How to interact with a print box using python - python

I have been using selenium to automatic printing documents and I am stuck on the print screen. As far as I know, selenium does not interact with the print screen so I am looking for an alternate situation that I can use with selenium. My code so far is down below, and all I need is code that will let me choose a new printer and then print. Also I want to change that printer to Save as PDF and then save the pdf to a file, so if that gives me a shortcut that would help a lot.
from selenium import webdriver
from selenium import *
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
driver = webdriver.Remote(
command_executor='http://127.0.0.1:4444/wd/hub',
desired_capabilities=DesiredCapabilities.CHROME) #This is because I am using remote web driver for my Mac, but it is the same as regular web driver
driver.execute("window.print()")
#Need code here

I used window.print() followed by execution of a python string containing the necessary js commands:
print_function = '''
let A = document.getElementsByTagName('print-preview-app')[0].shadowRoot;
let B = A.getElementById('sidebar').children[0].shadowRoot;
let C = B.getElementById('button-strip').children[0]
C.click()
'''
driver.execute_script(print_function)
Keep in mind that you also need to use driver.swich_to.window(window_handles[i]) to make sure you're interacting with the print box.
Once you enter into a shadowRoot element, you don't have the full compliment of driver.find_element_by methods available to you. You're limited to the methods available via JS when you are searching within a shadowRoot.

Found a suggestion that might work for you.
How to convert webpage into PDF by using Python
Maybe try pdfkit
import pdfkit
pdfkit.from_url('http://google.com', 'out.pdf')

Related

Is there a way to make it so that the bot opens the tab on the right side of my screen instead of the left side?

I am using VScode to run a bot that I made that can open up a google chrome page. The problem is the position on the screen that the bot opens the tab on. Is there a way to make it so that the bot opens the tab on the right side of my screen instead of the left side?
import time
import random
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
chromedriver = "/user/local/bin/chromedriver"
driver = webdriver.Chrome(chromedriver)
link = "https://docs/google/com/forms/d/e/1FAIpasdadTaerWE-ArYUfzNjfQosl_nlesd"
driver.get(link)
x_p = '//*[#id="mG61Hd"]/div/div[2]/div/div/div[2]div/span/div/div[1]'
submit_xp = '//*[#id="mG61Hd"]/div/div[2]/div[3]/div/div/div/span/span'
while(count < 25):
d = driver.find_element_by_xpath(x_p)
d.click()
time.sleep(0.5)
submit = driver.find_element_by_xpath(submit_xp)
submit.click()
count = count + 1
driver.get(link)
I tried looking on google, but since the question is really dumb and I don't really know how to rephrase it well, I would often find pages on a completely different subject.
I'm not sure if this will work since it also sounds really dumb, but when you insert maybe try using spaces to put to the right hand side of the screen or insert spaces to push to the right hand side of the screen. :)

use pywhatkkit in same tab instead of using new

I want to use pywhatkit to search in same tab instead of opening in new tab.I am using following code:
import pywhatkit as kit
kit.search(query)
It open new search query in new tab instead of using current tab. if anyone knows a way to handle this problem please help.
Creator/Author of the pywhatkit here, the library uses webbrowser module to search on Google and at this moment, for searching in the same tab you have to manually update the source code of the library.
To do so, go to Lib\site-packages\pywhatkit\mainfunctions.py and replace line number 230 with web.open(link,new=2), setting new=2 opens the url in same tab. I haven't tested this so I can't assure you that this will work so better to try it by importing the webbrowser module first and doing the same then update the source code.
One workaround that I found was to alter the code from the library, and I didn't actually called the library function.
import time
import webbrowser as web
import pyautogui as pg
import keyboard as kb
# Open the tab and wait for it to load
web.open(f"https://web.whatsapp.com/")
time.sleep(10)
message = 'Line 1%0aLine 2'
phone_number = '+5563999999999'
# Click on Chrome address bar then wait 1 second and click again to edit
# To find coordinates you can run
# >>> import mouseinfo
# >>> mouseinfo.MouseInfoWindow()
pg.click(1123,62)
time.sleep(1)
pg.click(1123,62)
# Type in the message, press enter, then wait page to load (8 sec) and click
# enter again to send the message
# These times will depend on internet and computer
kb.write('/send?phone=' + str(phone_number) + '&text=' + str(message_alt))
pg.press('enter')
time.sleep(8)
pg.press('enter')
# This last pause is to run this in a loop
time.sleep(2)

HTML snapshots using the selenium webdriver?

