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Download file from SFTP server in Python Paramiko

I am using Python Paramiko to retrieve/search file from an SFTP server. I get all file in the directory.
What I need is specific file from that directory. How do I get it?

Use Paramiko SFTPClient.get to download a single file:
with paramiko.SSHClient() as ssh:
ssh.connect(host, username=username, password=password)
with ssh.open_sftp() as sftp:\
sftp.get("/remote/path/file.txt", "/local/path/file.txt")
You will also have to deal with the server's host key verification.

What you need to do is create an ssh client, then execute an ls with piped grep to find your file. such as ls /srv/ftp | grep '^FTP_' to find files in the /srv/ftp directory and start with FTP. Then open an sftp connection and execute the get command to bring the files over.
EDIT: Martin below mentioned that there is a better way to get the directory contents using SFTPClient.listdir() - I have revised to that method. More info in the docs: https://docs.paramiko.org/en/stable/api/sftp.html
Putting all that together looks like
import paramiko
host = ''
port = 22
username = ''
password = ''
with paramiko.SSHClient() as client:
client.connect(host, port, username, password)
with client.open_sftp() as sftp:
files = sftp.listdir('/srv/ftp')
for i, file in enumerate(files):
if file and file.startswith('FTP'):
sftp.get(f'/srv/ftp/{file}', f'~/ftp/{file}')
print(f'Moved {file}')
This code is untested but should work. Hope that's clear.

Here is an answer in case you need a kind of find using a SFTP connection, not knowing the exact path and name of the file. If it is not what you were looking for, I am sorry.
I made a library named sftputil, based on paramiko, which implements advanced functionalities such as glob. To find a specific file and download it, you can do it this way :
from sftputil import SFTP
sftp = SFTP("hostname", "username", password="password")
# Here we look for a file with a name starting with `foo`
found_files = sftp.glob("directory/foo*")
# Here we look for the file `bar` in any subdirectory
found_files = sftp.glob("directory/*/bar")
# But you can use other patterns of course.
# And now the files can be downloaded
for f in found_files:
sftp.get(f, "my/local/path")
If you don’t know glob, you should read the python documentation, as this implementation works the same way.

I recently solved a similar issue of connecting to SFTP and downloading files via paramiko.
The code below assumes that you know the name of the file you are looking for (file_name). If there are multiple files you need, just add them to file_list.
import paramiko
host = 'host.name.com'
usr = 'username'
pwd = 'password'
remote_path = '/path/on/sftp/server/'
local_path = '/path/on/local/machine/'
file_name = 'specific_file_you_need.csv'
transport = paramiko.Transport((host,22))
transport.connect(None,usr,pwd)
sftp = paramiko.SFTPClient.from_transport(transport)
file_list = [file_name]
for file in file_list:
sftp.get(remote_path+'{0}'.format(file),
local_path+'{0}'.format(file))

Uploading file via Paramiko SFTP not working

I am using the below Python code to upload a file via SFTP using Paramiko. The connection "seems" to be fine, the code executes to the end, just the file isn't reaching the destination when I check in FileZilla.
I have checked and set permissions on the file to 777 (just to be sure). I have also checked my file path string in a separate terminal and the path is valid.
import paramiko
.
.
transport = paramiko.Transport((host, port))
transport.connect(username = username, password = password)
sftp = paramiko.SFTPClient.from_transport(transport)
sftp.put(filePath, "/") # Upload file to root FTP folder
sftp.close()
transport.close()
What can I do to debug this? Anything I can print out, check connection succeeded etc?

The second argument of SFTPClient.put (remotepath) is path to a file, not a folder:
the destination path on the SFTP server. Note that the filename should be included. Only specifying a directory may result in an error.
Try this:
sftp.put(filePath, "/filename")

How to transfer FileStorage object via FTP in python

I have a rester webservice (Flask Webservice) where clients sends me file object(Image or pdf); Now I want to store it into FTP location. How can I store file object(Image or pdf) to FTP location.
I am using Flask Webservice(Rester API), I able to receive file objct of type FileStorage. then I trying to store the file object(Image or pdf) to FTP using paramiko API paramiko.SFTPClient class to transfer/store the file to FTP. But it is not accepting the file object. It is expecting only local file path.
Below is the sample code which is used to transfer file to FTP
FTP Code:
import paramiko
transport = paramiko.Transport((host, port))
transport.connect(username = username, password = password)
sftp = paramiko.SFTPClient.from_transport(transport)
sftp.put(localpath, filepath)
Could you please suggest me how can I achieve file object store to FTP?

