I'm newly introduced to Python but I am now currently stuck with this code of mine where I just can't get the average guess game per game to work. If I could receive some help from you guys that'll be great! I would also love to hear any constructive feedback if there's any. Thank you!!
# A robust number-guessing game with hinting.
import random
total_guess = 0
num_games = 0
num_guesses = 0
print("Welcome to Guessing Game!")
print()
reply = input("Are you ready to play (Y or N)?").upper()
while reply != "Y" and reply != "N":
print("Invalid response")
reply = input("Another game (Y or N)? ").upper()
while reply == "Y":
# pick a random number from 0 to 100 (both inclusive)
# There is no error in the line below, which is
# equivalent to
# number = random.randint(0, 100)
number = random.randrange(0, 101)
# make it different from number so that it goes into loop
guess = number + 1
while guess != number :
guess = int(input("Your guess (0 - 100)? "))
num_guesses += 1
if guess < number :
print("Your guess is too low")
elif guess > number :
print("Your guess is too high")
else:
print("Bingo!")
# collect the statistics to calculate average guess per game
total_guess += num_guesses
num_games += 1
print("You got it right in " + str(num_guesses) + " tries.")
num_guesses = 0
print()
reply = input("Another game (Y or N)? ").upper()
while reply != "Y" and reply != "N":
print("Invalid response")
reply = input("Another game (Y or N)? ").upper()
print("Your average guess per game is", total_guess/num_games)
Your code was not properly indented.
import random
total_guess = 0
num_games = 0
num_guesses = 0
print("Welcome to Guessing Game!")
print()
reply = input("Are you ready to play (Y or N)?").upper()
while reply != "Y" and reply != "N":
print("Invalid response")
reply = input("Another game (Y or N)? ").upper()
while reply == "Y":
number = random.randrange(0, 11)
# make it different from number so that it goes into loop
guess = number + 1
while guess != number :
guess = int(input("Your guess (0 - 100)? "))
num_guesses += 1
if guess < number :
print("Your guess is too low")
elif guess > number :
print("Your guess is too high")
else:
print("Bingo!")
# collect the statistics to calculate average guess per game
total_guess += num_guesses
num_games += 1
print("You got it right in " + str(num_guesses) + " tries.")
num_guesses = 0
print()
reply = input("Another game (Y or N)? ").upper()
while reply != "Y" and reply != "N":
print("Invalid response")
reply = input("Another game (Y or N)? ").upper()
print("Your average guess per game is", total_guess/num_games)
Related
I am working on Guess the number program in Python. I had to make some enhancements to it and add:
User has a default limit of 15 guesses (when enter key is hit)
Ask for a limit to the number of guests - this part doesn't work in my code.
import random
def main():
print('\n'*40)
print('Welcome to the Guess number game!')
print('\n'*1)
player_name = input("What is your name? ") print('\n'*1)
try_again = 'y'
number_of_guesses = 0
error = 0
guess_limit = 15
while ((try_again == 'y') or (try_again == 'Y')):
try:
limit = input('You have 15 default guesses to start. Do you like to have different number of guesses? ')
if limit.upper() == 'Y':
limit = input('How many times would you like to play? ') # after I input number of guesses I cannot proceed to the actual game
else:
number = random.randint(1, 100)
while (guess_limit != 0):
guess = int(input("Enter an integer from 1 to 100: "))
if (guess < 1) or (guess > 100):
print("ERROR! Integer must be in the range 1-100! ")
else:
if guess < number:
print ("Guess is low!")
elif guess > number:
print ("Guess is high!")
else:
print('\n'*1)
print ("YOU WIN! You made " + str(number_of_guesses) + " guesses.")
break
number_of_guesses += 1
guess_limit -= 1
print(guess_limit, 'guesses left')
print()
else:
#if guess_limit == 0:
print ("YOU LOSE! You made " + str(number_of_guesses) + " guesses.")
except ValueError:
print('ERROR: Non-numeric data. Please enter valid number!')
print('\n'*1)
try_again = input("Play again? Enter 'Y' or 'y' for yes: ")
print('\n'*1)
main()
OUTPUT: Welcome to the Guess number game!
What is your name? d
You have 15 default guesses to start.
Do you like to have different number of guesses? y
How many times would you like to play? 3 # after this I have
Play again? Enter 'Y' or 'y' for yes: # this result
How can I change that code?
you have to use
guess_limit = input("How many times would you like to play? ")
and then you have to check if it is blank or not by simple if conditions
if guess_limit == "":
guess_limit = 15
Below is the full code with well commented.
