I have a file name called words.txt having Dictionary words in it. I call this file and ask the user to enter a word. Then try to find out whether this word is present in this file or not if yes print True else Word not found.
wordByuser = input("Type a Word:")
file = open('words.txt', 'r')
if wordByuser in file: #or if wordByuser==file:
print("true")
else:
print("No word found")
The words.txt files contain each letter in a single line and then the new letter on the second line.
Use this one line solution:
lines = file.read().splitlines()
if wordByuser in lines:
....
Read the file first, also use snake_case https://www.python.org/dev/peps/pep-0008/
user_word = input("Type a Word:")
with open('words.txt') as f:
content = f.read()
if user_word in content:
print(True)
else:
print('Word not found')
This function should do it:
def searchWord(wordtofind):
with open('words.txt', 'r') as words:
for word in words:
if wordtofind == word.strip():
return True
return False
You just need to add .read() to the file class you initiated.
Like this:
wordByuser = input("Type a Word:")
file = open('words.txt', 'r')
data = file.read()
if wordByuser in data:
print("true")
else:
print("No word found")
Related
This sounds like it has been asked before but I cannot find anything that helps me.
My code is:
with open('file directory', 'r') as file:
data = []
for line in file:
for word in line.split():
data.append(str(word))
last_word = str(data[-1])
if last_word == "bobby":
print("yes")
else:print("no")
I want to know if the last element of the text file which I turned into a list matches a string, for example "bobby". Instead, what I get is basically a counter of how many times bobby was mentioned in the list.
Terminal:
yes
yes
yes
How about:
with open('file directory', 'r') as file:
last_line = f.readlines()[-1]
print("yes" if last_line == "bobby" else "no")
or if you want to be short and cryptic:
with open('file directory', 'r') as file:
print("yes" if f.readlines()[-1] == "bobby" else "no")
If you want to look for the last word of each line, this works.
with open('asdf.txt', 'r') as file:
for line in file:
words = line.split()
try:
if words[-1] == "bobby":
print("yes")
else:
print("no")
except:
# blank line
pass
Instead of looping the file just turn it into a list and grab the last element. You're very close just the loop is unnecessary:
with open('file directory', 'r') as file:
data = file.readlines()
last_word = data[-1].split()[-1]
if last_word == "bobby":
print("yes")
else:
print("no")
I have this simple code that reads a txt file and accepts a word from the user to check if that word is in the txt document or not. It looks like this works only for a single word. I have to modify this code so that the user can input two or more words. Example; GOING HOME instead of just HOME. Any help please.
word = input('Enter any word that you want to find in text File :')
f = open("AM30.EB","r")
if word in f.read().split():
print('Word Found in Text File')
else:
print('Word not found in Text File')
I'm not sure this is exactly what you are looking for
f = open("AM30.EB","r")
word_list = []
while True:
word = input('Enter any word that you want to find in text File or 1 to stop entering words :')
if word == "1": break
word_list.append(word)
file_list = f.read().split()
for word in word_list:
if word in file_list:
print("Found word - {}".format(word))
These are case-sensitive solutions!
All words in query separately:
words = input('Enter all words that you want to find in text File: ').split()
f_data = []
with open("AM30.EB", "r") as f:
f_data = f.read().split()
results = list(map(lambda x: any([y == x for y in f_data]), words))
print("Found ")
for i in range(len(words)):
print(f"'{words[i]}'", end="")
if i < len(words) - 1:
print("and", end="")
print(f": {all(results)}")
Any word in query:
words = input('Enter any word that you want to find in the text File: ').split()
f_data = []
with open("AM30.EB", "r") as f:
f_data = f.read().split()
results = list(map(lambda x: any([y == x for y in f_data]), words))
if any(results):
for i in range(len(words)):
print(f"Found '{words[i]}': {results[i]}")
Exact phrase in query:
phrase = input('Enter a phrase that you want to find in the text File: ')
f_data = ""
with open("AM30.EB", "r") as f:
f_data = f.read()
print(f"Found '{phrase}': {f_data.count(phrase) > 0}")
This is case sensitive and checks for each word individually. Not sure if this is what you were looking for but hope it helps!
file1 = open('file.txt', 'r').read().split()
wordsFoundList = []
userInput = input('Enter any word or words that you want to find in text File :').split()
for word in userInput:
if word in file1:
wordsFoundList.append(word)
if len(wordsFoundList) == 0:
print("No words found in text file")
else:
print("These words were found in text file: " + str(wordsFoundList))
I am searching a text file for an input word. However, I am only meant to search the text in the file after the word "START". The first twenty-odd before "START" should be ignored. I know how to find "START", but not how to search the rest of the file once "START" is encountered. I would appreciate any guidance!
Here is what I have so far:
file = open("EnglishWords.txt", "r")
print("***** Anagram Finder *****")
word = input("Enter a word: ")
for line in file:
if "START" in line:
if word in line:
print("Yes, ", word, " is in the file.", sep="")
else:
print("Sorry, ", word, " is not in the file.", sep="")
file.close()
Here is a sample of the text file:
The name of Princeton University or Princeton may not be
used in advertising or publicity pertaining to
distribution of the software and/or database. Title to
copyright in this software, database and any associated
documentation shall at all times remain with Princeton
University and LICENSEE agrees to preserve same.
