Python Proper JSON Format - python

I need to post data to a REST API. One field, incident_type, needs to be passed in the below JSON format ( must include brackets, can't be just curly brackets ):
"incident_type_ids": [{
"name": "Phishing - General"
}],
When I try to force this in my code, it doesn't come out quite right. There will usually be some extra quote-escapes ( ex. output: "incident_type_ids": "[\\"{ name : Phishing - General }\\"]")and I realized that was because I was double-encoding the JSON data in the incident type variable to forcibly add the brackets ( in line 6 which has since been commented out ):
#incident variables
name = 'Incident Name 2'
description = 'This is the description'
corpID = 'id'
incident_type = '{ name : Phishing - General }'
#incident_type = json.dumps([incident_type])
incident_owner = 'Security Operations Center'
payload = {
'name':name,
'discovered_date':'0',
'owner_id':incident_owner,
'description':description,
'exposure_individual_name':corpID,
'incident_type_ids':incident_type
}
body=json.dumps(payload)
create = s.post(url, data=body, headers=headers, verify=False)
However since I commented out the line, I can't get incident_type in the format I need ( with brackets ).
So, my question is: How can I get the incident_type variable in the proper format in the final payload?
Input I manually got to work using product's interactive REST API:
{
"name": "Incident Name 2",
"incident_type_ids": [{
"name": "Phishing - General"
}],
"description": "This is the description",
"discovered_date": "0",
"exposure_individual_name": "id",
"owner_id": "Security Operations Center"
}
I figure my approach is wrong and I'd appreciate any help. I'm new to Python so I'm expecting this is a beginner's mistake.
Thanks for your help.

JSON square brackets are for arrays, which correspond to Python lists. JSON curly braces are for objects, which correspond to Python dictionaries.
So you need to create a list containing a dictionary, then convert that to JSON.
incident_type = [{"name": "Phishing - General"}]
incident_owner = 'Security Operations Center'
payload = {
'name':name,
'discovered_date':'0',
'owner_id':incident_owner,
'description':description,
'exposure_individual_name':corpID,
'incident_type_ids':incident_type
}
body=json.dumps(payload)
It's only slightly coincidental that the Python syntax for this is similar to the JSON syntax.

Related

format a json and then open it with the json.load () [duplicate]

I currently have JSON in the below format.
Some of the Key values are NOT properly formatted as they are missing double quotes (")
How do I fix these key values to have double-quotes on them?
{
Name: "test",
Address: "xyz",
"Age": 40,
"Info": "test"
}
Required:
{
"Name": "test",
"Address": "xyz",
"Age": 40,
"Info": "test"
}
Using the below post, I was able to find such key values in the above INVALID JSON.
However, I could NOT find an efficient way to replace these found values with double-quotes.
s = "Example: String"
out = re.findall(r'\w+:', s)
How to Escape Double Quote inside JSON
Using Regex:
import re
data = """{ Name: "test", Address: "xyz"}"""
print( re.sub("(\w+):", r'"\1":', data) )
Output:
{ "Name": "test", "Address": "xyz"}
You can use PyYaml. Since JSON is a subset of Yaml, pyyaml may overcome the lack of quotes.
Example
import yaml
dirty_json = """
{
key: "value",
"key2": "value"
}
"""
yaml.load(dirty_json, yaml.SafeLoader)
I had few more issues that I faced in my JSON.
Thought of sharing the final solution that worked for me.
jsonStr = re.sub("((?=\D)\w+):", r'"\1":', jsonStr)
jsonStr = re.sub(": ((?=\D)\w+)", r':"\1"', jsonStr)
First Line will fix this double-quotes issue for the Key. i.e.
Name: "test"
Second Line will fix double-quotes issue for the value. i.e. "Info": test
Also, above will exclude double-quoting within date timestamp which have : (colon) in them.
You can use online formatter. I know most of them are throwing error for not having double quotes but below one seems handling it nicely!
JSON Formatter
The regex approach can be brittle. I suggest you find a library that can parse the JSON text that is missing quotes.
For example, in Kotlin 1.4, the standard way to parse a JSON string is using Json.decodeFromString. However, you can use Json { isLenient = true }.decodeFromString to relax the requirements for quotes. Here is a complete example in JUnit.
import kotlinx.serialization.Serializable
import kotlinx.serialization.decodeFromString
import kotlinx.serialization.json.Json
import org.junit.jupiter.api.Assertions
import org.junit.jupiter.api.Test
#Serializable
data class Widget(val x: Int, val y: String)
class JsonTest {
#Test
fun `Parsing Json`() {
val w: Widget = Json.decodeFromString("""{"x":123, "y":"abc"}""")
Assertions.assertEquals(123, w.x)
Assertions.assertEquals("abc", w.y)
}
#Test
fun `Parsing Json missing quotes`() {
// Json.decodeFromString("{x:123, y:abc}") failed to decode due to missing quotes
val w: Widget = Json { isLenient = true }.decodeFromString("{x:123, y:abc}")
Assertions.assertEquals(123, w.x)
Assertions.assertEquals("abc", w.y)
}
}

