I am trying to copy elements of a doc from one doc file to other. The text part is easy, the images is where it gets tricky.
Attaching an image to explain the structure of the doc: Just some text and 1 image.
from docx import Document
import io
doc = Document('/Users/neha/Desktop/testing.docx')
new_doc = Document()
for elem in doc.element.body:
new_doc.element.body.append(elem)
new_doc.save('/Users/neha/Desktop/out.docx')
This gets me the whole structure of the doc in the new_doc but the image is still blank. Image below:
Good thing is I have the blank image in the right place so I thought of getting the byte level data from the previous image and insert it in the new doc. Here is how I extended the above code:
from docx import Document
import io
doc = Document('/Users/neha/Desktop/testing.docx')
new_doc = Document()
for elem in doc.element.body:
new_doc.element.body.append(elem)
im = doc.inline_shapes[0]
blip = im._inline.graphic.graphicData.pic.blipFill.blip
rId = blip.embed
doc_part = doc.part
image_part = doc_part.related_parts[rId]
bytes = image_part._blob #Here I get the byte level data for the image
im2 = new_doc.inline_shapes[0]
blip2 = im2._inline.graphic.graphicData.pic.blipFill.blip
rId2 = blip2.embed
document_part2 = new_doc.part
document_part2.related_parts[rId2]._blob = bytes
new_doc.save('/Users/neha/Desktop/out.docx')
But the image still shows empty in the new_doc. What should I do from here?
I figured out a solution a couple of days back. However the text loses formatting using this way, but the images are correctly placed.
So the idea is, for para in paras for the source doc, if there is text, I write it to dest doc. And if there is an inline image present, I add a unique identifier at that place in the dest doc (refer here to see how these identifiers work, and contexts in docxtpl). These identifiers and docxtpl proved to be particularly useful here. And then using those unique identifiers I create a 'context' (as shown below) which is basically a map mapping the unique identifier to its particular InlineImage, and finally I render this context..
Below is my code (Apologies for the unnecessary indentation, I copied it directly from my text editor, and shift+tab doesn't work here :P)
from docxtpl import DocxTemplate, InlineImage
import Document
import io
import xml.etree.ElementTree as ET
dest = DocxTemplate()
source = Document(source_path)
context = {}
ims = [im for im in source.inline_shapes]
im_addresses = []
im_streams = []
count = 0
for im in ims:
blip = im._inline.graphic.graphicData.pic.blipFill.blip
rId = blip.embed
doc_part = source.part
image_part = doc_part.related_parts[rId]
byte_data = image_part._blob
image_stream = io.BytesIO(byte_data)
im_streams.append(image_stream)
image_name = self.img_path+"img_"+"_"+str(count)+".jpeg"
with open(image_name, "wb") as fh:
fh.write(byte_data)
fh.close()
im_addresses.append(image_name)
count += 1
paras = source.paragraphs
im_idx = 0
for para in paras:
p = dest.add_paragraph()
r = p.add_run()
if(para.text):
r.add_text(para.text)
root = ET.fromstring(para._p.xml)
namespace = {'wp':"http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing"}
inlines = root.findall('.//wp:inline',namespace)
if(len(inlines) > 0):
uid = "img_"+str(im_idx)
r.add_text("{{ " + uid + " }}")
context[uid] = InlineImage(dest,im_addresses[im_idx])
im_idx += 1
try:
dest.render(context)
except Exception as e:
print(e)
dest.save(dest_path)
PS: If a paragraph has two images, this code will prove to be sub-optimal.. One will have to make some change in the following:
if(len(inlines) > 0):
uid = "img_"+str(im_idx)
r.add_text("{{ " + uid + " }}")
context[uid] = InlineImage(dest,im_addresses[im_idx])
im_idx += 1
Will have to add a for loop inside the if statement as well. Since I didn't need as usually my images were big enough, so they always came in different paragraphs. Just a side note for anyone who may need it..
Cheers!
You could try:
Extracting the images from the first document by unzipping the .docx file (per How can I search a word in a Word 2007 .docx file?)
Save those images to the file system (as foo.png, for instance)
Generate the new .docx file with Python and add the .png file using document.add_picture('foo.png').
