
What code should I add?
How about this:
def keep_click_attendance_link():
while datetime.datetime.now() < JustBefore:
click_attendance_link()
# Sleep for 60 secs before trying again
time.sleep(60)
while datetime.datetime.now() < Endtime:
# Sleep for 1 sec intervals:
time.sleep(1)
# eventually Leave the meeting at Endtime
leave_the_meeting()
I'm making a clock that shows me both the time in the UK and in Florida on a continuous loop but when I run the Code it only displays the time I started the run the Code.
Bear in mind that this is my first project. So any amateurish tips will also be helpful
The code itself:
#UK Time
from datetime import datetime
now = datetime.now()
current_time = now.strftime("%H:%M:%S")
#Florida time
from datetime import timedelta
minus_hours = now - timedelta(hours=5)
display_minus_hours = minus_hours.strftime("%H:%M:%S")
while True:
print('UK =', current_time)
print('Florida =', display_minus_hours)
you need to update your variables in the loop.
from datetime import datetime, timedelta
while True:
# UK Time
now = datetime.now()
current_time = now.strftime("%H:%M:%S")
# Florida time
minus_hours = now - timedelta(hours=5)
display_minus_hours = minus_hours.strftime("%H:%M:%S")
print('UK =', current_time)
print('Florida =', display_minus_hours)
p.s. this prints a lot of stuff out without changing, consider adding a time.sleep(1)
The problem is that the variable is only assigned once.
var = datetime.now()
while True:
print(var)
You need to update the variable every iteration.
while True:
var = datetime.now()
print(var)