How to continue looping after a module defined exception in Python? - python

I loop though a list of currencies in order to download price series from an API and it happens that some of them are not supported so that it raises a module defined exception class : ExchangeError: This currency pair is not supported.
When it occurs I would like to continue the loop to the next currency but for some reason I'm unable to handle the module exception.
Here is an example that works fine with a built-in exception :
f = [1,2,3,4,'A',5]
def foo(nb):
return nb /2
for i in f :
try:
print(foo(i))
except TypeError :
continue
As expected it returns :
0.5
1
1.5
2
2.5
But as soon as it is a module (or user defined) exception it throws an error saying the exception is not defined :
#retry(wait_exponential_multiplier=1000, wait_exponential_max=10000)
def apiFetchOHLC(obj, currency, timeframe, option):
ohlcv = obj().fetch_ohlcv(currency, timeframe, since = option)
return ohlc
for c in currencies_list :
...
try :
# Download data
ohlc = apiFetchOHLC(obj, c, tf, maxCandlesLimit)
# except : # works fine
except ExchangeError : # doesn't work
print("Oops! That was no valid currency. Continue...")
continue
This is the error I get when I run the loop :
except ExchangeError:
NameError: name 'ExchangeError' is not defined
To make it works I need to remove the exception type ExchangeError but to me it is not a workaround because it will continue the loop whatever the exception is, and sometimes I need to retry the download.
How can I achieve this with try and except or with the retrying package ? (link)

def foo(count):
try:
while(count < 10):
if(count%2 == 1):
raise Exception()
print(count)
count = count+1
except:
print( str(count) + ' -> Exception')
foo(count+1)
foo(2)
Whenever an exception occurs in a try block, handle it in except block as follows -
To continue the process you are doing in try block, you should reach the try block from an except block - keep the try block in a function, name it foo, so that you could call it from the except block
To continue from the next iteration, you need to know the previous iteration where the exception has been raised - pass an argument to that function

After identifying the problem better I have found that I needed to give the full name space of the exception class I want to catch:
for c in currencies_list :
...
try :
# Download data
ohlc = apiFetchOHLC(obj, c, tf, maxCandlesLimit)
except ccxt.ExchangeError :
print("Oops! That was no valid currency. Continue...")
continue

Related

Continue a nested loop after exception

I have a nested loop to get certain JSON elements the way I want, but occasionally, the API I'm fetching from gets messy and it breaks some of the fields - I am not exactly sure how to handle this since It seems to be different each time, so I'm wondering if there is a way to continue a nested for loop even if an exception occurs inside it, or at least go back to the first loop and continue again.
My code is like this:
fields = ['email', 'displayname', 'login']
sub_fields = ['level', 'name']
all_data = []
for d in data:
login_value = d['login']
if login_value.startswith('3b3'):
continue
student = fetched_student.student_data(login_value)
student = json.loads(student)
final_json = dict()
try:
for field in fields:
#print ("Student field here: %s" % student[field])
final_json[field] = student[field]
except Exception as e:
print (e) # this is where I get a random KeyValue Error
#print ("Something happening here: %s " % final_json[field])
finally:
for sub_field in sub_fields:
for element in student['users']:
if element.get(sub_field):
final_json[sub_field] = element.get(sub_field)
for element in student['campus']:
if element.get(sub_field):
final_json[sub_field] = element.get(sub_field)
all_data.append(final_json)
print (all_data)
Is there a way to just go back to the first try block and continue after the exception has occurred or simply just ignore it and continue?
Because as things are now, if the exception ever occurs it breaks everything.
EDIT1: I have tried putting continue like so:
try:
for field in fields:
#print ("Student field here: %s" % student[field])
final_json[field] = student[field]
except Exception as e:
print (e)
continue
for sub_field in sub_fields:
for element in student['users']:
But it still fails regardless.
Use this for the try block:
for field in fields:
try:
#print ("Student field here: %s" % student[field])
final_json[field] = student[field]
except Exception as e:
print (e)
continue
for sub_field in sub_fields:
for element in student['users']:
The issue is due to the indentation level of the try block, the continue was affecting the outer most loop. Changing the try block to be inside of the loop will catch the error in that loop and continue the iteration of that specific loop.
Possibly you can use dict's get method like this in your try block:
try:
for field in fields:
#print ("Student field here: %s" % student[field])
final_json[field] = student.get(field, "") # 2nd arg is fallback object
Depending on what is needed, you can pass in an fresh dict (aka JSON object), fresh list (aka JSON array), or a str like above to suit your downstream needs.