I am trying to capture all the visible content of a page as text. Let's say that one for example.
If I store the page source then I won't be capturing the comments section because it's loaded using javascript.
Is there a way to take HTML snapshots with selenium webdriver?
(Preferably expressed using the python wrapper)
Regardless of whether or not the HTML of the page is generated using JavaScript, you will still be able to capture it using driver.page_source.
I imagine the reason you haven't been able to capture the source of the comments section in your example is because it's contained in an iframe - In order to capture the html source for content within a frame/iframe you'll need to first switch focus to that particular frame followed by calling driver.page_source.
This code will take a screenshot of the entire page:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://dukescript.com/best/practices/2015/11/23/dynamic-templates.html')
driver.save_screenshot('screenshot.png')
driver.quit()
however, if you just want a screenshot of a specific element, you could use this:
def get_element_screenshot(element: WebElement) -> bytes:
driver = element._parent
ActionChains(driver).move_to_element(element).perform() # focus
src_base64 = driver.get_screenshot_as_base64()
scr_png = b64decode(src_base64)
scr_img = Image(blob=scr_png)
x = element.location["x"]
y = element.location["y"]
w = element.size["width"]
h = element.size["height"]
scr_img.crop(
left=math.floor(x),
top=math.floor(y),
width=math.ceil(w),
height=math.ceil(h))
return scr_img.make_blob()
Where the WebElement is the Element you're chasing. of course, this method requires you to import from base64 import b64decode and from wand.image import Image to handle the cropping.

Python Selenium: click() cannot trigger event

I try to use selenium to mimic my action on a website to convert PDF files to EXCEL files. There are three steps to complete the conversion:
Upload the PDF file.
Input email address.
Click the 'convert' button.
I wrote the code as below. However, every time I click the button the page just refreshes without actually converting the file.
from selenium import webdriver
import time
driver = webdriver.Chrome()
driver.get("https://pdftoexcelonline.com/en/")
# Upload file
el_upload = driver.find_element_by_name("file")
el_upload.send_keys("/path/to/the/file")
# Input email
el_email = driver.find_element_by_name("email")
el_email.clear()
el_email.send_keys("<email address>")
# Convert button
el_button = driver.find_element_by_id("convert_now")
el_button.click()
time.sleep(10)
driver.close()
This page works well when I completed the steps manually. What is reason that my code did not trigger the conversion?
One possible reason is the not enough execution time. You can add some sleep after each action to verify. Treat it as workaround if work.

