The profanity checker seems to be working but does not return either (response: false) or response: true)
Here is a look at the code:
import urllib.request
def read_text():
quotes = open("/Users/sellis/Desktop/movie_quotes.rtf")
contents_of_file = quotes.read()
print(contents_of_file)
quotes.close()
check_profanity(contents_of_file)
def check_profanity(text_to_check):
connection = urllib.request.urlopen(" http://www.wdylike.com/profanity?q"+text_to_check)
output = connection.read()
print(output)
connection.close()
read_text()
When it is run it comes up as:
{\rtf1\ansi\ansicpg1252\cocoartf1404\cocoasubrtf470
{\fonttbl\f0\fmodern\fcharset0 Courier;}
{\colortbl;\red255\green255\blue255;\red0\green0\blue0;}
\margl1440\margr1440\vieww10800\viewh8400\viewkind0
\deftab720
\pard\pardeftab720\sl280\partightenfactor0
\f0\fs24 \cf2 \expnd0\expndtw0\kerning0
\outl0\strokewidth0 \strokec2 -- Houston, we have a problem. (Apollo 13)\
\
-- Mama always said, life is like a box of chocolates. You never know what you are going to get. (Forrest Gump)\
\
-- You cant handle the truth. (A Few Good Men)\
\
-- I believe everything and I believe nothing. (A Shot in the Dark)\
}
Traceback (most recent call last):
File "/Users/sellis/Desktop/check_profanity.py", line 16, in <module>
read_text()
File "/Users/sellis/Desktop/check_profanity.py", line 8, in read_text
check_profanity(contents_of_file)
File "/Users/sellis/Desktop/check_profanity.py", line 11, in check_profanity
connection = urllib.request.urlopen(" http://www.wdylike.com/profanity?q"+text_to_check)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 532, in open
response = meth(req, response)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 570, in error
return self._call_chain(*args)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 504, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 505: HTTP Version Not Supported
After the code runs it is supposed to show a response: false or a response: true depending on if after reading the code the function discovers that there is a cuss word
Related
Hi i am newish to python, and working on modeling of the CV-19 outbreak in the UK.
Currently I am writting a program to automatically download the UK governments latest death statistics.
Here is my code so far:
import wget
url = "https://coronavirus.data.gov.uk/downloads/csv/coronavirus-cases_latest.csv"#
wget.download(url, 'C:/Users/Moshe/Downloads/Covid_19_uk_timeseries.csv')
Running this in pycharm I get:
C:\Users\Moshe\PycharmProjects\HelloWorld\venv\Scripts\python.exe C:/Users/Moshe/.PyCharmCE2019.1/config/scratches/Get_CV19_UK_stats.py
Traceback (most recent call last):
File "C:/Users/Moshe/.PyCharmCE2019.1/config/scratches/Get_CV19_UK_stats.py", line 6, in <module>
wget.download(url, 'C:/Users/Moshe/Downloads/Covid_19_uk_timeseries.csv')
File "C:\Users\Moshe\PycharmProjects\HelloWorld\venv\lib\site-packages\wget.py", line 526, in download
(tmpfile, headers) = ulib.urlretrieve(binurl, tmpfile, callback)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 247, in urlretrieve
with contextlib.closing(urlopen(url, data)) as fp:
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 531, in open
response = meth(req, response)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 641, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 569, in error
return self._call_chain(*args)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 503, in _call_chain
result = func(*args)
File "C:\Users\Moshe\AppData\Local\Programs\Python\Python37\lib\urllib\request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 308: Permanent Redirect
Process finished with exit code 1
The file I am trying to get can be found on this page:
https://coronavirus.data.gov.uk/?_ga=2.157835066.1251021075.1589887735-1783596499.1585566366
Why won't this work? and what do i need to change?
Can you verify that your output path is valid and writeable?
try
import wget
import os
output_dir = 'C:/Users/Moshe/Downloads'
output_file = 'Covid_19_uk_timeseries.csv'
assert os.path.exists(output_dir)
url = "https://coronavirus.data.gov.uk/downloads/csv/coronavirus-cases_latest.csv"#
wget.download(url, out = os.path.join(output_dir,output_file))
from googlefinance import getQuotes
print(getQuotes("NSE:M\&MFIN"),)
The ampersand is being treated as code but I want to treat it as text; I get a bad request exception:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/.../site-packages/googlefinance/__init__.py", line 70, in getQuotes
content = json.loads(request(symbols))
File "/.../site-packages/googlefinance/__init__.py", line 33, in request
resp = urlopen(req)
File "/.../urllib/request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "/.../urllib/request.py", line 532, in open
response = meth(req, response)
File "/.../urllib/request.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File "/.../urllib/request.py", line 570, in error
return self._call_chain(*args)
File "/.../urllib/request.py", line 504, in _call_chain
result = func(*args)
File "/.../urllib/request.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request
I tried to escape it (using a \) but this did not work either.
