"[WinError 6] The handle is invalid" with Urllib - python

import urllib.request
def Download(url, file_name):
urllib.request.urlretrieve(url, file_name)
f = open("links.txt", "r")
lines = f.readlines()
for line in lines:
for x in range (1, 5):
filenaame = x
cut_string = line.split('?$')
new_string = cut_string[0]
numerator = new_string.split('/1/')
separator = ''
link = (separator.join(numerator[0] + "/{}/".format(x) + numerator[1]))
file_name = link.split('/{}/'.format(x))
file_name = file_name[1]
file_name = file_name.split('.')
file_name = (separator.join(file_name[0] + "{}".format(filenaame)))
filenaame =+ 1
print("Downloading: {}".format(file_name))
Download(link, filenaame)
Error:
Traceback (most recent call last):
File "C:\python\downloader\rr.py", line 29, in <module>
Download(link, filenaame)
File "C:\python\downloader\rr.py", line 5, in Download
urllib.request.urlretrieve(url, file_name)
File "C:\python\lib\urllib\request.py", line 258, in urlretrieve
tfp = open(filename, 'wb')
OSError: [WinError 6] The handle is invalid
I have googled a lot about this and in every result I found the person was using the subprocess module, which I'm not, which makes it even more difficult.
The code is for downloading images. It does download the first one successfully, then it crashes. Anyone know what's causing the error? I'm still a beginner.

you're passing your counter as a second parameter. In the end the function uses that as a filename to copy the downloaded data to.
By passing an integer you enable the "pass a lowlevel file descriptor" to open:
file is either a string or bytes object giving the pathname (absolute or relative to the current working directory) of the file to be opened or an integer file descriptor of the file to be wrapped.
But the file descriptor doesn't exist (fortunately!)
Let's reproduce the issue here:
>>> open(4,"rb")
Traceback (most recent call last):
File "<string>", line 301, in runcode
File "<interactive input>", line 1, in <module>
OSError: [Errno 9] Bad file descriptor
the fix is obviously:
Download(link, file_name)
(I'd suggest that you rename your filenaame counter for something more meaningful, it avoids mistakes like that)

At this line,
urllib.request.urlretrieve(url, file_name)
here file_name should be a string so before calling Download(link, filenaame) make integer filenaame to string try.
Download(link, str(filenaame))
Sample working for downloading an image
def download_img(url):
name = random.randrange(100,1000)
full_name = str(name)+ ".jpg"
urllib.request.urlretrieve(url, full_name)
download_img("http://images.freeimages.com/images/small-previews/25d/eagle-1523807.jpg")

Related

Dropbox API - trying to upload a file

I've just rebuilt my Raspberry Pi and hence installed the latest version of the Dropbox API and now my program doesn't work. I think this is due to point 1 in these breaking changes: https://github.com/dropbox/dropbox-sdk-python/releases/tag/v7.1.0. I'm sure this question from SO (Dropbox API v2 - trying to upload file with files_upload() - throws TypeError) solves my problem... but as a newbie, I can't figure out how to actually implement it - and anyway, I'm already using f.read()... can anyone help?
This is my code:
def DropboxUpload(file):
sourcefile = "/home/pi/Documents/iot_pm2/dropbox_transfer/" + filename
targetfile = "/" + filename
dbx = dropbox.Dropbox(cfg.dropboxtoken)
f = open(sourcefile, "r")
filecontents = f.read()
try:
dbx.files_upload(filecontents, targetfile, mode=dropbox.files.WriteMode.overwrite)
except dropbox.exceptions.ApiError as err:
print(err)
f.close()
And this is the error:
Traceback (most recent call last):
File "/home/pi/Documents/iot_pm2/dropbox_uploader.py", line 20, in <module>
DropboxUpload(filename)
File "/home/pi/Documents/iot_pm2/dropbox_uploader.py", line 12, in DropboxUpload
dbx.files_upload(filecontents, targetfile, mode=dropbox.files.WriteMode.overwrite)
File "/usr/local/lib/python3.5/dist-packages/dropbox/base.py", line 2125, in files_upload
f,
File "/usr/local/lib/python3.5/dist-packages/dropbox/dropbox.py", line 272, in request
timeout=timeout)
File "/usr/local/lib/python3.5/dist-packages/dropbox/dropbox.py", line 363, in request_json_string_with_retry
timeout=timeout)
File "/usr/local/lib/python3.5/dist-packages/dropbox/dropbox.py", line 407, in request_json_string
type(request_binary))
TypeError: expected request_binary as binary type, got <class 'str'>
Thanks in advance.
You need to supply bytes, but you're supplying str.
You can get bytes by changing the file mode to binary. I.e., instead of:
f = open(sourcefile, "r")
do:
f = open(sourcefile, "rb")

Python I/O error: How do I fix this program for file paths with whitespace?

