Fabric 3 ask sudo password once - python

I am using fabric to automate some deployment stuff. Below is a sample of the code I used:
run(f"sudo -H -u www-data bash -c 'rm -r project_name' ")
run(f"sudo -H -u www-data bash -c '/opt/www-data/project-name/bin/pip install -r requirements.txt' ")
run("sudo systemctl stop gunicorn")
run("sudo systemctl start gunicorn")
Everytime each line of code was ran, the terminal ask for my user password, is there a way I can enter the password just once?
Edit:
I am using python3 and the essence of the script was to run the commands on a different user, rather than my own.
Update:
I achieved this by running fabric with "-I" param.
fabric -I deploy

Using run is not the ideal way to achieve this.
fabric.operations.sudo(*args, **kwargs) is something that can be used to achieve what you are attempting.
Please be careful with sudo :)

Every run() invocation is a separate shell, as would be a sudo() invocation. The sudo credentials are per shell, so they are gone every time.
A quick and dirty way would be to lump all commands into one sudo invocation.
A nicer way would be to have a sudoers file on the target host(s) and give each user the required privileges to run particular commands without entering a password.

You can create a fab script like below and then iterate over the host list you want to run the commands because you can passwd username and password in the script itself so to avoid password invocation:
# testCheck.py
#!/usr/bin/python2.7
import sys
from fabric.api import *
env.skip_bad_hosts=True
env.command_timeout=160
env.user = 'user_name'
env.shell = "/bin/sh -c"
env.warn_only = True
env.password = 'user_password'
def readhost():
env.hosts = [line.strip() for line in sys.stdin.readlines()]
def hosts():
with settings(warn_only=True):
output=sudo("ls -l /myfolder",shell=False)
# cat hostfile.txt| | /usr/local/bin/fab readhost -f testCheck.py hosts -P -z 5
OR supplying password at command line
# cat hostfile.txt | /usr/local/bin/fab readhost -f testCheck.py --password=your_pass hosts -P -z 5
--> argument "-P" refers to parallel execution method
--> argument "-z" refres to the number of concurrent processes to use in parallel mode
exapmle hostfile.txt:
server1
server2
server3
server4
Hope this will help.

If you are using ssh keys, then set the fabric environment variable key_filename:
env.key_filename='/path/to/key.pem'
# set the following as well
env.user='username'
env.host='hostaddr'
It will ask you for the password only one time.
Have a look at this question regarding avoid to enter any sudo password when using fabric.

Related

Ubuntu-userdel command or setting sudo priveleges (Python)? [duplicate]

