I am having a trouble mapping urls correctly. I've included my code below.
I am able to run the code just fine, but when I click the "about" hyperlink, I get an error saying
The current URL, rango/about/, didn't match any of these.
When I put in the URL just "rango/", removing the "about", I get the following error:
The current URL, rango/, didn't match any of these.
I am a complete beginner with Django and have been going through the Tango with Django book, but currently stuck with the exercises on Ch3.
Any help is much appreciated. Thank you!
tango_with_django_project.urls.py
from django.conf.urls import url
from django.contrib import admin
from django.conf.urls import include
from rango import views, urls
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^rango/',include('rango.urls')),
# above maps any URLs starting with rango/ to
# be handled by the rango application
url(r'^admin/', admin.site.urls),
]
rango.urls.py
from django.conf.urls import url
from rango import views
urlpatterns = [
url(r'^rango/', views.index, name='index'),
url(r'$^rango/about/',views.about,name='about'),
]
rango.views.py
from django.http import HttpResponse
def index(request):
return HttpResponse("Rango says hey there partner! \
<br/> <a href='/rango/about/'>about</a>")
def about(request):
return HttpResponse("Rango says here is the about page. \
<br/> <a href='/rango/'>index</a>")
# rango.urls.py
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^about/$',views.about,name='about'),
]
Related
Page not found (404)
Request Method:
GET
Request URL:
http://127.0.0.1:8000/
Using the URLconf defined in just.urls, Django tried these URL patterns, in this order:
1. admin/
2. shop/
The empty path didn't match any of these.
You're seeing this error because you have DEBUG= True in your Django settings file. Change that to False, and Django will display a standard 404 page.
Here is my code:
Main ecom\urls.py:------------>>>>
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('shop/', include('shop.urls'))
]
Now shop\urls.py:-------------->>>>
from django.urls import path
from . import views
urlpatterns = [
path("",views.index, name="ShopHome")
]
And shop\views.py:-------------->>>>
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("Shop Index")
Please help me guys
The only pages that should be working for you right now is /shop/ and /admin/. There is no root page because you have an include, which always start with /shop/ and checks the shop/urls. Not sure what you want, but if you want the root page to give you the index view, you can change ecom/urls shop url to:
path('', views.index, name="ShopName)
Dont forget to import the views of course
You have not defined blank URL. In main URLs.py, you have used path('shop/', include('shop.urls')), and in shop urls.py path("",views.index, name="ShopHome"). this path will redirect to http://127.0.0.1:8000/shop/ not http://127.0.0.1:8000/.
If you want blank url then do this:
ecom\urls.py:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('shop.urls'))
]
shop\urls.py
urlpatterns = [
path("",views.index, name="ShopHome")
]
remember whatever you add in path('', include('shop.urls')), it will be added in all URLs written inside shop app.
If you want a blank URL and also "shop" added in rest of the URLs, do this:
From shop import views
urlpatterns = [
path('admin/', admin.site.urls),
path('shop/', include('shop.urls'))
path('',views.index, name="ShopHome")
]
So I'm attempting to Django, and I've gotten a few urls working but one set just wont work.
It keeps asking for a argument but it shouldn't require one.
Error below.
NoReverseMatch at /
Reverse for 'about' with no arguments not found. 1 pattern(s) tried: ['$about/']
Error during template rendering
In template hub\templates\partials\footer.html, error at line 33
hub\templates\partials\footer.html line 33
About
hub/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.HomePageView.as_view(), name='index'),
url(r'^about/', views.AboutPageView.as_view(), name='about'),
url(r'^contact/', views.ContactPageView.as_view(), name='contact'),
]
storyarchive/urls.py
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^$', include('hub.urls', namespace='hub')),
url(r'^community/', include('community.urls', namespace='community')),
url(r'^forum/', include('forum.urls', namespace='forum')),
url(r'^story/', include('story.urls', namespace='story')),
url(r'^admin/', admin.site.urls),
]
It worked before I started to use the {% url %} builtin.
Django Version: 1.11.5
Python Version: 3.4.4
You need to remove the $ from your urlpattern which includes hub.urls. That only matches with an empty string. So it won't get matched with about.
Thats why it shows $about/ in your error log too. Change your storyarchive/urls.py like this:
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^', include('hub.urls', namespace='hub')),
url(r'^community/', include('community.urls', namespace='community')),
url(r'^forum/', include('forum.urls', namespace='forum')),
url(r'^story/', include('story.urls', namespace='story')),
url(r'^admin/', admin.site.urls),
]
Okay... let's try to explain things clearly. I've used Python Django to create a dynamic webpage/web-app. After completing the website I have published it using DigitalOcean and have successfully attached my purchased domain name to the name server of DigitalOcean. When I access my website, ordinanceservices.com, i get an error 404; however, if I type ordinanceservices.com/home it works as it should and displays the home page. How, by editing the python files, can I have it to where ordinanceservices.com will display the home page as opposed to error 404? I feel like there's something that I am doing that is fundamentally wrong regarding my .urls structure and thus a rewrite/redirect in the nginx config should not be necessary.