START
clobber
transversalis
squinter
cunner
damson
extrovertive
absorptive
Modifying your code, we have
file = open("EnglishWords.txt", "r")
print("***** Anagram Finder *****")
word = input("Enter a word: ")
start_looking = False
word_found = False
for line in file:
if not start_looking:
if "START" in line:
start_looking = True
else:
continue
if word in line:
print("Yes, ", word, " is in the file.", sep="")
word_found = True
break
if not word_found:
print("Sorry, ", word, " is not in the file.", sep="")
file.close()
As long as START hasn't been found, keep skipping over the lines of the file. If, however, you encounter START, reset your flag and begin looking.
Do a for after your word is found:
with open(myfile, 'r') as f:
for line in f:
if 'START' in line:
# do stuff to lines below 'START'
# you could do another for loop here to iterate
for line in f:
print (line) # just an example
Very similar to this other SO post. Credit for the syntax of my answer comes from its answer.
What about something with regex module ?
re.findall(r"START.*(word_to_search).*", entire_text)
This should return you the result only if there is a START before the word to search for. I hope that's what you're looking for.
EDIT :
For a solution line by line i would go with something like :
start_search = 0
with open(bigfile, "r") as f:
for line in f:
if "START" IN line:
start_search = 1
if start_search and word_to_search in line:
print("result foun")
return (word_to_search)
What about this ?
Keep it short, simple and explicit:
with open("EnglishWords.txt", 'r') as fin:
output = fin.readlines()
# Find the line that contains START
index = output.index("START")
# Search all the lines after that
for line in output[index+1:]:
if word in line:
print("Yes, ", word, " is in the file.", sep="")
else:
print("Sorry, ", word, " is not in the file.", sep="")
You could use Python's dropwhile() to locate the start of the words and iterate from there:
from itertools import dropwhile
print("***** Anagram Finder *****")
word = input("Enter a word: ").lower() + '\n'
with open("EnglishWords.txt") as f_words:
if word in dropwhile(lambda r: not r.startswith("START"), f_words):
print("Yes, {} is in the file".format(word.strip()))
else:
print("Sorry, {} is not in the file.".format(word.strip()))
You can use a boolean :
file = open(“testfile.txt”, “r”)
foundStart = False
for line in file:
if foundStart:
# do something...
elif line == "START":
foundStart = True
I have written a small script to compare a text files content to another text file containing a word list, however running it says that the matches cannot be found, I cannot fix the code to successfully compare them with correct results.
wordlist = input("What is your word list called?")
f = open(wordlist)
t = f.readlines()
l = ''.join(t).lower()
chatlog = input("What is your chat log called?")
with open(chatlog) as f:
found = False
for line in f:
line = line.lower()
if l in line:
print(line)
found = True
if not found:
print("not here")
wordlist = input("What is your word list called?")
f = open(wordlist)
l = set(w.strip().lower() for w in f)
chatlog = input("What is your chat log called?")
with open(chatlog) as f:
found = False
for line in f:
line = line.lower()
if any(w in line for w in l):
print(line)
found = True
if not found:
print("not here")
I am trying to write a program that opens a text document and replaces all four letter words with **. I have been messing around with this program for multiple hours now. I can not seem to get anywhere. I was hoping someone would be able to help me out with this one. Here is what I have so far. Help is greatly appreciated!
def censor():
filename = input("Enter name of file: ")
file = open(filename, 'r')
file1 = open(filename, 'w')
for element in file:
words = element.split()
if len(words) == 4:
file1 = element.replace(words, "xxxx")
alist.append(bob)
print (file)
file.close()
here is revised verison, i don't know if this is much better
def censor():
filename = input("Enter name of file: ")
file = open(filename, 'r')
file1 = open(filename, 'w')
i = 0
for element in file:
words = element.split()
for i in range(len(words)):
if len(words[i]) == 4:
file1 = element.replace(i, "xxxx")
i = i+1
file.close()
for element in file:
words = element.split()
for word in words:
if len(word) == 4:
etc etc
Here's why:
say the first line in your file is 'hello, my name is john'
then for the first iteration of the loop: element = 'hello, my name is john'
and words = ['hello,','my','name','is','john']
You need to check what is inside each word thus for word in words
Also it might be worth noting that in your current method you do not pay any attention to punctuation. Note the first word in words above...
To get rid of punctuation rather say:
import string
blah blah blah ...
for word in words:
cleaned_word = word.strip(string.punctuation)
if len(cleaned_word) == 4:
etc etc
Here is a hint: len(words) returns the number of words on the current line, not the length of any particular word. You need to add code that would look at every word on your line and decide whether it needs to be replaced.
Also, if the file is more complicated than a simple list of words (for example, if it contains punctuation characters that need to be preserved), it might be worth using a regular expression to do the job.
It can be something like this:
def censor():
filename = input("Enter name of file: ")
with open(filename, 'r') as f:
lines = f.readlines()
newLines = []
for line in lines:
words = line.split()
for i, word in enumerate(words):
if len(word) == 4:
words[i] == '**'
newLines.append(' '.join(words))
with open(filename, 'w') as f:
for line in newLines:
f.write(line + '\n')
def censor(filename):
"""Takes a file and writes it into file censored.txt with every 4-letterword replaced by xxxx"""
infile = open(filename)
content = infile.read()
infile.close()
outfile = open('censored.txt', 'w')
table = content.maketrans('.,;:!?', ' ')
noPunc = content.translate(table) #replace all punctuation marks with blanks, so they won't tie two words together
wordList = noPunc.split(' ')
for word in wordList:
if '\n' in word:
count = word.count('\n')
wordLen = len(word)-count
else:
wordLen = len(word)
if wordLen == 4:
censoredWord = word.replace(word, 'xxxx ')
outfile.write(censoredWord)
else:
outfile.write(word + ' ')
outfile.close()