This problem is solved by this package https://docxtpl.readthedocs.io/en/latest/
Related
I'm having a hard time trying to access/save images using the python-pptx library. So, if the image is of shape type PICTURE (that's shape.shape_type == MSO_SHAPE_TYPE.PICTURE) I can access/save the image easily using the 'blob' attribute. Here is the code:
import argparse
import os
from PIL import Image
import pptx
from pptx.enum.shapes import MSO_SHAPE_TYPE
from pptx import Presentation
from mdutils.mdutils import MdUtils
from mdutils import Html
def main():
parser = argparse.ArgumentParser()
parser.add_argument('ppt_name', type=str, help='add the name of the PowerPoint file(NOTE: the folder must be in the same directory as the prorgram file')
args = parser.parse_args()
pptx_name = args.ppt_name
pptx_name_formatted = pptx_name.split('.')[0]
prs = Presentation(pptx_name)
path = '{}_converted'.format(pptx_name_formatted)
if not os.path.exists(path):
os.mkdir(path)
images_folder = '{}_images'.format(pptx_name_formatted)
images_path = os.path.join(path, images_folder)
if not os.path.exists(images_path):
os.mkdir(images_path)
ppt_dict = {} #Keys: slide numbers, values: slide content
texts = []
slide_count = 0
picture_count = 0
for slide in prs.slides:
texts = []
slide_count += 1
for shape in slide.shapes:
if shape.has_text_frame:
if '\n' in shape.text:
splitted = shape.text.split('\n')
for word in splitted:
if word != '':
texts.append(word)
elif shape.text == '':
continue
else:
texts.append(shape.text)
elif shape.shape_type == MSO_SHAPE_TYPE.PICTURE:
with open('{}/image{}_slide{}.png'.format(images_path, picture_count, slide_count), 'wb') as f:
f.write(shape.image.blob)
picture_count += 1
ppt_dict[slide_count] = texts
ppt_content = ''
for k,v in ppt_dict.items():
ppt_content = ppt_content + ' - Slide number {}\n'.format(k)
for a in v:
ppt_content = ppt_content + '\t - {}\n'.format(a)
mdFile = MdUtils(file_name='{}/{}'.format(path,path)) #second argument isn't path, it just shares the path name.
mdFile.write(ppt_content)
mdFile.create_md_file()
if __name__ == "__main__":
main()
The problem is when the picture is of shape type 'auto shape' , I tried a lot of approaches but to no avail. When I do run the following code for a shape that I know is a picture:
if shape.shape_type == MSO_SHAPE_TYPE.AUTO_SHAPE:
print(shape.auto_shape_type)
print(shape.fill.type)
#indented because it's in a for loop
It outputs RECTANGLE for shape.auto_shape_type
and PICTURE for shape.fill.type
But what I want now is to save the picture (maybe by writing the the binary image bytestream of the image). Can someone help?
The "link" to the image (part, having the blob) is in the fill definition. Using that you can get to the image.
Print out the XML for the surroundings of the fill definition with shape.fill._xPr.xml. That will give you a look at what you need to navigate to. Good chance it will look something like "rId9" with some particular other number where the "9" placeholder is in that example. Probably in the neighborhood of something like "blipfill". The image is used as the "fill" of the shape, so that's what's going on here.
Then get the slide part with something like slide._part and use its .related_parts "dict" to look up the image "fill" part using the relationship-id (the string like "rId9").
image_part = slide._part.related_parts["rId9"]
The ImagePart implementation is here:
https://github.com/scanny/python-pptx/blob/master/pptx/parts/image.py#L21
and it gives access to the image and a lot of details about it as well.
You'll have to retrieve the "rId9"-like string using lxml calls, something roughly like:
rIds = shape.fill._xPr.xpath(".//#embed")
rId = rIds[0]
You'll need to do a little research on XPath to work out the right expression, based on the XML you print out in the earlier step. There's a lot out there on XPath, including here on SO, this is one resource to get started: http://www.rpbourret.com/xml/XPathIn5.htm
If you can't work it out, post the XML you printed out and we can get you to the next step.
Here is my approach, thanks to scanny.
for slide in prs.slides:
slide_count += 1
slide_parts = list(slide._part.related_parts.keys())
for part in slide_parts:
image_part = slide._part.related_parts[part]
if type(image_part) == pptx.parts.image.ImagePart or pptx.opc.package.Part:
file_startswith = image_part.blob[0:1]
if file_startswith == b'\x89' or file_startswith == b'\xff' or file_startswith == b'\x47':
with open('{}/image{}_slide{}.png'.format(images_path, picture_count, slide_count), 'wb') as f:
f.write(image_part.blob)
picture_count += 1
the if condition to check for PNG, JPEG or GIF is there because pptx.opc.package.Part isn't always an image.
