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Python Regex find all matches after specific word

I have a string as below
"Server: myserver.mysite.com\r\nAddress: 111.122.133.144\r\n\r\nName: myserver.mysite.com\r\nAddress: 123.144.412.111\r\nAliases: alias1.myserver.mysite.com\r\n\t myserver.mysite.com\r\n\r\n"
I'm currently struggling to write a function in python that will find all aliases and put them in a list. So basically, I need a list that will be ['alias1.myserver.mysite.com', 'myserver.mysite.com']
I tried the following code
pattern = '(?<=Aliases: )([\S*]+)'
name = re.findall(pattern, mystring)
but it only matches the first alias and not both of them.
Any ideas on this?
Greatly appreciated!

Try the following:
import re
s = "Server: myserver.mysite.com\r\nAddress: 111.122.133.144\r\n\r\nName: myserver.mysite.com\r\nAddress: 123.144.412.111\r\nAliases: alias1.myserver.mysite.com\r\n\t myserver.mysite.com\r\n\r\n"
l = re.findall(r'\S+', s.split('Aliases: ')[1])
print(l)
Prints:
['alias1.myserver.mysite.com', 'myserver.mysite.com']
Explanation
First we split the string into two pieces and keep the second piece with s.split('Aliases: ')[1]. This evaluates to the part of the string that follows 'Aliases: '.
Next we use findall with the regaular expression:
\S+
This matches all consecutive strings of one or more non-space characters.
But this can be more simply done in this case without using a regex:
s = "Server: myserver.mysite.com\r\nAddress: 111.122.133.144\r\n\r\nName: myserver.mysite.com\r\nAddress: 123.144.412.111\r\nAliases: alias1.myserver.mysite.com\r\n\t myserver.mysite.com\r\n\r\n"
l = s.split('Aliases: ')[1].split()
print(l)

Try this :
import re
regex = re.compile(r'[\n\r\t]')
t="Server: myserver.mysite.com\r\nAddress: 111.122.133.144\r\n\r\nName: myserver.mysite.com\r\nAddress: 123.144.412.111\r\nAliases: alias1.myserver.mysite.com\r\n\t myserver.mysite.com\r\n\r\n"
t = regex.sub(" ", t)
t = t.split("Aliases:")[1].strip().split()
print(t)

Extract number from a string using a pattern

I have strings like :
's3://bukcet_name/tables/name=moonlight/land/timestamp=2020-06-25 01:00:23.180745/year=2019/month=5'
And from it I would like to obtain a tuple contain the year value and the month value as first and second element of my tuple.
('2019', '5')
For now I did this :
([elem.split('=')[-1:][0] for elem in part[0].split('/')[-2:]][0], [elem.split('=')[-1:][0] for elem in part[0].split('/')[-2:]][1])
It isn't very elegant, how could I do better ?

Use, re.findall along with the given regex pattern:
import re
matches = re.findall(r'(?i)/year=(\d+)/month=(\d+)', string)
Result:
# print(matches)
[('2019', '5')]
Test the regex pattern here.

Perhaps regular expressions could do it. I would use regular expressions to capture the strings 'year=2019' and 'month=5' then return the item at index [-1] by splitting these two with the character '='. Hold on, let me open up my Sublime and try to write actual code which suits your specific case.
import re
search_string = 's3://bukcet_name/tables/name=moonlight/land/timestamp=2020-06-25 01:00:23.180745/year=2019/month=5'
string1 = re.findall(r'year=\d+', search_string)
string2 = re.findall(r'month=\d+', search_string)
result = (string1[0].split('=')[-1], string2[0].split('=')[-1]) print(result)

Replace string which has dynamic character in python

Trying to replace the string with regular expression and could not success.
The strings are "LIVE_CUS2_PHLR182" ,"LIVE_CUS2ee_PHLR182" and "PHLR182 - testing recovery".Here I need to get PHLR182 as an output with all the string but where second string has "ee" which is not constant. It can be string or number with 2 character.Below is the code what I have tried.
For first and last string I just simply used replace function like below.
s = "LIVE_CUS2_PHLR182"
s.replace("LIVE_CUS2_", ""), s.replace(" - testing recovery","")
>>> PHLR182
But for second I tried like below.
1. s= "LIVE_CUS2ee_PHLR182"
s.replace(r'LIVE_CUS2(\w+)*_','')
2. batRegex = re.compile(r'LIVE_CUS2(\w+)*_PHLR182')
mo2 = batRegex.search('LIVE_CUS2dd_PHLR182')
mo2.group()
3. re.sub(r'LIVE_CUS2(?is)/s+_PHLR182', '', r)
In all case I could not get "PHLR182" as an output. Please help me.

