Im living in Germany, where ZIP Codes are in most of the cases a 5 digit number f.e. 53525. I would really like to extract that information from a website using beautiful Soup.
I am new to Python/Beautiful Soup and I am not sure how to translate "Find every 5 Numbers in a row + "SPACE"" into Python language.
import requests
import urllib.request,re
from bs4 import BeautifulSoup
source = requests.get('DOMAIN').text
soup = BeautifulSoup(source, 'lxml')
soup.find_all(NOTSUREHERE)
In the simplest scenario:
NOTSUREHEREshould be replaced by name = 'tag_name', being tag_name a possible tag in which you are certain to find ZIP codes (and no other numerical field that could be mistaken by a ZIP Code)
Then, each element of that object should be passed to re.findall(regex, string) being: regex = '([0-9]{5})' (from what I understand the pattern was) and string the element from which you're extracting ZIP Codes.
import requests
import urllib.request,re
from bs4 import BeautifulSoup
source = requests.get('DOMAIN').text
soup = BeautifulSoup(source, 'lxml')
tag_list = soup.find_all(name = 'tag_name')
match_list = []
for tag in tag_list:
match_list.append(re.findall('([0-9]{5})', str(tag)))
You should watch out for possible matches that aren't ZIP codes. It could be the case of refining the soup.find_all() call by adding more arguments. The documentation might give you even more options, but the attrs argument could be set to {'target_attribute':'target_att_value'} those being an attribute and a value that definitely mark a tag with a ZIP code.
EDIT: Regarding possible empty elements, this link has a very straightforward solution: Removing empty elements from an array in Python
Related
I am trying to retrieve all strings from a webpage using BeautifulSoup and return a list of all the retrieved strings.
I have 2 approaches in mind:
Find all elements who have a text that is not null, append the text to result list and return it. I am having a hard time implementing this as I couldn't find any way to do it in BeautifulSoup.
Use BeautifulSoup's "find_all" method to find all attributes that I am looking for such as "p" for paragraphs, "a" for links etc. The problem I am facing with this approach is that for some reason, find_all is returning a duplicated output. For example, if a website has a link with a text "Get Hired", I am receiving "Get Hired" more than once in the output.
I am honestly not sure how to proceed from here and I have been stuck for several hours trying to figure out how to get all strings form a webpage.
Would really appreciate your help.
Use .stripped_strings to get all the strings with whitespaces stripped off.
.stripped_strings - Read the Docs.
Here is the code that returns a list of strings present inside the <body> tag.
import requests
from bs4 import BeautifulSoup
url = 'YOUR URL GOES HERE...'
r = requests.get(url)
soup = BeautifulSoup(r.text, 'lxml')
b = soup.find('body')
list_of_strings = [s for s in b.stripped_strings]
list_of_strings will have a list of all the strings present in the URL.
Post the code that you've used.
If I remember correctly, something like this should get the complete page in one variable "page" and all the text of the page would be available as page.text
import requests
URL = "https://realpython.github.io/fake-jobs/"
page = requests.get(URL)
print(page.text)
I am building a scraper where I want to extract the data from some tags as it is without any conversion. But Beautifulsoup changing some hex values to ASCII. For example, this code gets converted into ASCII
html = """\
<title>Billing address - PayPal</title>
<title>Billing address - PayPal</title>"""
Here's the small example of the code
from bs4 import BeautifulSoup
soup = BeautifulSoup(html, "lxml")
for element in soup.findAll(['title', 'form', 'a']):
print(str(element))
But I want to extract the data in the same form. I believe BeautifulSoup 4 auto converting HTML entities and this is what I don't want. Any help would be really appreciated.
BTW I am using Python 3.5 and Beautifulsoup 4
you might try using re module ( Regular Expressions ). for an instance the code below will extract the title tag info without converting it: (I assumed that you declared html variable before)
import re
result = re.search('\<title\>.*\<\/title\>',html).group(0)
print(result) # It'll print <title>Billing address - PayPal</title>
You may do the same for the other tags as well
I have to extract specific words from a HTML page and count the number of times the word has been repeated. How do I do this using beautiful soup in python? How do I pass the url in the soup and then count the words ?
This is my code till now. I have no idea what to do next.
import bs4 as bs
import urllib.request
source = urllib.request.urlopen('https://pythonprogramming.net/parsememcparseface/').read()
soup = bs.BeautifulSoup(source,'lxml')
for paragraph in soup.find_all('p'):
print(paragraph.string)
print(str(paragraph.text))
You could get all the text in the page using
soup.get_text()
After setting that to a variable you could then use the .count() method to find the amount that a certain string appears in the HTML page. e.g.
text = soup.get_text()
print (text.count('word'))
To make sure you aren't getting words inside words you could split everything with a space and then look for them in each index of the list. For example 'house' is inside 'houses' would be fixed by this.
I am trying to extract the article text from this article (https://www.vanityfair.com/style/society/2014/06/monica-lewinsky-humiliation-culture) and exclude the legal container in the bottom. The text part seems easy, but can't seem to get rid of the container. I have separated it with the legal variable for easier use.
Here is my code so far:
import requests
from bs4 import BeautifulSoup
base_url = 'https://www.vanityfair.com/style/society/2014/06/monica-lewinsky-humiliation-culture'
r = requests.get(base_url)
r_html = r.text
soup = BeautifulSoup(r_html)
legal = soup.find('div',{'class': 'legal-container'})
paragraphs = soup.find_all('p')
for text in paragraphs:
print text.get_text()
How should I go about this?
Always find the portion you want and see how you can extract that part alone, rather than getting all the text and then eliminating the unwanted ones.
In your case, the text you probably want are grouped in section tags within a div that has a class attribute of content drop-cap. You can get this using:
content_div = soup.find('div', {'class': 'content drop-cap'})
This way, you get the flexibility of grouping the text by sections:
sections = content_div.findAll('section')
However, if you still insist on getting all the paragraphs and exclude the legal container specifically, you can remove the legal container from the soup object.
From BeautifulSoup documentation:
decompose()
Tag.decompose() removes a tag from the tree, then completely destroys
it and its contents
If you choose to do this, then remove the tag(s) you don't want before extracting the text:
soup.find('div', {'class': 'legal-container'}).decompose()
I am using python to extract data from a webpage. The webpage has a reoccurring html div tag with class = "result" which contains other data in it (such as location, organisation etc...). I am able to successfully loop through the html using beautiful soup but when I add a condition such as if a certain word ('NHS' for e.g.) exists in the segment it doesn't return anything - though I know certain segments contain it. This is the code:
soup = BeautifulSoup(content)
details = soup.findAll('div', {'class': 'result'})
for detail in details:
if 'NHS' in detail:
print detail
Hope my question makes sense...
findAll returns a list of tags, not strings. Perhaps convert them to strings?
s = "<p>golly</p><p>NHS</p><p>foo</p>"
soup = BeautifulSoup(s)
details = soup.findAll('p')
type(details[0]) # prints: <class 'BeautifulSoup.Tag'>
You are looking for a string amongst tags. Better to look for a string amongst strings...
for detail in details:
if 'NHS' in str(detail):
print detail