Hangman printing in correct order - python

Hi im 2 weeks into my python class at school and i made a simple hangman type game heres the code
secret = "computers"
my_string = ""
guesses = 10
welcome = input("Welcome to hangman, whats your name? ")
print("Hi " + welcome + " lets get started.")
secret = "computers"
my_string = ""
guesses = 10
welcome = input("Welcome to hangman, whats your name? ")
print("Hi " + welcome + " lets get started.")
while guesses >= 0:
guess = input("Guess a letter: ")
if guess in secret:
print("Correct")
my_string = my_string + guess
print(my_string)
elif guess not in secret:
print("incorrect")
guesses = guesses - 1
print("You have " + str(guesses) + " left.")
if my_string == "computer":
print("Congrats you won!")
break
if guesses == -1:
print("You lost.")
break
the problem is that once i type a letter it does not print in the correct order. For example if I type "o" first and then guess the rest in the correct order it will print "ocmputers" if anyone can help i would really appreciate it.

Since you are new I would like to help you with a better version of hangman. The code below is chopped and changed version of your hangman. This is the code:
def choose_word():
word = 'computers'
return {'word':word, 'length':len(word)}
def guess_letter(word_, hidden_word_, no_guesses_, letters_):
print('---------------------------------------')
print('You have', no_guesses_, 'guesses left.')
print('Available letters:', letters_)
guess = input("Please guess a letter:")
guess = guess.lower()
if guess in letters_:
letters_ = letters_.replace(guess, '')
if guess in word_:
progress = list(hidden_word_)
character_position = -1
for character in word_:
character_position += 1
if guess == character:
progress[character_position] = guess
hidden_word_ = ''.join(progress)
print('Good guess =', hidden_word_)
else:
print('Oops! That letter is not in my word:', hidden_word_)
no_guesses_ = no_guesses_ - 1
else:
print('The letter "', guess, '" was already used!')
no_guesses_ = no_guesses_ - 1
if hidden_word_ == word_:
print('Congratulations, you won!')
return True
if no_guesses_ == 0 and hidden_word_ != word_:
print('Game over! Try again!')
return False
return guess_letter(word_, hidden_word_, no_guesses_, letters_)
def hangman():
hangman_word = choose_word()
print('Welcome to the game, Hangman!')
print('I am thinking of a word that is', hangman_word['length'], 'letters long.')
hidden_word = ''.join(['_'] * hangman_word['length'])
no_guesses = 8
letters = 'abcdefghijklmnopqrstuvwxyz'
guess_letter(hangman_word['word'], hidden_word, no_guesses, letters)
hangman()

You build the output sting this way:
my_string = my_string + guess
So you just put the correctly guessed letters one after another in the order they were guessed disregarding thier order in the secrete word.

Your conflicting lines are these ones
if guess in secret:
print("Correct")
my_string = my_string + guess
If you look closely, when you first add a letter, lets say o, my_string is empty, and then you add to it guess variable.
>>> print(my_string)
"o"
and then if you add c
>>> print(my_string)
"oc"
I would recommend having a different method for checking if you have entered a char of the secret word.

Related

Why does my code ignore my if statement for my hangman game? (python)

I just had a question about the code that I wrote below. I was just wondering about the if statement that I wrote with the "if guess not in secret_word:". When I run it as it's currently written, the condition doesn't even run or appear. However, when I swap it with the for statement which I wrote above, it runs just fine. I'm a bit new to programming, and I was just wondering if anyone could help me out with this. Why does the order of conditions matter here?
'''
import random
from words import words
secret_word = random.choice(words)
secret_letters = list(secret_word)
blanks = " _ " * len(secret_word)
already_guessed = []
lives = 10
print(blanks)
def valid_guess(): # function to make sure the letter guessed is valid (ie, not previously guessed)
is_letter = True
lives = 10
while True:
guess = (input("\nGuess a letter:"))
if guess in already_guessed:
print("You have already guessed this letter")
elif len(guess) != 1:
print("Please guess a single letter:")
is_letter = False
elif guess not in "abcdefghijklmnopqrstuvwxyz":
print("Please guess a LETTER:")
is_letter = False
if is_letter:
already_guessed.append(guess)
for guess in secret_word:
if guess in already_guessed:
print(guess + " ", end = "")
else:
print(" - ", end = "")
if guess not in secret_word:
lives -= 1
print(f"You lost a life! You only have {lives}/10 left!")
while True:
valid_guess()
'''
You could try this:
if guess in secret_word:
if guess in already_guessed:
print(guess + " ", end = "")
else:
print(" - ", end = "")
elif guess not in secret_word:
lives -= 1
print(f"You lost a life! You only have {lives}/10 left!")

