I have two modules in Python 3—main.py and gui.py—which are both in the same directory. My code is listed here:
main.py:
import gui
if __name__ == "__main__":
interface = gui.Gui()
interface.func1()
def foo():
interface.func2()
gui.py:
import main
class Gui:
def func1(self):
main.foo()
def func2(self):
pass
When calling main.foo() from gui.py, I get the following exception:
NameError: name 'interface' is not defined
If I move the foo() declaration to the top of the main.py file and then call it from main.py, I do not get this exception.
Why does this error occur when calling main.foo() from gui.py?
Note: This is my first question on StackOverflow, so I'm sorry if it is not well-written. Please tell me how I could improve it.
Related
In an effort to create a simple script for another question to highlight an issue I am having, I ran into this confusing problem. My code won't run. I read several other Stack Overflow answers and ensured that I am not using a pre-defined class. I am also not doing a cyclical import. I have no idea. I am new to Python.
TestClass.py:
class TestClass:
test_number = 10000 # Default score limit
def __init__(self):
pass
def check_test_number(self):
# this needs to be an instance method
print(TestClass.test_number)
TestScript.py:
import TestClass
def main():
t1 = TestClass.TestClass()
print(TestClass.test_number)
print(t1.check_test_number())
TestClass.test_number = 500
print(TestClass.test_number)
print(t1.check_test_number())
if __name__ == "__main__":
main()
I recieve this error:
AttributeError: module 'TestClass' has no attribute 'test_number'
Thanks in advance, guys!
You need to refer to the fields test_number and score_limit on lines print(TestClass.test_number) and TestClass.test_number= 500 like this: TestClass.TestClass.test_number or use expression from *your_file* import *ClassName*. In your code you're trying to refer not to a class field, but to a method or variable in the file TestClass.py. I advise you to use snake_case to name .py files to avoid confusions. I think your code can be rewritten like this (with renaming TestClass.py):
test_script.py
from test_class import TestClass
def main():
t1 = TestClass()
print(TestClass.test_number)
print(t1.check_test_number())
TestClass.test_number= 500
print(TestClass.test_number)
print(t1.check_test_number())
if __name__ == "__main__":
main()
One basic question in OOP.
test.py file content:
class test(object):
def __init__(self):
print 'INIT of test class'
obj = test()
Then I opened another file.
I just inherited from the above test class:
from test import test
class test1(test):
def __init__(self):
pass
So when I run this second file, the __init__() from the parent class is executed (the INIT got printed).
I read that I can avoid it by using
if __name__ == '__main__':
# ...
I can overcome this, but my question is why the parent class's init is executing as I am just importing this class only in my second file. Why is the object creation code executed?
Importing a module executes all module-level statements, including obj=test().
To avoid this, make an instance only when run as the main program, not when imported:
class test(object):
def __init__(self):
print 'INIT of test class'
if __name__ == '__main__':
obj=test()
The problem is not the inheritance but the import. In your case you execute obj=test() when importing:
from test import test
When you import test, its name __name__ is test.
But when you run your program on the command line as main program with python test.py, its name is __main__. So, in the import case, you skip obj=test()if you use:
if __name__ == '__main__':
obj=test()
I am trying to understand the usage of #main annotation in python.
With the below python program,
def cube(x):
return x * x * x
def run_tests():
printf("Should be 1:", cube(1))
printf("Should be 8:", cube(2))
printf("Should be 27:", cube(3))
#main
def main():
print("Starting")
run_tests()
print("Ending.")
I get the following error:
PS C:\Users\MOHET01\Desktop> python.exe -i .\cube.py
Traceback (most recent call last):
File ".\cube.py", line 9, in <module>
#main
NameError: name 'main' is not defined
>>>
Function that is imported from ucb is as shown below:
def main(fn):
"""Call fn with command line arguments. Used as a decorator.
The main decorator marks the function that starts a program. For example,
interact()
#main
def my_run_function():
# function body
Use this instead of the typical __name__ == "__main__" predicate.
"""
if inspect.stack()[1][0].f_locals['__name__'] == '__main__':
args = sys.argv[1:] # Discard the script name from command line
print(args)
print(*args)
print(fn)
fn(*args) # Call the main function
return fn
My question:
Despite i define function with intrinsic name main, Why do i see this error?
I should use this:
def main():
#Do something
if __name__ == "__main__":
#Here use the method that will be the main
main()
I hope this helps
The #main decorator is implemented in a file your course provides, but you have not imported it. The page you linked says to use
from ucb import main, interact
to import the ucb.py features in your program.
As for why the error says name 'main' is not defined, that's because the function definition doesn't actually finish defining anything until the decorators execute. The reuse of the name main for both the decorator and the decorated function is confusing; the main in #main is a different function from the main you're defining in def main(): .... The main in #main is defined to run the decorated function if the file is run as a script, while the main in def main(): ... is the function to be run.
I would strongly recommend not using anything like this decorator when you don't have to. The standard way to perform the task the decorator performs is to write
if __name__ == '__main__':
whatever_function_you_would_have_put_the_decorator_on()
or if you want to handle command line arguments like the decorator would,
if __name__ == '__main__':
import sys
whatever_function_you_would_have_put_the_decorator_on(*sys.argv[1:])
The decorator is an attempt to hide the issues of sys.argv and __name__ so you don't have to know about them, but it has a problem. If you try to write something like this:
#main
def hello():
print(hello_string)
hello_string = 'Hi there.'
you'll get a NameError, because hello_string won't be assigned until after the decorator runs. If you continue to write Python beyond this course, you'll find that using if __name__ == '__main__' is less bug-prone and more understandable to other programmers than using a decorator for this.
