Discord bot - issue saving a text file after hosting - python

OK, I have been trying to think of a solution/find a solution myself for quite some time but everything I am attempting either ends up not a solution, or too complex for me to attempt without knowing it will work.
I have a discord bot, made in python. The bots purpose is to parse a blog for HTML links, when a new HTML link is posted, it will the post the link into discord.
I am using a textfile to save the latest link, and then parsing the website every 30seconds to check if a new link has been posted by comparing the link at position 0 in the array to the link in the textfile.
Now, I have managed to host my bot on Heroku with some success however I have since learned that Heroku cannot modify my textfile since it pulls the code from github, any changes are reverted after ~24hours.
Since learning this I have attempted to host the textfile on an AWS S3 bucket, however I have now learned that it can add and delete files, but not modify existing ones, and can only write new files from existing files on my system, meaning if I could do this, I wouldn't need to do this since I would be able to modify the file actually on my system and not need to host it anywhere.
I am looking for hopefully simple solutions/suggestions.
I am open to changing the hosting/whatever is needed, however I cannot pay for hosting.
Thanks in advance.
EDIT
So, I am editing this because I have a working solution thanks to a suggestion commented below.
The solution is to get my python bot to commit the new file to github, and then use that commited file's content as the reference.
import base64
import os
from github import Github
from github import InputGitTreeElement
user = os.environ.get("GITHUB_USER")
password = os.environ.get("GITHUB_PASSWORD")
g = Github(user,password)
repo = g.get_user().get_repo('YOUR REPO NAME HERE')
file_list = [
'last_update.txt'
]
file_names = [
'last_update.txt',
]
def git_commit():
commit_message = 'News link update'
master_ref = repo.get_git_ref('heads/master')
master_sha = master_ref.object.sha
base_tree = repo.get_git_tree(master_sha)
element_list = list()
for i, entry in enumerate(file_list):
with open(entry) as input_file:
data = input_file.read()
if entry.endswith('.png'):
data = base64.b64encode(data)
element = InputGitTreeElement(file_names[i], '100644', 'blob', data)
element_list.append(element)
tree = repo.create_git_tree(element_list, base_tree)
parent = repo.get_git_commit(master_sha)
commit = repo.create_git_commit(commit_message, tree, [parent])
master_ref.edit(commit.sha)
I then have a method called 'check_latest_link' which checks my github repo's RAW format, and parses that HTML to source the contents and then assigns that content as a string to my variable 'last_saved_link'
import requests
def check_latest_link():
res = requests.get('[YOUR GITHUB PAGE LINK - RAW FORMAT]')
content = res.text
return(content)
Then in my main method I have the follow :
#client.event
async def task():
await client.wait_until_ready()
print('Running')
while True:
channel = discord.Object(id=channel_id)
#parse_links() is a method to parse HTML links from a website
news_links = parse_links()
last_saved_link = check_latest_link()
print('Running')
await asyncio.sleep(5)
#below compares the parsed HTML, to the saved reference,
#if they are not the same then there is a new link to post.
if last_saved_link != news_links[0]:
#the 3 methods below (read_file, delete_contents and save_to_file)
#are methods that simply do what they suggest to a text file specified elsewhere
read_file()
delete_contents()
save_to_file(news_links[0])
#then we have the git_commit previously shown.
git_commit()
#after git_commit, I was having an issue with the github reference
#not updating for a few minutes, so the bot posts the message and
#then goes to sleep for 500 seconds, this stops the bot from
#posting duplicate messages. because this is an async function,
#it will not stop other async functions from executing.
await client.send_message(channel, news_links[0])
await asyncio.sleep(500)

I am posting this so I can close the thread with an "Answer" - please refer to post edit.

