read_csv while skipping separator in certain columns - python

I have a poorly formatted json file.
I am reading it using
mydata=pd.read_csv(afilename,header=0,usecols=[0,1,
4,5,
6,7,
8,9],
names=['ID', 'event',
'a1','a2',
'a3','a4',
'a5','a6'])
Columns 1 and 0 are correctly read.
However, the following columns of my csv file might be malformed and contain stuff like
'{Foo={"name":"bar",quantity:1.0,quantity_type:"baz"}, Fuu={"name":"barbar" '
which include the separator ',' which unfortunately is used a separator also elsewhere , and results in additional splits.
I do not know in advance how many ',' to expect, so everytime I change my usecols/names list to receive fragments of the column that get split due to extra separators, I get errors because the number of columns is not right.

Since you are reading a JSON file you should use the read_json method instead of read_csv. This will work providing your JSON is properly formatted.
For example:
mydata = pd.read_json(afilename, orient='records')

Related

sep=';' not shaping dataframe in Python

I am importing a file that is semicolon delimited. my code:
df = pd.read_csv('bank-full.csv', sep = ';')
print(df.shape)
When I use this in Jupyter Notebooks and Spyder I get a shape output of (45211, 1). When I print my dataframe the data looks like this at this point:
<bound method NDFrame.head of age;"job";"marital";"education";"default";"balance";"housing";"loan";"contact";"day";"month";"duration";"campaign";"pdays";"previous";"poutcome";"y"
0 58;"management";"married";"tertiary";"no";2143...
I can get the correct shape by using
df = pd.read_csv('bank-full.csv', sep = '[;]')
print(df.shape)
or
df = pd.read_csv('bank-full.csv', sep = '\;')
print(df.shape)
However when I do this the data seems to get pulled in as though each row is a string. The first and last column get added preceding and ending double quotations respectively, and when I attempt to strip them nothing is working to remove them so either way I am stuck with many of my columns called objects and unable to force them into integers when needed. My data comes out like this:
"age ""job"" ""marital"" ""education"" ""default"" \
0 "58 ""management"" ""married"" ""tertiary"" ""no""
with final column:
""y"""
0 ""no"""
I have reached out to those in my class and had them send me their .csv file, restarted from scratch, tried a different UI, and even copy/pasted their line of code to read and shape the data and get nothing. I have used every resource except asking this here and am out of ideas.
CSVs are usually separated by commas, but sometimes the cells are separated by a different character(s). So, since I don't have access to your exact dataset, I will give you advice that should help you overall.
First, look at the CSV and assess what character(s) are separating each value, then use that as the value in "sep" during your pd.read_csv() call.
Then, whatever columns you want to convert to numeric, you can use pd.to_numeric() to convert the data type. This may present problems if any of the values in the column cannot be converted to numeric, and you will then need to do additional data cleaning.
Below is an example of how to do this to a particular column that I am calling "col":
import pandas as pd
df = pd.read_csv('bank-full.csv', sep = '[;]')
df[col] = pd.to_numeric(df[col])
Let me know if you have further questions, or better yet, share the data with me if you can't get this to work for you.