I'm trying to write a small script to mount a VirtualBox shared folder each time I execute the script. I want to do it with Python, because I'm trying to learn it for scripting.
The problem is that I need privileges to launch mount command. I could run the script as sudo, but I prefer it to make sudo by its own.
I already know that it is not safe to write your password into a .py file, but we are talking about a virtual machine that is not critical at all: I just want to click the .py script and get it working.
This is my attempt:
#!/usr/bin/env python
import subprocess
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
subprocess.Popen('sudo -S' , shell=True,stdout=subprocess.PIPE)
subprocess.Popen(sudoPassword , shell=True,stdout=subprocess.PIPE)
subprocess.Popen(command , shell=True,stdout=subprocess.PIPE)
My python version is 2.6
Many answers focus on how to make your solution work, while very few suggest that your solution is a very bad approach. If you really want to "practice to learn", why not practice using good solutions? Hardcoding your password is learning the wrong approach!
If what you really want is a password-less mount for that volume, maybe sudo isn't needed at all! So may I suggest other approaches?
Use /etc/fstab as mensi suggested. Use options user and noauto to let regular users mount that volume.
Use Polkit for passwordless actions: Configure a .policy file for your script with <allow_any>yes</allow_any> and drop at /usr/share/polkit-1/actions
Edit /etc/sudoers to allow your user to use sudo without typing your password. As #Anders suggested, you can restrict such usage to specific commands, thus avoiding unlimited passwordless root priviledges in your account. See this answer for more details on /etc/sudoers.
All the above allow passwordless root privilege, none require you to hardcode your password. Choose any approach and I can explain it in more detail.
As for why it is a very bad idea to hardcode passwords, here are a few good links for further reading:
Why You Shouldn’t Hard Code Your Passwords When Programming
How to keep secrets secret
(Alternatives to Hardcoding Passwords)
What's more secure? Hard coding credentials or storing them in a database?
Use of hard-coded credentials, a dangerous programming error: CWE
Hard-coded passwords remain a key security flaw
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
p = os.system('echo %s|sudo -S %s' % (sudoPassword, command))
Try this and let me know if it works. :-)
And this one:
os.popen("sudo -S %s"%(command), 'w').write('mypass')
To pass the password to sudo's stdin:
#!/usr/bin/env python
from subprocess import Popen, PIPE
sudo_password = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'.split()
p = Popen(['sudo', '-S'] + command, stdin=PIPE, stderr=PIPE,
universal_newlines=True)
sudo_prompt = p.communicate(sudo_password + '\n')[1]
Note: you could probably configure passwordless sudo or SUDO_ASKPASS command instead of hardcoding your password in the source code.
Use -S option in the sudo command which tells to read the password from 'stdin' instead of the terminal device.
Tell Popen to read stdin from PIPE.
Send the Password to the stdin PIPE of the process by using it as an argument to communicate method. Do not forget to add a new line character, '\n', at the end of the password.
sp = Popen(cmd , shell=True, stdin=PIPE)
out, err = sp.communicate(_user_pass+'\n')
subprocess.Popen creates a process and opens pipes and stuff. What you are doing is:
Start a process sudo -S
Start a process mypass
Start a process mount -t vboxsf myfolder /home/myuser/myfolder
which is obviously not going to work. You need to pass the arguments to Popen. If you look at its documentation, you will notice that the first argument is actually a list of the arguments.
I used this for python 3.5. I did it using subprocess module.Using the password like this is very insecure.
The subprocess module takes command as a list of strings so either create a list beforehand using split() or pass the whole list later. Read the documentation for moreinformation.
#!/usr/bin/env python
import subprocess
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'.split()
cmd1 = subprocess.Popen(['echo',sudoPassword], stdout=subprocess.PIPE)
cmd2 = subprocess.Popen(['sudo','-S'] + command, stdin=cmd1.stdout, stdout=subprocess.PIPE)
output = cmd2.stdout.read.decode()
sometimes require a carriage return:
os.popen("sudo -S %s"%(command), 'w').write('mypass\n')
Please try module pexpect. Here is my code:
import pexpect
remove = pexpect.spawn('sudo dpkg --purge mytool.deb')
remove.logfile = open('log/expect-uninstall-deb.log', 'w')
remove.logfile.write('try to dpkg --purge mytool\n')
if remove.expect(['(?i)password.*']) == 0:
# print "successfull"
remove.sendline('mypassword')
time.sleep(2)
remove.expect(pexpect.EOF,5)
else:
raise AssertionError("Fail to Uninstall deb package !")
To limit what you run as sudo, you could run
python non_sudo_stuff.py
sudo -E python -c "import os; os.system('sudo echo 1')"
without needing to store the password. The -E parameter passes your current user's env to the process. Note that your shell will have sudo priveleges after the second command, so use with caution!
I know it is always preferred not to hardcode the sudo password in the script. However, for some reason, if you have no permission to modify /etc/sudoers or change file owner, Pexpect is a feasible alternative.
Here is a Python function sudo_exec for your reference:
import platform, os, logging
import subprocess, pexpect
log = logging.getLogger(__name__)
def sudo_exec(cmdline, passwd):
osname = platform.system()
if osname == 'Linux':
prompt = r'\[sudo\] password for %s: ' % os.environ['USER']
elif osname == 'Darwin':
prompt = 'Password:'
else:
assert False, osname
child = pexpect.spawn(cmdline)
idx = child.expect([prompt, pexpect.EOF], 3)
if idx == 0: # if prompted for the sudo password
log.debug('sudo password was asked.')
child.sendline(passwd)
child.expect(pexpect.EOF)
return child.before
It works in python 2.7 and 3.8:
from subprocess import Popen, PIPE
from shlex import split
proc = Popen(split('sudo -S %s' % command), bufsize=0, stdout=PIPE, stdin=PIPE, stderr=PIPE)
proc.stdin.write((password +'\n').encode()) # write as bytes
proc.stdin.flush() # need if not bufsize=0 (unbuffered stdin)
without .flush() password will not reach sudo if stdin buffered.
In python 2.7 Popen by default used bufsize=0 and stdin.flush() was not needed.
For secure using, create password file in protected directory:
mkdir --mode=700 ~/.prot_dir
nano ~/.prot_dir/passwd.txt
chmod 600 ~/.prot_dir/passwd.txt
at start your py-script read password from ~/.prot_dir/passwd.txt
with open(os.environ['HOME'] +'/.prot_dir/passwd.txt') as f:
password = f.readline().rstrip()
import os
os.system("echo TYPE_YOUR_PASSWORD_HERE | sudo -S TYPE_YOUR_LINUX_COMMAND")
Open your ide and run the above code. Please change TYPE_YOUR_PASSWORD_HERE and TYPE_YOUR_LINUX_COMMAND to your linux admin password and your desired linux command after that run your python script. Your output will show on terminal. Happy Coding :)
You can use SSHScript . Below are example codes:
## filename: example.spy
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
$$echo #{sudoPassword} | sudo -S #{command}
or, simply one line (almost the same as running on console)
## filename: example.spy
$$echo mypass | sudo -S mount -t vboxsf myfolder /home/myuser/myfolder
Then, run it on console
sshscript example.spy
Where "sshscript" is the CLI of SSHScript (installed by pip).
solution im going with,because password in plain txt in an env file on dev pc is ok, and variable in the repo and gitlab runner is masked.
use .dotenv put pass in .env on local machine, DONT COMMIT .env to git.
add same var in gitlab variable
.env file has:
PASSWORD=superpass
from dotenv import load_dotenv
load_dotenv()
subprocess.run(f'echo {os.getenv("PASSWORD")} | sudo -S rm /home//folder/filetodelete_created_as_root.txt', shell=True, check=True)
this works locally and in gitlab. no plain password is committed to repo.
yes, you can argue running a sudo command w shell true is kind of crazy, but if you have files written to host from a docker w root, and you need to pro-grammatically delete them, this is functional.