A simple solution would be to save your FileStorage object on disk, and then give the path to paramiko sftp client (your localpath variable).
Note that this is a non-optimised solution since it requires to write data on disk then re-read it.
For a more optimised solution, according to paramiko's SFTP doc, you could use the method
putfo(fl, remotepath, file_size=0, callback=None, confirm=True)
That would replace your line sftp.put(localpath, filepath) by sftp.putfo(filestorage_object, filepath)

Upload file via SFTP with Python

I wrote a simple code to upload a file to a SFTP server in Python. I am using Python 2.7.
import pysftp
srv = pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log")
srv.cd('public') #chdir to public
srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/
# Closes the connection
srv.close()
The file did not appear on the server. However, no error message appeared. What is wrong with the code?
I have enabled logging. I discovered that the file is uploaded to the root folder and not under public folder. Seems like srv.cd('public') did not work.

I found the answer to my own question.
import pysftp
srv = pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log")
with srv.cd('public'): #chdir to public
srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/
# Closes the connection
srv.close()
Put the srv.put inside with srv.cd

Do not use pysftp it's dead. Use Paramiko directly. See also pysftp vs. Paramiko.
The code with Paramiko will be pretty much the same, except for the initialization part.
import paramiko
with paramiko.SSHClient() as ssh:
ssh.load_system_host_keys()
ssh.connect(host, username=username, password=password)
sftp = ssh.open_sftp()
sftp.chdir('public')
sftp.put('C:\Users\XXX\Dropbox\test.txt', 'test.txt')
To answer the literal OP's question: the key point here is that pysftp Connection.cd works as a context manager (so its effect is discarded without with statement), while Paramiko SFTPClient.chdir does not.

import pysftp
with pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log") as sftp:
sftp.cwd('/root/public') # The full path
sftp.put('C:\Users\XXX\Dropbox\test.txt') # Upload the file
No sftp.close() is needed, because the connection is closed automatically at the end of the with-block
I did a minor change with cd to cwd
Syntax -
# sftp.put('/my/local/filename') # upload file to public/ on remote
# sftp.get('remote_file') # get a remote file

paramiko SFTP hangs on get

I'm trying to use paramiko to get a file via SFTP.
It connects, I can list directories and it even downloads the first megabyte or so of the file but then it just hangs. No exception, no error, nothing. It just hangs there indefinitely.
Here's the code I'm working with:
import paramiko
t = paramiko.Transport( host )
t.connect( username=uname, password=passwd )
f = paramiko.SFTPClient.from_transport( t )
print f.listdir()
f.get( fname, fname ) #it hangs on this line :\
I have sftp access to the host in question but no shell access.
The host contains a single file that I need to fetch regularly and process in a python script.
Any help with this problem or alternate solutions to doing SFTP in Python are greatly appreciated :)

I was experiencing the same problem as Ulfur. He posted his own fix/workaround as a comment to another answer, so I decided to add it as a proper answer to make it more visible.
The basic idea is to not use the .get() method, but to loop over the lines. The following is a Python 3 implementation.
transport = None
sftp = None
sftp_path = 'some/sftp/path'
dst_path = '/some/local/path'
try:
transport = paramiko.Transport((SFTP_HOST, SFTP_PORT))
transport.set_log_channel('delapi')
transport.connect(username=SFTP_USER, password=SFTP_PASS)
sftp = paramiko.SFTPClient.from_transport(transport)
with sftp.open(sftp_path, 'r') as remote:
with open(dst_path, 'w') as local:
for line in remote:
local.write(line)
except SSHException:
print("SSH error")
finally:
if sftp:
sftp.close()
if transport:
transport.close()

I suggest you fire up Wireshark on the client and see what's happening at the protocol level. You won't be able to read the data in the packets as it will be encrypted, but you will see what's going on at the TCP/IP level and that might provide a clue.