How to upload file ( picture ) with selenium, python

How to upload a picture on a web application with the selenium testing tool? I am using python.
I tried many things, but nothing worked.
What I'm doing is this (make sure drv is an instance of webdriver):
drv.find_element_by_id("IdOfInputTypeFile").send_keys(os.getcwd()+"/image.png")
and then find your submit button and click it.
A very easy way to control components like windows file selector (or just your OS in general) is by using pyautogui. You can install pyautogui through pip
import pyautogui
... # set the webdriver etc.
...
...
element_present = EC.presence_of_element_located((By.XPATH, "//button[#title='Open file selector']")) # Example xpath
WebDriverWait(self.driver, 10).until(element_present).click() # This opens the windows file selector
pyautogui.write('C:/path_to_file')
pyautogui.press('enter')
I am using fine-uploader, running selenium tests with pytest and this worked for me:
elm = driver.find_element_by_xpath("//input[#type='file']")
elm.send_keys(os.getcwd() + "/tests/sample_files/Figure1.tif")
No form submission or Enter key is needed in my case.
I added an answer for anyone looking to use deal with the annoying msofiledialogs. This is working off of saravanan's proposed solution, but more fleshed out for Python.
I had a similar problem with a script I'm working on for a company on the side. I'm attempting to upload documents for a company's clients, but due to the way their site worked, I could not utilize send_keys to directly send the path, so I had to rely on msofiledialog.
You only need to install AutoIt
https://pypi.python.org/pypi/PyAutoIt/0.3 or just "pip install -U pyautoit" through the cmd screen
type "import autoit" on your script page
Type the following before the file dialog pops up in your script:
autoit.win_active("Open")
autoit.control_send("Open","Edit1",r"C:\Users\uu\Desktop\TestUpload.txt")
autoit.control_send("Open","Edit1","{ENTER}")
It will look for the open file dialog window and fill it out and press enter.
"Open" is the title of my file dialog screen. Put the title of yours in place of "Open". There are more creative ways to utilize AutoIt's functions, but this is an easy, straightforward way for beginners.
Edit: DO NOT. DO NOT use control_send on most things if you can avoid it. It has a well-known issue of sending erroneous text. In my case, the colon in my file path was being turned into a semi colon. If you need to send input keys, it should be fine, however if you need to send text, use control_set_text. It has the same syntax.
autoit.control_set_text("Open","Edit1",r"C:\Users\uu\Desktop\TestUpload.txt")
All these approach wont work with modern image uploaders in olx !!!
Alternative approach (only for windows )
1. Automation of windows can be done using Autoit
2. Install Autoit and SciTe Script editor
3. Autoit code :(imageupload.au3)
WinActivate("File Upload"); for chrome use "open" that is the name of the window that pops
send("D:\images\image1.png"); path of the file
Send("{ENTER}")
4. compile it to get an .exe file(imageupload.exe)
5. Now from python call the .exe file like
import os
import os.system('C:\images\imageupload.exe') #path of the .exe file
Upload input control opens a native dialog (it is done by browser) so clicking on the control or browse button via Selenium will just pop the dialog and the test will hang.
The workaround is to set the value of the upload input via JavaScript (in Java it is done via JavascriptExecutor) and then submit the form.
See this question for sample in C#, I am sure there's also a way to call JavaScript in Python but I never used Selenium Python bindings
Here is the code that i used:
Imagepath = "C:\User\Desktop\image.png"
driver.find_element_by_xpath('//html/body/input').send_keys(Imagepath)
driver.find_element_by_xpath('//html/body/button').click()
I accept the Answer by karloskar. Note It is not working for FireFox (59). And it is works with Chrome Driver only.
import win32com.client
shell = win32com.client.Dispatch("WScript.Shell")
shell.Sendkeys("C:\text.txt")
shell.Sendkeys("~")
Will resolve the issue
You can easily add this one line of code to solve the problem:
driver.find_element_by_xpath("your fullpath").send_keys("C://1.png(your file root")
But pay attention, sometimes maybe you put a wrong xpath in first field. follow below steps for reach to rightful xpath:
open the inspect and click exactly on the box which you want to
upload the file.
right click on the html code and select xpath full address from copy
sub menu.
paste the root in xpath field in the code.
full code to achieve file upload using autoit tool.
