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Pulling p tags from multiple URLs

I've struggled on this for days and not sure what the issue could be - basically, I'm trying to extract the profile box data (picture below) of each link -- going through inspector, I thought I could pull the p tags and do so.
I'm new to this and trying to understand, but here's what I have thus far:
-- a code that (somewhat) succesfully pulls the info for ONE link:
import requests
from bs4 import BeautifulSoup
# getting html
url = 'https://basketball.realgm.com/player/Darius-Adams/Summary/28720'
req = requests.get(url)
soup = BeautifulSoup(req.text, 'html.parser')
container = soup.find('div', attrs={'class', 'main-container'})
playerinfo = container.find_all('p')
print(playerinfo)
I then also have a code that pulls all of the HREF tags from multiple links:
from bs4 import BeautifulSoup
import requests
def get_links(url):
links = []
website = requests.get(url)
website_text = website.text
soup = BeautifulSoup(website_text)
for link in soup.find_all('a'):
links.append(link.get('href'))
for link in links:
print(link)
print(len(links))
get_links('https://basketball.realgm.com/dleague/players/2022')
get_links('https://basketball.realgm.com/dleague/players/2021')
get_links('https://basketball.realgm.com/dleague/players/2020')
So basically, my goal is to combine these two, and get one code that will pull all of the P tags from multiple URLs. I've been trying to do it, and I'm really not sure at all why this isn't working here:
from bs4 import BeautifulSoup
import requests
def get_profile(url):
profiles = []
req = requests.get(url)
soup = BeautifulSoup(req.text, 'html.parser')
container = soup.find('div', attrs={'class', 'main-container'})
for profile in container.find_all('a'):
profiles.append(profile.get('p'))
for profile in profiles:
print(profile)
get_profile('https://basketball.realgm.com/player/Darius-Adams/Summary/28720')
get_profile('https://basketball.realgm.com/player/Marial-Shayok/Summary/26697')
Again, I'm really new to web scraping with Python but any advice would be greatly appreciated. Ultimately, my end goal is to have a tool that can scrape this data in a clean way all at once.
(Player name, Current Team, Born, Birthplace, etc).. maybe I'm doing it entirely wrong but any guidance is welcome!

You need to combine your two scripts together and make requests for each player. Try the following approach. This searches for <td> tags that have the data-td=Player attribute:
import requests
from bs4 import BeautifulSoup
def get_links(url):
data = []
req_url = requests.get(url)
soup = BeautifulSoup(req_url.content, "html.parser")
for td in soup.find_all('td', {'data-th' : 'Player'}):
a_tag = td.a
name = a_tag.text
player_url = a_tag['href']
print(f"Getting {name}")
req_player_url = requests.get(f"https://basketball.realgm.com{player_url}")
soup_player = BeautifulSoup(req_player_url.content, "html.parser")
div_profile_box = soup_player.find("div", class_="profile-box")
row = {"Name" : name, "URL" : player_url}
for p in div_profile_box.find_all("p"):
try:
key, value = p.get_text(strip=True).split(':', 1)
row[key.strip()] = value.strip()
except: # not all entries have values
pass
data.append(row)
return data
urls = [
'https://basketball.realgm.com/dleague/players/2022',
'https://basketball.realgm.com/dleague/players/2021',
'https://basketball.realgm.com/dleague/players/2020',
]
for url in urls:
print(f"Getting: {url}")
data = get_links(url)
for entry in data:
print(entry)

Scraping links from buttons on a page

I am trying to scrape the links from the "box score" button on this page. The button is supposed to look like this
http://www.espn.com/nfl/boxscore?gameId=400874795
I tried to use this code to see if I could access the buttons but I cannot.
from bs4 import BeautifulSoup
import requests
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
advanced = url
r = requests.get(advanced)
data = r.text
soup = BeautifulSoup(data,"html.parser")
for link in soup.find_all('a'):
print link

As wpercy mentions in his comment, you can't do this using requests, as a suggestion you should use selenium together with Chromedriver/PhantomJS for handling the JavaScript:
from selenium import webdriver
from bs4 import BeautifulSoup
url = "http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2"
browser = webdriver.Chrome()
browser.get(url)
html = browser.page_source
soup = BeautifulSoup(html,'html.parser')
boxList = soup.findAll('a',{'name':'&lpos=nfl:scoreboard:boxscore'})
All score buttons's a tag have the attribute name = &lpos=nfl:scoreboard:boxscore, so we first use .findAll and now a simple list comprehension can extract each href attribute:
>>> links = [box['href'] for box in boxList]
>>> links
['/nfl/boxscore?gameId=400874795', '/nfl/boxscore?gameId=400874854', '/nfl/boxscore?gameId=400874753', '/nfl/boxscore?gameId=400874757', '/nfl/boxscore?gameId=400874772', '/nfl/boxscore?gameId=400874777', '/nfl/boxscore?gameId=400874767', '/nfl/boxscore?gameId=400874812', '/nfl/boxscore?gameId=400874761', '/nfl/boxscore?gameId=400874764', '/nfl/boxscore?gameId=400874781', '/nfl/boxscore?gameId=400874796', '/nfl/boxscore?gameId=400874750', '/nfl/boxscore?gameId=400873867', '/nfl/boxscore?gameId=400874775', '/nfl/boxscore?gameId=400874798']