Fabric sudo() not respecting env.password

I'm trying to prefill env.password using --initial-password-prompt, but remote is throwing back some strangeness. Let's say that I'm trying to cat a root-owned file as testuser, with 600 permissions on the file. I'm calling sudo('cat /home/testuser/test.txt'), and getting this back:
[testuser#testserver] sudo: cat /home/testuser/test.txt
[testuser#testserver] out: cat: /home/testuser/test.txt: Permission denied
[testuser#testserver] out:
Fatal error: sudo() received nonzero return code 1 while executing!
Requested: cat /home/testuser/test.txt
Executed: sudo -S -p 'sudo password:' -u "testuser" /bin/bash -l -c "cat /home/testuser/test.txt"
Is that piping the prompt right back into the input? I tried using sudo() with pty=False to see if it was an issue with the pseudoterminal, but to no avail.
Here's the weird part: calling run('sudo cat /home/testuser/test.txt') and invoking fab without --initial-password-prompt passes back a password prompt from remote, and on entering the password, everything works fine.
Naturally, running ssh -t testuser#testserver 'sudo cat /home/user/test.txt' prompts for a password and returns the contents of the file correctly. Do I have an issue with my server's shell config, or is the issue with how I'm using sudo()?
Down the line, I'm likely to set up a deploy user with no-password sudo and restricted commands. That'll probably moot the issue, but I'd like to figure this one out if possible. I'm running an Ubuntu 14.10 VPS, in case that's relevant.
Oh, my mistake. I had foolishly set env.sudo_user to my deploy user testuser, thinking that it was specifying the invoking user on remote. In fact, it was specifying the target user, and I was attempting to sudo into myself. Whoops.

