Python XML get immediate child elements only - python

I have an xml file as below:
<?xml version="1.0" encoding="utf-8"?>
<EDoc CID="1000101" Cname="somename" IName="iname" CSource="e1" Version="1.0">
<RIGLIST>
<RIG RIGID="100001" RIGName="RgName1">
<ListID>
<nodeA nodeAID="1000011" nodeAName="node1A" nodeAExtID="9000011" />
<nodeA nodeAID="1000012" nodeAName="node2A" nodeAExtID="9000012" />
<nodeA nodeAID="1000013" nodeAName="node3A" nodeAExtID="9000013" />
<nodeA nodeAID="1000014" nodeAName="node4A" nodeAExtID="9000014" />
<nodeA nodeAID="1000015" nodeAName="node5A" nodeAExtID="9000015" />
<nodeA nodeAID="1000016" nodeAName="node6A" nodeAExtID="9000016" />
<nodeA nodeAID="1000017" nodeAName="node7A" nodeAExtID="9000017" />
</ListID>
</RIG>
<RIG RIGID="100002" RIGName="RgName2">
<ListID>
<nodeA nodeAID="1000021" nodeAName="node1B" nodeAExtID="9000021" />
<nodeA nodeAID="1000022" nodeAName="node2B" nodeAExtID="9000022" />
<nodeA nodeAID="1000023" nodeAName="node3B" nodeAExtID="9000023" />
</ListID>
</RIG>
</RIGLIST>
</EDoc>
I need to search for the Node value RIGName and if match is found print out all the values of nodeAName
Example:
Searching for RIGName = "RgName2" should print all the values as node1B, node2B, node3B
As of now I am only able to get the first part as below:
import xml.etree.ElementTree as eT
import re
xmlfilePath = "Path of xml file"
tree = eT.parse(xmlfilePath)
root = tree.getroot()
for elem in root.iter("RIGName"):
# print(elem.tag, elem.attrib)
if re.findall(searchtxt, elem.attrib['RIGName'], re.IGNORECASE):
print(elem.attrib)
count += 1
How can I get only the immediate child node values?

Switching from xml.etree to lxml would give you a way to do it in a single go because of a much better XPath query language support:
In [1]: from lxml import etree as ET
In [2]: tree = ET.parse('input.xml')
In [3]: root = tree.getroot()
In [4]: root.xpath('//RIG[#RIGName = "RgName2"]/ListID/nodeA/#nodeAName')
Out[4]: ['node1B', 'node2B', 'node3B']

Related

How to Extract the Information from XML Soap Response?