here is the solution i did , and it scrapes all the link which are there on the url you have provided in your answer . you can check it out
# from BeautifulSoup import *
from bs4 import BeautifulSoup
# import requests
import urllib
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
# advanced = url
html = urllib.urlopen(url).read()
# r = requests.get(html)
# data = r.text
soup = BeautifulSoup(html)
tags = soup('a')
# for link in soup.find_all('a'):
for i,tag in enumerate(tags):
# print tag;
print i;
ans = tag.get('href',None)
print ans;
print "\n";

The answer from Gopal Chitalia didn't work for me, so I decided to post the working one (for python 3.6.5)
# from BeautifulSoup import *
from bs4 import BeautifulSoup
# import requests
import urllib
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
# advanced = url
html = urllib.request.urlopen(url)
# urlopen(url).read()
# r = requests.get(html)
# data = r.text
soup = BeautifulSoup(html)
tags = soup('a')
# for link in soup.find_all('a'):
for i,tag in enumerate(tags):
# print tag;
print (i);
ans = tag.get('href',None)
print (ans);
print ("\n");

How to extract href links from anchor tags using BeautifulSoup?

I've been trying to extract just the links corresponding to the jobs on each page. But for some reason they dont print when I execute the script. No errors occur.
for the inputs I put engineering, toronto respectively. Here is my code.
import requests
from bs4 import BeautifulSoup
import webbrowser
jobsearch = input("What type of job?: ")
location = input("What is your location: ")
url = ("https://ca.indeed.com/jobs?q=" + jobsearch + "&l=" + location)
r = requests.get(url)
rcontent = r.content
prettify = BeautifulSoup(rcontent, "html.parser")
all_job_url = []
for tag in prettify.find_all('div', {'data-tn-element':"jobTitle"}):
for links in tag.find_all('a'):
print (links['href'])

You should be looking for the anchor a tag. It looks like this:
<a class="turnstileLink" data-tn-element="jobTitle" href="/rc/clk?jk=3611ac98c0167102&fccid=459dce363200e1be" ...>Project <b>Engineer</b></a>
Call soup.find_all and iterate over the result set, extracting the links through the href attribute.
import requests
from bs4 import BeautifulSoup
# valid query, replace with something else
url = "https://ca.indeed.com/jobs?q=engineer&l=Calgary%2C+AB"
r = requests.get(url)
soup = BeautifulSoup(r.content, "html.parser")
all_job_url = []
for tag in soup.find_all('a', {'data-tn-element':"jobTitle"}):
all_job_url.append(tag['href'])

how do I create a list from a sitemap.xml file to extract the url in python?

I need to create a code to extract a word from one scrape of images.
I'll explain, from a page sitemap.xml ,my code must try in every link present in this xml file, found insiede each link if there a specific word, inside an image link.
the sitemap is adidas = http://www.adidas.it/on/demandware.static/-/Sites-adidas-IT-Library/it_IT/v/sitemap/product/adidas-IT-it-it-product.xml
this is the code i created for search the image contains the word "ZOOM" :
import requests
from bs4 import BeautifulSoup
html = requests.get(
'http://www.adidas.it/scarpe-superstar/C77124.html').text
bs = BeautifulSoup(html)
possible_links = bs.find_all('img')
for link in possible_links:
if link.has_attr('src'):
if link.has_key('src'):
if 'zoom' in link['src']:
print link['src']
but im search a metod to scrape a list in automatic
thankyou so much
i try to do this for have list :
from bs4 import BeautifulSoup
import requests
url = "http://www.adidas.it/on/demandware.static/-/Sites-adidas-IT-Library/it_IT/v/sitemap/product/adidas-IT-it-it-product.xml"
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data)
for url in soup.findAll("loc"):
print url.text
but i cant to attach request..
i can find the word "Zoom" in any link present in sitemap.xml
thankyou so much

import requests
from bs4 import BeautifulSoup
import re
def make_soup(url):
r = requests.get(url)
soup = BeautifulSoup(r.text, 'lxml')
return soup
# put urls in a list
def get_xml_urls(soup):
urls = [loc.string for loc in soup.find_all('loc')]
return urls
# get the img urls
def get_src_contain_str(soup, string):
srcs = [img['src']for img in soup.find_all('img', src=re.compile(string))]
return srcs
if __name__ == '__main__':
xml = 'http://www.adidas.it/on/demandware.static/-/Sites-adidas-IT-Library/it_IT/v/sitemap/product/adidas-IT-it-it-product.xml'
soup = make_soup(xml)
urls = get_xml_urls(soup)
# loop through the urls
for url in urls:
url_soup = make_soup(url)
srcs = get_src_contain_str(url_soup, 'zoom')
print(srcs)

