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Python socket throwing the following error ConnectionResetError: [Errno 54] Connection reset by peer

I have been trying to create a messaging service in python using sockets. I have written the code to host two connections and allow one to send messages to the other using username and host_addr.
But every time I try to connect the second client and send a message from the first getting the following error.
ConnectionResetError: [Errno 54] Connection reset by peer
Server.py
import socket
import _thread as thread
HOST = "127.0.0.1" # Standard loopback interface address (localhost)
PORT = 1237 # Port to listen on (non-privileged ports are > 1023)
user_mapping = {}
def on_new_client(conn, addr):
data = conn.recv(1024)
data = data.decode()
print(data)
print(user_mapping)
if data[:8] == "username":
user_mapping[data[9:]] = (addr, data[9:])
elif data[0] == "#":
for i in user_mapping.values():
if i[0] == addr:
from_user = i[1]
else:
str = "user not found"
conn.sendto(str.encode(), addr)
str = "%s:%s" % (from_user, data[data.find(":") + 1:])
conn.sendto(str.encode(), user_mapping[data[1:data.find(":")](0)])
else:
pass
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(10)
while True:
conn, addr = s.accept()
thread.start_new_thread(on_new_client,(conn,addr))
s.close()
Client.py
import socket
HOST = "127.0.0.1" # The server's hostname or IP address
PORT = 1237 # The port used by the server
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
username = input("Enter user name")
str = "username: %s" % username
s.send(str.encode())
while True:
message = input(username+">")
s.send(message.encode())
data = s.recv(1024)
print(data)
Was hoping some would could answer why this is happening and guide me to any good links where there is Information on creating a messaging service in python.

Client is sending 2 messages and then receiving one.
But server just listen once and then send one or two packages.
Chronologically:
Client sends a package, and server reads it.
Then both client and server try to send a package. Both packages that won't meet a listening peer.
Then client try to receive a package, but server won't send (he already sent it before) or it may send but its too late because communication is already broken.
Concepts you may implement always:
If one talk, another one may listen.
If a package is mean to be sent, it shall be sent anyway. Dont let a 'if' statment that send package when at 'else' that does not (or viceversa).
==== EDIT ====
About solution:
You need to work with paralel loops.
Take a look at this code https://www.neuralnine.com/tcp-chat-in-python/
He uses two threads on client, one for keep listening for new server updates (messages for other people) and another one to wait input from user.

Send and receive messages on same port? Peer to peer message app python

I'm trying to create a peer to peer message app, I understand I need each instance of the app to be both a server and a client as I've got for the below code but I'm wondering how to set up the ports, can I send and receive messages on the same port?
The below code is one instance of the app, I can communicate with another version but I have to set the other version to send messages on port 9000 and receive messages on 6190. This won't work going forward as how would a third user connect?
Current situation:
User 1: Receives on 9000, sends on 6190
User 2: Receives on 6190, sends on 9000
import socket
import time
import threading
global incoming
def server_socket(): #call server_socket() in build method?
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('', 9000))
s.listen(1)
host_name = socket.gethostname()
ip_address = socket.gethostbyname(host_name)
print("IP address is: ", ip_address)
except socket.error as e:
print("Socket Error !!", "Unable To Setup Local Socket. Port In Use")
while True:
conn, addr = s.accept()
incoming_ip = str(addr[0])
data = conn.recv(4096)
data = data.decode('utf-8')
print("message recieved is: ", data)
conn.close()
s.close()
def client_send_message():
message = "Hello World"
message = message.encode('utf-8')
c = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
c.connect(("127.0.0.1", 6190))
except Exception as e:
print("Connection Refused", "The Address You Are Trying To Reach Is Currently Unavailable")
try:
c.send(message)
except Exception as e:
print(e)
c.close()
t = threading.Thread(target=server_socket)
t.start()
for i in range(5):
time.sleep(30)
client_send_message()

You currently use TCP and with this design you need a separat socket for each client. You can exchange data on this socket in both directions though. More common for peer to peer networks is UDP: here you can use a single socket to recvfrom data from arbitrary clients and sendto data to arbitrary clients.