We have a requirement to get the data from a SOAP XML Response.
Below is the associated XML file
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetResultResponse xmlns="http://www.relatics.com/">
<GetResultResult>
<Report ReportName="RFC" GeneratedOn="2022-12-22" EnvironmentID="XXXX" EnvironmentName="Systematic Assurance – an XXX Solution" EnvironmentURL="https://XXXX.relaticsonline.com/" WorkspaceID="XXXXX" WorkspaceName="P - ADL Program Management - XXX" TargetDevice="Pc" ReportField="" xmlns="">
<Change_module>
<applied_individual_change_request Change_Request="TestKZIreport" RFC_GUID="XXXXX">
<code RFC_Code="VtW-0101" />
<progress RFC_Progress="agreed" />
<applied_individual_project_organisation Organisation="XXXX" />
<applied__individual_discipline Discipline="Highways" />
<specification Specification="Context of Documents">
<code Specification_Code="1.1.1a" />
</specification>
<applied_individual_workpackage Workpackage="Enabling work">
<code Workpackage_Code="WP-01" />
</applied_individual_workpackage>
<physical_object Physical_Object="Train Station">
<code Physical_Object_Code="TFO-0001" />
</physical_object>
<person approver="XXX" />
<applied_individual_change_consequence_qualification Consequence_Value="10 days">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Schedule" />
</applied_individual_change_consequence_qualification>
<document Document_Name="WI 300 Design.pdf">
<code Document_Code="DOC-0002" />
</document>
<answer_status BR_Status="no" />
<applied_individual_business_rule Business_Rule="Change Review compliance">
<code BR_Code="BR-006" />
</applied_individual_business_rule>
<applied_individual_change_consequence_qualification Consequence_Value="XXX">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Finance" />
</applied_individual_change_consequence_qualification>
</applied_individual_change_request>
</Change_module>
</Report>
</GetResultResult>
</GetResultResponse>
</soap:Body>
</soap:Envelope>
i need all the tag values after Change_module.i tried some online help in Stack overflow but it didn't work.
I never worked with XML documents before and here is the sample code i
tried from Stack Overflow.
import xml.etree.ElementTree as ET
import pandas as pd
import numpy as np
tree = ET.parse("Relatics_XML.xml")
root = tree.getroot()
print(root.tag)
print(root.attrib)
namespaces = {"soap": "http://www.w3.org/2003/05/soap-envelope/",
"xsi": "http://www.w3.org/2001/XMLSchema-instance",
"xsd": "http://www.w3.org/2001/XMLSchema/",
'a': 'http://www.relatics.com/',}
names = tree.findall('./soap:Body''/a:GetResultResponse''/a:GetResultResult', namespaces)
print(names)
for name in names:
print(name.text)
i tried different methods like find and findall and also inside the method i try to pass different values but all its printing is null.
I'm not sure how to get the values out of tags.
Using xml.etree.ElementTree make life easier.
documentation in here
It can parsing tag attribute or innerText.
import xml.etree.ElementTree as ET
xml = """\
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetResultResponse xmlns="http://www.relatics.com/">
<GetResultResult>
<Report ReportName="RFC" GeneratedOn="2022-12-22" EnvironmentID="XXXX" EnvironmentName="Systematic Assurance – an XXX Solution" EnvironmentURL="https://XXXX.relaticsonline.com/" WorkspaceID="XXXXX" WorkspaceName="P - ADL Program Management - XXX" TargetDevice="Pc" ReportField=""
xmlns="">
<Change_module>
<applied_individual_change_request Change_Request="TestKZIreport" RFC_GUID="XXXXX">
<code RFC_Code="VtW-0101" />
<progress RFC_Progress="agreed" />
<applied_individual_project_organisation Organisation="XXXX" />
<applied__individual_discipline Discipline="Highways" />
<specification Specification="Context of Documents">
<code Specification_Code="1.1.1a" />
</specification>
<applied_individual_workpackage Workpackage="Enabling work">
<code Workpackage_Code="WP-01" />
</applied_individual_workpackage>
<physical_object Physical_Object="Train Station">
<code Physical_Object_Code="TFO-0001" />
</physical_object>
<person approver="XXX" />
<applied_individual_change_consequence_qualification Consequence_Value="10 days">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Schedule" />
</applied_individual_change_consequence_qualification>
<document Document_Name="WI 300 Design.pdf">
<code Document_Code="DOC-0002" />
</document>
<answer_status BR_Status="no" />
<applied_individual_business_rule Business_Rule="Change Review compliance">
<code BR_Code="BR-006" />
</applied_individual_business_rule>
<applied_individual_change_consequence_qualification Consequence_Value="XXX">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Finance" />
</applied_individual_change_consequence_qualification>
</applied_individual_change_request>
</Change_module>
</Report>
</GetResultResult>
</GetResultResponse>
</soap:Body>
</soap:Envelope>
"""
root = ET.fromstring(xml)
print("RFC_Code: " + str(root.find(".//code[#RFC_Code]").attrib))
print("RFC_Progress: " + str(root.find(".//progress[#RFC_Progress]").attrib))
print("specification: " + str(root.find(".//specification[#Specification]").attrib))
print("Specification_Code: " + str(root.find(".//code[#Specification_Code]").attrib))
print("Workpackage_Code: " + str(root.find(".//code[#Workpackage_Code]").attrib))
print("Document_Code: " + str(root.find(".//code[#Document_Code]").attrib))
Result
$ python get-data.py
RFC_Code: {'RFC_Code': 'VtW-0101'}
RFC_Progress: {'RFC_Progress': 'agreed'}
specification: {'Specification': 'Context of Documents'}
Specification_Code: {'Specification_Code': '1.1.1a'}
Workpackage_Code: {'Workpackage_Code': 'WP-01'}
Document_Code: {'Document_Code': 'DOC-0002'}
If you using xml file open, using this code
with open('data.xml', 'r') as xml_file:
root = ET.parse(xml_file)

