I need to get from which admin page(app) current request is from in django admin.
Currently request.resolver_match.app_name only returns "admin" which is not what I want.
I have noticed that my app name is in 'view_name' and 'url_name' but is it reliable to parse these variables to access current app name?
Django 1.11 LTS
EDIT: For example, when a user enters admin page for my course app with the above method I still only get 'admin' in my request which should be 'course' not 'admin'. My ultimate goal is to hide some of my app model fields in admin page based on user group.
Thanks
From a ModelAdmin you have access to the model via self.model. In a ModelAdmin method you can thus get the app name using self.model._meta.app_label.
I you need to access it from the template rather than the ModelAdmin, self.model._meta is passed to the context as opts. You can thus access it via {% if opts.app_label == "some_app" %}.
you can simply do this by tracking requested.user i.e who is logged in currently.
something like this
if(requested.user=='admin'):
(show all fields)
else:
(show mentioned fields)
here you are restricting access of your's models fields based on currently logged in user
Related
I'm building a Django server for my company and I'm still unfamiliar with some processes. I'm sure this is super simple, I'm just completely unaware of how this works.
How do I differentiate between user's data so it doesn't get mixed up?
If Jill is a user and she requests a page of her profile data, how do I not send her Jack's profile data, especially if there are multiple models invovled?
For example, the code in the view would look like this:
def display_profile(request)
profile = Profile.objects.get(???) # What do I put in here?
I understand that I can do:
def display_profile(request, user)
profile = Profile.objects.get(user_id=user)
But that's not my design intention.
Thank you in advance.
As documented
Django uses sessions and middleware to hook the authentication system into request objects.
These provide a request.user attribute on every request which
represents the current user. If the current user has not logged in,
this attribute will be set to an instance of AnonymousUser, otherwise
it will be an instance of User.
So in your case (notice field not being called user_id )
profile = Profile.objects.get(user=user)
In your Django view, you can access the current user with request.user.
So if you want to get a Profile instance matching your current logged in user, just do a query as follow:
profile = Profile.objects.get(user=request.user)
This assumes you have a user foreign key field (or OneToOne) in your Profile model.
so I have set up Django allauth on my Django project and connected to Instagram,
when doing so I have now on my admin site Social accounts category with my account registers, all good so far
on the lower page, I can see a field called extra data,
how can I put it inside the normal Users database so I can use it to take how many followers I got out of the extra data?
can I request the followers with the Token i have maybe?
You can simply access the SocialAccount model like any other django model:
from allauth.socialaccount.models import SocialAccount
def instagram(request):
data = SocialAccount.objects.get(user=request.user).extra_data
follows = data.get('counts')
return render(request, 'Path.to.html', {"follows": follows})
I have installed the django-registration app to my project. After a successful log in step, I am redirecting the user to localhost:8000/ - this is my default testing host and port. And I am displaying somewhere on the page, the username of the logged in user.
What I want to do now is that when I click the username some options like edit profile or change password will appear. My questions are the following:
Should I create another model (inside another new app) containing fields like profile photo, gender, birthday etc and add a foreign key to the User model from django.contrib.auth.models ? Or should I modify the model from django-registration to add some additional fields but which I do not ask for at registration phase and only update them later?
if I want my profile edit feature to be at /accounts/edit, which would be the best practice to do it? to edit the URLconf of my project and add a line like (r'^accounts/edit$',.....) just before (r'^accounts/', include('registration.backends.default.urls')), ?
I hope I made myself clear. I'm trying to figure out which would be the best approach before coding, as I am new to Django... Thanks
I find it's easier to decouple the profile table from the auth table. Just like you mentioned you can use a foreign key relationship to link that profile to the user. You can also apply a lambda inside of your profile table to automatically create a profile when a new user object is created.
Inside your template you can link to the profile page dynamically based on the current authenticated party by using
{% if request.user.is_authenticated %}
Update Profile
{% endif %}
user_profile being the name of your app which holds your user_profile table. That way when the request is made you use the regular expression for the current user id (similar to the polls example provided by django) to get the id number of the currently logged in user than inside the views you just query the database for that particular user.
views.py
def myView(request, user_id):
userProfile = UserProfile.objects.get(user.pk=user_id)
This is a high level example to give an idea of one way to accomplish it.
I have install Django admin & created some active user & group by admin page.
I need to do login form & views, which will check if user is valid or not do task in the basis of permission.
I have tried following steps.(for reference)
Copied admin login.html for testing & paste it foo_project/templates/registration/login.html
Added in urls.py
from django.contrib.auth.views import login
url(r'^login/', login),
Now by running 127.0.0.1:8080/login
When I am entering valid user-name & password its trying to open /accounts/profile/ & it's not found in urls.py. And if I am entering invalid username or password its doing nothing.
So I simple need to link a page if login successful(user created by admin) & check which type of permission & group he is.Admin created auth_user table in my db.sqlite3
I am new to Django & using version 1.6.
I read document & tried built-in login() in views.py. Got unsuccess.
Is there any built-in for above need. Please describe in depth if possible.
In settings.py create this entry:
LOGIN_REDIRECT_URL = "your_redirect_url"
The user will be redirected to this page after login. Then on the url you will create which will respond to "your_redirect_url" (and should be defined somewhere in your urls.py), you can check the permissions, or groups. For more help about checking permissions, groups, you can find it here.
The login_required decorator can be really useful on implementing your view for your "redirect_url", because you don't want anonymous users accessing to this part of the site, right?
I have a custom user model (it's actually named User as I didn't see any need to name it otherwise) in my Django 1.5c1 project (currently running on the latest from the Django 1.5 branch on github). AUTH_USER_MODEL is defined in my settings properly, so the auth module works correctly and I can log in etc. fine.
However, with the custom user module enabled, the admin site doesn't work. When I add admin.autodiscover() to my urls.py, every page on the site (not just admin pages) throws a NotRegistered exception and says The model User is not registered. The traceback shows that admin.autodiscover() is trying to call admin.site.unregister(User), apparently before it has registered that model.
I tried renaming my user model to something other than User, but it didn't seem to work. I also tried creating my own admin.py for that app, and then I tried manually registering my custom User model with the custom UserAdmin model specified in admin.py before admin.autodiscover() ran, but that actually caused a separate exception saying that User was already registered.
What should I try next in order to get admin.autodiscover() working?
It looks like you need to jump through a few extra hoops if you want your custom User model to work with the admin. From the documentation:
...your User model must define some additional attributes and methods.
These methods allow the admin to control access of the User to admin
content:
class models.CustomUser
is_staff True if the user is allowed to have access to the admin site.
is_active True if the user account is currently active.
has_perm(perm, obj=None) True if the user has the named
permission.
has_module_perms(app_label) True if the user has perm
to access models in the given app.
I set up a brand new empty project with a custom user model and attempted to recreate the situation, which led to a diagnosis: we had added the django-usertools package to the project, which has not been updated for Django 1.5 and apparently conflicts with custom user models. Removing that package from the installed apps list in settings resolved the issue.