Actually, I think since I'm checking for the beginning of image_part.blob, I don't think I need to include say if type(image_part) == pptx.parts.image.ImagePart or pptx.opc.package.Part:
But as long as it's working...
I'd like to use PyMuPDF : I'd like to split a pdf, with for each splitted file, a file named with the name of the bookmark, with only page
I've succefully my files, for exemple 4 PDF files for a 4 pages PDF source.... but in the several pdf, I don't have one page but with a random number of page ?
import sys, fitz
file = '/home/ilyes/Bulletins_Originaux.pdf'
bookmark = ''
try:
doc = fitz.open(file)
toc = doc.getToC(simple = True)
except Exception as e:
print(e)
for i in range(len(toc)):
documentPdfCible=toc[i][1]
documentPdfCibleSansSlash=documentPdfCible.replace("/","-")
numeroPage=toc[i][2]
pagedebut=numeroPage
pagefin=numeroPage + 1
print (pagedebut)
print (pagefin)
doc2 = fitz.open(file)
doc2.insertPDF(doc, from_page = pagedebut, to_page = pagefin, start_at = 0)
doc2.save('/home/ilyes/' + documentPdfCibleSansSlash + ".pdf")
doc2.close
Could you tell me what's wrong ?
Maybee because I use always "doc2" in the loop ?
Thanks you,
Abou Ilyès
Seems weird, that you open the same document twice.
You open your pdf file at doc = fitz.open(file) and again at doc2 = fitz.open(file).
Then you insert pages into the same file by doc2.insertPDF(doc, from_page = pagedebut, to_page = pagefin, start_at = 0).
Of course the doc files toc will get messed up completely by "randomly" inserting pages.
I recommend to replace doc2 = fitz.open(file) with doc2 = fitz.open()
This will create an empty "in memory" pdf (see the documentation), in which you can then insert the pages you need from doc. Then save this as a new pdf by its bookmark title by running
doc2.save('/home/ilyes/' + documentPdfCibleSansSlash + ".pdf")
I have a list of pdf files and I need to highlight specific text on each page of these files and save a snapshot for each of the text instances.
So far I am able to highlight the text and save the entire page of a pdf file as a snapshot. But, I want to find the position of highlighted text and take a zoomed in the snapshot which will be more detailed compared to the full page snapshot.
I'm pretty sure there must be a solution to this problem. I am new to Python and hence I am not able to find it. I would be really grateful if someone can help me out with this.
I have tried using PyPDF2, Pymupdf libraries but I couldn't figure out the solution. I also tried highlighting by providing coordinates which works but couldn't find a way to get these coordinates as output.
[![Sample snapshot from the code[![\]\[1\]][1]][1]][1]
#import PyPDF2
import os
import fitz
from wand.image import Image
import csv
#import re
#from pdf2image import convert_from_path
check = r'C:\Users\Pradyumna.M\Desktop\Pradyumna\Automation\Intel Bytes\Create Source Docs\Sample Check 8 Apr 2019'
dir1 = check + '\\Source Docs\\'
dir2 = check + '\\Output\\'
dir = [dir1, dir2]
for x in dir:
try:
os.mkdir(x)
except FileExistsError:
print("Directory ", x, " already exists")
### READ PDF FILE
with open('upload1.csv', newline='') as myfile:
reader = csv.reader(myfile)
for row in reader:
rowarray = '; '.join(row)
src = rowarray.split("; ")
file = check + '\\' + src[4] + '.pdf'
print(file)
#pdfFileObj = open(file,'rb')
#pdfReader = PyPDF2.PdfFileReader(pdfFileObj)
#print("Total number of pages: " + str(pdfReader.numPages))
doc = fitz.open(file)
print(src[5])
for i in range(int(src[5])-1, int(src[5])):
i = int(i)
page = doc[i]
print("Processing page: " + str(i))
text = src[3]
#SEARCH TEXT
print("Searching: " + text)
text_instances = page.searchFor(text)
for inst in text_instances:
highlight = page.addHighlightAnnot(inst)
file1 = check + '\\Output\\' + src[4] + '_output.pdf'
print(file1)
doc.save(file1, garbage=4, deflate=True, clean=True)
### Screenshot
with(Image(filename=file1, resolution=150)) as source:
images = source.sequence
newfilename = check + "\\Source Docs\\" + src[0] + '.jpeg'
Image(images[i]).save(filename=newfilename)
print("Screenshot of " + src[0] + " saved")
"couldn't find a way to get these coordinates as output"
- you can get the coordinates out by doing this:
for inst in text_instances:
print(inst)
inst are fitz.Rect objects which contain the top left and bottom right coordinates of the piece of text that was found. All the information is available in the docs.