Related

Python Code not opening VlC player of twitch stream instances

Hello so I don't stream right but wanted to make a video on peoples reactions when they are suddenly hit with a lot of people (this would be accompanied by a chat bot too and ill tell them what it was as well as ask for use permissions). So I thought it would be fun to look at view bots for twitch and found one online (code below). so I ran in installed streamlink via Pip and windows executable and it seems to run "found matching plugin twitch for URL "Stream link"" but it doesn't actually increase viewership and I can only assume this is because its not actually opening the Vlc instances, so here I am wondering what I need to do I have the latest version of python and git isnt trying to download and install anything so im assuming streamlink is all I need but im kind confused why it woudnt be opening the VLC instance any help is most appreciated.
Edit: oh and I do have the proxies and using a small amount to try and get it to work first, and will buy more later but after I get this to work!
import concurrent.futures, time, random, os
#desired channel url
channel_url = 'https://www.twitch.tv/StreamerName'
#number of viewer bots
botcount = 10
#path to proxies.txt file
proxypath = "C:\Proxy\proxy.txt"
#path to vlc
playerpath = r'"C:\Program Files\VideoLAN\VLC\vlc.exe"'
#takes proxies from proxies.txt and returns to list
def create_proxy_list(proxyfile, shared_list):
with open(proxyfile, 'r') as file:
proxies = [line.strip() for line in file]
for i in proxies:
shared_list.append((i))
return shared_list
#takes random proxies from the proxies list and adds them to another list
def randproxy(proxylist, botcount):
randomproxylist = list()
for _ in range(botcount):
proxy = random.choice(proxylist)
randomproxylist.append(proxy)
proxylist.remove(proxy)
return (randomproxylist)
#launches a viewer bot after a short delay
def launchbots(proxy):
time.sleep(random.randint(5, 10))
os.system(f'streamlink --player={playerpath} --player-no-close --player-http --hls-segment-timeout 30 --hls-segment-attempts 3 --retry-open 1 --retry-streams 1 --retry-max 1 --http-stream-timeout 3600 --http-proxy {proxy} {channel_url} worst')
#calls the launchbots function asynchronously
def main(randomproxylist):
with concurrent.futures.ThreadPoolExecutor() as executer:
executer.map(launchbots, randomproxylist)
if __name__ == "__main__":
main(randproxy(create_proxy_list(proxypath, shared_list=list()), botcount))

Azure API Not Working(sorry for the title I have no idea what's wrong)

As I said already sorry for the title. I have never worked with Azure API and have no idea what is wrong with the code, as I just copied from the documentation and put in my information.
Here is the code:
from azure.cognitiveservices.speech import AudioDataStream, SpeechConfig, SpeechSynthesizer, SpeechSynthesisOutputFormat
from azure.cognitiveservices.speech.audio import AudioOutputConfig
speech_config = SpeechConfig(subscription="ImagineHereAreNumbers", region="westeurope")
speech_config.speech_synthesis_language = "en-US"
speech_config.speech_synthesis_voice_name = "ChristopherNeural"
audio_config = AudioOutputConfig(filename=r'C:\Users\TheD4\OneDrive\Desktop\SpeechFolder\Azure.wav')
synthesizer = SpeechSynthesizer(speech_config=speech_config, audio_config=audio_config)
synthesizer.speak_text_async("A simple test to write to a file.")
Well as I run this I get no error and in fact, get in my desired folder a .wav file, but this file has 0 bytes and it looks corrupted.
Now here is why I have no idea of what's wrong because if I remove this
speech_config.speech_synthesis_language = "en-US"
speech_config.speech_synthesis_voice_name = "ChristopherNeural"
So it becomes this
from azure.cognitiveservices.speech import AudioDataStream, SpeechConfig, SpeechSynthesizer, SpeechSynthesisOutputFormat
from azure.cognitiveservices.speech.audio import AudioOutputConfig
speech_config = SpeechConfig(subscription="ImagineHereAreNumbers", region="westeurope")
audio_config = AudioOutputConfig(filename=r'C:\Users\TheD4\OneDrive\Desktop\SpeechFolder\Azure.wav')
synthesizer = SpeechSynthesizer(speech_config=speech_config, audio_config=audio_config)
synthesizer.speak_text_async("A simple test to write to a file.")
It now works all of the sudden, but with what I assume to be the basic/common voice.
So here is my question: how do I choose a voice that I want(btw is this one "en-US-JennyNeural" style="customerservice" or something among these lines)
Thank You in advance!
ChristopherNeural is not a valid voice name. The actual name of the voice is en-US-ChristopherNeural.
speech_config.speech_synthesis_voice_name = "en-US-ChristopherNeural"
This is well-documented on the Language support page of the Speech services documentation.
For other, more fine-grained control over voice characteristics, you'll require the use of SSML as outlined in text-to-speech-basics.py.

How to make python download an image from a URL but if the image is already downloaded it doesnt

So say from a random api, lets say api.example.com as an example. It sends a random image once you go on it and sends the json for it. So like {"url": "api.example.com/img1.png"}. After de-jsonifying it how can i download the image and save it in some folder, but if its already downloaded so say the image name is taken it will not download it.
Edit: here is my code i done so far.
`
url = f"https://nekos.life/api/v2/img/neko"
response = requests.get(url)
response.raise_for_status()
jsonResponse = response.`json()
urll = (jsonResponse["url"])
urllib.request.urlretrieve(urll, "neko.png")`
as said in this article, i think [os.path][1] can do the job pretty well.
just try to use
os.path.exists(phot_path)
that should be it.
[1]: https://linuxize.com/post/python-check-if-file-exists/