Running fabric scripts as root

I am trying to use fabric to automate some administrative work that I am doing on a couple of servers. The general flow is the following:
SSH with local user
run: sudo su - to become root (providing local user password again)
Do the work as root :)
Unfortunately using run('sudo su -') blocks execution of the scripts and allows user input. When I type exit or Ctrl+D the scipt resumes, but without root privileges.
I have seen a similar problem in Switching user in Fabric but I am restricted to sudo su - because I am not allowed to change the /etc/sudoers file which contains the following line:
localuser ALL = /usr/bin/su -
I browsed the source of fabric trying to find a workaround but with no success.
Having faced the same problem as yours, (only sudo su - user allowed by admin, sudo -u user -c cmd not allowed), here's my working solution with fabric:
from ilogue.fexpect import expect, expecting, run
def sudosu(user, cmd):
cmd += ' ;exit'
prompts = []
prompts += expect('bash', cmd)
prompts += expect('assword:', env.password)
with expecting(prompts):
run('sudo su - ' + user)
def host_type():
sudosu('root', 'uname -s')
There are several solutions for your issue. First, you want to run commands using sudo. You can use the fabric method sudo instead of run that runs a shell command on a remote host, with superuser privileges(sudo ref).
For example, these commands are executed using sudo :
sudo("~/install_script.py")
sudo("mkdir /var/www/new_docroot", user="www-data")
sudo("ls /home/jdoe", user=1001)
result = sudo("ls /tmp/")
Another idea is that you want to wrap a set of commands (that need to be sudoed).
You can use Fabric context managers (ref) to do that. Particularly, you can use prefix or settings.
For example:
with settings(user='root'):
run('do something')
run('do another thing')
will ask you once the root password then execute commands as root.
You can tweek settings to store the password.
There is one solution for the following problem Sorry, user localuser is not allowed to execute '/usr/bin/su - -c /bin/bash -l -c pwd' as root on hostname.
You can try sudo('mkdir ~/test_fabric',shell=False). Using param shell to avoid the bash param -l.