Socket Programming : client stops responding after sending 3 messages to the server

I'm quite new to socket programming, and I was wondering why the client stops responding after I send 3 messages to the server. Basically I send a message twice and the server responds to the client. The third time, the client just runs infinitely and the server doesn't receive anything.
Does it have something to do with overload? How does that work, especially with socket.listen()
Here is the code for reference:
client.py
# Import socket module
import socket
# Create a socket object
s = socket.socket()
# Define the port on which you want to connect
port = 12345
# connect to the server on local computer
s.connect(('127.0.0.1', port))
while True:
msg = input("Enter your message: ")
if msg != "quit":
s.send((msg).encode())
else:
# close the connection
s.close()
# receive data from the server
new_msg = (s.recv(1024).decode())
print ("[CLIENT]: ", new_msg)
server.py
# first of all import the socket library
import socket
# next create a socket object
s = socket.socket()
print ("Socket successfully created")
# reserve a port on your computer in our
# case it is 12345 but it can be anything
port = 12345
# Next bind to the port
# we have not typed any ip in the ip field
# instead we have inputted an empty string
# this makes the server listen to requests
# coming from other computers on the network
s.bind(('', port))
print ("socket binded to %s" %(port))
# a forever loop until we interrupt it or
# an error occurs
while True:
# put the socket into listening mode
s.listen(20)
print ("socket is listening")
# Establish connection with client.
c, addr = s.accept()
print('Got connection from', addr)
msg = c.recv(1024).decode()
if msg == "quit":
# Close the connection with the client
c.close()
else:
print ("[SERVER]: Recieved data: ", msg)
print ("[SERVER]: sending", msg)
c.send((msg).encode())

You still need a better understanding on how a listening socket works:
it listens only once
it accepts only once per connection
it can read and send as many packets as required until either side closes the connection
at that point (and for a single threaded server) it is ready to accept a new connection
You server.py should become:
...
s.bind(('', port))
print ("socket binded to %s" %(port))
# put the socket into listening mode
s.listen(20)
print ("socket is listening")
# a forever loop until we interrupt it or
# an error occurs
while True:
# Establish connection with client.
c, addr = s.accept()
print('Got connection from', addr)
while True:
msg = c.recv(1024).decode()
if len(msg) == 0: # the client does not send anything but just closes its side
# Close the connection with the client
c.close()
print('Client disconnected')
break
else:
print ("[SERVER]: Recieved data: ", msg)
print ("[SERVER]: sending", msg)
c.send((msg).encode())
A small fix for the client side:
...
if msg != "quit":
s.send((msg).encode())
else:
# close the connection
s.close()
break # break out of the loop after closing connection
But that is not all: TCP is a stream protocol. You should be prepared for packets send from one side to be splitted or re-assembled before reaching other side. The only guarantee is that bytes arrive in same order that they were send, but not necessarily in same packets.

Python Socket, how do i choose between s.send and conn.send?

def send_Button():
try:
myMsg = "ME: " + text.get()
msg = text.get()
conn.send(msg) ###
textBox.insert(END, myMsg + "\n")
textEntry.delete(0, END)
textBox.yview_pickplace("end")
except NameError:
myMsg = "ME: " + text.get()
msg = text.get()
conn.send(msg) ###
textBox.insert(END, myMsg + "\n")
textEntry.delete(0, END)
textBox.yview_pickplace("end")
This program uses the tkinter module with socket in python2.7. My program allows for you to either connect to a server to chat with or host a server for others to connect to you, but whenever I try and test it out then the lines with the '###' on always bring up an error and it doesn't work, the error which comes up is: "NameError: global name 'conn' is not defined" OR "error: [Errno 10057] A request to send or receive data was disallowed because the socket is not connected and (when sending on a datagram socket using a sendto call) no address was supplied".
Any help please?