When running the codes.
file_path = raw_input("Drag the text file here: ")
file_path = file_path.strip()
file_handle = open(file_path, 'r')
for line in file_handle:
print line
Output:
Drag the text file here: /Users/user_name/Desktop/white\ space/text.txt
Traceback (most recent call last):
File "desktop/test.py", line 3, in <module>
file_handle = open(file_path, 'r')
IOError: [Errno 2] No such file or directory: '/Users/user_name/Desktop/white\\ space/text.txt'
The program runs fine for any pathname without whitespace.
The immediate fix would be removing the escaped '\\' characters, file_path.strip().replace('\\', '')
This should return /Users/user_name/Desktop/white space/text.txt which is a valid path for you to use.
Look into os.path for ways to handle pathnames.

cannot write file with full path in Python

I am using Pandas on Mac, to read and write a CSV file, and the weird thing is when using full path, it has error and when using just a file name, it works. I post my code which works and which not works in my comments below, and also detailed error messages. Anyone have any good ideas?
sourceDf = pd.read_csv(path_to_csv)
sourceDf['nameFull'] = sourceDf['nameFirst'] + ' ' + sourceDf['nameLast']
sourceDf.to_csv('newMaster.csv') # working
sourceDf.to_csv('~/Downloads/newMaster.csv') # not working
Traceback (most recent call last):
File "/Users/foo/PycharmProjects/DataWranglingTest/CSVTest1.py", line 36, in <module>
add_full_name(path_to_csv, path_to_new_csv)
File "/Users/foo/PycharmProjects/DataWranglingTest/CSVTest1.py", line 28, in add_full_name
sourceDf.to_csv('~/Downloads/newMaster.csv')
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/frame.py", line 1189, in to_csv
formatter.save()
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/format.py", line 1442, in save
encoding=self.encoding)
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/common.py", line 2831, in _get_handle
f = open(path, mode)
IOError: [Errno 2] No such file or directory: '~/Downloads/newMaster.csv'
Tried to use prefix r, but not working,
path_to_csv = r'~/Downloads/Master.csv'
path_to_new_csv = r'~/Downloads/Master_new.csv'
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/frame.py", line 1189, in to_csv
formatter.save()
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/format.py", line 1442, in save
encoding=self.encoding)
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/common.py", line 2831, in _get_handle
f = open(path, mode)
IOError: [Errno 2] No such file or directory: '~/Downloads/Master_new.csv'
thanks in advance,
Lin
Try using os.path.join().
import os
(...)
output_filename = 'newMaster.csv'
output_path = os.path.join('Downloads', output_filename)
(...)
sourceDf.to_csv(output_path)
Use the same methodology to point pandas.read_csv() in the right direction.
You didn't specify python version.
On 3.4 you can use pathlib, otherwise use os.path.join() or quoting:
sourceDf.to_csv(r'~/Downloads/newMaster.csv')
Notice the r.
The problem is that /n is newline, which is not allowed in a path.