Multiple Try/Except for Validate Config-File

Thats my first question on Stackoverflow and im a totally Python beginner.
I want to write, to get firm with python, a small Backup-Programm, the main part is done, but now i want to make it a bit "portable" and use a Config file, which i want to Validate.
My class "getBackupOptions" should be give Back a validate dict which should be enriched with "GlobalOptions" and "BackupOption" so that i finally get an fully "BackupOption" dict when i call "getBackupOptions.BackupOptions".
My Question now is, (in this Example is it easy, because its only the Function which check if the Path should be Recursive searched or not) how to simplify my Code?
For each (possible) Error i must write a new "TryExcept" Block - Can i Simplify it?
Maybe is there another way to Validate Config Files/Arrays?
class getBackupOptions:
def __init__(self,BackupOption,GlobalOptions):
self.BackupOption = BackupOption
self.GlobalOptions = GlobalOptions
self.getRecusive()
def getRecusive(self):
try:
if self.BackupOption['recursive'] != None:
pass
else:
raise KeyError
except KeyError:
try:
if self.GlobalOptions['recursive'] != None:
self.BackupOption['recursive'] = self.GlobalOptions['recursive']
else:
raise KeyError
except KeyError:
print('Recusive in: ' + str(self.BackupOption) + ' and Global is not set!')
exit()
Actually i only catch an KeyError, but what if the the Key is there but there is something else than "True" or "False"?
Thanks a lot for you help!
You may try this
class getBackupOptions:
def __init__(self,BackupOption,GlobalOptions):
self.BackupOption = BackupOption
self.GlobalOptions = GlobalOptions
self.getRecusive()
def getRecusive(self):
if self.BackupOption.get('recursive') == 'True' and self.GlobalOptions.get('recursive') == 'True':
self.BackupOption['recursive'] = self.GlobalOptions['recursive']
else:
print('Recusive in: ' + str(self.BackupOption) + ' and Global is not set!')
exit()
Here get method is used, therefore KeyError will not be faced.
If any text other than True comes in the field it will be considered as False.

Same Exceptions with different specific message

I tried to write a code that can distinguish the following four different errors.
TypeError: The first parameter is not an integer;
TypeError: The second parameter is not a string;
ValueError: The value of the first parameter is not in the range of 1 to 13; or
ValueError: The value of the second parameter is not one of the strings in the set {'s', 'h', 'c', 'd'}.
However, I only can get the first one to work but not the other three errors. I tried different ways to make it work, but still can't figure out what's wrong.
class Card: # One object of class Card represents a playing card
rank = ['','Ace','Two','Three','Four','Five','Six','Seven','Eight','Nine','Ten','Jack','Queen','King']
suit = {'d':'Diamonds', 'c':'Clubs', 'h':'Hearts', 's':'Spades'}
def __init__(self, rank=2, suit=0): # Card constructor, executed every time a new Card object is created
if type(rank) != int:
raise TypeError()
if type(suit) != str:
raise TypeError()
if rank != self.rank:
raise ValueError()
if suit != 'd' or 'c' or 'h' or 's':
raise ValueError()
self.rank = rank
self.suit = suit
def getRank(self): # Obtain the rank of the card
return self.rank
def getSuit(self): # Obtain the suit of the card
return Card.suit[self.suit]
def bjValue(self): # Obtain the Blackjack value of a card
return min(self.rank, 10)
def __str__(self): # Generate the name of a card in a string
return "%s of %s" % (Card.rank[int(self.rank)], Card.suit[self.suit])
if __name__ == "__main__": # Test the class Card above and will be skipped if it is imported into separate file to test
try:
c1 = Card(19,13)
except TypeError:
print ("The first parameter is not an integer")
except TypeError:
print ("The second parameter is not a string")
except ValueError:
print ("The value of first parameter is not in the range of 1 to 13")
except ValueError:
print ("The value of second parameter is not one of the strings in the set {'s','h','c','d'}")
print(c1)
I know maybe it is due to that I have same TypeError and ValueError. Therefore, Python can't distinguish the second TypeError which I hit c1 = Card(13,13) is different from the first TypeError. So, I only get the message that "The first parameter is not an integer" when I have c1 = Card(13,13).
You are trying to distinguish between the error sources in completely the wrong place. By the time the error gets out of Card.__init__, there is no way to tell why e.g. a TypeError was thrown. For each error class (TypeError, ValueError) only the first except will ever be triggered:
try:
...
except TypeError:
# all TypeErrors end up here
except TypeError:
# this is *never* reached
except ValueError:
# all ValueErrors end up here
except ValueError:
# this is *never* reached
Instead, you should provide the specific error messages inside Card.__init__, when you actually raise the error and already know what the reason is:
if not isinstance(rank, int): # better than comparing to type
raise TypeError("The first parameter is not an integer")
Then you can handle them much more simply:
try:
c1 = Card(19,13)
except (TypeError, ValueError) as err: # assign the error to the name 'err'
print(err) # whichever we catch, show the user the message
else:
print(c1) # only print the Card if there were no errors
If you have a particular need to distinguish between different errors of the same class, you can either explicitly check the message:
except TypeError as err:
if err.args[0] == "The first parameter is not an integer":
# do whatever you need to
or create your own, more specific Exception sub-classes, so you can have separate except blocks:
class FirstParamNotIntError(Exception):
pass
(this is just an example, they are too specific in your particular case).
It's probably worth having a read through the documentation on exceptions and the tutorial on using them.

