We Keep Coding

Python list iterate not working as expected

I have a file called list.txt:
['d1','d2','d3']
I want to loop through all the items in the list. Here is the code:
deviceList = open("list.txt", "r")
deviceList = deviceList.read()
for i in deviceList:
print(i)
Here the issue is that, when I run the code, it will split all the characters:
% python3 run.py
[
'
d
1
'
,
'
d
2
'
,
'
d
3
'
]
It's like all the items have been considered as 1 string? I think needs to be parsed? Please let me know what am I missing..

Simply because you do not have a list, you are reading a pure text...
I suggest writing the list without the [] so you can use the split() function.
Write the file like this: d1;d2;d3
and use this script to obtain a list
f = open("filename", 'r')
line = f.readlines()
f.close()
list = line.split(";")
if you need the [] in the file, simply add a strip() function like this
f = open("filename", 'r')
line = f.readlines()
f.close()
strip = line.strip("[]")
list = strip.split(";")
should work the same

This isn't the cleanest solution, but it will do if your .txt file is always just in the "[x,y,z]" format.
deviceList = open("list.txt", "r")
deviceList = deviceList[1:-1]
deviceList = deviceList.split(",")
for i in deviceList:
print(i)
This takes your string, strips the "[" and "]", and then separates the entire string between the commas and turns that into a list. As other users have suggested, there are probably better ways to store this list than a text file as it is, but this solution will do exactly what you are asking. Hope this helps!

python open csv search for pattern and strip everything else

I got a csv file 'svclist.csv' which contains a single column list as follows:
pf=/usr/sap/PL5/SYS/profile/PL5_D00_s4prd1
pf=/usr/sap/PL5/SYS/profile/PL5_ASCS01_s4prdascs
I need to strip each line from everything except the PL5 directoy and the 2 numbers in the last directory
and should look like that
PL5,00
PL5,01
I started the code as follow:
clean_data = []
with open('svclist.csv', 'rt') as f:
for line in f:
if line.__contains__('profile'):
print(line, end='')
and I'm stuck here.
Thanks in advance for the help.

you can use the regular expression - (PL5)[^/].{0,}([0-9]{2,2})
For explanation, just copy the regex and paste it here - 'https://regexr.com'. This will explain how the regex is working and you can make the required changes.
import re
test_string_list = ['pf=/usr/sap/PL5/SYS/profile/PL5_D00_s4prd1',
'pf=/usr/sap/PL5/SYS/profile/PL5_ASCS01_s4prdascs']
regex = re.compile("(PL5)[^/].{0,}([0-9]{2,2})")
result = []
for test_string in test_string_list:
matchArray = regex.findall(test_string)
result.append(matchArray[0])
with open('outfile.txt', 'w') as f:
for row in result:
f.write(f'{str(row)[1:-1]}\n')
In the above code, I've created one empty list to hold the tuples. Then, I'm writing to the file. I need to remove the () at the start and end. This can be done via str(row)[1:-1] this will slice the string.
Then, I'm using formatted string to write content into 'outfile.csv'

You can use regex for this, (in general, when trying to extract a pattern this might be a good option)
import re
pattern = r"pf=/usr/sap/PL5/SYS/profile/PL5_.*(\d{2})"
with open('svclist.csv', 'rt') as f:
for line in f:
if 'profile' in line:
last_two_numbers = pattern.findall(line)[0]
print(f'PL5,{last_two_numbers}')
This code goes over each line, checks if "profile" is in the line (this is the same as _contains_), then extracts the last two digits according to the pattern

I made the assumption that the number is always between the two underscores. You could run something similar to this within your for-loop.
test_str = "pf=/usr/sap/PL5/SYS/profile/PL5_D00_s4prd1"
test_list = test_str.split("_") # splits the string at the underscores
output = test_list[1].strip(
"abcdefghijklmnopqrstuvwxyz" + str.swapcase("abcdefghijklmnopqrstuvwxyz")) # removing any character
try:
int(output) # testing if the any special characters are left
print(f"PL5, {output}")
except ValueError:
print(f'Something went wrong! Output is PL5,{output}')