Python - Search and export information from JSON

This is the structure of my json file
},
"client1": {
"description": "blabla",
"contact name": "",
"contact email": "",
"third party organisation": "",
"third party contact name": "",
"third party contact email": "",
"ranges": [
"1.1.1.1",
"2.2.2.2",
"3.3.3.3"
]
},
"client2": {
"description": "blabla",
"contact name": "",
"contact email": "",
"third party organisation": "",
"third party contact name": "",
"third party contact email": "",
"ranges": [
"4.4.4.4",
"2.2.2.2"
]
},
I've seen ways to export specific parts of this json file but not everything. Basically all I want to do is search through the file using user input.
All I'm struggling with is how I actually use the user input to search and print everything under either client1 or client2 based on the input? I am sure this is only 1 or 2 lines of code but cannot figure it out. New to python. This is my code
data = json.load(open('clients.json'))
def client():
searchq = input('Client to export: '.capitalize())
search = ('""'+searchq+'"')
a = open('Log.json', 'a+')
a.write('Client: \n')
client()
This should get you going:
# Safely open the file and load the data into a dictionary
with open('clients.json', 'rt') as dfile:
data = json.load(dfile)
# Ask for the name of the client
query = input('Client to export: ')
# Show the corresponding entry if it exists,
# otherwise show a message
print(data.get(query, 'Not found'))
I'm going to preface this by saying this is 100% a drive-by answering, but one thing you could do is have your user use a . (dot) delimited format for specifying the 'path' to the key in the dictionary/json structure, then implementing a recursive function to seek out the value under that path like so:
def get(query='', default=None, fragment=None):
"""
Recursive function which returns the value of the terminal
key of the query string supplied, or if no query
is supplied returns the whole fragment (dict).
Query string should take the form: 'each.item.is.a.key', allowing
the user to retrieve the value of a key nested within the fragment to
an arbitrary depth.
:param query: String representation of the path to the key for which
the value should be retrieved
:param default: If default is specified, returns instead of None if query is invalid
:param fragment: The dictionary to inspect
:return: value of the specified key or fragment if no query is supplied
"""
if not query:
return fragment
query = query.split('.')
try:
key = query.pop(0)
try:
if isinstance(fragment, dict) and fragment:
key = int(key) if isinstance(fragment.keys()[0], int) else key
else:
key = int(key)
except ValueError:
pass
fragment = fragment[key]
query = '.'.join(query)
except (IndexError, KeyError) as e:
return default if default is not None else None
if not fragment:
return fragment
return get(query=query, default=default, fragment=fragment)
There are going to be a million people who come by here with better suggestions than this and there are doubtless many improvements to be made to this function as well, but since I had it lying around I thought I'd put it here, at least as a starting point for you.
Note:
Fragment should probably be made a positional argument or something. IDK. Its not because I had to rip some application specific context out (it used to have a sensible default state) and I didn't want to start re-writing stuff, so I leave that up to you.
You can do some cool stuff with this function, given some data:
d = {
'woofage': 1,
'woofalot': 2,
'wooftastic': ('woof1', 'woof2', 'woof3'),
'woofgeddon': {
'woofvengers': 'infinity woof'
}
}
Try these:
get(fragment=d, query='woofage')
get(fragment=d, query='wooftastic')
get(fragment=d, query='wooftastic.0')
get(fragment=d, query='woofgeddon.woofvengers')
get(fragment=d, query='woofalistic', default='ultraWOOF')
Bon voyage!
Pass the json format into Dict then look into the topic you want and Read or write it
import json
r = {'is_claimed': True, 'rating': 3.5}
r = json.dumps(r) # Here you have json format {"is_claimed": true, "rating": 3.5}
Json to Dict:
loaded_r = json.loads(r) # {'is_claimed': True, 'rating': 3.5}
print (r)#Print json format
print (loaded_r) #Print dict
Read the Topic
Data=loaded_r['is_claimed'] #Print Topic desired
print(Data) #True
Overwrite the topic
loaded_r['is_claimed']=False
And also this would do the same
print(loaded_r['client1']['description'])