Not getting anything while parsing xml file in python

I am a beginner in python and trying to parse the below string from xmlfile where I can get an output like below :
Expected output :{macman:(linkedin,facebook,stack overflow)}
so that I can find out which user has which clients
XML File : <user name="macman"> <client name="linkedin" />
<client name="facebook" /> <client name="stack overflow" />
</user>
Code i am trying :
import urllib.request as url
import xml.etree.ElementTree as ET
xmlfile=url.urlopen(r'file:///D:/Python/user.html')
tree=ET.parse(xmlfile)
root=tree.getroot()
print(root.tag)
for item in root.findall("./user"):
users={}
for child in item:
users[child.tag]=child.text
print(users)
You need to findall() the client not the user. So, your code should look like this:
...
users = {root.get("name"): []}
for item in root.findall("client"):
users[root.get("name")].append(item.get("name"))
print(users)
#{'macman': ['linkedin', 'facebook', 'stack overflow']}
Below
import xml.etree.ElementTree as ET
xml = '''<r><user name="macman1"> <client name="linkedin1" />
<client name="facebook1" /> <client name="stack overflow1" />
</user><user name="macman2"> <client name="linkedin2" />
<client name="facebook2" /> <client name="stack overflow2" />
</user></r>'''
root = ET.fromstring(xml)
data = {u.attrib['name']: [c.attrib['name'] for c in u.findall('./client')] for u in root.findall('.//user')}
print(data)
output
{'macman2': ['linkedin2', 'facebook2', 'stack overflow2'], 'macman1': ['linkedin1', 'facebook1', 'stack overflow1']}

python ElementTree remove issue

I have xml file as following:
<plugin-config>
<properties>
<property name="AZSRVC_CONNECTION" value="diamond_plugins#AZSRVC" />
<property name="DIAMOND_HOST" value="10.0.230.1" />
<property name="DIAMOND_PORT" value="3333" />
</properties>
<pack-list>
<vsme-pack id="monthly_50MB">
<campaign-list>
<campaign id="2759" type="SOB" />
<campaign id="2723" type="SUBSCRIBE" />
</campaign-list>
</vsme-pack>
<vsme-pack id="monthly_500MB">
<campaign-list>
<campaign id="3879" type="SOB" />
<campaign id="3885" type="SOB" />
<campaign id="2724" type="SUBSCRIBE" />
<campaign id="1111" type="COB" /></campaign-list>
</vsme-pack>
</pack-list>
</plugin-config>
And trying to run this Python script to remove 'campaign' with specific id.
import xml.etree.ElementTree as ET
tree = ET.parse('pack-assign-config.xml')
root = tree.getroot()
pack_list = root.find('pack-list')
camp_list = pack_list.find(".//vsme-pack[#id='{pack_id}']".format(pack_id=pack_id)).find('campaign-list').findall('campaign')
for camp in camp_list:
if camp.get('id') == '2759':
camp_list.remove(camp)
tree.write('out.xml')
I run script but out is the same as input file, so does not remove element.
Issue :
this is wrong way to find the desired node . you are searching for vsme-pack and the trying to find campaign-list and campaign ? which incorrect format.
camp_list = pack_list.find(".//vsme-pack[#id='{pack_id}']".format(pack_id=pack_id)).find('campaign-list').findall('campaign')
Fixed Code Example
here is the working code which removes the node from xml
import xml.etree.ElementTree as ET
root = ET.parse('pack-assign-config.xml')
# Alternatively, parse the XML that lives in 'filename_path'
# tree = ElementTree.parse(filename_path)
# root = tree.getroot()
# Find the parent element of each "weight" element, using XPATH
for parent in root.findall('.//pack-list/'):
# Find each weight element
for element in parent.findall('campaign-list'):
for camp_list in element.findall('campaign'):
if camp_list.get('id') == '2759' or camp_list.get('id') == '3879' :
element.remove(camp_list)
root.write("out.xml")
hope this helps