I think this is what you need:
import re
texts = """LIVE_CUS2_PHLR182
LIVE_CUS2ee_PHLR182
PHLR182 - testing recovery""".split('\n')
pat = re.compile(r'(LIVE_CUS2\w{,2}_| - testing recovery)')
# 1st alt pattern | 2nd alt pattern
# Look for 'LIV_CUS2_' with up to two alphanumeric characters after 2
# ... or Look for ' - testing recovery'
results = [pat.sub('', text) for text in texts]
# replace the matched pattern with empty string
print(f'Original: {texts}')
print(f'Results: {results}')
Result:
Original: ['LIVE_CUS2_PHLR182', 'LIVE_CUS2ee_PHLR182', 'PHLR182 - testing recovery']
Results: ['PHLR182', 'PHLR182', 'PHLR182']
Python Demo: https://repl.it/repls/ViolentThirdAutomaticvectorization
Regex Demo: https://regex101.com/r/JiEVqn/2

How to start at a specific letter and end when it hits a digit?

I have some sample strings:
s = 'neg(able-23, never-21) s2-1/3'
i = 'amod(Market-8, magical-5) s1'
I've got the problem where I can figure out if the string has 's1' or 's3' using:
word = re.search(r's\d$', s)
But if I want to know if the contains 's2-1/3' in it, it won't work.
Is there a regex expression that can be used so that it works for both cases of 's#' and 's#+?
Thanks!

You can allow the characters "-" and "/" to be captured as well, in addition to just digits. It's hard to tell the exact pattern you're going for here, but something like this would capture "s2-1/3" from your example:
import re
s = "neg(able-23, never-21) s2-1/3"
word = re.search(r"s\d[-/\d]*$", s)

I'm guessing that maybe you would want to extract that with some expression, such as:
(s\d+)-?(.*)$
Demo 1
or:
(s\d+)-?([0-9]+)?\/?([0-9]+)?$
Demo 2
Test
import re
expression = r"(s\d+)-?(.*)$"
string = """
neg(able-23, never-21) s211-12/31
neg(able-23, never-21) s2-1/3
amod(Market-8, magical-5) s1
"""
print(re.findall(expression, string, re.M))
Output
[('s211', '12/31'), ('s2', '1/3'), ('s1', '')]

Splitting a string using re module of python

I have a string
s = 'count_EVENT_GENRE in [1,2,3,4,5]'
#I have to capture only the field 'count_EVENT_GENRE'
field = re.split(r'[(==)(>=)(<=)(in)(like)]', s)[0].strip()
#o/p is 'cou'
# for s = 'sum_EVENT_GENRE in [1,2,3,4,5]' o/p = 'sum_EVENT_GENRE'
which is fine
My doubt is for any character in (in)(like) it is splitting the string s at that character and giving me first slice.(as after "cou" it finds one matching char i:e n). It's happening for any string that contains any character from (in)(like).
Ex : 'percentage_AMOUNT' o/p = 'p'
as it finds a matching char as 'e' after p.
So i want some advice how to treat (in)(like) as words not as characters , when splitting occurs/matters.
please suggest a syntax.

Answering your question, the [(==)(>=)(<=)(in)(like)] is a character class matching single characters you defined inside the class. To match sequences of characters, you need to remove [ and ] and use alternation:
r'==?|>=?|<=?|\b(?:in|like)\b'
or better:
r'[=><]=?|\b(?:in|like)\b'
You code would look like:
import re
ss = ['count_EVENT_GENRE in [1,2,3,4,5]','coint_EVENT_GENRE = "ROMANCE"']
for s in ss:
field = re.split(r'[=><]=?|\b(?:in|like)\b', s)[0].strip()
print(field)
However, there might be other (easier, or safer - depending on the actual specifications) ways to get what you want (splitting with space and getting the first item, use re.match with r'\w+' or r'[a-z]+(?:_[A-Z]+)+', etc.)
If your value is at the start of the string and starts with lowercase ASCII letters, and then can have any amount of sequences of _ followed with uppercase ASCII letters, use:
re.match(r'[a-z]+(?:_[A-Z]+)*', s)
Full demo code:
import re
ss = ['count_EVENT_GENRE in [1,2,3,4,5]','coint_EVENT_GENRE = "ROMANCE"']
for s in ss:
fieldObj = re.match(r'[a-z]+(?:_[A-Z]+)*', s)
if fieldObj:
print(fieldObj.group())

If you want only the first word of your string, then this should do the job:
import re
s = 'count_EVENT_GENRE in [1,2,3,4,5]'
field = re.split(r'\W', s)[0]
# count_EVENT_GENRE

Is there anything wrong with using split?
>>> s = 'count_EVENT_GENRE in [1,2,3,4,5]'
>>> s.split(' ')[0]
'count_EVENT_GENRE'
>>> s = 'coint_EVENT_GENRE = "ROMANCE"'
>>> s.split(' ')[0]
'coint_EVENT_GENRE'
>>>