Web crawler - following links

Please bear with me. I am quite new at Python - but having a lot of fun. I am trying to code a web crawler that crawls through election results from the last referendum in Denmark. I have managed to extract all the relevant links from the main page. And now I want Python to follow each of the 92 links and gather 9 pieces of information from each of those pages. But I am so stuck. Hope you can give me a hint.
Here is my code:
import requests
import urllib2
from bs4 import BeautifulSoup
# This is the original url http://www.kmdvalg.dk/
soup = BeautifulSoup(urllib2.urlopen('http://www.kmdvalg.dk/').read())
my_list = []
all_links = soup.find_all("a")
for link in all_links:
link2 = link["href"]
my_list.append(link2)
for i in my_list[1:93]:
print i
# The output shows all the links that I would like to follow and gather information from. How do I do that?

Here is my solution using lxml. It's similar to BeautifulSoup
import lxml
from lxml import html
import requests
page = requests.get('http://www.kmdvalg.dk/main')
tree = html.fromstring(page.content)
my_list = tree.xpath('//div[#class="LetterGroup"]//a/#href') # grab all link
print 'Length of all links = ', len(my_list)
my_list is a list consist of all links. And now you can use for loop to scrape information inside each page.
We can for loop through each links. Inside each page, you can extract information as example. This is only for the top table.
table_information = []
for t in my_list:
page_detail = requests.get(t)
tree = html.fromstring(page_detail.content)
table_key = tree.xpath('//td[#class="statusHeader"]/text()')
table_value = tree.xpath('//td[#class="statusText"]/text()') + tree.xpath('//td[#class="statusText"]/a/text()')
table_information.append(zip([t]*len(table_key), table_key, table_value))
For table below the page,
table_information_below = []
for t in my_list:
page_detail = requests.get(t)
tree = html.fromstring(page_detail.content)
l1 = tree.xpath('//tr[#class="tableRowPrimary"]/td[#class="StemmerNu"]/text()')
l2 = tree.xpath('//tr[#class="tableRowSecondary"]/td[#class="StemmerNu"]/text()')
table_information_below.append([t]+l1+l2)
Hope this help!

A simple approach would be to iterate through your list of urls and parse them each individually:
for url in my_list:
soup = BeautifulSoup(urllib2.urlopen(url).read())
# then parse each page individually here
Alternatively, you could speed things up significantly using Futures.
from requests_futures.sessions import FuturesSession
def my_parse_function(html):
"""Use this function to parse each page"""
soup = BeautifulSoup(html)
all_paragraphs = soup.find_all('p')
return all_paragraphs
session = FuturesSession(max_workers=5)
futures = [session.get(url) for url in my_list]
page_results = [my_parse_function(future.result()) for future in results]

This would be my solution for your problem
import requests
from bs4 import BeautifulSoup
def spider():
url = "http://www.kmdvalg.dk/main"
source_code = requests.get(url)
plain_text = source_code.text
soup = BeautifulSoup(plain_text, 'html.parser')
for link in soup.findAll('div', {'class': 'LetterGroup'}):
anc = link.find('a')
href = anc.get('href')
print(anc.getText())
print(href)
# spider2(href) call a second function from here that is similar to this one(making url = to herf)
spider2(href)
print("\n")
def spider2(linktofollow):
url = linktofollow
source_code = requests.get(url)
plain_text = source_code.text
soup = BeautifulSoup(plain_text, 'html.parser')
for link in soup.findAll('tr', {'class': 'tableRowPrimary'}):
anc = link.find('td')
print(anc.getText())
print("\n")
spider()
its not done... i only get a simple element from the table but you get the idea and how its supposed to work.

Here is my final code that works smooth. Please let me know if I could have done it smarter!
import urllib2
from bs4 import BeautifulSoup
import codecs
f = codecs.open("eu2015valg.txt", "w", encoding="iso-8859-1")
soup = BeautifulSoup(urllib2.urlopen('http://www.kmdvalg.dk/').read())
liste = []
alle_links = soup.find_all("a")
for link in alle_links:
link2 = link["href"]
liste.append(link2)
for url in liste[1:93]:
soup = BeautifulSoup(urllib2.urlopen(url).read().decode('iso-8859-1'))
tds = soup.findAll('td')
stemmernu = soup.findAll('td', class_='StemmerNu')
print >> f, tds[5].string,";",tds[12].string,";",tds[14].string,";",tds[16].string,";", stemmernu[0].string,";",stemmernu[1].string,";",stemmernu[2].string,";",stemmernu[3].string,";",stemmernu[6].string,";",stemmernu[8].string,";",'\r\n'
f.close()