Override function decorator argument - python

I've a base class and a child class. Base class has a class variable which is passed to decorator. Now, when I inherit Base into child, and change the variable value, the decorator does not take the over-ride class variable value.
Here's the code:-
class Base():
variable = None
#decorator(variable=variable)
def function(self):
pass
class Child(Base):
variable = 1
Without overriding the function again: How do I pass child class variable to the decorator?

The comment from deceze already explained why this is not getting reflected on the sub classes.
One workaround is, you can build the logic on the decorator side.
Ie, something like this.
def decorator(_func=None, *, variable):
def decorator_func(func):
def wrapper(self, *args, **kwargs):
variable_value = getattr(self.__class__, variable)
print(variable_value)
# You can use this value to do rest of the work.
return func(self, *args, **kwargs)
return wrapper
if _func is None:
return decorator_func
else:
return decorator_func(_func)
Also update the decorator syntax from #decorator(variable=variable) to #decorator(variable='variable')
class Base:
variable = None
#decorator(variable='variable')
def function(self):
pass
DEMO
b = Base()
b.function() # This will print `None`.
Lets try with the subclass
b = Child()
b.function() # This will print `1`.

Related

Tracking decorated methods of children classes in python

In python, how can I setup a parent class to track methods with a specific decorator for each child seperatly? A quick code snippet of what I am trying to do:
class Parent:
decorated_func_dict = {} #dictionary that stores name->func for decorated functions
def get_func_by_decorator_name(self, name):
#stuff
pass
class Child1(Parent):
#func_name("Bob")
def bob_func(self, *args):
pass
#func_name("Tom")
def func2(self, *args):
pass
class Child2(Parent):
#func_name("Bob")
def func_bob2(self, *args):
pass
foo = Child1()
bar = Child2()
foo.get_func_by_decorator_name("Bob")
#Returns foo.bob_func
bar.get_func_by_decorator_name("Bob")
#Returns bar.func_bob2
Using Python 3.9.
A decorator is not something that makes a function look pretty. It is a callable that ingests an object (not only functions), does some arbitrary operations, and returns a replacement object.
In this case, your decorator should be storing references to function objects in a dictionary somewhere. The problem is that you won't be able to reference the class in which the functions are defined until it is created, which happens well after the decorator is run. You can avoid this by storing the name of the class as well as the name of the function.
The final step here is to properly bind the function objects to methods on the right object. That is something that get_func_by_decorated_name can do for you.
In sum, you can write something like this:
decorated_func_dict = {}
def func_name(cls_name, func_name):
def decorator(func):
decorated_func_dict.setdefault(cls_name, {})[func_name] = func
return func
return decorator
class Parent:
def get_func_by_decorator_name(self, name):
return decorated_func_dict[type(self).__name__][name].__get__(self)
class Child1(Parent):
#func_name("Child1", "Bob")
def bob_func(self, *args):
pass
#func_name("Child1", "Tom")
def func2(self, *args):
pass
class Child2(Parent):
#func_name("Child2", "Bob")
def func_bob2(self, *args):
pass
And indeed you get:
>>> foo.get_func_by_decorator_name("Bob")
<bound method Child1.bob_func of <__main__.Child1 object at 0x000001D58181E070>>
>>> bar.get_func_by_decorator_name("Bob")
<bound method Child2.func_bob2 of <__main__.Child2 object at 0x000001D582041F10>>
Another way to do this is to give your functions a name attribute, which you can then aggregate into a mapping in __init_subclass__ in Parent. This allows you to make an interface a bit closer to what you originally intended:
def func_name(func_name):
def decorator(func):
func.special_name = func_name
return func
return decorator
class Parent:
def __init_subclass__(cls):
cls.decorated_func_dict = {}
for item in cls.__dict__.values():
if hasattr(item, 'special_name'):
cls.decorated_func_dict[item.special_name] = item
del item.special_name # optional
def get_func_by_decorator_name(self, name):
return self.decorated_func_dict[name].__get__(self)
class Child1(Parent):
#func_name("Bob")
def bob_func(self, *args):
pass
#func_name("Tom")
def func2(self, *args):
pass
class Child2(Parent):
#func_name("Bob")
def func_bob2(self, *args):
pass
The results are identical to the first example.
The easiest way would of course be to get access to the child's namespace before the class is created, e.g. with a metaclass.