Accessing nested objects with python

I have a response that I receive from foursquare in the form of json. I have tried to access the certain parts of the object but have had no success. How would I access say the address of the object? Here is my code that I have tried.
url = 'https://api.foursquare.com/v2/venues/explore'
params = dict(client_id=foursquare_client_id,
client_secret=foursquare_client_secret,
v='20170801', ll=''+lat+','+long+'',
query=mealType, limit=100)
resp = requests.get(url=url, params=params)
data = json.loads(resp.text)
msg = '{} {}'.format("Restaurant Address: ",
data['response']['groups'][0]['items'][0]['venue']['location']['address'])
print(msg)
Here is an example of json response:
"items": [
{
"reasons": {
"count": 0,
"items": [
{
"summary": "This spot is popular",
"type": "general",
"reasonName": "globalInteractionReason"
}
]
},
"venue": {
"id": "412d2800f964a520df0c1fe3",
"name": "Central Park",
"contact": {
"phone": "2123106600",
"formattedPhone": "(212) 310-6600",
"twitter": "centralparknyc",
"instagram": "centralparknyc",
"facebook": "37965424481",
"facebookUsername": "centralparknyc",
"facebookName": "Central Park"
},
"location": {
"address": "59th St to 110th St",
"crossStreet": "5th Ave to Central Park West",
"lat": 40.78408342593807,
"lng": -73.96485328674316,
"labeledLatLngs": [
{
"label": "display",
"lat": 40.78408342593807,
"lng": -73.96485328674316
}
],
the full response can be found here
Like so
addrs=data['items'][2]['location']['address']
Your code (at least as far as loading and accessing the object) looks correct to me. I loaded the json from a file (since I don't have your foursquare id) and it worked fine. You are correctly using object/dictionary keys and array positions to navigate to what you want. However, you mispelled "address" in the line where you drill down to the data. Adding the missing 'a' made it work. I'm also correcting the typo in the URL you posted.
I answered this assuming that the example JSON you linked to is what is stored in data. If that isn't the case, a relatively easy way to see exact what python has stored in data is to import pprint and use it like so: pprint.pprint(data).
You could also start an interactive python shell by running the program with the -i switch and examine the variable yourself.
data["items"][2]["location"]["address"]
This will access the address for you.
You can go to any level of nesting by using integer index in case of an array and string index in case of a dict.
Like in your case items is an array
#items[int index]
items[0]
Now items[0] is a dictionary so we access by string indexes
item[0]['location']
Now again its an object s we use string index
item[0]['location']['address]

