i was trying to decrypt an AES ciphertext with Python 3.
I know that the key has been encoded as it follows (javascript) :
var k = CryptoJS.SHA256("\x93\x39\x02\x49\x83\x02\x82\xf3\x23\xf8\xd3\x13\x00");
if(u == "\x68\x34\x63\x6b\x33\x72") {
var enc = CryptoJS.AES.encrypt(p, CryptoJS.enc.Hex.parse(k.toString().substring(0,32)), { iv: CryptoJS.enc.Hex.parse(k.toString().substring(32,64)) });
if(enc == "PKhuCrfh3RUw4vie3OMa8z4kcww1i7198ly0Q4rpuyA=") {
t = true;
}
}
Now, as you can see the IV of the encryption is 32 characters long, however in python 3 i can't use a string of length 32 as my IV.
I use the following code :
def decrypt(encrypted, passphrase_full):
half1_passphrase = passphrase_full[0:32]
half2_passphrase = passphrase_full[32:]
print(len(half2_passphrase))
IV = half2_passphrase
aes = AES.new(half1_passphrase, AES.MODE_CBC, IV)
return aes.decrypt(encrypted)
And i get
ValueError: IV must be 16 bytes long
So, how can i decrypt my string correctly ?
Thank you very much
Related
I need to have a python code and a swift code exchange encrypted message.
Here's what I tried:
Fernet
After a review of the options, I thought that a symetric key algorithm could work well.
In python (as usual), it is straightforward to encrypt and decrypt:
Fernet(key).encrypt(b"mdg") # encrypt
Fernet(key).decrypt(encryptedMsg) # decrypt
In swift, it seemed initially straightforward with something along the lines of:
func encrypt(key: String, msg: String) throws -> String {
let data = Data(base64URL: key)!
let symetricKey = try! SymmetricKey(data: d)
let msgUtf8 = msg.data(using: .utf8)!
let sealBox = try! AES.GCM.seal(msgUtf8, using: symetricKey, nonce: nil)
return sealBox.combined.base64EncodedString();
}
However, I have been unable to find the algorithm in swift matching python's Fernet.
ChaCha
While searching for the problem, I landed on this amazing answer from Bram. Very unfortunately it only solves one side of my problem : encrypting messages in python and decoding them in swift. I also need the reverse process.
How to solve this?
To start, we first need a way to create secure random values to generate the IV and keys. You can also generate the keys using CryptoKit's SymmetricKey and extract the data from them, but for now, I'll use this function.
extension Data {
static func secureRandom(ofSize size: Int) -> Data {
var output = [UInt8](repeating: 0, count: size)
_ = SecRandomCopyBytes(kSecRandomDefault, size, &output)
return Data(output)
}
}
We then require the possibility to compute the AES CBC ciphertext, which can be done using CommonCrypto.
func encrypt(plaintext: Data, key: Data, iv: Data) -> Data {
var encryptor: CCCryptorRef?
defer {
CCCryptorRelease(encryptor)
}
var key = Array(key)
var iv = Array(iv)
var plaintext = Array(plaintext)
CCCryptorCreate(CCOperation(kCCEncrypt), CCAlgorithm(kCCAlgorithmAES), CCOperation(kCCOptionPKCS7Padding), &key, key.count, &iv, &encryptor)
var outputBytes = [UInt8](repeating: 0, count: CCCryptorGetOutputLength(encryptor, plaintext.count, false))
CCCryptorUpdate(encryptor, &plaintext, plaintext.count, &outputBytes, outputBytes.count, nil)
var movedBytes = 0
var finalBytes = [UInt8](repeating: 0, count: CCCryptorGetOutputLength(encryptor, 0, true))
CCCryptorFinal(encryptor, &finalBytes, finalBytes.count, &movedBytes)
return Data(outputBytes + finalBytes[0 ..< movedBytes])
}
and the HMAC with the SHA-256 hash function. I recommend using CryptoKit's HMAC implementation here, but to keep things simple, I went with the CommonCrypto implementation.