Replacing dot with comma from a dataframe using Python

I have a dataframe for example df :
I'm trying to replace the dot with a comma to be able to do calculations in excel.
I used :
df = df.stack().str.replace('.', ',').unstack()
or
df = df.apply(lambda x: x.str.replace('.', ','))
Results :
Nothing changes but I receive his warning at the end of an execution without errors :
FutureWarning: The default value of regex will change from True to
False in a future version. In addition, single character regular
expressions willnot be treated as literal strings when regex=True.
View of what I have :
Expected Results :
Updated Question for more information thanks to #Pythonista anonymous:
print(df.dtypes)
returns :
Date object
Open object
High object
Low object
Close object
Adj Close object
Volume object
dtype: object
I'm extracting data with the to_excel method:
df.to_excel()
I'm not exporting the dataframe in a .csv file but an .xlsx file
Where does the dataframe come from - how was it generated? Was it imported from a CSV file?
Your code works if you apply it to columns which are strings, as long as you remember to do
df = df.apply() and not just df.apply() , e.g.:
import pandas as pd
df = pd.DataFrame()
df['a'] =['some . text', 'some . other . text']
df = df.apply(lambda x: x.str.replace('.', ','))
print(df)
However, you are trying to do this with numbers, not strings.
To be precise, the other question is: what are the dtypes of your dataframe?
If you type
df.dtypes
what's the output?
I presume your columns are numeric and not strings, right? After all, if they are numbers they should be stored as such in your dataframe.
The next question: how are you exporting this table to Excel?
If you are saving a csv file, pandas' to_csv() method has a decimal argument which lets you specify what should be the separator for the decimals (tyipically, dot in the English-speaking world and comma in many countries in continental Europe). Look up the syntax.
If you are using the to_excel() method, it shouldn't matter because Excel should treat it internally as a number, and how it displays it (whether with a dot or comma for decimal separator) will typically depend on the options set in your computer.
Please clarify how you are exporting the data and what happens when you open it in Excel: does Excel treat it as a string? Or as a number, but you would like to see a different separator for the decimals?
Also look here for how to change decimal separators in Excel: https://www.officetooltips.com/excel_2016/tips/change_the_decimal_point_to_a_comma_or_vice_versa.html
UPDATE
OP, you have still not explained where the dataframe comes from. Do you import it from an external source? Do you create it/ calculate it yourself?
The fact that the columns are objects makes me think they are either stored as strings, or maybe some rows are numeric and some are not.
What happens if you try to convert a column to float?
df['Open'] = df['Open'].astype('float64')
If the entire column should be numeric but it's not, then start by cleansing your data.
Second question: what happens when you use Excel to open the file you have just created? Excel displays a comma, but what character Excel sues to separate decimals depends on the Windows/Mac/Excel settings, not on how pandas created the file. Have you tried the link I gave above, can you change how Excel displays decimals? Also, does Excel treat those numbers as numbers or as strings?

Pyspark: how to read a .csv file?

I am trying to read a .csv file that has a strange format.
This is what I am doing
df = spark.read.format('csv').option("header", "true").option("delimiter", ',').load("muyFile.csv"))
df.show(5)
I do not understand why the lonlat entry of the third id is transposed. It seems that the file has two different delimiters. Your help would be much appreciated!
your tag field probably contains comma as a value which is treated as the delimiter.
enclose your data in quotes or any other quote char(remember to set .option('quote','')) and read the data again. It should work

How do I prevent a value from converting to a date or executing as division?

I have a column in a dataframe that has values in the format XX/XX (Ex: 05/23, 4/22, etc.) When I convert it to a csv, it converts to a date. How do I prevent this from happening?
I tried putting an equals sign in front but then it executes like division (Ex: =4/20 comes out to 0.5).
df['unique_id'] = '=' + df['unique_id']
I want the output to be in the original format XX/XX (Ex: 5/23 stays 5/23 in the csv file in Excel).
Check the datatypes of your dataframe with df.dtypes. I assume your column is interpreted as date. Then you can do df[col] = df[col].astype(np_type_you_want)
If that doenst bring the wished result, check why the column is interpreted as date when creating the df. Solution depends on where you get the data from.
The issue is not an issue with python or pandas. The issue is that excel thinks its clever and assumes it knows your data type. you were close with trying to put an = before your data but your data needs to be wrapped in qoutes and prefixed with an =. I cant claim to have come up with this answer myself. I obtained it from this answer
The following code will allow you to write a CSV file that will then open in excel without any formating trying to convert to date or executing division. However it shoudl be noted that this is only really a strategy if you will only be opening the CSV in excel. as you are wrapping formating info around your data which will then be stripped out by excel. If you are using this csv in any other software you might need to rethink about it.
import pandas as pd
import csv
data = {'key1': [r'4/5']}
df = pd.DataFrame.from_dict(data)
df['key1'] = '="' + df['key1'] + '"'
print(df)
print(df.dtypes)
with open(r'C:\Users\cd00119621\myfile.csv', 'w') as output:
df.to_csv(output)
RAW OUTPUT in file
,key1
0,"=""4/5"""
EXCEL OUTPUT

Pandas read_csv silently converting and messing up dates and strings?

I am reading a csv file that has two adjacent columns containing dates like this:
29/11/2004 00:00,29/11/2005 00:00,2,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL
When I read this using read_csv and then write it back to csv using the to_csv method, it gets converted to
29/11/2004 00:00,00:00.0,2.0,,,,,,,,
I have got two questions about this: Why does it read the first date okay but thinks the second, which seems to have exactly the same format, is 0? And why do the NULLs get converted to empty strings?
Here is the code I am using:
df = pandas.read_csv(filepath, sep = ",")
df.to_csv("C:\\tmp\\test.csv")
Not sure the reason for the missing date. I think it's influenced by other rows.
For the NULL string problem, keep_default_na can help you to avoid that:
df = pd.read_csv('test.csv', sep=',', keep_default_na=False)

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