u can just copy paste this and u can run, it will work since it is a acti-time demo.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as ec
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
import time
import os
def fileUploading():
driver = webdriver.Firefox()
driver.implicitly_wait(20)
wait = WebDriverWait(driver, 10)
driver.get("https://demo.actitime.com/login.do");
driver.find_element(By.ID,"username").send_keys("admin")
driver.find_element(By.NAME, "pwd").send_keys("manager")
driver.find_element(By.XPATH, "//div[.='Login ']").click()
wait.until(ec.element_to_be_clickable((By.XPATH, "(//div[#class='popup_menu_icon'])[3]")))
driver.find_element(By.XPATH, "(//div[#class='popup_menu_icon'])[3]").click()
wait.until(ec.element_to_be_clickable((By.XPATH, "//a[contains(text(),'Contact actiTIME Support')]")))
driver.find_element(By.XPATH, "//a[contains(text(),'Contact actiTIME Support')]").click()
wait.until(ec.element_to_be_clickable((By.XPATH,"//div[#class='dz-default dz-message']")))
driver.find_element(By.XPATH,"//div[#class='dz-default dz-message']").click()
os.system("C:\\Users\\mallikar\\Desktop\\screenUpload.exe")
time.sleep(2000)
fileUploading()
below is the content of autoit code:
WinWaitActive("File Upload")
Send("D:\SoftwareTestingMaterial\UploadFile.txt")
Send("{ENTER}")
download autoIt and autoIt SCITE editor tool.
once done install autoit and the open the scite editor and paste the above code and save it with .au3 extension and once saved, right click on the file and select complile script(x64), now .exe file is created.
now use the below code:
os.system("C:\\Users\\mallikar\\Desktop\\screenUpload.exe")
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("http://www.example.org")
def upload_file():
upload_file = driver.find_element_by_id("paste here id of file which
is
enter code here`shown in html code...")
upload_file.send_keys("copy the path of file from your pc with name and
paste here...")
if toast message is disappeared within seconds you can use Chropath extension in chrome to find its xpath
This is a pure python code.
Instead of using control_send, use control_set_text to resolve inconsistencies present in the string sent to the window. See this link for reference: https://www.autoitscript.com/forum/topic/85929-incorrect-string-being-sent-via-controlsend/
import autoit
autoit.win_wait_active("Open")
autoit.control_set_text("Open", "Edit1", imgPath)
autoit.send("{ENTER}")
Use PyAutoGui if sendkeys function is not working on buttons.
sample code:
import pyautogui
driver.find_element_by_xpath("Enter Xpath of File upload button").click()
time.sleep(4) #waiting for window popup to open
pyautogui.write(r"C:\Users\AmarKumar\FilesForUploading\image.jpg") #path of File
pyautogui.press('enter')
I have used below script format to upload the images. This may help you.
Imagepath=os.path.abspath('.\\folder1\\subfolder2\file1.jpg')
driver.find_element_by_id("Id of the element").clear()
driver.find_element_by_id("Id of the element").send_keys(Imagepath)
if you do not have ID of the object ,then you can use xpath or css selector accordingly.
Using splinter :
browser.attach_file('file_chooser_id',fully_qualified_file_path)
If you are using service you will get an exception
service = Service('driver_path')
service.start()
driver = webdriver.Remote(service.service_url)
choose_image = driver.find_element(By.ID, 'id')
choose_image.send_keys(os.getcwd()+'/image.jpg')
Exception :
selenium.common.exceptions.WebDriverException: Message: unknown command: unknown command: session/$sessionId/se/file
Working code (suggestion - use id of the element instead of other)
driver=webdriver.Chrome(executable_path=driver_path)
choose_image=driver.find_element(By.ID, 'id')
choose_image.send_keys(os.path.join(os.getcwd(), 'image.jpg'))
In case you want to upload multiple pictures, you can alter the single image answer as follows:
images = ["/path/to/image1.png", "/path/to/image2.png","/path/to/image3.png"]
drv.find_element_by_id("IdOfInputTypeFile").send_keys("\n".join(images))
Note that the input form should have the multiple attribute set to True.
I post a solution that i consider best. it is a modification on solution by #sherlock (see my comment on that post)
import autoit
autoit.win_wait_active("Open")
autoit.control_set_text("Open", "Edit1", imgPath)
autoit.control_click("Open", "Button1")
Install these three
sudo apt-get install python3-tk python3-dev
pip install tk
pip install PyAutoGUI
use these two line of code.
pyautogui.write('/home/image.jpg')
pyautogui.press('enter')

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