# import only system from os
from os import system
import random
def main():
# For clearing the screen
system('cls')
# For adding blank line
blank_line = '\n'*1
print('Welcome to the Guess number game!')
print(blank_line)
player_name = input("What is your name? ")
print(blank_line)
# to start the loop initially try_again = 'y'
try_again = 'y'
# Count number of guesses by player
number_of_guesses = 0
while (try_again.lower() == 'y'):
# Get number of times player want to guess
guess_limit = input("How many times would you like to play? ")
# If player enter nothing and hit enter
# then default value of guess_limit is 15
if guess_limit == "":
guess_limit = 15
# Convert the guess_limit to int data type
guess_limit = int(guess_limit)
# If user inputted number then go inside this try block
# else go inside except block
try:
# Generate random number in betwee 1-99 to be guess by the player
number = random.randint(1, 99)
# Loop untill there is no guesses left
while (guess_limit != 0):
# Player guess
guess = int(input("Enter an integer from 1 to 99: "))
# Check for valid number i.e number should be betwee 1 - 99
while ((guess < 1) or (guess > 99)):
guess = int(
input("ERROR! Please enter an integer in the range from 1 to 99: "))
# Check for High and low guess
if guess < number:
print("Guess is low")
elif guess > number:
print("Guess is high")
# If it is neither high nor low
else:
print(blank_line)
print("YOU WIN! You made " +
str(number_of_guesses) + " guesses.")
# To get out of the loop
break
# decrement the guess_limit by 1 on every iteration
guess_limit -= 1
print(guess_limit, 'guesses left')
# Increment number of guesses by the player
number_of_guesses += 1
print()
# If guess_limit is equal to 0, it means player have not guessed the number
# And player lose
if guess_limit == 0:
print("YOU LOSE! You made " +
str(number_of_guesses) + " guesses.")
except ValueError:
print('ERROR: Non-numeric data. Please enter valid number!')
print(blank_line)
# Ask again to play again
# If player enter anything other than 'Y' or 'y' then exit the game
try_again = input("Play again? Enter 'Y' or 'y' for yes: ")
print(blank_line)
main()
I am creating a python random counting game. I'm having some difficulties with certain parts. Can anyone here review my code? I'm having difficulty with trying to implement a try/except and a tries function that counts the user's attempts. I also have to verify that the number is a legitimate input and not a variable. So far I've gotten this far and its coming along good. I just need alittle help ironing out a few things. Thanks guys you rock.
Here is the code below:
import random
def main():
start_game()
play_again()
tries()
print("Welcome to the number guessing game")
print("I'm thinking of a number between 1 and 50")
def start_game():
secret_number = random.randint(1,50)
user_attempt_number = 1
user_guess = 0
while user_guess != secret_number and user_attempt_number < 5:
print("---Attempt", user_attempt_number)
user_input_text = input("Guess what number I am thinking of: ")
user_guess = int(user_input_text)
if user_guess > secret_number:
print("Too high")
elif user_guess < secret_number:
print("Too low")
else:
print("Right")
user_attempt_number += 1
if user_guess != secret_number:
print("You ran out of attempts. The correct number was"
+str(secret_number)+ ".")
def play_again():
while True:
play_again = input("Do you want to play again?")
if play_again == 'yes':
main()
if play_again =='no':
print("Thanks for playing")
break
def tries():
found= False
max_attempts=50
secret_number = random.randint(1, 50)
while tries <= max_attempts and not found:
user_input_text = start_game()
user_guess_count=+1
if user_input_text == secret_number:
print("It took you {} tries.".format(user_guess_count))
found = True
main()
Try this method:
def play_game():
print("Enter the upper limit for the range of numbers: ")
limit = int(input())
number = random.randint(1, limit)
print("I'm thinking of a number from 1 to " + str(limit) + "\n")
count = 1 #new line
while True:
guess = int(input("Your guess: "))
if guess < number:
print("Too low.")
elif guess > number:
print("Too high.")
elif guess == number:
print("You guessed it in " + str(count) + " tries.\n")
count = count+
Im getting a syntax error for elif option ==2:. I was wondering what I need to do to fix it. I followed the pseudocode my professor gave us but it still won't run. I'm wondering if I shouldn't have used elif or maybe something about the indentation is off.