I managed to highlight points and also save a cropped region using the following snippet of code. I am using python 3.7.1 and my output for fitz.version is ('1.14.13', '1.14.0', '20190407064320').
import fitz
doc = fitz.open("foo.pdf")
inst_counter = 0
for pi in range(doc.pageCount):
page = doc[pi]
text = "hello"
text_instances = page.searchFor(text)
five_percent_height = (page.rect.br.y - page.rect.tl.y)*0.05
for inst in text_instances:
inst_counter += 1
highlight = page.addHighlightAnnot(inst)
# define a suitable cropping box which spans the whole page
# and adds padding around the highlighted text
tl_pt = fitz.Point(page.rect.tl.x, max(page.rect.tl.y, inst.tl.y - five_percent_height))
br_pt = fitz.Point(page.rect.br.x, min(page.rect.br.y, inst.br.y + five_percent_height))
hl_clip = fitz.Rect(tl_pt, br_pt)
zoom_mat = fitz.Matrix(2, 2)
pix = page.getPixmap(matrix=zoom_mat, clip = hl_clip)
pix.writePNG(f"pg{pi}-hl{inst_counter}.png")
doc.close()
I tested this on a sample pdf that i peppered with "hello":
Some of the outputs from the script:
I composed the solution out of the following pages of the documentation:
Tutorial page to get introduced into the library
page.searchFor to figure out the return type of the searchFor method
fitz.Rect to understand what the returned objects from page.searchFor are
Collection of Recipes page (called faq in the URL) to figure out how to crop and save part of a pdf page
I am trying to find product names in an xml file i downloaded. I have figured out how to display every result using a while loop. My problem is, i want to only display the first 10 results. Also, i need be able to call each result individually.
For example: print(read_xml_code.start_tag_5) would print the 5th product in the XML file.
print(read_xml_code.start_tag_10) would print the 10th
here is my code so far:
# Define the Static webpage XML file
static_webpage_1 = 'StaticStock/acoustic_guitar.html'
def Find_static_webpage_product_name():
# Open and read the contents of the first XML file
read_xml_code = open(static_webpage_1, encoding="utf8").read()
# Find and print the static page title.
start_tag = '<title><![CDATA['
end_tag = ']]></title>'
end_position = 0
starting_position = read_xml_code.find(start_tag, end_position)
end_position = read_xml_code.find(end_tag, starting_position)
while starting_position != -1 and end_position!= -1:
print(read_xml_code[starting_position + len(start_tag) : end_position]+ '\n')
starting_position = read_xml_code.find(start_tag, end_position)
end_position = read_xml_code.find(end_tag, starting_position)
#call function
Find_static_webpage_product_name()
There is an HTML parser in the python standard library (python 3):
https://docs.python.org/3/library/html.parser.html
You can easily wait for the tag event and do some counting with a member variable for instance.
Also, do not forget to close your resources (with open(static_webpage_1, encoding="utf8") as f:...)
For my project, I get a plain text file (report.txt) from another program. It is all formatted in plain text. If you open it in Notepad, it looks nice (as much as a plain text file can). When I open the file in Word and show the paragraphs, I see the ... for spaces and the backwards P for pararaph.
I need to convert this file to PDF and add some other PDF pages to make one final PDF. All this happens in Python.
I am having trouble converting the report.txt to pdf. I have ReportLab, and am able to read the file and make a few changes (like change the text to Courier), but the spacing gets lost. When the file gets read, it appears to strip any extra spaces.
Questions:
a) is there an easier way to convert the report.txt to pdf?
b) If not, is there a way to keep my spaces when I read the file?
c) Or is there a parameter I'm missing from my paragraph style that will keep the original look?