You are using the function before it is defined. In other words, you need to define the main function higher up (in the document) than where you use it as a decorator:
def main():
pass
#main
def somefunction():
pass
The #main notation means the main function is being used to "decorate", or modify, another function. There are various articles on python decorators:
http://simeonfranklin.com/blog/2012/jul/1/python-decorators-in-12-steps/
http://www.artima.com/weblogs/viewpost.jsp?thread=240808
http://www.jeffknupp.com/blog/2013/11/29/improve-your-python-decorators-explained/
You can only use a decorator on a different function. Example:
def foo(f):
def inner():
print("before")
f()
print("after")
return inner
#foo
def bar():
print("bar")
if __name__ == "__main__":
bar()
Output:
before
bar
after
I know it's a greenhorn question. But. I have a very simple module that contains a class, and I want to call the module to run from another. Like so:
#module a, to be imported
import statements
if __name__ == '__main__':
class a1:
def __init__(self, stuff):
do stuff
def run_proc():
do stuff involving 'a1' when called from another module
#Module that I'll run, that imports and uses 'a':
if __name__ == '__main__':
import a
a.run_proc()
However, for reasons that are likely obvious to others, I get the error Attribute Error: 'Module' object has no attribute 'run_proc' Do I need a static method for this class, or to have my run_proc() method within a class, that I initialize an instance of?
Move the
if __name__ == '__main__':
in module a to the end of the file and add pass or some test code.
Your problems are that:
Any thing in the scope of if __name__ == '__main__': is only considered in the top level file.
You are defining a class but not creating a class instance.
module a, to be imported
import statements
class a1:
def __init__(self, stuff):
do stuff
def run_proc():
#do stuff involving 'a1' when called from another module
if __name__ == '__main__':
pass # Replace with test code!
Module that I'll run, that imports and uses 'a':
import a
def do_a():
A = a.a1() # Create an instance
A.run_proc() # Use it
if __name__ == '__main__':
do_a()
Classes B and C both derive from base class A, and neither override A's method test(). B is defined in the same module as A; C is defined in a separate module. How is it that calling B.test() prints "hello", but calling C.test() fails? Shouldn't either invocation end up executing A.test() and therefore be able to resolve the symbol "message" in mod1's namespace?
I'd also gratefully receive hints on where this behaviour is documented as I've been unable to turn up anything. How are names resolved when C.test() is called, and can "message" be injected into one of the namespaces somehow?
FWIW, the reason I haven't used an instance variable (e.g. set A.message = "hello") is because I'm wanting to access a "global" singleton object and don't want to have an explicit referent to it in every other object.
mod1.py:
import mod2
class A(object):
def test(self):
print message
class B(A):
pass
if __name__ == "__main__":
message = "hello"
A().test()
B().test()
mod2.C().test()
mod2.py:
import mod1
class C(mod1.A):
pass
output is:
$ python mod1.py
hello
hello
Traceback (most recent call last):
File "mod1.py", line 14, in <module>
mod2.C().test()
File "mod1.py", line 5, in test
print message
NameError: global name 'message' is not defined
Many thanks!
EOL is correct, moving the "main" part of the program into a new file mod3.py does indeed make things work.
http://bytebaker.com/2008/07/30/python-namespaces/ further clarifies the issue.
In my original question, it turns out that the variable message ist stored in the __main__ module namespace because mod1.py is being run as a script. mod2 imports mod1, but it gets a separate mod1 namespace, where the variable message does not exist. The following code snippet demonstrates more clearly as it writes message into mod1's namespace (not that I'd recommend this be done in real life), causing the expected behaviour.
import sys
class A(object):
def test(self):
print message
class B(A):
pass
if __name__ == "__main__":
import mod2
message = "hello"
sys.modules["mod1"].message = message
A().test()
B().test()
mod2.C().test()
I think the best real-world fix is to move the "main" part of the program into a separate module, as EOL implies, or do:
class A(object):
def test(self):
print message
class B(A):
pass
def main():
global message
message = "hello"
A().test()
B().test()
# resolve circular import by importing in local scope
import mod2
mod2.C().test()
if __name__ == "__main__":
# break into mod1 namespace from __main__ namespace
import mod1
mod1.main()
Could you use a class attribute instead of a global? The following works
import mod2
class A(object):
message = "Hello" # Class attribute (not duplicated in instances)
def test(self):
print self.message # Class A attribute can be overridden by subclasses
class B(A):
pass
if __name__ == "__main__":
A().test()
B().test()
mod2.C().test()
Not using globals is cleaner: in the code above, message is explicitly attached to the class it is used in.
That said, I am also very curious as to why the global message is not found by mod2.C().test().
Things work as expected, though, if the cross-importing is removed (no main program in mod1.py, and no import mod2): importing mod1 and mod2 from mod3.py, doing mod1.message = "Hello" there and mod2.C().test() works. I am therefore wondering if the problem is not related to cross-importing…