func computeHMAC(_ data: Data, using key: Data) -> Data {
var data = Array(data)
var key = Array(key)
var macOut = [UInt8](repeating: 0, count: Int(CC_SHA256_DIGEST_LENGTH))
CCHmac(CCHmacAlgorithm(kCCHmacAlgSHA256), &key, key.count, &data, data.count, &macOut)
return Data(macOut)
}
This brings all of this together into the following
let plaintext = Data("Hello world!".utf8)
let signingKey = Data.secureRandom(ofSize: kCCKeySizeAES128)
let cryptoKey = Data.secureRandom(ofSize: kCCKeySizeAES128)
let fernetKey = (signingKey + cryptoKey).base64EncodedString()
let version: [UInt8] = [0x80]
let timestamp: [UInt8] = {
let timestamp = Int(Date().timeIntervalSince1970).bigEndian
return withUnsafeBytes(of: timestamp, Array.init)
}()
let iv = Data.secureRandom(ofSize: kCCBlockSizeAES128)
let ciphertext = encrypt(plaintext: plaintext, key: cryptoKey, iv: iv)
let hmac = computeHMAC(version + timestamp + iv + ciphertext, using: signingKey)
let fernetToken = (version + timestamp + iv + ciphertext + hmac).base64EncodedString()
print("Fernet key: \(fernetKey)")
print("Fernet token: \(fernetToken)")
An example output can be
Fernet key: 7EwFlYNKTGfj+2fSgL3AUqtrRqRs4D1TWNK7t2XbGJQ=
Fernet token: gAAAAABivCLM0y0poDtGOohT1yK4XTDJppYPJdu4fuDTZ5tb9P9KP5ACgX8aJq4imsSdbzOCcvY3Tueo4FYbwyG+ZugozILL+Q==
We can use this in python using cryptography.io's implementation
from cryptography.fernet import Fernet
key = b'7EwFlYNKTGfj+2fSgL3AUqtrRqRs4D1TWNK7t2XbGJQ='
token = b'gAAAAABivCLM0y0poDtGOohT1yK4XTDJppYPJdu4fuDTZ5tb9P9KP5ACgX8aJq4imsSdbzOCcvY3Tueo4FYbwyG+ZugozILL+Q=='
Fernet(key).decrypt(token)
# b'Hello world!'
I have this encrypt with AES function in python:
def encrypt_text(self):
raw = self.PKCS7_padding()
iv = Random.new().read(self.block_size)
cipher = AES.new(self.key, AES.MODE_CBC, iv)
encrypted = base64.b64encode(iv + cipher.encrypt(raw))
return encrypted
And then padding it with:
def PKCS7_padding(self):
return self.text+chr(16-len(self.text)%16)*(16-len(self.text)%16)
But when I send it to this c# function
public static string DecryptString(string key, string cipherText)
{
byte[] iv = new byte[16];
byte[] buffer = Convert.FromBase64String(cipherText);
using (Aes aes = Aes.Create())
{
aes.Key = Convert.FromBase64String(key);
aes.IV = iv;
ICryptoTransform decryptor = aes.CreateDecryptor(aes.Key, aes.IV);
using (MemoryStream memoryStream = new MemoryStream(buffer))
{
using (CryptoStream cryptoStream = new CryptoStream((Stream)memoryStream, decryptor, CryptoStreamMode.Read))
{
using (StreamReader streamReader = new StreamReader((Stream)cryptoStream))
{
return streamReader.ReadToEnd();
}
}
}
}
}
Say i send "hello world"
I get a weird mix of the string i sent plus random non pritable characters. EX: "�Ȯ�Ŗf�"��Xhello world"
The key is generated as follows:
key = base64.b64encode(os.urandom(32))
return key.decode()
I do not get any errors but weird text any ideas Thanks! If you have any questions please feel free to ask
In the Python code, a random IV is generated and concatenated with the ciphertext. However, in the C# code, the separation of IV and ciphertext is missing. Instead, a zero IV is applied and the concatenation of IV and ciphertext is decrypted, which causes the problem.
The separation of IV and ciphertext can be added to the C# code e.g. as follows:
byte[] buffer = ...
byte[] ct = new byte[buffer.Length - iv.Length];
Buffer.BlockCopy(buffer, 0, iv, 0, iv.Length);
Buffer.BlockCopy(buffer, iv.Length, ct, 0, ct.Length);
buffer = ct;
using ...
Note that PyCryptodome supports padding in a dedicated module: Crypto.Util.Padding.
Also, in the Python code the Base64 encoded key is nowhere Base64 decoded (but maybe the corresponding code was just not posted).
I have some already encrypted data which needs to be decrypted using python. The decryption logic in C# looks as given below.
using System.Security.Cryptography;
private const string Url_ENCRYPTION_KEY = "abcd123456";
private readonly static byte[] URL_SALT = Encoding.ASCII.GetBytes(Url_ENCRYPTION_KEY.Length.ToString());
public static string Decrypt(string inputText) {
try {
if (!string.IsNullOrEmpty(inputText)) {
RijndaelManaged rijndaelCipher = new RijndaelManaged();
byte[] encryptedData = Convert.FromBase64String(inputText.Replace(" ", "+"));
PasswordDeriveBytes secretKey = new PasswordDeriveBytes(Url_ENCRYPTION_KEY, URL_SALT);
using (ICryptoTransform decryptor =
rijndaelCipher.CreateDecryptor(secretKey.GetBytes(32), secretKey.GetBytes(16))) {
using (MemoryStream memoryStream = new MemoryStream(encryptedData)) {
using (CryptoStream cryptoStream =
new CryptoStream(memoryStream, decryptor, CryptoStreamMode.Read)) {
byte[] plainText = new byte[encryptedData.Length];
int decryptedCount = cryptoStream.Read(plainText, 0, plainText.Length);
return Encoding.Unicode.GetString(plainText, 0, decryptedCount);
}
}
}
}
}
catch(Exception ex) {
//clsErrorHandler.LogError(ex);
}
return inputText;
}
I have tried libs like pprp and python's cryptography but the solutions out there use PBKDF2, while the C# code here supplies the decryptor bytes of key and salt as key and IV values.
