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How to append specific html to a Django code block using only Python/Django?

I have a form I'm working with in Django.
I have a built in error message I'm trying to get to render on the form.
My first step is to get the error message to render on the form and then I will go into the function and tweak when it shows up.
My problem emerges when it comes to doing it in python.
Normally, my preferred way would be to JQuery for the footer and use JavaScript to append/prepend the HTML. Then set it to show/hide based on conditionals.
However, for this I am wanting to do it in Python to make it easier for the people working w/ me.
Here's an example of the error message HTML I would like to use for appending to something else in JS.
error_field.append('<em for="name" class="form-error-message text-danger">');
Here is an example of the Django Code Block I would like to add it within
{% block form-footer %}
{{ block.super }}
{% endblock %}
What is the easiest way to accomplish this within Python/Django? To be clear, I can figure out the conditional stuff myself. Just the rendering of the specific HTML/CSS error class I have already created. I should be able to do the conditional/function part of this myself.

I can just show you an example, this is a part of my project
views.py
try:
user=User.objects.get(username=username)
except:
messages.info(request,'username does not exist')
return redirect('login')
return render(request,'users/login-register.html')
html
{% if messages %}
{% for i in messages %}
<div class="alert alert--{{i.tags}}">
<p class="alert__message">{{i}}</p>
<button class="alert__close">x</button>
</div>
{% endfor %}
{% endif %}
You can use this anywhere in your html page. This is a common page, and everything in here is extended. And of course this is an example similar to your problem. Check it out if you want

Django/Wagtail - How to create a conditional in template that checks for url path?

I'm struggling to finding a quick and easy solution to show HTML content based on a conditional that checks if the wagtail page is at root, aka '/'.
According to the Wagtail docs, I can also make this work using original request object from Django:
Additionally request. is available and contains Django’s request
object.
This is essentially what I want to do. I use the page object here from wagtail but it might be better if I used the request object from Django instead. How can I
{% if page.request.path == '/' %}
<div> show something </div>
{% else %}
#show nothing
{% endif %}
How can I structure a conditional to solve what I'm trying to do?

Access request
The request object can be accessed via request and not page.request.
A helpful tip is to add {% debug %} to see ALL the context that is available to the current template while working locally and debugging.
{% if request.path == '/' %}
<div> show something </div>
{% else %}
#show nothing
{% endif %}
More info
Within Wagtail the request object should be available to all templates, however you may need to enable this by following the instructions about Using RequestContext in the Django docs.
Alternatively this Django request in template answer provides a clear example of what to update in your settings file.

populate google chart datatable with arrayToDataTable in django template

I have a list of tuples passed to the template.
I want to populate a datatable with it.
Here is the code.
Does anyone know what is wrong with it? Currently nothing shows on the webpage.
Thank you.
var dt=new google.visualization.arrayToDataTable([
['Name','LastGPA','CurGPA','IntervalA','IntervalB','Major'],
{% for d in data %}
[{{d.0}},{{d.1}},{{d.2}},{{d.3}},{{d.4}},{{d.5}}]
{% if not forloop.last %},{% endif %}
{% endfor %}
]);
summary_table.draw(dt);

Here's a helper module for using the Visualization API with Django queries. You might find it easier to work with passing JSON, rather than building it in the template.

Django get current view in template

How can I get the full name of the current view (my_app.views.index) in a template in Django 1.5?
With forms, I have an object called "view" in the template which I read using a template tag.
But with DetailViews I doesn't see anything similar.
Is there a way using a custom template processor?
Thanks
EDIT
Situation 1:
I retrieve a page, for example '/foo/bar/5/edit'.
Django will call 'foo.views.editbar' with pk=5.
This view renders an template 'foo/bar_form.html'
Situation 2:
If I retrieve '/foo/bar/new'
Django will call 'foo.views.newbar'
This view renders the same template as above ('foo/bar_form.html')
How can I check in this template 'foo/bar_form.html', from which view it has been rendered?
The result should be one of
'foo.views.editbar'
'foo.views.newbar'

Type just in view
{% with request.resolver_match.view_name as view_name %}
...
{{ view_name }}
...
{% endwith %}

I'm not sure I completely understand the requirement, but take a look at inspect.stack.
inspect.stack()[1][3]

Just set attribute to request object in view:
setattr(request, 'view', 'app.views.func')
and check this in template:
{% if request.view == 'app.views.func' %}
do something
{% endif %}
It worked for me.

Using variables with a django template

I have a developed a filter which does alot of database queries in my django templete. I have several uses for the same filter with the same values which will provide the same result on the same templete. I wish to save the filter result in a variable within the templete so I can make sure I dont re-run the same queries over again.
I cant send this from my view because I am doing this filter call in a for loop for each object in my model.
an example of what I need can be seen in the url tag :
{% url 'path.to.view' arg arg2 as the_url %}
I need the "as" operation over a filter.

{% with bla=arg|foo %}
{% url 'view' bla %}
{% endwith %}