Putting guessed letters instead of dashes / Hangman / Python

i made hangman and am using this code. everything works fine, i just want to replace dashes in the list [lenghtDashes] with the correctly guessed letter in the corresponding place. i could not find any information online or here as well. maybe someone knows.
im open to any improvement suggestions as well.
secWord = input("What is the word for others to guess?: ")
life = 10
#starting information
i = 1
while i < 10:
print(".")
i += 0.01
#dots so players can not see the word
print("you have 10 tries to guess the word")
print("you will have to choose between gessing a letter (l) or a word (w) in start of every turn")
print("however, if you guess the word incorrectly you will lose immediately")
ans = input("are you ready to begin?: ")
while ans != "yes":
ans = input("now? ")
#rules
i = 1
while i < 10:
print(".")
i += 0.01
#dots for taking players to start
lenghtDashes = []
for letter in range(len(secWord)):
lenghtDashes.append("_")
#making dashes list
print("let's begin")
print("the word has " + str(len(secWord)) + " letters.")
appended = "".join(lenghtDashes)
print(appended)
#info for players
usedLetters = []
guessedLetters = []
wordLis = []
while life > 0 and ans != secWord:
print("are you guessing letter or a word?")
guessThing = input("l / w : ")
#for guessing a word
if guessThing == "w":
ans = input("What is the secret word?: ")
if ans == secWord:
print("Congratulations, you have guessed the right word\nYou won!")
else:
print("You guessed the word incorrectly\n The word was " + secWord + " \n You lost!")
exit()
#=================================================================
#for guessing a letter
elif guessThing == "l":
letList = [letter for letter in secWord]
guLett = input("Guess the letter \n(single letter only): ")
usedLetters.append(guLett)
if guLett in letList:
guessedLetters.append(guLett)
letListPlus = [letter for letter, x in enumerate(letList) if x == guLett]
letListPlusPlus = [num + 1 for num in letListPlus]
print("///")
print("///")
print("///")
print("Letters that you have used : " + str(usedLetters))
print("Letter that are correct: " + str(guessedLetters))
print("The position of letter " + str(guLett) + " is " + str(letListPlusPlus))
else:
print("///")
print("///")
print("///")
print("incorrect guess, you have " + str(life - 1) + " guesses remaining")
life = life - 1
print("Letters that you have used are: " + str(usedLetters))
print("Letter that are correct: " + str(guessedLetters))
#=================================================================
Whenever you need your in-progress word to be displayed (like "o_e_f_ow"), call this function:
def wordWithDashes(guessedLetters, letList):
return [letter if letter in guessedLetters else "_" for letter in letList]
It creates a new list from letList with missing letters replaced with "_". You can use str on it if you want a string result.
You don't need to keep track of lenghtDashes. Just compute it from the guessed letters and the actual word whenever you need it, as the code I provided does.