I think that you are trying to get the program to act as a Client or as a Server just changing s.send() to conn.send() saddly it isn't that simple.
Socket Initializzation
The socket have to be initialized before sending or receiving data.
For a client usually it's something like this.
send_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM) # Create the socket
send_socket.connect((serverIp, serverPort)) # Connect to the server
send_socket.send(data) # Send the data to the server
And like this for a Server:
listen_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM) # Create the socket
listen_socket.bind(("0.0.0.0", port)) # Set the socket to accept client from every interface on the port port
listen_socket.listen(1) # Put the server on listen on the port setted before
accept_socket, addr = self.listen_socket.accept() # when a client connect return the socket to talk with it
data = self.accept_socket.recv(buffer_size) # Receive data form the client of max size buffer_size
Docs examples
From your question I guess that with s.send() and conn.send() you are talking about
this example from the python 2.7 socket docs
Here are four minimal example programs using the TCP/IP protocol: a server that echoes all data that it receives back (servicing only one client), and a client using it. Note that a server must perform the sequence socket(), bind(), listen(), accept() (possibly repeating the accept() to service more than one client), while a client only needs the sequence socket(), connect(). Also note that the server does not sendall()/recv() on the socket it is listening on but on the new socket returned by accept().
Client
Echo client program
import socket
HOST = 'daring.cwi.nl' # The remote host
PORT = 50007 # The same port as used by the server
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
s.sendall('Hello, world')
data = s.recv(1024)
s.close()
print 'Received', repr(data)
the client is pretty stright forward, it create the socket s and then after using s.connect() it just send data through it.
Server
The server one is where there there are both s and conn
Echo server program
import socket
HOST = '' # Symbolic name meaning all available interfaces
PORT = 50007 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data:
break
conn.sendall(data)
conn.close()
in this one first of all we create a socket s on which the server will listen and then using s.accept() it will wait till a client connect to the server and then return the conn which is the socket of the connected client.
So to receive or send data to the client you have to use conn.
Notes
As said in the documentation in these two example the server accept only one client. So if you want to deal with multiple clients you have to repeat the accept step and possibly generate a new Thread for each client so that other clients don't have to wait for each others.

Server send data in python

I'm writing a simple client server app in python, where the client is listening every type of data entering in the specific port, and I want to when receiving a data flow, send back to the connected client (which have a dinamic ip) a string, in this case "001". But when I try to send the message, it fails!
#!/usr/bin/env python
import socket
TCP_IP = '192.168.1.115'
TCP_PORT = 55001
BUFFER_SIZE = 1024
MESSAGE = '01'
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP, TCP_PORT))
s.listen(1)
conn, addr = s.accept()
print ('Connection address:', addr)
while 1:
data = conn.recv(BUFFER_SIZE)
if not data: break
print ('received data:', data)
conn.send(data) # echo
print ('Sending data to client...')
addr change every connection .. i cannot manage this!
s.connect((addr, TCP_PORT))
s.send(MESSAGE)
data = s.recv(BUFFER_SIZE)
s.close()

(Connected stream) sockets are bidirectional, so there's no need to call connect to get a connection to the client—you already have one.
But you want to know why your code fails. And there are at least three problems with it.
First, after you call listen or connect on a socket, you can't call connect again; you will get an exception (EISCONN on POSIX, something equivalent on Windows). You will have to create a new socket.
Second, is client actually binded and listening for a connection on the same port as the server? If not, your connect can't work. If so, the bind will fail if the client and server are on the same machine.
Third, the addr you get back from accept is a (host, port) pair, not just a host. So, as written, you're trying to connect((('192.168.1.115', 12345), 55001)), which obviously isn't going to work.

You are trying to reply to the client using the server listening socket (s). This is only possible in UDP Servers. Since this is a TCP Server you have to use the conn which is crated using s.accept() to communication with remote client.