import random
print("Welcome to the guess my number program")
while True:
print("1. You guess the number")
print("2. You type a number and see if the computer can guess it")
print("3. Exit")
option = int(input("Please enter your number here: "))
if option ==1:
#generates a random number
mynumber = random.randint(1,11)
#number of guesses
count = 1
while True:
try:
guess = int(input("Guess a number between 1 and 10:"))
while guess < 1 or guess > 10:
guess = int(input("Guess a number between 1 and 10:")) # THIS LINE HERE
except:
print("Numbers Only")
continue
#prints if the number you chose is too low and adds 1 to the counter
if guess < mynumber:
print("The number you chose is too low")
count= count+1
#prints if the number you chose is too high and adds 1 to the counter
elif guess > mynumber:
print("The number you choose is too high")
count = count+1
#If the number you chose is correct it will tell you that you guessed the number and how many attempts it took
elif guess == mynumber:
print("You guessed it in " , count , "attempts")
break
elif option == 2:
number = int(input("Please Enter a Number: "))
count = 1
while True:
randomval = random.randint(1,11)
if (number < randomval):
print("Too high")
elif (number > randomval):
print("Too low")
count = count+1
elif (number==randomval):
print("The computer guessed it in" + count + "attempts. The number was" + randomval)
break
else:
break
The problem is simple. There is no continuity between if option == 1 and elif option == 2, because of the in between while loop. What you have to do is remove the el part of elif option == 2 and just write if option == 2.
I haven't tested the whole program myself. But at a glance, this should rectify the problem.
Please comment if otherwise.
I have the following code for a random number guessing game:
import random
number = random.randint(1,100)
name = input('Hi, Whats your name?')
print ("Well", name, "i am thinking of a number between 1 and 100, take a guess")
guess1 = input()
if guess1 == number:
print ("Good job, you got it!")
while guess1 != number:
if guess1 > number:
print ('your guess is too high')
if guess1 < number:
print ('your guess is too low')
which throws the error that > or < cannot be used between str and int.
What should I do so it doesn't trigger that error?
There are two errors in your code.
You need to convert the input for guess1 from a string (by default) to an integer before you can compare it to the number (an integer).
The while loop will never stop since you are not letting the user input another value.
Try this:
import random
number = random.randint(1,100)
name = input('Hi, Whats your name?')
print ("Well", name, "i am thinking of a number between 1 and 100, take a guess")
guess1 = int(input()) # convert input from string to integer
while guess1 != number:
if guess1 > number:
print ('your guess is too high. Try again.')
elif guess1 < number:
print ('your guess is too low. Try again.')
guess1 = int(input()) # asks user to take another guess
print("Good job, you got it!")
You can make use of a while loop here - https://www.tutorialspoint.com/python/python_while_loop.htm
The logic should be:
answer_is_correct = False
while not answer_is_correct :
Keep receiving input until answer is correct
I hope this works for you:
import random
myname = input('Hello, what is your name?')
print('Well',myname,'am thinking of a number between 1 and 100')
number = random.randint(1,100)
guess = 0
while guess < 4:
guess_number = int(input('Enter a number:'))
guess += 1
if guess_number < number:
print('Your guess is to low')
if guess_number > number:
print('Your guess is to high')
if guess_number == number:
print('Your guess is correct the number is',number)
break
if guess == 4:
break
print('The number i was thinking of is',number)
from random import randint
print("you wanna guess a number between A to B and time of guess:")
A = int(input("A:"))
B = int(input("B:"))
time = int(input("time:"))
x = randint(1, 10)
print(x)
while time != 0:
num = int(input("Enter: "))
time -= 1
if num == x:
print("BLA BLA BLA")
break
print("NOPE !")
if time == 0:
print("game over")
break
Code in Python 3 for guessing game:
import random
def guessGame():
while True:
while True:
try:
low, high = map(int,input("Enter a lower number and a higher numer for your game.").split())
break
except ValueError:
print("Enter valid numbers please.")
if low > high:
print("The lower number can't be greater then the higher number.")
elif low+10 >= high:
print("At least lower number must be 10 less then the higher number")
else:
break
find_me = random.randint(low,high)
print("You have 6 chances to find the number...")
chances = 6
flag = 0
while chances:
chances-=1
guess = int(input("Enter your guess : "))
if guess<high and guess>low:
if guess < find_me:
print("The number you have entered a number less then the predicted number.",end="//")
print("{0} chances left.".format(chances))
elif guess > find_me:
print("The number you have entered a number greater then the predicted number.",end="//")
print("{0} chances left.".format(chances))
else:
print("Congrats!! you have succesfully guessed the right answer.")
return
else:
print("You must not input number out of range")
print("{0} chances left.".format(chances))
print("The predicted number was {0}".format(find_me))
You can conditions within the while loop to check if its right. It can be done the following way.
import random
print('Hello! What is your name?')
myName = input()
number = random.randint(1, 100)
print('Well, ' + myName + ', I am thinking of a number between 1 and 100.')
