Scraping data from website graph with Python - python

As an exercise, I am trying to scrape data from a dynamic graph using Python. The graph can be found at this link (let's say I want the data from the first one).
Now, I was thinking of doing something like:
src = 'https://marketchameleon.com/Overview/WFT/IV/#_ABSTRACT_RENDERER_ID_11'
import json
import urllib.request
with urllib.request.urlopen(src) as url:
data = url.read()
reply = json.loads(data)
However, I receive an error message on the last line of the code, saying:
JSONDecodeError: Expecting value
"data" is not empty, so I believe there is a problem with the format of the information within it. Does someone have an idea to solve this issue? Thanks!

I opened that link and see that the site loads data from another URL - https://marketchameleon.com/charts/histStockChartData?p=747&m=12&_=1534060722519
You can use json.loads() function twice and do some hacks with headers (urllib2.Request is your friend in case of Python 2) since server returns HTTP 500 when you don't imitate browser
src = 'https://marketchameleon.com/charts/histStockChartData?p=747&m=12'
import json
import urllib.request
user_agent = {
'Host': 'marketchameleon.com',
'Connection': 'keep-alive',
'Pragma': 'no-cache',
'Cache-Control': 'no-cache',
'Upgrade-Insecure-Requests': 1,
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Language': 'ru-RU,ru;q=0.9,en-US;q=0.8,en;q=0.7,kk;q=0.6'
}
request = urllib.request.Request(src, headers=user_agent)
data = urllib.request.urlopen(request).read()
print(data)
reply = json.loads(data)
table = json.loads(reply['GTable'])
print(table)

Related

BeautifulSoup find_all not finding all containers of a class

I'm trying to write a script to scrape some data off a Zillow page (https://www.zillow.com/homes/for_rent/38.358484,-77.27869,38.218627,-77.498417_rect/X1-SSc26hnbsm6l2u1000000000_8e08t_sse/). Obviously I'm just trying to gather data from every listing. However I cannot grab the data from every listing as it only finds 9 instances of the class I'm searching for ('list-card-addr') even though I've checked the html from listings it does not find and the class exists. Anyone have any ideas for why this is? Here's my simple code
from bs4 import BeautifulSoup
import requests
req_headers = {
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.8',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}
url="https://www.zillow.com/homes/for_rent/38.358484,-77.27869,38.218627,-77.498417_rect/X1-SSc26hnbsm6l2u1000000000_8e08t_sse/"
response = requests.get(url, headers=req_headers)
data = response.text
soup = BeautifulSoup(data,'html.parser')
address = soup.find_all(class_='list-card-addr')
print(len(address))
Data is stored within a comment. You can regex it out easily as string defining JavaScript object you can handle with json
import requests, re, json
r = requests.get('https://www.zillow.com/homes/for_rent/?searchQueryState=%7B%22pagination%22%3A%7B%7D%2C%22savedSearchEnrollmentId%22%3A%22X1-SSc26hnbsm6l2u1000000000_8e08t%22%2C%22mapBounds%22%3A%7B%22west%22%3A-77.65840518457031%2C%22east%22%3A-77.11870181542969%2C%22south%22%3A38.13250414385234%2C%22north%22%3A38.444339281260426%7D%2C%22isMapVisible%22%3Afalse%2C%22filterState%22%3A%7B%22sort%22%3A%7B%22value%22%3A%22mostrecentchange%22%7D%2C%22fsba%22%3A%7B%22value%22%3Afalse%7D%2C%22fsbo%22%3A%7B%22value%22%3Afalse%7D%2C%22nc%22%3A%7B%22value%22%3Afalse%7D%2C%22fore%22%3A%7B%22value%22%3Afalse%7D%2C%22cmsn%22%3A%7B%22value%22%3Afalse%7D%2C%22auc%22%3A%7B%22value%22%3Afalse%7D%2C%22fr%22%3A%7B%22value%22%3Atrue%7D%2C%22ah%22%3A%7B%22value%22%3Atrue%7D%7D%2C%22isListVisible%22%3Atrue%2C%22mapZoom%22%3A11%7D',
headers = {'User-Agent':'Mozilla/5.0'})
data = json.loads(re.search(r'!--(\{"queryState".*?)-->', r.text).group(1))
print(data['cat1'])
print(data['cat1']['searchList'].keys())
Within this are details on pagination and the next url, if applicable, to get all results. You have only asked for page 1 here.
For example, print addresses
for i in data['cat1']['searchResults']['listResults']:
print(i['address'])