Apply decorator to class method which accesses class attribute

Is it possible to write a decorator that acts upon a class's method and uses the class's attributes? For example, I would like to add a decorator to functions that will return an error if one of the class's attributes (which is set when the user calls the function) is False.
For example, my attempt (broken code since is_active can't access MyClass's methods):
def is_active(active):
if active == False:
raise Exception("ERROR: Class is inactive")
class MyClass():
def __init__(self, active):
self.active = active
#is_active
def foo(self, variable):
print("foo")
return variable
#is_active
def bar(self, variable):
print("bar")
return variable
where the expected behaviour is:
cls = MyClass(active=True)
cls.foo(42)
---> function prints "foo" and returns 42
cls = MyClass(active=False)
cls.foo(42)
---> function raises an exception as the active flag is False
The above is a dummy example and the actual use case is more complex, but hopefully this shows the problem I'm facing.
If the above is possible, my extra question is: is it possible to "hide"/delete the methods from the instantiated class based on this flag. For example, if the user instantiates the class with a active=False then when they're using iPython and press <tab>, they can only see the methods which are permitted to be used?
Thank you.
Decorators can be confusing. Note a function is passed as a parameter and the decorator expects that a function (or callable object) is returned. So you just need to return a different function. You have everything else you need since self is passed as the first argument to a class method. You just need to add a new function in your decorator that does what you want.
def is_active_method(func):
def new_func(*args, **kwargs):
self_arg = args[0] # First argument is the self
if not self_arg.active:
raise Exception("ERROR: Class is inactive")
return func(*args, **kwargs)
return new_func
class MyClass():
def __init__(self, active):
self.active = active
#is_active_method
def foo(self, variable):
print("foo")
return variable
#is_active_method
def bar(self, variable):
print("bar")
return variable
m = MyClass(True) # Prints foo from the method
m.foo(2)
m = MyClass(False) # Outputs the exception
m.foo(2)

How to pass class variables to Parameterized Decorators

I've a decorator which takes parameters.
def decorator(abc):
def inner(func):
def wrapper(*args, **kwargs):
print(abc) # prints base class variable
# do something
return True
return wrapper
return inner
I've Child-Parent Classes as follow:-
class ABC():
abc = 1
#decorator(abc)
def func(self):
return True
class DEF(ABC):
abc = 2
obj = DEF()
print(obj.func())
The problem that I'm facing is while passing child class variable to the decorator, it still takes the base class variable.
How do I pass the child class variable to the decorator?
Your decorator is being passed a concrete value at definition time of the base class and its function. There is no attribute access whatsoever and the function does not get magically redefined and redecorated with a new value in the derived class.
It also makes little sense to pass a class attribute to a method decorator in the first place as the method has dynamic access to it via the passed instance anyway. You can do the much simpler:
def decorator(func):
def inner(self, *args, **kwargs):
print(self.__class__.abc) # actually prints the class attribute
# do something
return True
return inner
class ABC(object):
abc = 1
#decorator
def func(self):
return True
>>> a = ABC()
>>> a.func()
1
True
>>> b = DEF()
>>> b.func()
2
True
A simple way would be to considere that what you want to process in the decorator is the run time value of an attribute. Then you just pass the attribute name and use it at run time. That is enough, because a method gets its object as its first parameter:
def decorator(attr):
def inner(func):
def wrapper(*args, **kwargs):
print(getattr(args[0], attr)) # prints current attribute
# do something
return True
return wrapper
return inner
class ABC():
abc = 1
#decorator('abc')
def func(self):
return True
class DEF(ABC):
abc = 2
obj = DEF()
obj.func()
gives as expected:
2
True
One other solution could be to override the method in DEF, since according to DEF.__mro__, since python cannot find the method declared in DEF, it will go to parent class and find it there, passing in ABC's class attribute.
Output of DEF.__mro__:
(__main__.DEF, __main__.ABC, object)
A proposed solution:
class ABC(object):
abc = 1
#decorator(abc)
def func(self):
return True
class DEF(ABC):
abc = 2
#decorator(abc)
def func(self):
return True

Access derived class attribute in base class function decorator

I want to do something like:
class A(Resource):
#dec(from_file=A.docpath)
def get(self):
pass
class B(A):
docpath = './docs/doc_for_get_b.json'
class C(A):
docpath = './docs/doc_for_get_c.json'
def dec(*args, **kwargs):
def inner(f):
docpath = kwargs.get('from_file')
f.__kwargs__ = open(path, 'r').read()
return f
return inner
The functions that will be called are B.get and C.get, never A.get.
How can I access the custom attribute docpath defined in class B or class C and pass it to the decorator of the get function in class A ?
Current solution: Put the decorator on each derived class ...
class A(Resource):
def _get(self):
pass
class B(A):
#dec(from_file='./docs/doc_for_get_b.json')
def get(self):
return self._get()
class C(A)
#dec(from_file='./docs/doc_for_get_c.json')
def get(self):
return self._get()
This works but it's pretty ugly compared to the one-line declaration of the classes in the previous code.
To access a class's attributes inside the decorator is easy:
def decorator(function):
def inner(self):
self_type = type(self)
# self_type is now the class of the instance of the method that this
# decorator is wrapping
print('The class attribute docpath is %r' % self_type.docpath)
# need to pass self through because at the point function is
# decorated it has not been bound to an instance, and so it is just a
# normal function which takes self as the first argument.
function(self)
return inner
class A:
docpath = "A's docpath"
#decorator
def a_method(self):
print('a_method')
class B(A):
docpath = "B's docpath"
a = A()
a.a_method()
b = B()
b.a_method()
In general I've found using multiple levels of decorators, i.e. decorator factory functions that create decorators such as you've used and such as:
def decorator_factory(**kwargs):
def decorator_function(function):
def wrapper(self):
print('Wrapping function %s with kwargs %s' % (function.__name__, kwargs))
function(self)
return wrapper
return decorator_function
class A:
#decorator_factory(a=2, b=3)
def do_something(self):
print('do_something')
a = A()
a.do_something()
a difficult thing to get right and not easy to comprehend when reading code, so I would err towards using class attributes and generic superclass methods in favour of lots of decorators.
So in your case, don't pass the file path in as an argument to your decorator factory, but set it as a class attribute on your derived classes, and then write a generic method in your superclass that reads the class attribute from the instance's class.