Debugging a "guess the word " game

There is one small problem with my code , after I get all the letters correct, I had to enter another letter only it will show that I got it right. What is the problem?
import random
import string
import sys
def split(word):
return list(word)
alphabet = 'abcdefghijklmnopqrstuvwxyz'
list(alphabet)
words = ['hat','pop' ,'cut' , 'soup' , 'you' , 'me' , 'gay' , 'lol' ]
guess_word = []
wrong_letters_storage = []
secret_word = random.choice(words)
word_length = print("the length of the word is " + str(len(secret_word)))
correct_letters = split(secret_word)
def words():
for letter in secret_word:
guess_word.append("-")
return print("the words that you are guessing is " + str(guess_word))
def guessing():
while True:
c = 0
b = 7
while c <= 7:
print("")
hide = ""
print("you have " + str(b) + " guess left")
print("Wrong letters : " + str(wrong_letters_storage))
command = input("guess: ").lower()
if not '-' in guess_word:
print("you win!")
break
elif command == 'quit':
print("thank you for playing my game")
break
else:
if not command in alphabet :
print("pick an alphabet")
elif command in wrong_letters_storage:
print("you have picked this word")
else :
if command in secret_word :
print("right")
c += 1
b -= 1
for x in range(0, len(secret_word)):
if correct_letters[x] == command:
guess_word[x] = command
print(guess_word)
elif not command in secret_word :
print("wrong")
wrong_letters_storage.append(command)
c += 1
b -= 1
else :
print("error")
print("*"*20)
return print("Thank you for playing my game")
words()
guessing()
print("the words that you are guessing is " + secret_word )
Your code has several "problems":
you check if the current solution has no more '-' in it, after you ask for the next character input()
return print("whatever") returns None because the print function prints and returns None
you use variables with single_letter_names that make it hard to know what they are for
you use list's instead of set()'s for lookups (its fine here, but not optimal)
You can fix your problem by moving the test statement before the input() command:
# your code up to here
while True:
c = 0
b = 7
while c <= 7:
if not '-' in guess_word:
print("you win!")
break
print("")
hide = ""
print("you have " + str(b) + " guess left")
print("Wrong letters : " + str(wrong_letters_storage))
command = input("guess: ").lower()
if command == 'quit':
print("thank you for playing my game")
break
else:
# etc.
It would probably be better to do some more refaktoring:
import random
import string
import sys
def join_list(l):
return ''.join(l)
def guessing():
# no need to put all this in global scope
alphabet = frozenset(string.ascii_lowercase) # unchangeable set of allowed letters
words = ['hat', 'pop', 'cut', 'soup', 'you', 'me', 'beautiful', 'lol']
secret = random.choice(words) # your random word
secret_word = list(secret.lower()) # your random word as lowercase list
wrong = set() # set of wrongly guessed characters
right = set() # set of already correctly guessed characters
correct = frozenset(secret_word) # set of letters in your word, not changeable
guess_word = ['-' for k in correct] # your guessed letters in a list
guesses = 7
guessed = 0
print("The length of the word is ", len(secret))
# loop until breaked from (either by guessing correctly or having no more guesses)
while True:
print("")
print(f"you have {guesses-guessed} guess left")
if wrong: # only print if wrong letters guessed
print(f"Wrong letters : {wrong}")
# print whats know currently:
print(f"Guess so far: {join_list(guess_word)}")
command = input("guess: ").strip().lower()
try:
if command != "quit":
command = command[0]
except IndexError:
print("Input one letter")
continue
if command == 'quit':
print("thank you for playing my game")
break
else:
if command not in alphabet:
print("pick an alphabet")
continue
elif command in (wrong | right):
print("you already picked this letter")
continue
else :
guessed += 1
# always lookup in set of lowercase letters
if command in correct:
right.add(command)
for i,letter in enumerate(secret_word):
if command == letter:
# use the correct capitalisation from original word
guess_word[i] = secret[i]
else:
print("wrong")
wrong.add(command)
print("*"*20)
# break conditions for win or loose
if join_list(secret_word) == join_list(guess_word):
print("You won.")
break
elif guessed == guesses:
print(f"You lost. Word was: {join_list(secret_word)}")
break
guessing()

Nested While loop in hangman

I am creating a hangman game.Here are the conditions
User will be given six chances for wrong choices
If the letter was already entered, user will be notified that letter already exists (user will not be penalised for double wrong entry)
Now my question is :
I want to display the message that "user lost the game" if the number of wrong guessed letters goes to 7 and exists the loop but it is not happening
here is my code:
print("Welcome to Hangman"
"__________________")
word = "Python"
wordlist=list(word)
wordlist.sort()
print(wordlist)
print("Word's length is", len(word))
letter=" "
used_letter=[]
bad_letter=[]
guess=[]
tries=0
while len(bad_letter)<7:
while guess != wordlist or letter !="exit":
letter = input("Guess your letter:")
if letter in word and letter not in used_letter:
guess.append(letter)
print("good guess")
elif letter in used_letter:
print("letter already used")
else:
bad_letter.append(letter)
print("bad guess")
used_letter.append(letter)
tries+=1
print("You have ",6 - len(bad_letter), " tries remaining")
print(guess)
print("You have made ",tries," tries so far")
guess.sort()
print("Thank you for playing the game, you guessed in ",tries," tries.")
print("Your guessed word is", word)
print("you lost the game")
I am very new to python so i would appreciate help in basic concepts
It seems like your while len(bad_letter) < loop is never exiting because of the while loop below it which is checking for the right answer or exit entry runs forever.
What you should do is only have one master while loop which takes in a new input each time and then check to see if that input matches any of the conditions you are looking for.
You could structure it something like this:
bad_letter = []
tries = 0
found_word = False
while len(bad_letter) < 7:
letter = input("Guess your letter:")
if letter == 'exit':
break # Exit game loop
if letter in word and letter not in used_letter:
guess.append(letter)
print("good guess")
elif letter in used_letter:
print("letter already used")
else:
bad_letter.append(letter)
print("bad guess")
used_letter.append(letter)
tries+=1
print("You have ", 6 - len(bad_letter), " tries remaining")
print(guess)
print("You have made ",tries," tries so far")
guess.sort()
if guess == wordlist:
found_word = True
break # Exits the while loop
print("Thankyou for playing tha game, you guessed in ",tries," tries.")
print("Your guessed word is", word)
if found_word:
print("You won")
else:
print("you lost the game")
Solution
word = 'Zam'
guesses = []
guesses_string = ''
bad_guesses = []
chances = 6
def one_letter(message=""):
user_input = 'more than one letter'
while len(user_input) > 1 or user_input == '':
user_input = input(message)
return user_input
while chances > 0:
if sorted(word.lower()) == sorted(guesses_string.lower()):
print("\nYou guessed every letter! (" + guesses_string + ")")
break
guess = one_letter("\nGuess a letter: ")
if guess in guesses or guess in bad_guesses:
print("You already guessed the letter " + guess + ".")
continue
elif guess.lower() in word.lower():
print("Good guess " + guess + " is in the word!.")
guesses.append(guess)
guesses_string = ''.join(guesses)
print("Letters guessed: " + guesses_string)
else:
print("Sorry, " + guess + " is not in the word.")
bad_guesses.append(guess)
chances -= 1
print(str(chances) + " chances remaning.")
if chances == 0:
print("\nGame Over, You Lose.")
else:
word_guess = ''
while word_guess.lower() != word.lower():
word_guess = input("Guess the word: ('quit' to give up) ")
if word_guess.lower() == 'quit':
print("You gave up, the word was " + word.title() + "!")
break
if word_guess.lower() == word.lower():
print("\nCongratulations YOU WON! The word was "
+ word.title() + "!")
Hey there! I'm new to programming (week 2) and keep seeing these 'hangman' games popup, since today is my break from learning, I the goals you were trying to achieve and ran with it.
Added some extra features in here such as breaking the loop if the all letters are guessed, and then asking the user to guess the final word.
Notes
There is a ton of Refactoring you could do with this(almost breaks my heart to post this raw form) but I just blurted it on on the go.
Also note that my original goal was to stick to your problem of not allowing the same letter to be entered twice. So this solution only works for words that contain no duplicate letters.
Hope this helps! When I get some time I'll Refactor it and update, best of luck!
Updates
Added bad_guesses = [] allows to stop from entering bad guess twice.