Workaround for blocked GET requests in Python

I'm trying to retrieve and process the results of a web search using requests and beautifulsoup.
I've written some simple code to do the job, and it returns successfully (status = 200), but the content of the request is just an error message "We're sorry for any inconvenience, but the site is currently unavailable.", and has been the same for the last several days. Searching within Firefox returns results without issue, however. I've run the code using a URL for the UK-based site and it works without issue so I wonder if the US site is set up to block attempts to scrape web searches.
Are there ways to mask the fact I'm attempting to retrieve search results from within Python (eg, masquerading as a standard search within Firefox) or some other work around to allow access to the search results?
Code included for reference below:
import pandas as pd
from requests import get
import bs4 as bs
import re
# works
# baseURL = 'https://www.autotrader.co.uk/car-search?sort=sponsored&radius=1500&postcode=ky119sb&onesearchad=Used&onesearchad=Nearly%20New&onesearchad=New&make=TOYOTA&model=VERSO&year-from=1990&year-to=2017&minimum-mileage=0&maximum-mileage=200000&body-type=MPV&fuel-type=Diesel&minimum-badge-engine-size=1.6&maximum-badge-engine-size=4.5&maximum-seats=8'
# doesn't work
baseURL = 'https://www.autotrader.com/cars-for-sale/Certified+Cars/cars+under+50000/Jeep/Grand+Cherokee/Seattle+WA-98101?extColorsSimple=BURGUNDY%2CRED%2CWHITE&maxMileage=45000&makeCodeList=JEEP&listingTypes=CERTIFIED%2CUSED&interiorColorsSimple=BEIGE%2CBROWN%2CBURGUNDY%2CTAN&searchRadius=0&modelCodeList=JEEPGRAND&trimCodeList=JEEPGRAND%7CSRT%2CJEEPGRAND%7CSRT8&zip=98101&maxPrice=50000&startYear=2015&marketExtension=true&sortBy=derivedpriceDESC&numRecords=25&firstRecord=0'
a = get(baseURL)
soup = bs.BeautifulSoup(a.content,'html.parser')
info = soup.find_all('div', class_ = 'information-container')
price = soup.find_all('div', class_ = 'vehicle-price')
d = []
for idx, i in enumerate(info):
ii = i.find_next('ul').find_all('li')
year_ = ii[0].text
miles = re.sub("[^0-9\.]", "", ii[2].text)
engine = ii[3].text
hp = re.sub("[^\d\.]", "", ii[4].text)
p = re.sub("[^\d\.]", "", price[idx].text)
d.append([year_, miles, engine, hp, p])
df = pd.DataFrame(d, columns=['year','miles','engine','hp','price'])
By default, Requests sends a unique user agent when making requests.
>>> r = requests.get('https://google.com')
>>> r.request.headers
{'User-Agent': 'python-requests/2.22.0', 'Accept-Encoding': 'gzip, deflate', 'Accept': '*/*', 'Connection': 'keep-alive'}
It is possible that the website you are using is trying to avoid scrapers by denying any request with a user agent of python-requests.
To get around this, you can change your user agent when sending a request. Since it's working on your browser, simply copy your browser user agent (you can Google it, or record a request to a webpage and copy your user agent like that). For me, it's Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.142 Safari/537.36 (what a mouthful), so I'd set my user agent like this:
>>> headers = {
... 'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.142 Safari/537.36'
... }
and then send the request with the new headers (the new headers are added to the default headers, they don't replace them unless they have the same name):
>>> r = requests.get('https://google.com', headers=headers) # Using the custom headers we defined above
>>> r.request.headers
{'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.142 Safari/537.36', 'Accept-Encoding': 'gzip, deflate', 'Accept': '*/*', 'Connection': 'keep-alive'}
Now we can see that the request was sent with our preferred headers, and hopefully the site won't be able to tell the difference between Requests and a browser.

How to get right JSON responce from POST request from PYTHON script

Task is to get JSON responce from POST request from particular website.
Everything works fine in browser as follows. You may simulate the case yourself tryin to start enter text into Start Location field.
webaddress to check: https://www.hapag-lloyd.com/en/online-business/schedules/interactive-schedule.html
Chrome Dev Tool Screen 1 - Request URL and Header
Chrome Dev Tool Screen 2 - POST data
JSON RESPONCE (it must be like this)
{"rows":[{"LOCATION_COUNTRYABBREV":"GE","LOCATION_BUSINESSPOSTALCODE":"","LOCATION_BUSINESSLOCATIONNAME":"BATUMI","LOCATION_BUSINESSLOCODE":"GEBUS","STANDARDLOCATION_BUSINESSLOCODE":"GEBUS","LOCATION_PORTTYPE":"S","DISPLAYNAME":""}]}
My code as follows:
import requests
url = 'https://www.hapag-lloyd.com/en/online-business/schedules/interactive-schedule.html?_sschedules_interactive=_raction&action=getTypeAheadService'
POST_QUERY = 'batumi'
params = {
'query': POST_QUERY,
'reportname': 'FRTA0101',
'callConfiguration': "[resultLines=10,readDef1=location_businessLocationName STARTSWITH,readDef2=location_businessLocode STARTSWITH,readClause1=location_businessLocode<>'' AND location_portType='S' AND stdSubLocation_string10='STD',readClause2=location_businessLocode<>'' AND location_portType<>'S' AND stdSubLocation_string10='STD',readClause3=location_businessLocode<>'' AND location_portType='S' AND stdSubLocation_string10='SUB',readClause4=location_businessLocode<>'' AND stdSubLocation_string10='SUB',readClause5=location_businessLocode='' AND stdSubLocation_string10='SUB',sortDef1=location_businessLocationName ASC,resultAttr1=location_businessLocationName,resultAttr2=location_businessLocode,resultAttr3=location_businessPostalCode,resultAttr4=standardLocation_businessLocode,resultAttr5=location_countryAbbrev,resultAttr6=location_portType]"
}
headers = {
"Accept": "*/*",
'Accept-Encoding': 'gzip, deflate',
'Accept-Language': 'en-EN,en;q=0.9,en-US;q=0.8,en;q=0.7',
'Cache-Control': 'no-cache',
'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
'DNT': '1',
'Host': 'www.hapag-lloyd.com',
'Origin': 'https://www.hapag-lloyd.com',
'Pragma': 'no-cache',
# 'Proxy-Connection': 'keep-alive',
'Referer': 'https://www.hapag-lloyd.com/en/online-business/schedules/interactive-schedule.html',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36'
}
print('Testing location: ', POST_QUERY)
var_cities = requests.post(url,data=params,headers=headers)
print(var_cities.content) #it does print some %$#%$
Python Print Content Screen
My question is "How to get right JSON responce from POST request from PYTHON script"?
I think using BeautifulSoup is a better option.
Try this
Python Convert HTML into JSON using Soup
print(var_cities.text)
This returns the html as string. Is this what you expected to get as a response? And to convert this into json, look at the answer above...