Python class method decorator

I write a decorator for class method
def decor(method):
def wrapped(self, *args, **kwargs):
return method(self, *args, **kwargs)
# [*]
return wrapped
I would like use this like:
class A(metaclass=mymetaclass):
#decor
def meth(self):
pass
How I can in decorator add method/variable to class which has decorated method? I need it do near [*].
Inside wrapped I could write self.__class__, but what to do here?
I cannot imagine a way to meet such a requirement, because decor function only receives a function object that knows nothing about a containing class.
The only workaround that I can imagine is to use a parameterized decorator and pass it the class being decorated
def decor(cls):
def wrapper(method):
def wrapped(self, *args, **kwargs):
return self.method(*args, **kwargs)
print method # only a function object here
return wrapped
print cls # here we get the class and can manipulate it
return wrapper
class A
#decor(A)
def method(self):
pass
Alternatively, you could decorate the class itself:
def cdecor(cls):
print 'Decorating', cls # here we get the class and can manipulate it
return cls
#cdecor
class B:
def meth(self):
pass
gives:
Decorating __main__.B
It looks like you just wanted to decorate one of a classes functions, not specifically an #classmethod. Here's a simple way that I did it when I wanted to call a classes save function when the function returned a successful result:
def save_on_success(func):
""" A decorator that calls a class object's save method when successful """
def inner(self, *args, **kwargs):
result = func(self, *args, **kwargs)
if result:
self.save()
return result
return inner
Here is an example of how it was used:
class Test:
def save(self):
print('saving')
#save_on_success
def test(self, var, result=True):
print('testing, var={}'.format(var))
return result
Testing to make sure it works as expected:
>>> x = Test()
>>> print(x.test('test True (should save)', result=True))
testing, var=test True (should save)
saving
True
>>> print(x.test('test False (should not save)', result=False))
testing, var=test False (should not save)
False
It looks like it is not directly possible, according to this response :
Get Python function's owning class from decorator
What you could do instead is providing a decorator for your class, something like that :
class InsertMethod(object):
def __init__(self, methodToInsert):
self.methodToInsert = methodToInsert
def __call__(self, classObject):
def wrapper(*args, **kwargs):
setattr(classObject, self.methodToInsert.__name__, self.methodToInsert)
return classObject(*args, **kwargs)
return wrapper
def IWillBeInserted(self):
print "Success"
#InsertMethod(IWillBeInserted)
class Something(object):
def __init__(self):
pass
def action(self):
self.IWillBeInserted()
a = Something()
a.action()
Actually, you may decorate the class itself:
def class_decorator(class_):
class_.attribute = 'value'
class_.method = decorate(class_.method)
return class_
#class_decorator
class MyClass:
def method(self):
pass
I'm a little late to the party, but late is better than never eh? :)
We can do this by decorating our class method with a decorator which is itself a class object, say B, and then hook into the moment when Python calls B.__get__ so to fetch the method. In that __get__ call, which will be passed both the owner class and the newly generated instance of that class, you can elect to either insert your method/variable into the original owner class, or into the newly defined instance.
class B(object):
def __init__(self, f):
self.f = f
def __call__(self, *args, **kwargs):
return self.f(*args, **kwargs)
def __get__(self, instance, owner):
instance.inserted = True
# owner.inserted = True
def wrapper(*args, **kwargs):
return self(instance, *args, **kwargs)
return wrapper
class A:
#B
def method(self):
pass
if __name__ == "__main__":
a = A()
a.method()
b = A()
print(hasattr(a, 'inserted'))
print(hasattr(b, 'inserted'))
In this example, we're wrapping def method(self) with #B. As written, the inserted attribute inserted will only persist in the a object because it's being applied to the instance. If we were to create a second object b as shown, the inserted attribute is not included. IE, hasattr(a, 'inserted') prints True and hasattr(b, 'inserted') prints False. If however we apply inserted to the owner class (as shown in the commented out line) instead, the inserted attribute will persist into all future A() objects. IE hasattr(a, 'inserted') prints True and hasattr(b, 'inserted') prints True, because b was created after a.method() was called.

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