Here is the specific error:
Page not found (404)
Request Method: GET
Request URL: http://ordinanceservices.com/
Using the URLconf defined in django_project.urls, Django tried these URL patterns, in this order:
^admin/
^ ^home/ [name='home']
^ ^contact/ [name='contact']
^ ^services/ [name='services']
The current URL, , didn't match any of these.
I somewhat understand what is happening here though I do not know how to fix this. Next I will provide my .urls files for each folder that contains such:
/django_project urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
)
/company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
/company views.py
from django.shortcuts import render
def home(request):
return render(request, 'company/home.html')
def contact(request):
return render(request, 'company/contact.html')
def services(request):
return render(request, 'company/services.html')
What I am aiming to do, without needing to redirect the main URL using the nginx config files to do so, is to edit my urls and views structure of my Python files to ensure that the normal URL, ordinanceservices.com, will actually display a page; preferably the home page of my webpage.
I have a hunch that it has to do with the fact that I do not have a views.index for the r'^admin/' to reach to. I am not certain but I have been trying to figure this out for hours. Does anyone have a clue what I can do to fix this?
You haven't defined anything at the root url. Add one more line to your company urls.py so it becomes
//company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
First of all, check if you have added www.yourdomain.com or yourdomain.com to ALLOWED_HOST = ['www.yourdomain.com','yourdomain.com'] in your settings.py
and then in your company/urls.py do this
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^contact/$', views.contact, name='contact'),
url(r'^services/$', views.services, name='services'),
]
and in your main urls.py add this code
from django.conf.urls import url,include
from django.contrib import admin
admin.autodiscover()
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
]
I'm trying out Python Django. With eclipse pyDev. But I'm unable to simply get my first url to display.
This urls.py is from the Cr package.
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index')
]
This urlspy is from the Crowd package.
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'Crowd/', include('Cr.urls'))
]
So what I've understood from this the Crowd package is the "main" webservice(?), and by using include I can whenever the regular expression matches Crowd, will pass it on to the other urls.py(Cr). But the debugger passes:
Using the URLconf defined in Crowd.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, crowd, didn't match any of these.
my views.py file
from django.shortcuts import HttpResponse
def index(request):
return HttpResponse('<h1>Hello World!</h1>')
I tried to access it with http://127.0.0.1:8000/Crowd
Below is an image of the project folder.
Can we see your settings.py file? There is a place in there where you define your project's url file. I'm assuming it's right now either not there or it's pointing to the wrong place, because Django can't find your urls.py file.
For example, in my settings.py file for one of my projects, I have:
ROOT_URLCONF = 'Freya.urls'
Where "Freya" is my project name
Just for reference, not that I know this will solve your problem, this is what (part of) my urls.py file looks like for one of my projects:
from django.conf.urls import patterns, url
import views
urlpatterns = patterns(
'',
url(r'^$', views.index, name='index'),
url(r'^login/$', views.login, name='login'),
url(r'^logout/$', views.logout, name='logout'),
)
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'Crowd/', include('Cr.urls'))
]
just use this urls.py file
I'm totally new to Django, and I'm trying to understand how does it work (I'm more used to PHP and Spring frameworks.
I have a project called testrun and inside it an app called graphs, so my views.py looks like:
#!/usr/bin/python
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, World. You're at the graphs index.")
then, in graphs/urls.py:
from django.conf.urls import patterns, url, include
from graphs import views
urlpatterns = patterns(
url(r'^$', views.index, name='index'),
)
finally, at testrun/urls.py:
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'testrun.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^graphs/', include('graphs.urls')),
url(r'^admin/', include(admin.site.urls)),
)
However, when I try to access http://127.0.0.1:8000/graphs/ I get:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/graphs/
Using the URLconf defined in testrun.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, graphs/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
What am I doing wrong that I can't get that simple message to be displayed in the browser?
To expand on my comment, the first argument to patterns() function is
a prefix to apply to each view function
You can find more information here:
https://docs.djangoproject.com/en/dev/topics/http/urls/#syntax-of-the-urlpatterns-variable
Therefore in graphs/urls.py you need to fix the patterns call like so:
urlpatterns = patterns('', # <-- note the `'',`
url(r'^$', views.index, name='index'),
)