How to obtain a JSON response from the stats.nba.com API?

I'm just trying to simply use a Python get request to access JSON data from stats.nba.com. It seems pretty straight-forward as I can enter the URL into your browser and get the results I'm looking for. However, whenever I run this the program just runs to no end. I'm wondering if I have to include some type of headers information in my get request.
The code is below:
import requests
url = 'http://stats.nba.com/stats/commonteamroster?LeagueID=00&Season=2017-18&TeamID=1610612756'
response=requests.get(url)
print response.text
I have tried to visit the url you given, you can add header to your request to avoid this problem (the minimum information you need to provide is User-Agent, I think you can use more header information as you can):
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'}
response = requests.get(url, headers=headers)
The stats.nba.com website need your 'User-Agent' header information.
You can get your request header information from Network tab in the browser.
Take chrome as example, when you press F12, and visit url you given, you can find the relative request information, the most useful information is request headers.
You need to use headers. Try copying from your browser's network tab. Here's what worked for me:
request_headers = {
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Encoding': 'gzip, deflate',
'Accept-Language': 'en-US,en;q=0.8',
'Connection': 'keep-alive',
'Host': 'stats.nba.com',
'Upgrade-Insecure-Requests': '1',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}
And here's the modified get:
response = requests.get(url, headers = request_headers)

Retrieve the Request Headers from a page

Is there a possible way to retrieve the content of request header from a page such as this:
Accept:*/*
Accept-Encoding:gzip, deflate, br
Accept-Language:en-US,en;q=0.8,id;q=0.6
Connection:keep-alive
Cookie:SPC_IA=-1; SPC_EC=-; SPC_F=oTIBQWRUjdH7sWSqJu1UBBA1o3zy5j1C; REC_T_ID=9af9f032-8d77-11e7-b124-1866da5681e2; SPC_T_ID="VkC0m8L3ZwixZk8y836Lhq4XucdTWJQtxOT+CCjn+u7HhYZ0zEcK/BI8L3dT2/em76AgwKj3p9ysfh7yUnOrq9CqS4lRPFaqLTpEuecgX8U="; SPC_U=-; SPC_T_IV="PA3yjLFENXXf8Tzq685zSg=="; csrftoken=SiNmh7GZo00aZ3a0gxIqEaNjB38zhCQI; bannerShown=true; django_language=id; sessionid=15fgkr8ohrult2zkmgu2xyiwwnm4ejcx; SPC_SC_TK=; UYOMAPJWEMDGJ=; SPC_SC_UD=; SPC_SI=i94582s7ffe99b47y3qomp1siqy4adz5
Host:shopee.co.id
If-None-Match:"75c23fc0e3e55d18c21158ab8a335ab4;gzip"
If-None-Match-:55b03-c56af1c195a559f1680c15f63d56f07a
Referer:https://shopee.co.id/SHARP-LED-TV-24INCH-LC24LE175ITT_sby-Area-Surabaya-i.24413460.298360054
User-Agent:Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36
X-API-SOURCE:pc
X-Requested-With:XMLHttpRequest
I want to store the value of "If-None-Match-: xxxx" in my code without having to manually do it, so for every page I open using the for loop that I have in my code, every page's "If-None-Match-: xxxx" value is saved as a variable.
I tried using
r = requests.get(url)
r.headers
But it only prints out the HTTP response header.
I was wondering if there's a way.
For getting the header of client side request header you need to get re.request.headers
import requests
res = requests.request('GET', "https://www.google.com")
print res.request.headers
Output
{'Connection': 'keep-alive', 'Accept-Encoding': 'gzip, deflate', 'Accept': '*/*', 'User-Agent': 'python-requests/2.13.0'}

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