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KNN Classifier Python

I am currently using the scikit learn module in order to help with a crime prediction problem. I am having an issue batch coding the entire Dataframe that I have with the knn.predict method.
How can I batch code the entire two columns of my Dataframe with the knn.predict() method in order to store in another Dataframe the output?
import numpy as np
import pandas as pd
from sklearn.model_selection import train_test_split
knn_df = pd.read_csv("/Users/helenapunset/Desktop/knn_dataframe.csv")
# x is the set of features
x = knn_df[['latitude', 'longitude']]
# y is the target variable
y = knn_df['Class']
# train and test data
x_train, x_test, y_train, y_test = train_test_split(x, y, random_state=0)
from sklearn.neighbors import KNeighborsClassifier
knn = KNeighborsClassifier(n_neighbors = 5)
# training the data
knn.fit(x_train,y_train)
# test score was approximately 69%
knn.score(x_test,y_test)
# this is predicted to be a safe zone
crime_prediction = knn.predict([[25.787882, -80.358427]])
print(crime_prediction)
In the last line of the code I was able to add the two features I am using which are latitude and longitude from my Dataframe labeled knn_df. But, this is a single point I have been searching through the documentation on a process for streamlining this knn prediction for the entire Dataframe and cannot seem to find a way to do this. Is there somehow a possibility of using a for loop for this?

Let the new set to be predicted is 'knn_df_predict'. Assuming same column names,try the following lines of code :
x_new = knn_df_predict[['latitude', 'longitude']] #formating features
crime_prediction = knn.predict(x_new) #predicting for the new set
knn_df_predict['prediction'] = crime_prediction #Adding the prediction to dataframe

How to create a train_test_split based on a conditional in python

I know how to utilize a basic train_test_split:
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=123)
However, what if I want to divide my training and testing set by a variable, in this case year. I want all values where year==2019 to be my test set while year<2019 is my training set. How can I alter the code above to make that happen?

Let me explain with an example:
If your corpus have 1000 data points and you want 700/300 for train/test, find data points with year == 2019 take (move) them to the end of the corpus and consider them as test data with something like bellow: (suppose 200 data point satisfy year == 2019 condition)
X_test, y_test = X[800:1000], y[800:1000]
and for example 300 data points have year < 2019 after moving them to top:
X_train, y_train = X[0:300], y[0:300]
Now for rest of your corpus (from 300 to 800) redefine X and Y like:
X = data.iloc[301:799]
Y = label.iloc[301:799]
and then use train_test_split for new X and Y and join new X_test, y_test, X_train, y_train with the previous ones.

How to make machine learning predictions for empty rows?

I have a dataset that shows whether a person has diabetes based on indicators, it looks like this (original dataset):
I've created a straightforward model in order to predict the last column (Outcome).
#Libraries imported
import pandas as pd
from sklearn.preprocessing import StandardScaler
from sklearn.model_selection import train_test_split
from sklearn.linear_model import LogisticRegression
#Dataset imported
data = pd.read_csv('diabetes.csv')
#Assign X and y
X = data.iloc[:,:-1].values
y = data.iloc[:,-1].values
#Data preprocessed
sc = StandardScaler()
X = sc.fit_transform(X)
#Dataset split between train and test
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.2, random_state = 0)
model = LogisticRegression()
model.fit(X_train, y_train)
y_pred = model.predict(X_test)
# Predicting the results for the whole dataset
y_pred2 = model.predict(data)
#Add prediction column to original dataset
data['prediction'] = y_pred2
However, I get the following error: ValueError: X has 9 features per sample; expecting 8.
My questions are:
Why can't I create a new column with the predictions for my entire dataset?
How can I make predictions for blank outcomes (that need to be predicted), that is to say, should I upload the file again? Let's say I want to predict the folowing:
Rows to predict:
Please let me know if my questions are clear!

You are feeding data (with all 9 initial features) to a model that was trained with X (8 features, since Outcome has been removed to create y), hence the error.
What you need to do is:
Get predictions using X instead of data
Append the predictions to your initial data set
i.e.:
y_pred2 = model.predict(X)
data['prediction'] = y_pred2
Keep in mind that this means that your prediction variable will come from both data that have already been used for model fitting (i.e. the X_train part) as well as from data unseen by the model during training (the X_test part). Not quite sure what your final objective is (and neither this is what the question is about), but this is a rather unusual situation from an ML point of view.
If you have a new dataset data_new to predict the outcome, you do it in a similar way; always assuming that X_new has the same features with X (i.e. again removing the Outcome column as you have done with X):
y_new = model.predict(X_new)
data_new['prediction'] = y_new

LinearRegression in Python giving incorrect results?