From what I looked the PasswordDeriveBytes function basically work as a somewhat modified PBKDF1,
but all of the solutions I tried fail with somekind of esoteric this size doesn't match with that size errors.
Here is one implementation of PasswordDeriveBytes I found floating out there but I am at a loss on how to do something similar to secretKey.GetBytes(32) and creating a decryptor
import hashlib
from base64 import b64decode
def MS_PasswordDeriveBytes(pstring, salt, hashfunc, iterations, keylen):
if iterations > 0:
lasthash = hashlib.sha1(pstring+salt).digest()
iterations -= 1
else:
print("Iterations must be > 0")
#If iterations is 1 then basically the same thing happens as 2 based on my testing
#if iterations == 0 and keylen > len(lasthash):
#print("Dunno what happens here")
#return -1
for i in range(iterations-1):
lasthash = hashlib.sha1(lasthash)
bytes = hashlib.sha1(lasthash).digest()
ctrl = 1
while len(bytes) < keylen:
bytes += hashlib.sha1(str(ctrl)+lasthash).digest()
ctrl += 1
return(bytes[:keylen])
stpass = 'amp4Z0wpKzJ5Cg0GDT5sJD0sMw0IDAsaGQ1Afik6NwXr6rrSEQE='
slt = 'aGQ1Afik6NampDT5sJEQE4Z0wpsMw0IDAD06rrSswXrKzJ5Cg0G='
initv = '#1B2c3D4e5F6g7H8'
enc_str = b64decode('B5YDTLEDBjd+8zy5lzEfjw==')
derbytes = MS_PasswordDeriveBytes(stpass, slt, hashlib.sha1, iterations=2, keylen=32)
I am trying to rewrite a node.js decoding function in python
this is the function I am trying to rewrite
module.exports.decrypt = function (data, key, iv, hmacKey) {
iv = iv.slice(0, 16)
var decipherer = crypto.createDecipheriv('aes-128-ctr', key, iv)
var hmac
if (hmacKey) {
hmac = crypto.createHmac('sha1', hmacKey).update(data).digest()
}
return {
data: decipherer.update(data),
hmac: hmac
}
}
the key parameter is generated by crypto.pbkdf2Sync function of node's standard library.
What I implemented in python is
from Crypto.Cipher import AES
from Crypto.Util import Counter
def decrypt(data, key, iv, hmac=None):
iv = iv[:16]
ctr = Counter.new(128)
cipher = AES.new(key, mode=AES.MODE_CTR, IV=iv, counter=ctr)
return cipher.decrypt(data)
I provided the python decrypt function the same same data that the js function receives.
since the data and key, iv params that the js function expects are binary buffers, I copied them to the python code as hex strings and then used binascii.unhexlify in the python code before passing them to the ecrypt python function.
so the arguments that I am providing to both functions are (hex)
data 972acf88c5d7
key 129b6e542600889a75ec7659d9dc23df
iv 31323331323331323331323331323331323331323331313233313233313233313233
The python function returns gibberish.
can anyone help?
thanks!
I am adding a go application to an already existing python codebase. I've been having trouble dealing with encryption between the languages. This is using go 1.2.1 and Python 2.7.x / PyCrypto 2.7a1.