inputNumber = int(raw_input('Enter the number')
while inputNumber != number:
print "Sorry wrong number , try again"
inputNumber = int(raw_input('Enter the number')
print "Congrats!"
from random import *
def play_game():
print("Let's play a number guessing game")
# Selecting a random number between 1 and 100
number = randint(1, 100)
choice = int(input("I am thinking of a number between 1 and 100. Could you guess what it is? "))
# Guide the user towards the right guess
# Loop will continue until user guesses the right number
while choice != number:
if choice < number:
choice = int(input("Too low. Can you try again? "))
elif choice > number:
choice = int(input("Too high. Can you try again? "))
continue_game = input("You guessed it right! Would you like to play it again? (Y/N) ")
# Restart the game if user wishes to play again
if continue_game == "Y":
print("--" * 42)
play_game()
else:
print("Thanks for playing :)")
exit(0)
play_game()
This question already has answers here:
Ask the user if they want to repeat the same task again
(2 answers)
Closed 4 years ago.
Basically it's a guessing game and I have literally all the code except for the last part where it asks if the user wants to play again. how do I code that, I use a while loop correct?
heres my code:
import random
number=random.randint(1,1000)
count=1
guess= eval(input("Enter your guess between 1 and 1000 "))
while guess !=number:
count+=1
if guess > number + 10:
print("Too high!")
elif guess < number - 10:
print("Too low!")
elif guess > number:
print("Getting warm but still high!")
elif guess < number:
print("Getting warm but still Low!")
guess = eval(input("Try again "))
print("You rock! You guessed the number in" , count , "tries!")
while guess == number:
count=1
again=str(input("Do you want to play again, type yes or no "))
if again == yes:
guess= eval(input("Enter your guess between 1 and 1000 "))
if again == no:
break
One big while loop around the whole program
import random
play = True
while play:
number=random.randint(1,1000)
count=1
guess= eval(input("Enter your guess between 1 and 1000 "))
while guess !=number:
count+=1
if guess > number + 10:
print("Too high!")
elif guess < number - 10:
print("Too low!")
elif guess > number:
print("Getting warm but still high!")
elif guess < number:
print("Getting warm but still Low!")
guess = eval(input("Try again "))
print("You rock! You guessed the number in" , count , "tries!")
count=1
again=str(input("Do you want to play again, type yes or no "))
if again == "no":
play = False
separate your logic into functions
def get_integer_input(prompt="Guess A Number:"):
while True:
try: return int(input(prompt))
except ValueError:
print("Invalid Input... Try again")
for example to get your integer input and for your main game
import itertools
def GuessUntilCorrect(correct_value):
for i in itertools.count(1):
guess = get_integer_input()
if guess == correct_value: return i
getting_close = abs(guess-correct_value)<10
if guess < correct_value:
print ("Too Low" if not getting_close else "A Little Too Low... but getting close")
else:
print ("Too High" if not getting_close else "A little too high... but getting close")
then you can play like
tries = GuessUntilCorrect(27)
print("It Took %d Tries For the right answer!"%tries)
you can put it in a loop to run forever
while True:
tries = GuessUntilCorrect(27) #probably want to use a random number here
print("It Took %d Tries For the right answer!"%tries)
play_again = input("Play Again?").lower()
if play_again[0] != "y":
break
Don't use eval (as #iCodex said) - it's risky, use int(x). A way to do this is to use functions:
import random
import sys
def guessNumber():
number=random.randint(1,1000)
count=1
guess= int(input("Enter your guess between 1 and 1000: "))
while guess !=number:
count+=1
if guess > (number + 10):
print("Too high!")
elif guess < (number - 10):
print("Too low!")
elif guess > number:
print("Getting warm but still high!")
elif guess < number:
print("Getting warm but still Low!")
guess = int(input("Try again "))
if guess == number:
print("You rock! You guessed the number in ", count, " tries!")
return
guessNumber()
again = str(input("Do you want to play again (type yes or no): "))
if again == "yes":
guessNumber()
else:
sys.exit(0)
Using functions mean that you can reuse the same piece of code as many times as you want.
Here, you put the code for the guessing part in a function called guessNumber(), call the function, and at the end, ask the user to go again, if they want to, they go to the function again.
I want to modify this program so that it can ask the user whether or not they want to input another number and if they answer 'no' the program terminates and vice versa. This is my code:
step=int(input('enter skip factor: '))
num = int(input('Enter a number: '))
while True:
for i in range(0,num,step):
if (i % 2) == 0:
print( i, ' is Even')
else:
print(i, ' is Odd')
again = str(input('do you want to use another number? type yes or no')
if again = 'no' :
break