This question already has answers here:
Find objects between two dates MongoDB
(17 answers)
Mongodb query specific month|year not date
(5 answers)
Closed 4 years ago.
I am trying to write a mongo query in python to get the monthly and weekly range from days.
So far I have
my_collection.find({
'date':{
'$gte': date_start,
'$lte': date_end
}
}
It returns the day range between date_start and date_end, I tried to use '$month': 'gte', 'lte' but is not working, does anyone has any ideas how to get monthly and weekly based on the start date and end? The date_start and date_end are datetime objects.
Example ( date_start = 2017-01-01, date_end = 2017-12-01) I want to return just the month between this two range(start, end): 01, 02, 03, 04, 05, 06 ..
I just went through the same examples that has been asked before and what I asked is different, in my situation I have two dates, start and end.. now from this two dates I just want to display the month by combining the two dates together.. so far I haven't seen an example of how to do it.
Thanks
Related
This question already has answers here:
How can I convert a string into a date object and get year, month and day separately?
(4 answers)
Closed 2 months ago.
I have a bunch of number sequences like "221201" meaning the year 2022, month 12 and day 01 (so 2022-12-01). How can I convert number sequences in this format into the actual date using python?
I've tried using the dateutil library but couldn't figure out how to get it to recognize this format.
from datetime import datetime
date_str = '221201'
date_obj = datetime.strptime(date_str, '%y%m%d')
print(type(date_obj))
print(date_obj) # printed in default format
You can learn more about strptime in this link
This question already has answers here:
Pandas: How to create a datetime object from Week and Year?
(4 answers)
Closed 4 months ago.
I have the following data:
week = [202001, 202002, 202003, ..., 202052]
Where the composition of the variable is [year - 4 digits] + [week - 2 digits] (so, the first row means it's the first week of 2020, and so on).
I want to transform this, to a date-time variable [YYYY - MM - DD]. I'm not sure what day could fit in this format :( maybe the first saturday of every week.
week_date = [2020-01-04, 2020-01-11, 2020-01-18, ...]
It seems like a simple sequence, neverthless I have some missings values on the data, so my n < number of weeks of 2020.
The main purpose of this conversion is that I can have a fit model to train in prophet. I also think I need no missing values when incorporating the data into prophet, so maybe the answer could be also adding 0 to my time series?
Any ideas? Thanks
Try:
l = [202001, 202002, 202003, 202052]
out [datetime.datetime.fromisocalendar(int(x[:4]), int(x[4:]), 6).strftime("%Y-%m-%d") for x in map(str,l)]
print(out)
outputs:
['2020-01-04', '2020-01-11', '2020-01-18', '2020-12-26']
Here I used 6 as the week day but chose as you want
This makes a datetime object from the first and last part of each number after mapping them to a string, then outputs a string back with strftime and the right format.
This question already has answers here:
Converting unix timestamp string to readable date
(19 answers)
Closed 2 years ago.
I have in Python 3.7 a date in form of an integer that represents the number of hours from 1/1/1900 00 Hours. Can I transform it into string of format dd/mm/yyyy?
for example:
timenumber = 1043148
timestring = magictrickfunctions(timenumber)
print(timestring)
should give "01/01/2017"
Are you sure it gives you 01/01/2017 instead of 01/01/2019?
To obtain the number of days divide your total hours by /24 this will give you the number of days. You can then specify that as shown below. I am using pandas library here.
import pandas as pd
start_date = "01/01/1900"
date_1 = pd.to_datetime(start_date)
end_date = date_1 + pd.DateOffset(days=43464) #specify the number of days and add it to your start_date
print(end_date)
Outtput
2019-01-01 00:00:00
This question already has answers here:
Getting the date of the first day of the week
(2 answers)
Python: give start and end of week data from a given date
(5 answers)
Closed 3 years ago.
I am trying to get the timestamp of monday at 00:00 of the current week in python. I know that for a specific date, the timestamp can be found using
baseTime = int(datetime.datetime.timestamp(datetime.datetime(2020,1,1)))
However, I want my program to automatically find out, based on the date, which date monday of the current week was, and then get the timestamp. That is to say, it would return different dates this week and next week, meaning different timestamps.
I know that the current date can be found using
import datetime
today = datetime.date.today()
Thanks in advance
I am trying to get the timestamp of monday at 00:00 of the current week in python
You could use timedelta method from datetime package.
from datetime import datetime, timedelta
now = datetime.now()
monday = now - timedelta(days = now.weekday())
print(monday)
Output
2020-01-27 08:47:01
This question already has answers here:
Generate a list of datetimes between an interval
(5 answers)
Closed 8 years ago.
I have a starting date (lets say January 5th 2014) and an end date (lets say July 10th 2014). I know that an event occurs every Wednesday. Is there an easy way in Python to output all Wednesday with date between those date ranges?
So assuming January 7th is a Wednesday, then the code snippet would output 01.07.2014, 01.14.2014, 01.21.2014, and so on.
To get the first specific weekday after a given date, just add a timedelta of the difference in the weekdays:
wed = 2 # from the datetime.weekday definition
first_wed = start + datetime.timedelta(days=(7 + wed - start.weekday()) % 7)
Once you have that, please see Generate a list of datetimes between an interval in python.