Using os.path.join with os.path.getsize, returning FileNotFoundError

In conjunction with my last question, I'm onto printing the filenames with their sizes next to them in a sort of list. Basically I am reading filenames from one file (which are added by the user), taking the filename and putting it in the path of the working directory to print it's size one-by-one, however I'm having an issue with the following block:
print("\n--- Stats ---\n")
with open('userdata/addedfiles', 'r') as read_files:
file_lines = read_files.readlines()
# get path for each file and find in trackedfiles
# use path to get size
print(len(file_lines), "files\n")
for file_name in file_lines:
# the actual files should be in the same working directory
cwd = os.getcwd()
fpath = os.path.join(cwd, file_name)
fsize = os.path.getsize(fpath)
print(file_name.strip(), "-- size:", fsize)
which is returning this error:
tolbiac wpm-public → ./main.py --filestatus
--- Stats ---
1 files
Traceback (most recent call last):
File "./main.py", line 332, in <module>
main()
File "./main.py", line 323, in main
parseargs()
File "./main.py", line 317, in parseargs
tracking()
File "./main.py", line 204, in tracking
fsize = os.path.getsize(fpath)
File "/usr/lib/python3.4/genericpath.py", line 50, in getsize
return os.stat(filename).st_size
FileNotFoundError: [Errno 2] No such file or directory: '/home/tolbiac/code/wpm-public/file.txt\n'
tolbiac wpm-public →
So it looks like something is adding a \n to the end of file_name, I'm not sure if thats something used in the getsize module, I tried this with os.stat, but it did the same thing.
Any suggestions? Thanks.
When you're reading in a file, you need to be aware of how the data is being seperated. In this case, the read-in file has a filename once per line seperated out by that \n operator. Need to strip it then before you use it.
for file_name in file_lines:
file_name = file_name.strip()
# rest of for loop

Python, unpacking a .jar file, doesnt work

So, I'm trying to unzip a .jar file using this code:
It won't unzip, only 20 / 500 files, and no folders/pictures
The same thing happens when I enter a .zip file in filename.
Any one any suggestions?
import zipfile
zfilename = "PhotoVieuwer.jar"
if zipfile.is_zipfile(zfilename):
print "%s is a valid zip file" % zfilename
else:
print "%s is not a valid zip file" % zfilename
print '-'*40
zfile = zipfile.ZipFile( zfilename, "r" )
zfile.printdir()
print '-'*40
for info in zfile.infolist():
fname = info.filename
data = zfile.read(fname)
if fname.endswith(".txt"):
print "These are the contents of %s:" % fname
print data
filename = fname
fout = open(filename, "w")
fout.write(data)
fout.close()
print "New file created --> %s" % filename
print '-'*40
But, it doesn't work, it unzips maybe 10 out of 500 files
Can anyone help me on fixing this?
Already Thanks!
I tried adding, what Python told me, I got this:
Oops! Your edit couldn't be submitted because:
body is limited to 30000 characters; you entered 153562
and only the error is :
Traceback (most recent call last):
File "C:\Python27\uc\TeStINGGFDSqAEZ.py", line 26, in <module>
fout = open(filename, "w")
IOError: [Errno 2] No such file or directory: 'net/minecraft/client/ClientBrandRetriever.class'
The files that get unzipped:
amw.Class
amx.Class
amz.Class
ana.Class
ane.Class
anf.Class
ang.Class
ank.Class
anm.Class
ann.Class
ano.Class
anq.Class
anr.Class
anx.Class
any.Class
anz.Class
aob.Class
aoc.Class
aod.Class
aoe.Class
This traceback tells you what you need to know:
Traceback (most recent call last):
File "C:\Python27\uc\TeStINGGFDSqAEZ.py", line 26, in <module>
fout = open(filename, "w")
IOError: [Errno 2] No such file or directory: 'net/minecraft/client/ClientBrandRetriever.class'
The error message says that either the file ClientBrandRetriever.class doesn't exist or the directory net/minecraft/client does not exist. When a file is opened for writing Python creates it, so it can't be a problem that the file does not exist. It must be the case that the directory does not exist.
Consider that this works
>>> open('temp.txt', 'w')
<open file 'temp.txt', mode 'w' at 0x015FF0D0>
but this doesn't, giving nearly identical traceback to the one you are getting:
>>> open('bogus/temp.txt', 'w')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IOError: [Errno 2] No such file or directory: 'bogus/temp.txt'
Creating the directory fixes it:
>>> os.makedirs('bogus')
>>> open('bogus/temp.txt', 'w')
<open file 'bogus/temp.txt', mode 'w' at 0x01625D30>
Just prior to opening the file you should check if the directory exists and create it if necessary.
So to solve your problem, replace this
fout = open(filename, 'w')
with this
head, tail = os.path.split(filename) # isolate directory name
if not os.path.exists(head): # see if it exists
os.makedirs(head) # if not, create it
fout = open(filename, 'w')
If python -mzipfile -e PhotoVieuwer.jar dest works then you could:
import zipfile
with zipfile.ZipFile("PhotoVieuwer.jar") as z:
z.extractall()

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