I have a comma-separated CSV file with two numerical columns - inputs and outputs. They are correlated in a (more or less linear function), see below. The sample I have is very small.
Below, is the Python code I wrote using sklearn in order to predict values. Somehow it's not giving me the correct values (reasonable predictions). I am quite new to this, so please bear with me.
import pandas as pd
data = pd.read_csv("data.csv", header=None, names=['kg', 'cm'])
labels = data['kg']
train1 = data.drop(['kg'], axis=1) # In all honesty, I don't understand this.
from sklearn.cross_validation import train_test_split
x_train, x_test, y_train, y_test = train_test_split(train1, labels, test_size=0.10, random_state=2)
from sklearn.linear_model import LinearRegression
reg = LinearRegression()
reg.fit(x_train, y_train)
reg.score(x_test, y_test)
reg.predict(80) # Gives an incorrect value of about 108.
Data.
89,155
86,161
82.5,168
79.25,174
76.25,182
73,189
70,198
66.66,207
63.5,218
60.25,229
57,241
54,257
51,259

Actually you are having problem understanding your own code.
import pandas as pd
data = pd.read_csv("data.csv", header=None, names=['kg', 'cm'])
labels = data['kg']
train1 = data.drop(['kg'], axis=1) # In all honesty, I don't understand this.
Until here what you have done is that you have loaded the dataframe. After that you seprated X and y from the dataset.
labels represent the y values.
train1 represent the x values.
Since you wrote you can't understand :- train1 = data.drop(['kg'], axis=1)
Let me explain this. What this does is that from the dataframe which consist both column 'kg' and 'cm'. It removes 'kg' column (axis = 1 means column, axis = 0 means row). Hence only 'cm' is remaining which is your x.
from sklearn.cross_validation import train_test_split
x_train, x_test, y_train, y_test = train_test_split(train1, labels, test_size=0.10, random_state=2)
from sklearn.linear_model import LinearRegression
reg = LinearRegression()
reg.fit(x_train, y_train)
reg.score(x_test, y_test)
reg.predict(80) # Gives an incorrect value of about 108.
Now you train the model on x values which represents 'cm' and y values which represent 'kg'.
When you predict(80) what happens is that you input the 'cm' value to be 80. Let me just plot the 'cm' vs 'kg' for training data.
When you input height as 80 this means that you are going more left, even more left than your plot. Hence as you can see x decrease y increase. It means that as 'cm' decrease means 'kg' increase. Hence ouput is 110 which is more.

from io import StringIO
input_data=StringIO("""89,155\n
86,161\n
82.5,168\n
79.25,174\n
76.25,182\n
73,189\n
70,198\n
66.66,207\n
63.5,218\n
60.25,229\n
57,241\n
54,257\n
51,259""")
import pandas as pd
data = pd.read_csv(input_data, header=None, names=['kg', 'cm'])
labels = data['cm']
train1 = data.drop(['cm'], axis=1) #This is similar to selecting the kg column
from sklearn.model_selection import train_test_split
x_train, x_test, y_train, y_test = train_test_split(train1, labels, test_size=0.10, random_state=2)
from sklearn.linear_model import LinearRegression
reg = LinearRegression()
reg.fit(x_train, y_train)
reg.score(x_test, y_test)
import numpy as np
reg.predict(np.array([80]).reshape(-1, 1)) # 172.65013306.

I think you are having problems with small data size. The code flow looks normal to me, I would suggest you try to find the p-value for the input-output. This will tell you if the correlation found from your linear regression is significant or not (p-value <0.05).
You can find p-value using:
from scipy.stats import linregress
print(linregress(input, output))
To find p-value using scikit learn you probably need to use the formula to find p-value. Good luck.

scikit-learn: how to scale back the 'y' predicted result

I'm trying to learn scikit-learn and Machine Learning by using the Boston Housing Data Set.
# I splitted the initial dataset ('housing_X' and 'housing_y')
from sklearn.cross_validation import train_test_split
X_train, X_test, y_train, y_test = train_test_split(housing_X, housing_y, test_size=0.25, random_state=33)
# I scaled those two datasets
from sklearn.preprocessing import StandardScaler
scalerX = StandardScaler().fit(X_train)
scalery = StandardScaler().fit(y_train)
X_train = scalerX.transform(X_train)
y_train = scalery.transform(y_train)
X_test = scalerX.transform(X_test)
y_test = scalery.transform(y_test)
# I created the model
from sklearn import linear_model
clf_sgd = linear_model.SGDRegressor(loss='squared_loss', penalty=None, random_state=42)
train_and_evaluate(clf_sgd,X_train,y_train)
Based on this new model clf_sgd, I am trying to predict the y based on the first instance of X_train.
X_new_scaled = X_train[0]
print (X_new_scaled)
y_new = clf_sgd.predict(X_new_scaled)
print (y_new)
However, the result is quite odd for me (1.34032174, instead of 20-30, the range of the price of the houses)
[-0.32076092 0.35553428 -1.00966618 -0.28784917 0.87716097 1.28834383
0.4759489 -0.83034371 -0.47659648 -0.81061061 -2.49222645 0.35062335
-0.39859013]
[ 1.34032174]
I guess that this 1.34032174 value should be scaled back, but I am trying to figure out how to do it with no success. Any tip is welcome. Thank you very much.

You can use inverse_transform using your scalery object:
y_new_inverse = scalery.inverse_transform(y_new)

Bit late to the game:
Just don't scale your y. With scaling y you actually loose your units. The regression or loss optimization is actually determined by the relative differences between the features. BTW for house prices (or any other monetary value) it is common practice to take the logarithm. Then you obviously need to do an numpy.exp() to get back to the actual dollars/euros/yens...