I have an array with 4 integer elements for example [1,0,1,0]
I want to convert it into string '1010'
How do that?
I've tried this
b=''.join(str(syndrome_noised.T))
print(b)
but I got '[1,0,1,0]'.
How this string without brackets.
The reason this fails is because you apply str(..) to the matrix. This will generate a single string. This string is however iterable, so you ''.join(..) the characters of that string back together, turning it into the original string again.
What you probably need to do, is convert every single element into a string, and then join these together, like:
b = ''.join(str(x) for x in syndrome_noised.T)
We thus iterate over the elements x in the syndrome_noised.T array, and we each time map it to a str(..), we then join these together.
We can shorten the code a bit, but still have the same semantics, with map:
b = ''.join(map(str, syndrome_noised.T))
syndrome_noised = [1,0,1,0]
''.join(str(x) for x in syndrome_noised)
you could do this by using a for loop like below:
text = str()
for i in array:
text += str(i)
print(text)
and that would return 1010
Related
I am working on an IPV4 breakdown where I have the necessary values in a string variable to represent the binary
(example: 00000000.00000000.00001111.11111111) This is a string
I need a way to turn this string into binary to then properly convert it to it's proper integer value
(in this case 0.0.15.255)
I've seen posts asking about something similar but attempting to apply it to what I'm working on has been unsuccessful
Apologies if this made no sense this is my first time posing a question here
You can achieve this using int() with base argument.
You can know more about int(x,base) - here
Split the string at '.' and store it in a list lst
For every item in lst, convert the item (binary string) to decimal using int(item, base=2) and then convert it into string type.
Join the contents of lst using .
s = '00000000.00000000.00001111.11111111'
lst = s.split('.')
lst = [str(int(i,2)) for i in lst]
print('.'.join(lst))
# Output
0.0.15.255
First split the string on . then convert each to integer equivalent of the binary representation using int builtin passing base=2, then convert to string, finally join them all on .
>>> text = '00000000.00000000.00001111.11111111'
>>> '.'.join(str(int(i, base=2)) for i in text.split('.'))
# output
'0.0.15.255'
You should split the data, convert and combine.
data = "00000000.00000000.00001111.11111111"
data_int = ".".join([str(int(i, 2)) for i in data.split(".")])
print(data_int) # 0.0.15.255
Welcome! Once you have a string like this
s = '00000000.00000000.00101111.11111111'
you may get your integers in one single line:
int_list = list(map(lambda n_str: int(n_str, 2), s.split('.')))
For example, is it possible to convert the input
x = 10hr
into something like
y = 10
z = hr
I considering slicing, but the individual parts of the string will never be of a fixed length -- for example, the base string could also be something like 365d or 9minutes.
I'm aware of split() and re.match which can separate items into a list/group based on delimitation. But I'm curious what the shortest way to split a string containing a string and an integer into two separate variables is, without having to reassign the elements of the list.
You could use list comprehension and join it as a string
x='10hr'
digits="".join([i for i in x if not i.isalpha()])
letters="".join([i for i in x if i.isalpha()])
You don't need some fancy function or regex for your use case
x = '10hr'
i=0
while x[i].isdigit():
i+=1
The solution assumes that the string is going to be in format you have mentioned: 10hr, 365d, 9minutes, etc..
Above loop will get you the first index value i for the string part
>>i
2
>>x[:i]
'10'
>>x[i:]
'hr'
I have the following array:
a =['1','2']
I want to convert this array into the below format :
a=[1,2]
How can I do that?
You can do it like that. You change each element of a (which are strings) in an integer.
a=[int(x) for x in a]
This single inverted comma you are talking about is the difference between str and int. This is pretty basic python stuff.
A string is a characters, displayed with the inverted comma's around it. 'Hello' is a string, but '1' can be a string too.
In you case ['1','2'] is a list of strings, and [1,2] is a list of numbers.
To convert a string to an int, you can do what is called casting. This is converting one type to another (They have to be compatible though.) Casting 'hello' to a number doesn't make sense and won't work.