Putting custom error messages in Python

I want to create custom error messages for a function.
def tr( launch_speed , launch_angle_deg , num_samples ):
#Error displays
try:
launch_speed>0
except:
raise Exception("Launch speed has to be positive!")
try:
0<launch_angle_deg<90
except:
raise Exception("Launch angle has to be 0 to 90 degrees!")
try:
um_samples = int(input())
except:
raise Exception("Integer amount of samples!")
try:
num_samples >=2
except:
raise Exception("At least 2 samples!")
Essentially, what I want is to get an error message every time a wrong value has been written in the function variables, and I've tried creating these messages based on what I've gathered on the Internet, but it doesn't seem to work.
You can't use try: except: for everything; for example, launch_speed>0 will not raise an error for negative values. Instead, I think you want e.g.
if launch_speed < 0: # note spacing, and if not try
raise ValueError("Launch speed must be positive.") # note specific error
You should also test for and raise more specific errors (see "the evils of except"), e.g.:
try:
num_samples = int(raw_input()) # don't use input in 2.x
except ValueError: # note specific error
raise TypeError("Integer amount of samples!")
You can see the list of built-in errors in the documentation.
Why not go one step further and build your own exception types? There's a quick tutorial in the docs which could be used something like:
class Error(Exception):
"""Base class for exceptions defined in this module"""
pass
class LaunchError(Error):
"""Errors related to the launch"""
pass
class LaunchSpeedError(LaunchError):
"""Launch speed is wrong"""
pass
class LaunchAngleError(LaunchError):
"""Launch angle is wrong"""
pass
class SamplesError(Error):
"""Error relating to samples"""
pass
In this case the default functionality of Exception is fine, but you may be able to get finer granularity in what you catch by defining extra exceptions.
if launch_speed < 0:
raise LaunchSpeedError("Launch speed must be positive")
if 0 <= launch_angle < 90:
raise LaunchAngleError("Launch angle must be between 0 and 90")
um_samples = input()
try:
um_samples = int(um_samples)
except ValueError:
raise SampleError("Samples must be an integer, not {}".format(um_samples))
if um_samples < 2:
raise SampleError("Must include more than one sample, not {}".format(str(um_samples)))

Jump into the line instruction that caused an exception in python after the exception is called

Is there any way to return back and repeat the instruction that was handling an exception in Python?
E.g. if we get some data by input() method, and for some reason is caused an exception (e.g. when trying to convert the input string into int), we raised the exception, but after the exception, I would like again to go to the same line where the input() is.
Just note, "continue" is not an option, even if it is in a loop, because it could be several different input() assigning them to a different variables in different parts of the loop.
So the question again is:
while 1:
try:
foo = int(input(">")
...some other code here...
bar = int(input(">")
...some other code here...
fred = int(input(">")
...some other code here...
except Exception:
... do something for error handling and ...
jump_back_and_repeat_last_line_that_caused_the_exception
Imagine that the above code could be in a loop, and the exception can be caused in any instruction (foo... bar... fred...etc, or even can be any other line). So, if it fails in the "bar" line, it should try again the "bar" line.
Is there any reserved word to do this in python?
Define a function; Handle exception there.
def read_int():
while 1:
try:
value = int(input('>'))
except ValueError:
# Error handling + Jump back to input line.
continue
else:
return value
while 1:
foo = read_int()
bar = read_int()
fred = read_int()
There might be a way to do that, but it will probably result with a very poor design.
If I understand you correctly, then your problem is with the exception caused by calling input.
If that is indeed the case, then you should simply implement it in a separate method, which will handle the exception properly:
foo = getUserInput()
...some other code here...
bar = getUserInput()
...some other code here...
fred = getUserInput()
...some other code here...
def getUserInput():
while 1:
try:
return int(input(">"))
except Exception:
pass
don't do nothing in except:
while 1:
try:
a=int(raw_input('input an integer: ')) #on python2 it's "raw_input" instead of "input"
break
except ValueError, err:
# print err
pass
print 'user input is:', a
output is:
D:\U\ZJ\Desktop> py a.py
input an integer: a
input an integer: b
input an integer: c
input an integer: 123
user input is: 123

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