Function in django views run 2 times without reason

I have problem because I can not find the reason why my function in Django views.py sometimes runs two times. When I go to url, which call function create_db in Django view, function read json files from directory, parse it and write the data in the database. Most of the time it works perfectly, but sometimes for no reason it runs two times and write the same data in the data base. Does anyone know what can be the reason why code is sometimes done twice and how can I solve the problem?
Here is my create_db function:
def create_db(request):
response_data = {}
try:
start = time.time()
files = os.listdir()
print(files)
for filename in files:
if filename.endswith('.json'):
print(filename)
with open(f'{filename.strip()}', encoding='utf-8') as f:
data = json.load(f)
for item in data["CVE_Items"]:
import_item(item)
response_data['result'] = 'Success'
response_data['message'] = 'Baza podatkov je ustvarjena.'
except KeyError:
response_data['result'] = 'Error'
response_data['message'] = 'Prislo je do napake! Podatki niso bili uvozeni!'
return HttpResponse(json.dumps(response_data), content_type='application/json')
The console output that I expect:
['nvdcve-1.0-2002.json', 'nvdcve-1.0-2003.json', 'nvdcve-1.0-2004.json', 'nvdcve-1.0-2005.json', 'nvdcve-1.0-2006.json', 'nvdcve-1.0-2007.json', 'nvdcve-1.0-2008.json', 'nvdcve-1.0-2009.json', 'nvdcve-1.0-2010.json', 'nvdcve-1.0-2011.json', 'nvdcve-1.0-2012.json', 'nvdcve-1.0-2013.json', 'nvdcve-1.0-2014.json', 'nvdcve-1.0-2015.json', 'nvdcve-1.0-2016.json', 'nvdcve-1.0-2017.json']
nvdcve-1.0-2002.json
nvdcve-1.0-2003.json
nvdcve-1.0-2004.json
nvdcve-1.0-2005.json
nvdcve-1.0-2006.json
nvdcve-1.0-2007.json
nvdcve-1.0-2008.json
nvdcve-1.0-2009.json
nvdcve-1.0-2010.json
nvdcve-1.0-2011.json
nvdcve-1.0-2012.json
nvdcve-1.0-2013.json
nvdcve-1.0-2014.json
nvdcve-1.0-2015.json
nvdcve-1.0-2016.json
nvdcve-1.0-2017.json
Console output when error happened:
['nvdcve-1.0-2002.json', 'nvdcve-1.0-2003.json', 'nvdcve-1.0-2004.json', 'nvdcve-1.0-2005.json', 'nvdcve-1.0-2006.json', 'nvdcve-1.0-2007.json', 'nvdcve-1.0-2008.json', 'nvdcve-1.0-2009.json', 'nvdcve-1.0-2010.json', 'nvdcve-1.0-2011.json', 'nvdcve-1.0-2012.json', 'nvdcve-1.0-2013.json', 'nvdcve-1.0-2014.json', 'nvdcve-1.0-2015.json', 'nvdcve-1.0-2016.json', 'nvdcve-1.0-2017.json']
nvdcve-1.0-2002.json
['nvdcve-1.0-2002.json', 'nvdcve-1.0-2003.json', 'nvdcve-1.0-2004.json', 'nvdcve-1.0-2005.json', 'nvdcve-1.0-2006.json', 'nvdcve-1.0-2007.json', 'nvdcve-1.0-2008.json', 'nvdcve-1.0-2009.json', 'nvdcve-1.0-2010.json', 'nvdcve-1.0-2011.json', 'nvdcve-1.0-2012.json', 'nvdcve-1.0-2013.json', 'nvdcve-1.0-2014.json', 'nvdcve-1.0-2015.json', 'nvdcve-1.0-2016.json', 'nvdcve-1.0-2017.json']
nvdcve-1.0-2002.json
nvdcve-1.0-2003.json
nvdcve-1.0-2003.json
nvdcve-1.0-2004.json
nvdcve-1.0-2004.json
nvdcve-1.0-2005.json
nvdcve-1.0-2005.json
nvdcve-1.0-2006.json
nvdcve-1.0-2006.json
nvdcve-1.0-2007.json
nvdcve-1.0-2007.json
nvdcve-1.0-2008.json
nvdcve-1.0-2008.json
nvdcve-1.0-2009.json
nvdcve-1.0-2009.json
nvdcve-1.0-2010.json
nvdcve-1.0-2010.json
nvdcve-1.0-2011.json
nvdcve-1.0-2011.json
nvdcve-1.0-2012.json
nvdcve-1.0-2012.json
nvdcve-1.0-2013.json
nvdcve-1.0-2013.json
nvdcve-1.0-2014.json
nvdcve-1.0-2014.json
nvdcve-1.0-2015.json
nvdcve-1.0-2015.json
nvdcve-1.0-2016.json
nvdcve-1.0-2016.json
nvdcve-1.0-2017.json
nvdcve-1.0-2017.json
The problem is not in the code which you show us. Enable logging for the HTTP requests which your application receives to make sure the browser sends you just a single request. If you see two requests, make sure they use the same session (maybe another user is clicking at the same time).
If it's from the same user, maybe you're clicking the button twice. Could be a hardware problem with the mouse. To prevent this, use JavaScript to disable the button after the first click.