Casting '1' to a number is possible by calling int('1') which will result in 1
In your case you can cast all elements in you list by calling a = [int(x) for x in a].
For more info on types see this article.
For information on list comprehensions (What I used to change your list) see this article.
Say we have an numpy.ndarray with numpy.str_ elements. For example, below arr is the numpy.ndarray with two numpy.str_ elements like this:
arr = ['12345"""ABCDEFG' '1A2B3C"""']
Trying to perform string slicing on each numpy element.
For example, how can we slice the first element '12345"""ABCDEFG' so that we replace its 10 last characters with the string REPL, i.e.
arr = ['12345REPL' '1A2B3C"""']
Also, is it possible to perform string substitutions, e.g. substitute all characters after a specific symbol?
Strings are immutable, so you should either create slices and manually recombine or use regular expressions. For example, to replace the last 10 characters of the first element in your array, arr, you could do:
import numpy as np
import re
arr = np.array(['12345"""ABCDEFG', '1A2B3C"""'])
arr[0] = re.sub(arr[0][-10:], 'REPL', arr[0])
print(arr)
#['12345REPL' '1A2B3C"""']
If you want to replace all characters after a specific character you could use a regular expression or find the index of that character in the string and use that as the slicing index.
EDIT: Your comment is more about regular expressions than simply Python slicing, but this is how you could replace everything after the triple quote:
re.sub('["]{3}(.+)', 'REPL', arr[0])
This line essentially says, "Find the triple quote and everything after it, but only replace every character after the triple quotes."
In python, strings are immutable. Also, in NumPy, array scalars are immutable; your string is therefore immutable.
What you would want to do in order to slice is to treat your string like a list and access the elements.
Say we had a string where we wanted to slice at the 3rd letter, excluding the third letter:
my_str = 'purple'
sliced_str = my_str[:3]
Now that we have the part of the string, say we wanted to substitute z's for every letter following where we sliced. We would have to work with the new string that pulled out the letters we wanted, and create an additional string with the desired string that we want to create:
# say I want to replace the end of 'my_str', from where we sliced, with a string named 's'
s = 'dandylion'
new_string = sliced_str + s # returns 'pudandylion'
Because string types are immutable, you have to store elements you want to keep, then combine the stored elements with the elements you would like to add in a new variable.
np.char has replace function, which applies the corresponding string method to each element of the array:
In [598]: arr = np.array(['12345"""ABCDEFG', '1A2B3C"""'])
In [599]: np.char.replace(arr,'"""ABCDEFG',"REPL")
Out[599]:
array(['12345REPL', '1A2B3C"""'],
dtype='<U9')
In this particular example it can be made to work, but it isn't nearly as general purpose as re.sub. Also these char functions are only modestly faster than iterating on the array. There are some good examples of that in #Divakar's link.
I am trying to find the sum of all numbers in a list but every time I try I get an error that it cannot convert the string to float. Here is what I have so far.
loop = True
float('elec_used')
while (loop):
totalelec = sum('elec_used')
print (totalelec)
loop = False
You need none of your code above. The while loop is unnecessary and it looks like its just exiting the loop in one iteration i.e. its not used correctly. If you're simply summing all the values in the list:
sum([float(i) for i in elec_used])
If this produces errors, please post your elec_used list. It probably contains string values or blank spaces.
'elec_used' is of type string of characters. You can not convert characters to the float. I am not sure why you thought you could do it. However you can convert the numeric string to float by typecasting it. For example:
>>> number_string = '123.5'
>>> float(number_string)
123.5
Now coming to your second part, for calculating the sum of number. Let say your are having the string of multiple numbers. Firstly .split() the list, type-cast each item to float and then calculate the sum(). For example:
>>> number_string = '123.5 345.7 789.4'
>>> splitted_num_string = number_string.split()
>>> number_list = [float(num) for num in splitted_num_string]
>>> sum(number_list)
1258.6
Which could be written in one line using list comprehension as:
>>> sum(float(item) for item in number_string.split())
1258.6
OR, using map() as:
>>> sum(map(float, number_string.split()))
1258.6