Using sudo with Python script

I'm trying to write a small script to mount a VirtualBox shared folder each time I execute the script. I want to do it with Python, because I'm trying to learn it for scripting.
The problem is that I need privileges to launch mount command. I could run the script as sudo, but I prefer it to make sudo by its own.
I already know that it is not safe to write your password into a .py file, but we are talking about a virtual machine that is not critical at all: I just want to click the .py script and get it working.
This is my attempt:
#!/usr/bin/env python
import subprocess
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
subprocess.Popen('sudo -S' , shell=True,stdout=subprocess.PIPE)
subprocess.Popen(sudoPassword , shell=True,stdout=subprocess.PIPE)
subprocess.Popen(command , shell=True,stdout=subprocess.PIPE)
My python version is 2.6
Many answers focus on how to make your solution work, while very few suggest that your solution is a very bad approach. If you really want to "practice to learn", why not practice using good solutions? Hardcoding your password is learning the wrong approach!
If what you really want is a password-less mount for that volume, maybe sudo isn't needed at all! So may I suggest other approaches?
Use /etc/fstab as mensi suggested. Use options user and noauto to let regular users mount that volume.
Use Polkit for passwordless actions: Configure a .policy file for your script with <allow_any>yes</allow_any> and drop at /usr/share/polkit-1/actions
Edit /etc/sudoers to allow your user to use sudo without typing your password. As #Anders suggested, you can restrict such usage to specific commands, thus avoiding unlimited passwordless root priviledges in your account. See this answer for more details on /etc/sudoers.
All the above allow passwordless root privilege, none require you to hardcode your password. Choose any approach and I can explain it in more detail.
As for why it is a very bad idea to hardcode passwords, here are a few good links for further reading:
Why You Shouldn’t Hard Code Your Passwords When Programming
How to keep secrets secret
(Alternatives to Hardcoding Passwords)
What's more secure? Hard coding credentials or storing them in a database?
Use of hard-coded credentials, a dangerous programming error: CWE
Hard-coded passwords remain a key security flaw
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
p = os.system('echo %s|sudo -S %s' % (sudoPassword, command))
Try this and let me know if it works. :-)
And this one:
os.popen("sudo -S %s"%(command), 'w').write('mypass')
To pass the password to sudo's stdin:
#!/usr/bin/env python
from subprocess import Popen, PIPE
sudo_password = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'.split()
p = Popen(['sudo', '-S'] + command, stdin=PIPE, stderr=PIPE,
universal_newlines=True)
sudo_prompt = p.communicate(sudo_password + '\n')[1]
Note: you could probably configure passwordless sudo or SUDO_ASKPASS command instead of hardcoding your password in the source code.
Use -S option in the sudo command which tells to read the password from 'stdin' instead of the terminal device.
Tell Popen to read stdin from PIPE.
Send the Password to the stdin PIPE of the process by using it as an argument to communicate method. Do not forget to add a new line character, '\n', at the end of the password.
sp = Popen(cmd , shell=True, stdin=PIPE)
out, err = sp.communicate(_user_pass+'\n')
subprocess.Popen creates a process and opens pipes and stuff. What you are doing is:
Start a process sudo -S
Start a process mypass
Start a process mount -t vboxsf myfolder /home/myuser/myfolder
which is obviously not going to work. You need to pass the arguments to Popen. If you look at its documentation, you will notice that the first argument is actually a list of the arguments.
I used this for python 3.5. I did it using subprocess module.Using the password like this is very insecure.
The subprocess module takes command as a list of strings so either create a list beforehand using split() or pass the whole list later. Read the documentation for moreinformation.
#!/usr/bin/env python
import subprocess
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'.split()
cmd1 = subprocess.Popen(['echo',sudoPassword], stdout=subprocess.PIPE)
cmd2 = subprocess.Popen(['sudo','-S'] + command, stdin=cmd1.stdout, stdout=subprocess.PIPE)
output = cmd2.stdout.read.decode()
sometimes require a carriage return:
os.popen("sudo -S %s"%(command), 'w').write('mypass\n')
Please try module pexpect. Here is my code:
import pexpect
remove = pexpect.spawn('sudo dpkg --purge mytool.deb')
remove.logfile = open('log/expect-uninstall-deb.log', 'w')
remove.logfile.write('try to dpkg --purge mytool\n')
if remove.expect(['(?i)password.*']) == 0:
# print "successfull"
remove.sendline('mypassword')
time.sleep(2)
remove.expect(pexpect.EOF,5)
else:
raise AssertionError("Fail to Uninstall deb package !")
To limit what you run as sudo, you could run
python non_sudo_stuff.py
sudo -E python -c "import os; os.system('sudo echo 1')"
without needing to store the password. The -E parameter passes your current user's env to the process. Note that your shell will have sudo priveleges after the second command, so use with caution!
I know it is always preferred not to hardcode the sudo password in the script. However, for some reason, if you have no permission to modify /etc/sudoers or change file owner, Pexpect is a feasible alternative.
Here is a Python function sudo_exec for your reference:
import platform, os, logging
import subprocess, pexpect
log = logging.getLogger(__name__)
def sudo_exec(cmdline, passwd):
osname = platform.system()
if osname == 'Linux':
prompt = r'\[sudo\] password for %s: ' % os.environ['USER']
elif osname == 'Darwin':
prompt = 'Password:'
else:
assert False, osname
child = pexpect.spawn(cmdline)
idx = child.expect([prompt, pexpect.EOF], 3)
if idx == 0: # if prompted for the sudo password
log.debug('sudo password was asked.')
child.sendline(passwd)
child.expect(pexpect.EOF)
return child.before
It works in python 2.7 and 3.8:
from subprocess import Popen, PIPE
from shlex import split
proc = Popen(split('sudo -S %s' % command), bufsize=0, stdout=PIPE, stdin=PIPE, stderr=PIPE)
proc.stdin.write((password +'\n').encode()) # write as bytes
proc.stdin.flush() # need if not bufsize=0 (unbuffered stdin)
without .flush() password will not reach sudo if stdin buffered.
In python 2.7 Popen by default used bufsize=0 and stdin.flush() was not needed.
For secure using, create password file in protected directory:
mkdir --mode=700 ~/.prot_dir
nano ~/.prot_dir/passwd.txt
chmod 600 ~/.prot_dir/passwd.txt
at start your py-script read password from ~/.prot_dir/passwd.txt
with open(os.environ['HOME'] +'/.prot_dir/passwd.txt') as f:
password = f.readline().rstrip()
import os
os.system("echo TYPE_YOUR_PASSWORD_HERE | sudo -S TYPE_YOUR_LINUX_COMMAND")
Open your ide and run the above code. Please change TYPE_YOUR_PASSWORD_HERE and TYPE_YOUR_LINUX_COMMAND to your linux admin password and your desired linux command after that run your python script. Your output will show on terminal. Happy Coding :)
You can use SSHScript . Below are example codes:
## filename: example.spy
sudoPassword = 'mypass'
command = 'mount -t vboxsf myfolder /home/myuser/myfolder'
$$echo #{sudoPassword} | sudo -S #{command}
or, simply one line (almost the same as running on console)
## filename: example.spy
$$echo mypass | sudo -S mount -t vboxsf myfolder /home/myuser/myfolder
Then, run it on console
sshscript example.spy
Where "sshscript" is the CLI of SSHScript (installed by pip).
solution im going with,because password in plain txt in an env file on dev pc is ok, and variable in the repo and gitlab runner is masked.
use .dotenv put pass in .env on local machine, DONT COMMIT .env to git.
add same var in gitlab variable
.env file has:
PASSWORD=superpass
from dotenv import load_dotenv
load_dotenv()
subprocess.run(f'echo {os.getenv("PASSWORD")} | sudo -S rm /home//folder/filetodelete_created_as_root.txt', shell=True, check=True)
this works locally and in gitlab. no plain password is committed to repo.
yes, you can argue running a sudo command w shell true is kind of crazy, but if you have files written to host from a docker w root, and you need to pro-grammatically delete them, this is functional.