Here is the Python sample:
import Crypto.Cipher
import Crypto.Hash.HMAC
import Crypto.Hash.SHA256
import Crypto.PublicKey.RSA
from binascii import hexlify, unhexlify
#encrypt
payload = unhexlify("abababababababababababababababababababababababababababababababab")
password = unhexlify("0123456789ABCDEF0123456789ABCDEF0123456789ABCDEF0123456789ABCDEF")
iv = unhexlify("00000000000000000000000000000000")
print "IV: ", hexlify(iv), "len: ", len(iv)
print "Password length: ", len(password)
cipher = Crypto.Cipher.AES.new(
key=password,
mode=Crypto.Cipher.AES.MODE_CFB,
IV=iv)
payload = cipher.encrypt(payload)
print hexlify(payload) #dbf6b1877ba903330cb9cf0c4f530d40bf77fe2bf505820e993741c7f698ad6b
And this is the Go sample:
package main
import (
"fmt"
"crypto/cipher"
"crypto/aes"
"encoding/hex"
)
// encrypt
func main() {
payload, err1 := hex.DecodeString("abababababababababababababababababababababababababababababababab")
password, err2 := hex.DecodeString("0123456789ABCDEF0123456789ABCDEF0123456789ABCDEF0123456789ABCDEF")
iv, err3 := hex.DecodeString("00000000000000000000000000000000")
if err1 != nil {
fmt.Printf("error 1: %v", err1)
return
}
if err2 != nil {
fmt.Printf("error 2: %v", err2)
return
}
if err3 != nil {
fmt.Printf("error 3: %v", err3)
return
}
aesBlock, err4 := aes.NewCipher(password)
fmt.Printf("IV length:%v\n", len(iv))
fmt.Printf("password length:%v\n", len(password))
if err4 != nil {
fmt.Printf("error 4: %v", err4)
return
}
cfbDecrypter := cipher.NewCFBEncrypter(aesBlock, iv)
cfbDecrypter.XORKeyStream(payload, payload)
fmt.Printf("%v\n", hex.EncodeToString(payload)) // db70cd9e6904359cb848410bfa38d7d0a47b594f7eff72d547d3772c9d4f5dbe
}
Here is the golang link, I could not find a Python pastebin that had PyCrypto installed.
As suggested by the title & source, the two snippets produce different cyphertext:
Python: dbf6b1877ba903330cb9cf0c4f530d40bf77fe2bf505820e993741c7f698ad6b
Golang: db70cd9e6904359cb848410bfa38d7d0a47b594f7eff72d547d3772c9d4f5dbe
Both languages can decrypt their 'native' cypthertext, but neither can decrypt the others'. Because the python implementation already exists, I'm looking for a solution that will allow Go to decrypt cyphertext encrypted with the example PyCrypto AES settings & key size.
Research on the current system has revealed that our python system uses CFB8 (8 bit segments). Go does not support this out of the box, but the source code used in the current CFBDecrypter / CFBEncrypter looks like it can be adapted fairly easily.
If anyone is looking for Go implementation of CFB mode with segment size = 8 you can use this:
import "crypto/cipher"
// CFB stream with 8 bit segment size
// See http://csrc.nist.gov/publications/nistpubs/800-38a/sp800-38a.pdf
type cfb8 struct {
b cipher.Block
blockSize int
in []byte
out []byte
decrypt bool
}
func (x *cfb8) XORKeyStream(dst, src []byte) {
for i := range src {
x.b.Encrypt(x.out, x.in)
copy(x.in[:x.blockSize-1], x.in[1:])
if x.decrypt {
x.in[x.blockSize-1] = src[i]
}
dst[i] = src[i] ^ x.out[0]
if !x.decrypt {
x.in[x.blockSize-1] = dst[i]
}
}
}
// NewCFB8Encrypter returns a Stream which encrypts with cipher feedback mode
// (segment size = 8), using the given Block. The iv must be the same length as
// the Block's block size.
func newCFB8Encrypter(block cipher.Block, iv []byte) cipher.Stream {
return newCFB8(block, iv, false)
}
// NewCFB8Decrypter returns a Stream which decrypts with cipher feedback mode
// (segment size = 8), using the given Block. The iv must be the same length as
// the Block's block size.
func newCFB8Decrypter(block cipher.Block, iv []byte) cipher.Stream {
return newCFB8(block, iv, true)
}
func newCFB8(block cipher.Block, iv []byte, decrypt bool) cipher.Stream {
blockSize := block.BlockSize()
if len(iv) != blockSize {
// stack trace will indicate whether it was de or encryption
panic("cipher.newCFB: IV length must equal block size")
}
x := &cfb8{
b: block,
blockSize: blockSize,
out: make([]byte, blockSize),
in: make([]byte, blockSize),
decrypt: decrypt,
}
copy(x.in, iv)
return x
}
It seems that the cipher can be made compatible to Go's crypto/cipher if we change segment_size of AES object from the default 8 to AES.block_size*8 (which is 128), like this:
Crypto.Cipher.AES.new(
key=password,
mode=Crypto.Cipher.AES.MODE_CFB,
IV=iv,
segment_size=AES.block_size*8
)
I found that easiest way to deal with this from Python side is to use M2Crypto library.
Final code looks like:
import M2Crypto.EVP
iv = ciphertext[:16]
ciphertext = ciphertext[16:]
cipher = M2Crypto.EVP.Cipher('aes_256_cfb', t, iv, 0)
text = cipher.update(ciphertext)
print text
Works perfect without need to change something in Go.
i solve by adapt python code like this (golang encode and python decode):
# golang encode
padNum := len(data) % 16
if padNum != 0 {
for i := 0; i < 16-padNum; i++ {
data = append(data, ',')
}
}
# python decode
cipher = AES.new(key=self.key, mode=AES.MODE_CFB, IV=iv,segment_size=128)