How can I treat this ampersand as text?
The library is rather naive in that it just appends the symbols to a URL without proper encoding, see the source code:
def buildUrl(symbols):
symbol_list = ','.join([symbol for symbol in symbols])
# a deprecated but still active & correct api
return 'http://finance.google.com/finance/info?client=ig&q=' \
+ symbol_list
You can work around this by manually quoting up front, using the urllib.parse.quote() function:
from urllib.parse import quote
print(getQuotes(quote("NSE:M&MFIN")))
Demo:
>>> from googlefinance import getQuotes
>>> from urllib.parse import quote
>>> print(getQuotes(quote("NSE:M&MFIN")))
[{'ID': '11784956', 'StockSymbol': 'M&MFIN', 'Index': 'NSE', 'LastTradePrice': '416.55', 'LastTradeWithCurrency': '₹416.55', 'LastTradeTime': '3:30PM GMT+5:30', 'LastTradeDateTime': '2017-08-18T15:30:00Z', 'LastTradeDateTimeLong': 'Aug 18, 3:30PM GMT+5:30'}]
Anyway, I'm trying to write a simple request to the Amazon API using the following code:
ak = "***"
sk = "***"
at = "***"
import bottlenose
amazon = bottlenose.Amazon(ak, sk, at, "DE")
response=amazon.ItemLookup(ItemId="B00KWAO4CI")
print(response.price_and_currency)
It should return an XML object. Instead I get the following result:
Traceback (most recent call last):
File "simpleamazon.py", line 7, in <module>
response=amazon.ItemLookup(ItemId="B00KWAO4CI")
File "/Library/Python/2.7/site-packages/bottlenose/api.py", line 251, in __call__
{'api_url': api_url, 'cache_url': cache_url})
File "/Library/Python/2.7/site-packages/bottlenose/api.py", line 212, in _call_api
return urllib2.urlopen(api_request, timeout=self.Timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 475, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
Up until recently I received HTTP Error 400 instead. To my knowledge I haven't changed anything. I've also tried using response groups, but it resulted in the same error(s).
Do you have any leads?
Using Python 3.5.2
I'm setting my jenkins environment and, as part of this process, I need to create a slave node.
Bellow follow the script that is crashing:
import jenkins
server = jenkins.Jenkins('http://localhost:9090')
server.create_node('slave')
Follows the output:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/jenkins/__init__.py", line 1156, in create_node
self._build_url(CREATE_NODE, params), b''))
File "/usr/local/lib/python2.7/dist-packages/jenkins/__init__.py", line 341, in jenkins_open
response = urlopen(req, timeout=self.timeout).read()
File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 410, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 448, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 400: Bad Request
Use jenkinsapi module,
from jenkinsapi.jenkins import Jenkins
server = Jenkins('http://localhost:9090')
server.create_node('slave')
It appears to be a bug in python-jenkins 0.4.11, which was fixed by commit
302eb5dad6439842e076fead5bd76f20f615e6a8.
I got a similar error, upgrading python-jenkins fixed it.
I try to learn python network programming from book "Foundation of Python Network Programming" Apres,
first we learn about 'virtualenv' and I install virtualenv , try to get 'googlemap package' and try using simple program call 'search1' :
#!/usr/bin/env python
# Foundations of Python Network Programming - Chapter 1 - search1.py
from googlemaps import GoogleMaps
address = '207 N. Defiance St, Archbold, OH'
print GoogleMaps().address_to_latlng(address)
after that I try running it,
the result from the book is
$ python search1.py
(41.5228242, -84.3063479)
the result I get is error liket this
Traceback (most recent call last):
File "search1.py", line 6, in
print GoogleMaps().address_to_latlng(address)
File "/home/administrator/gmapenv/local/lib/python2.7/site-packages/googlemaps.py", line 310, in address_to_latlng
return tuple(self.geocode(address)['Placemark'][0]['Point']['coordinates'][1::-1])
File "/home/administrator/gmapenv/local/lib/python2.7/site-packages/googlemaps.py", line 259, in geocode
url, response = fetch_json(self._GEOCODE_QUERY_URL, params=params)
File "/home/administrator/gmapenv/local/lib/python2.7/site-packages/googlemaps.py", line 50, in fetch_json
response = urllib2.urlopen(request)
File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 407, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 520, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 445, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 379, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 528, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
What make this error , because it I run down step by step like in the book