Find and Remove function call with brackets

I'm working on a python script that will allow me to remove some attributes from a function call in a Java class. The problem is I can't find the right regex to include both the name of the attribute and the brackets.
The string I'm looking to remove is, as an example, 'withContentDescription("random text")'
What is the correct way to include the () brackets and the random content of those within my code?
import re
filein = '/path/file.java'
fileout = '/path/newfile.java'
f = open(filein,'r')
filedata = f.read()
f.close()
print("Removing Content Descriptor")
newdata = filedata.strip("withContentDescription\)")
f = open(fileout,'w')
f.write(newdata)
print("--- Done")
f.close()
I'd like to obtain something like
old string: allOf(withId(someinfo), withContentDescription("Text"))
new string: allOf(withId(someinfo))

Using re.sub
Ex:
import re
s = 'allOf(withId(someinfo), withContentDescription("Text"))'
print(re.sub(r",\s*(withContentDescription\(.*?\))", "", s))
Output:
allOf(withId(someinfo))

Python compare two files using a list

Im trying to compare two files via regex strings and print the output. I seem to have an issue with my loop as only the last line gets printed out. What am I missing ?
import re
delist = [r'"age":.*",',r'"average":.*",',r'"class":.*",']
with open('test1.txt', 'r') as bolo:
boloman = bolo.read()
for dabo in delist:
venga = re.findall(dabo, boloman)
for vaga in venga:
with open ('test.txt', 'r' ) as f:
content = f.read()
venga2 = re.findall(dabo, content)
for vaga2 in venga2:
mboa = content.replace(vaga2,vaga,1)
print (mboa)

At first, a problem I see is that you are always setting mboa with the only result. I think what you really want to do is to create a list and append it to that list.
import re
mboa = []
delist = [r'"age":.*",',r'"average":.*",',r'"class":.*",']
with open('test1.txt', 'r') as bolo:
boloman = bolo.read()
for dabo in delist:
venga = re.findall(dabo, boloman)
for vaga in venga:
with open ('test.txt', 'r' ) as f:
content = f.read()
venga2 = re.findall(dabo, content)
for vaga2 in venga2:
mboa.append(content.replace(vaga2,vaga,1))
print (mboa)
does that solve the issue? if it doesn't add a comment to this question and I'll try to fix it out ;)

Python: replace a string in a CSV file

I am a beginner and I have an issue with a short code. I want to replace a string from a csv to with another string, and put out a new
csv with an new name. The strings are separated with commas.
My code is a catastrophe:
import csv
f = open('C:\\User\\Desktop\\Replace_Test\\Testreplace.csv')
csv_f = csv.reader(f)
g = open('C:\\Users\\Desktop\\Replace_Test\\Testreplace.csv')
csv_g = csv.writer(g)
findlist = ['The String, that should replaced']
replacelist = ['The string that should replace the old striong']
#the function ?:
def findReplace(find,replace):
s = f.read()
for item, replacement in zip(findlist,replacelist):
s = s.replace(item,replacement)
g.write(s)
for row in csv_f:
print(row)
f.close()
g.close()

You can do this with the regex package re. Also, if you use with you don't have to remember to close your files, which helps me.
EDIT: Keep in mind that this matches the exact string, meaning it's also case-sensitive. If you don't want that then you probably need to use an actual regex to find the strings that need replacing. You would do this by replacing find_str in the re.sub() call with r'your_regex_here'.
import re
# open your csv and read as a text string
with open(my_csv_path, 'r') as f:
my_csv_text = f.read()
find_str = 'The String, that should replaced'
replace_str = 'The string that should replace the old striong'
# substitute
new_csv_str = re.sub(find_str, replace_str, my_csv_text)
# open new file and save
new_csv_path = './my_new_csv.csv' # or whatever path and name you want
with open(new_csv_path, 'w') as f:
f.write(new_csv_str)