Using JSON dict in Django

I'm trying to access certain fields of information in JSON dict. My code is set up as the following:
Views.py
def viewIssues(request):
r = requests.get(bucket_url)
issue_payload = r.json()
issue = json.loads(str(issue_payload))
context = {
"issue_title": issue['issues']['title'],
"issue_content": issue['issues']['content'],
"title": "View Issues",
}
return render(request, "view_issues.html", context)
str(issue_payload) gives me this:
{
'search':None,
'count':1,
'filter':{
},
'issues':[
{
'priority':'major',
'comment_count':0,
'utc_created_on':'2016-11-12 01:48:16+00:00',
'utc_last_updated':'2016-11-12 01:48:16+00:00',
'status':'new',
'title':'example issue',
'reported_by':{
'is_staff':False,
'display_name':'display name',
'is_team':False,
'resource_uri':'/1.0/users/username',
'avatar':'https://bitbucket.org/account/username/avatar/32/?ts=1479493904',
'first_name':'firstname',
'username':'username',
'last_name':'lastname'
},
'is_spam':False,
'content':'blah blah',
'metadata':{
'milestone':None,
'component':None,
'version':None,
'kind':'bug'
},
'local_id':1,
'created_on':'2016-11-12T02:48:16.052',
'resource_uri':'/1.0/repositories/username/supportal2016test/issues/1',
'follower_count':1
}
]
}
However when I try to use the json.loads and indices ['issues']['title'] and ['issues']['title'] I get an error:
JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)
I'm wondering if it's because the converted payload has quotations on each field (i.e. 'issues'). Any help would be much appreciated.
The .json() call already parses the JSON result and returns a Python structure in this case a dictionary. Then your call
issue = json.loads(str(issue_payload))
forces the dictionary into a string and tries to parse it again. But the dictionary string representation contains ' around strings and not " as required in JSON.
To cut the long story short: issue_payload is what you want already.

Json organization

I use JSON for one of my project. For example, I have the JSON structure.
{
"address":{
"streetAddress": {
"aptnumber" : "21",
"building_number" : "2nd",
"street" : "Wall Street",
},
"city":"New York"
},
"phoneNumber":
[
{
"type":"home",
"number":"212 555-1234"
}
]
}
Now I have a bunch of modules using this structure, and it expects to see certain fields in the received json. For the example above, I have two files: address_manager and phone_number_manager. Each will be passed the relevant information. So address_manager will expect a dict that has keys 'streetAddress' and 'city'.
My question is: Is it possible to set up a constant structure so that every time I change the name of a field in my JSON structure (e.g. I want to change 'streetAddress' to 'address'), I don't have to make change in several places?
My naive approach is to have a bunch of constants (e.g.
ADDRESS = "address"
ADDRESS_STREET_ADDRESS = "streetAddress"
..etc..
) and so if I want to change the name of one of my fields in JSON structure, I just have to make change in one place. However, this seems to be very inefficient because my constant naming would be terribly long once I reach the third or fourth layer of the JSON structure (e.g. ADDRESS_STREETADDRESS_APTNUMBER, ADDRESS_STREETADDRESS_BUILDINGNUMBER)
I am doing this in python, but any generic answer would be OK.
Thanks.
Like Cameron Sparr suggested in a comment, don't have your constant names include all levels of your JSON structure. If you have the same data in multiple places, it will actually be better if you reuse the same constant. For example, suppose your JSON has a phone number included in the address:
{
"address": {
"streetAddress": {
"aptnumber" : "21",
"building_number" : "2nd",
"street" : "Wall Street"
},
"city":"New York",
"phoneNumber":
[
{
"type":"home",
"number":"212 555-1234"
}
]
},
"phoneNumber":
[
{
"type":"home",
"number":"212 555-1234"
}
]
}
Why not have a single constant PHONES = 'phoneNumber' that you use in both places? Your constants will have shorter names, and it is more logically coherent. You would end up using it like this (assuming JSON is stored in person):
person[ADDRESS][PHONES][x] # Phone numbers associated with that address
person[PHONES][x] # Phone numbers associated with the person
Instead of
person[ADDRESS][ADDRESS_PHONES][x]
person[PHONE_NUMBERS][x]
You can write a script than when you change the constant, change the structure in all json files.
Example:
import json
CHANGE = ('steet', 'streetAddress')
json_data = None
with open('file.json') as jfile:
json_data = jfile.load(jfile)
json_data[CHANGE[1]], json_data[CHANGE[0]] = json_data[CHANGE[0]], None

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