Here's my code:
# ------------------------------------
# Styles
# ------------------------------------
styleSheet = getSampleStyleSheet()
mystyle = ParagraphStyle(name='normal',fontName='Courier',
fontSize=10,
alignment=TA_JUSTIFY,
leading=1.2*12,
parent=styleSheet['Normal'])
#=====================================================================================
model_report = 'report.txt'
# Create document for writing to pdf
doc = SimpleDocTemplate(str(pdfPath), \
rightMargin=40, leftMargin=40, \
topMargin=40, bottomMargin=25, \
pageSize=A4)
doc.pagesize = portrait(A4)
# Container for 'Flowable' objects
elements = []
# Open the model report
infile = file(model_report).read()
report_paragraphs = infile.split("\n")
for para in report_paragraphs:
para1 = '<font face="Courier" >%s</font>' % para
elements.append(Paragraph(para1, style=mystyle))
doc.build(elements)
I've created a small helper function to convert a multi-line text to a PDF file in a "report look" by using a monospaced font. Too long lines are wrapped at spaces so that it will fit the page width:
import textwrap
from fpdf import FPDF
def text_to_pdf(text, filename):
a4_width_mm = 210
pt_to_mm = 0.35
fontsize_pt = 10
fontsize_mm = fontsize_pt * pt_to_mm
margin_bottom_mm = 10
character_width_mm = 7 * pt_to_mm
width_text = a4_width_mm / character_width_mm
pdf = FPDF(orientation='P', unit='mm', format='A4')
pdf.set_auto_page_break(True, margin=margin_bottom_mm)
pdf.add_page()
pdf.set_font(family='Courier', size=fontsize_pt)
splitted = text.split('\n')
for line in splitted:
lines = textwrap.wrap(line, width_text)
if len(lines) == 0:
pdf.ln()
for wrap in lines:
pdf.cell(0, fontsize_mm, wrap, ln=1)
pdf.output(filename, 'F')
This is how you would use this function to convert a text file to a PDF file:
input_filename = 'test.txt'
output_filename = 'output.pdf'
file = open(input_filename)
text = file.read()
file.close()
text_to_pdf(text, output_filename)
ReportLab is the usual recommendation-- as you can see from the "Related" questions on the right side of this page.
Have you tried creating text with just StyleSheet['Normal']? I.e., if you get proper-looking output with the following, the problem is somehow with your style.
Paragraph(para1, style=StyleSheet['Normal'])
For converting text or text file into pdf, module fpdf shall be installed using pip install fpdf in command-line Interface.
run the below code and you will find the pdf file in folder-
from fpdf import FPDF
pdf = FPDF()
# Add a page
pdf.add_page()
# set style and size of font
# that you want in the pdf
pdf.set_font("Arial", size = 15)
# open the text file in read mode
f = open("path where text file is stored\\File_name.txt", "r")
# insert the texts in pdf
for x in f:
pdf.cell(50,5, txt = x, ln = 1, align = 'C')
# save the pdf with name .pdf
pdf.output("path where you want to store pdf file\\File_name.pdf")
reference: https://www.geeksforgeeks.org/convert-text-and-text-file-to-pdf-using-python/
I had similar issue. I solved with this code:
from reportlab.lib.pagesizes import letter
from reportlab.pdfgen import canvas
from reportlab.lib.utils import ImageReader
from PIL import Image
# .....
# ..... some exta code unimportant for this issue....
# ....
# here it is
ptr = open("tafAlternos.txt", "r") # text file I need to convert
lineas = ptr.readlines()
ptr.close()
i = 750
numeroLinea = 0
while numeroLinea < len(lineas):
if numeroLinea - len(lineas) < 60: # I'm gonna write every 60 lines because I need it like that
i=750
for linea in lineas[numeroLinea:numeroLinea+60]:
canvas.drawString(15, i, linea.strip())
numeroLinea += 1
i -= 12
canvas.showPage()
else:
i = 750
for linea in lineas[numeroLinea:]:
canvas.drawString(15, i, linea.strip())
numeroLinea += 1
i -= 12
canvas.showPage()
Pdf looks exactly same as original text file
You can create a canvas with pdf_canvas = canvas.Canvas('output_file.pdf') and generate the PDF with pdf_canvas.save().