lxml, get xml between elements

given this sample xml:
<xml>
<pb facs="id1" />
<aa></aa>
<aa></aa>
<lot-of-xml></lot-of-xml>
<pb facs="id2" />
<bb></bb>
<bb></bb>
<lot-of-xml></lot-of-xml>
</xml>
i need to parse it and get all the content between pb, saving into distinct external files.
expected result:
$ cat id1
<aa></aa>
<aa></aa>
<lot-of-xml></lot-of-xml>
$ cat id2
<bb></bb>
<bb></bb>
<lot-of-xml></lot-of-xml>
what is the correct xpath axe to use?
from lxml import etree
xml = etree.parse("sample.xml")
for pb in xml.xpath('//pb'):
filename = pb.xpath('#facs')[0]
f = open(filename, 'w')
content = **{{ HOW TO GET THE CONTENT HERE? }}**
f.write(content)
f.close()
is there any xpath expression to get all descendants and stop when reached a new pb?
Do you want to extract the tag between two pb's? If yes then that's not quite possible because it is not a tag in between pb's rather than an individual tag on the same level as pb as you have closed the tag pb . If you close the tag after the test tag then test can become a child of pb.
In other words if your xml is like this:
<xml>
<pb facs="id1">
<test></test>
</pb>
<test></test>
<pb facs="id2" />
<test></test>
<test></test>
</xml>
Then you can use
import xml.etree.ElementTree as ET
tree = ET.parse('test.xml')
root = tree.getroot()
for child in root:
for subchild in child:
print subchild
to print the subchild('test') with pb as a parent.
Well if that's not the case (you just want to extract the attributes of pb tag)then you can use either of the two methods shown below to extract the elements.
With python's inbuilt etree
import xml.etree.ElementTree as ET
tree = ET.parse('sample.xml')
root = tree.getroot()
for child in root:
if child.get('facs'):
print child.get('facs')
With the lxml library you can parse it like this:
tree = etree.parse('test.xml')
root = tree.getroot()
for child in root:
if child.get('facs'):
print child.get('facs')
OK, I tested this code:
lists = []
for node in tree.findall('*'):
if node.tag == 'pb':
lists.append([])
else:
lists[-1].append(node)
Output:
>>> lists
[[<Element test at 2967fa8>, <Element test at 2a89030>, <Element lot-of-xml at 2a89080>], [<Element test at 2a89170>, <Element test at 2a891c0>, <Element lot-of-xml at 2a89210>]]
Input file (just in case):
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xml>
<pb facs="id1" />
<test></test>
<test></test>
<lot-of-xml></lot-of-xml>
<pb facs="id2" />
<test></test>
<test></test>
<lot-of-xml></lot-of-xml>
</xml>

how can I select all descendants of a certain element with ElementTree in Python 3.3?

This is the sample data.
input.xml
<root>
<entry id="1">
<headword>go</headword>
<example>I <hw>go</hw> to school.</example>
</entry>
</root>
I'd like to put node and its descendants into . That is,
output.xml
<root>
<entry id="1">
<headword>go</headword>
<examplegrp>
<example>I <hw>go</hw> to school.</example>
</examplegrp>
</entry>
</root>
My poor and incomplete script is:
import codecs
import xml.etree.ElementTree as ET
fin = codecs.open(r'input.xml', 'rb', encoding='utf-8')
data = ET.parse(fin)
root = data.getroot()
example = root.find('.//example')
for elem in example.iter():
---and then I don't know what to do---
Here's an example of how it can be done:
text = """
<root>
<entry id="1">
<headword>go</headword>
<example>I <hw>go</hw> to school.</example>
</entry>
</root>
"""
import lxml.etree
import StringIO
data = lxml.etree.parse(StringIO.StringIO(text))
root = data.getroot()
for entry in root.xpath('//example/ancestor::entry[1]'):
examplegrp = lxml.etree.SubElement(entry,"examplegrp")
nodes = [node for node in entry.xpath('./example')]
for node in nodes:
entry.remove(node)
examplegrp.append(node)
print lxml.etree.tostring(root,pretty_print=True)
which will output:
<root>
<entry id="1">
<headword>go</headword>
<examplegrp><example>I <hw>go</hw> to school.</example>
</examplegrp></entry>
</root>
http://docs.python.org/3/library/xml.dom.html?highlight=xml#node-objects
http://docs.python.org/3/library/xml.dom.html?highlight=xml#document-objects
You probably want to follow some paradigm of creating a Document Element and appending reach result to it.
group = Document.createElement(tagName)
for found in founds:
group.appendNode(found)
Or something like this

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