How to reveal letters if correct to what is inputted

I am creating a hangman game , where a user will enter a word in which another user will have to guess.
I have got the word to print with dashes, however when I input a letter which is in the word, I cannot get it to remove the dashes.
#output a game of hangman
letters= ["A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z,a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z"]
for i in range(1):
print("Welcome to Hangman")
word_guess = str(input("Please enter a word for user 2 to guess:"))
print("Word to be guessed:"+str(word_guess))
length_of_word=len(word_guess)
display=("-"*length_of_word)
print("Display:"+str(display))
for i in range(1):
print("Welcome to Hangman Player 2")
letter_guess=str(input("Please guess a letter:"))
if letter_guess in word_guess:
print("Yay you have a match")
display=display.rstrip(display)
print(display)
Hangman
Try this code, is not refinished, but it works. Maybe it can give you some ideas. To work, you got to be connected, otherwise put the file with words on the computer.
from urllib.request import urlopen
from random import choice
w0 = urlopen("https://raw.githubusercontent.com/Xethron/Hangman/master/words.txt")
w = [str(x).replace("b'", "").replace("\\n", "") for x in w0]
word = choice(w)
word = word.replace("'", "")
strips = list("_" * len(word))
chosen = []
def guess():
y = input("Guess a letter: ")
if y in chosen:
print("You have choose this letter yet, retry...")
guess()
chosen.append(y)
if y in word:
if "_" not in strips:
print("GREAT, YOU WIN!")
print()
print()
pass
print("Great the letter is in the word")
indexes = [x for x, y2 in enumerate(word) if y == y2]
for ind in indexes:
strips[ind] = y
for ch in strips:
print("[" + ch + "]", end='')
print("You`ve choosen: ", "".join(chosen))
print()
print()
guess()
else:
print("This letter is not in the word, try again")
print("".join(strips))
print("You`ve choosen: ", "".join(chosen))
def start():
for ch in range(len(word)):
guess()
print("Game over " * 5)
print("The word was " + word)
print("\n" * 5)
print("HANGMAN - Giovanni Gianni Gatto")
print("print start() to restart")
print()
start()
I had a hangman lying around which I adapted to your needs. What you need is to have a list with found items [] and when you print the word to display you show only letters which are in the found items else _.
print(' '.join(i if i in found else '_' for i in secretword))
Here is a full example of a game where it asks for one_guess (a function) until the length of found items is equal too the length of the set of the secretword (set removes duplicate letters). Try it:
def print_word():
print(' '.join(i if i in found else '_' for i in secretword))
def valid_input():
while True:
guess = input("Guess a letter: ({})".format(''.join(i for i in alpha)))
if guess in alpha:
alpha.remove(guess)
return guess
else:
print("Not valid input!")
def one_guess():
print_word()
guess = valid_input()
if guess in letters:
print("You found one!\n")
letters.remove(guess)
found.append(guess)
else:
print("You didn't find one!\n")
secretword = "animal"
alpha = list("abcdefghijklmnopqrstuvwxyz")
letters = list(set(secretword))
found = []
while True:
one_guess()
if len(set(secretword)) == len(found):
print("You won!")

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