Can I prevent fabric from prompting me for a sudo password?

I am using Fabric to run commands on a remote server. The user with which I connect on that server has some sudo privileges, and does not require a password to use these privileges. When SSH'ing into the server, I can run sudo blah and the command executes without prompting for a password. When I try to run the same command via Fabric's sudo function, I get prompted for a password. This is because Fabric builds a command in the following manner when using sudo:
sudo -S -p <sudo_prompt> /bin/bash -l -c "<command>"
Obviously, my user does not have permission to execute /bin/bash without a password.
I've worked around the problem by using run("sudo blah") instead of sudo("blah"), but I wondered if there is a better solution. Is there a workaround for this issue?
Try passing shell=False to sudo. That way /bin/bash won't be added to the sudo command. sudo('some_command', shell=False)
From line 503 of fabric/operations.py:
if (not env.use_shell) or (not shell):
real_command = "%s %s" % (sudo_prefix, _shell_escape(command))
the else block looks like this:
# V-- here's where /bin/bash is added
real_command = '%s %s "%s"' % (sudo_prefix, env.shell,
_shell_escape(cwd + command))
You can use:
from fabric.api import env
# [...]
env.password = 'yourpassword'
In your /etc/sudoers file add
user ALL=NOPASSWD: some_command
where user is your sudo user and some_command the command you want to run with fabric, then on the fabric script run sudo it with shell=False:
sudo('some_command', shell=False)
this works for me
In your /etc/sudoers file, you could add
user ALL=NOPASSWD: /bin/bash
...where user is your Fabric username.
Obviously, you can only do this if you have root access, as /etc/sudoers is only writable by root.
Also obviously, this isn't terribly secure, as being able to execute /bin/bash leaves you open to essentially anything, so if you don't have root access and have to ask a sysadmin to do this for you, they probably won't.
Linux noob here but I found this question while trying to install graphite-fabric onto an EC2 AMI. Fabric kept prompting for a root password.
The evntual trick was to pass in the ssh private key file to fabric.
fab -i key.pem graphite_install -H root#servername
You can also use passwords for multiple machines:
from fabric import env
env.hosts = ['user1#host1:port1', 'user2#host2.port2']
env.passwords = {'user1#host1:port1': 'password1', 'user2#host2.port2': 'password2'}
See this answer: https://stackoverflow.com/a/5568219/552671
I recently faced this same issue, and found Crossfit_and_Beer's answer confusing.
A supported way to achieve this is via using env.sudo_prefix, as documented by this github commit (from this PR)
My example of use:
env.sudo_prefix = 'sudo '

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