Upload image to facebook using the Python API

I have searched the web far and wide for a still working example of uploading a photo to facebook through the Python API (Python for Facebook). Questions like this have been asked on stackoverflow before but non of the answers I have found work anymore.
What I got working is:
import facebook as fb
cfg = {
"page_id" : "my_page_id",
"access_token" : "my_access_token"
}
api = get_api(cfg)
msg = "Hello world!"
status = api.put_wall_post(msg)
where I have defined the get_api(cfg) function as this
graph = fb.GraphAPI(cfg['access_token'], version='2.2')
# Get page token to post as the page. You can skip
# the following if you want to post as yourself.
resp = graph.get_object('me/accounts')
page_access_token = None
for page in resp['data']:
if page['id'] == cfg['page_id']:
page_access_token = page['access_token']
graph = fb.GraphAPI(page_access_token)
return graph
And this does indeed post a message to my page.
However, if I instead want to upload an image everything goes wrong.
# Upload a profile photo for a Page.
api.put_photo(image=open("path_to/my_image.jpg",'rb').read(), message='Here's my image')
I get the dreaded GraphAPIError: (#324) Requires upload file for which non of the solutions on stackoverflow works for me.
If I instead issue the following command
api.put_photo(image=open("path_to/my_image.jpg",'rb').read(), album_path=cfg['page_id'] + "/picture")
I get GraphAPIError: (#1) Could not fetch picture for which I haven't been able to find a solution either.
Could someone out there please point me in the right direction of provide me with a currently working example? It would be greatly appreciated, thanks !
A 324 Facebook error can result from a few things depending on how the photo upload call was made
a missing image
an image not recognised by Facebook
incorrect directory path reference
A raw cURL call looks like
curl -F 'source=#my_image.jpg' 'https://graph.facebook.com/me/photos?access_token=YOUR_TOKEN'
As long as the above calls works, you can be sure the photo agrees with Facebook servers.
An example of how a 324 error can occur
touch meow.jpg
curl -F 'source=#meow.jpg' 'https://graph.facebook.com/me/photos?access_token=YOUR_TOKEN'
This can also occur for corrupted image files as you have seen.
Using .read() will dump the actual data
Empty File
>>> image=open("meow.jpg",'rb').read()
>>> image
''
Image File
>>> image=open("how.png",'rb').read()
>>> image
'\x89PNG\r\n\x1a\n\x00\x00\x00\rIHDR\x00...
Both of these will not work with the call api.put_photo as you have seen and Klaus D. mentioned the call should be without read()
So this call
api.put_photo(image=open("path_to/my_image.jpg",'rb').read(), message='Here's my image')
actually becomes
api.put_photo('\x89PNG\r\n\x1a\n\x00\x00\x00\rIHDR\x00...', message='Here's my image')
Which is just a string, which isn't what is wanted.
One needs the image reference <open file 'how.png', mode 'rb' at 0x1085b2390>
I know this is old and doesn't answer the question with the specified API, however, I came upon this via a search and hopefully my solution will help travelers on a similar path.
Using requests and tempfile
A quick example of how I do it using the tempfile and requests modules.
Download an image and upload to Facebook
The script below should grab an image from a given url, save it to a file within a temporary directory and automatically cleanup after finished.
In addition, I can confirm this works running on a Flask service on Google Cloud Run. That comes with the container runtime contract so that we can store the file in-memory.
import tempfile
import requests
# setup stuff - certainly change this
filename = "your-desired-filename"
filepath = f"{directory}/{filename}"
image_url = "your-image-url"
act_id = "your account id"
access_token = "your access token"
# create the temporary directory
temp_dir = tempfile.TemporaryDirectory()
directory = temp_dir.name
# stream the image bytes
res = requests.get(image_url, stream=True)
# write them to your filename at your temporary directory
# assuming this works
# add logic for non 200 status codes
with open(filepath, "wb+") as f:
f.write(res.content)
# prep the payload for the facebook call
files = {
"filename": open(filepath, "rb"),
}
url = f"https://graph.facebook.com/v10.0/{act_id}/adimages?access_token={access_token}"
# send the POST request
res = requests.post(url, files=files)
res.raise_for_status()
if res.status_code == 200:
# get your image data back
image_upload_data = res.json()
temp_dir.cleanup()
if "images" in image_upload_data:
return image_upload_data["images"][filepath.split("/")[-1]]
return image_upload_data
temp_dir.cleanup() # paranoid: just in case an error isn't raised

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