We Keep Coding

How to use requests library to POST a python object in flask? [duplicate]

I need to POST a JSON from a client to a server. I'm using Python 2.7.1 and simplejson. The client is using Requests. The server is CherryPy. I can GET a hard-coded JSON from the server (code not shown), but when I try to POST a JSON to the server, I get "400 Bad Request".
Here is my client code:
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)
Here is the server code.
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
def POST(self):
self.content = simplejson.loads(cherrypy.request.body.read())
Any ideas?

Starting with Requests version 2.4.2, you can use the json= parameter (which takes a dictionary) instead of data= (which takes a string) in the call:
>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
'data': '{"key": "value"}',
'files': {},
'form': {},
'headers': {'Accept': '*/*',
'Accept-Encoding': 'gzip, deflate',
'Connection': 'close',
'Content-Length': '16',
'Content-Type': 'application/json',
'Host': 'httpbin.org',
'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
'X-Request-Id': 'xx-xx-xx'},
'json': {'key': 'value'},
'origin': 'x.x.x.x',
'url': 'http://httpbin.org/post'}

It turns out I was missing the header information. The following works:
import requests
url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)

From requests 2.4.2 (https://pypi.python.org/pypi/requests), the "json" parameter is supported. No need to specify "Content-Type". So the shorter version:
requests.post('http://httpbin.org/post', json={'test': 'cheers'})

Which parameter between data / json / files you need to use depends on a request header named Content-Type (you can check this through the developer tools of your browser).
When the Content-Type is application/x-www-form-urlencoded, use data=:
requests.post(url, data=json_obj)
When the Content-Type is application/json, you can either just use json= or use data= and set the Content-Type yourself:
requests.post(url, json=json_obj)
requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})
When the Content-Type is multipart/form-data, it's used to upload files, so use files=:
requests.post(url, files=xxxx)

The better way is：
url = "http://xxx.xxxx.xx"
data = {
"cardno": "6248889874650987",
"systemIdentify": "s08",
"sourceChannel": 12
}
resp = requests.post(url, json=data)

headers = {"charset": "utf-8", "Content-Type": "application/json"}
url = 'http://localhost:PORT_NUM/FILE.php'
r = requests.post(url, json=YOUR_JSON_DATA, headers=headers)
print(r.text)

Works perfectly with python 3.5+
client:
import requests
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})
server:
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
#cherrypy.tools.json_in()
#cherrypy.tools.json_out()
def POST(self):
self.content = cherrypy.request.json
return {'status': 'success', 'message': 'updated'}

With current requests you can pass in any data structure that dumps to valid JSON , with the json parameter, not just dictionaries (as falsely claimed by the answer by Zeyang Lin).
import requests
r = requests.post('http://httpbin.org/post', json=[1, 2, {"a": 3}])
this is particularly useful if you need to order elements in the response.

I solved it this way:
from flask import Flask, request
from flask_restful import Resource, Api
req = request.json
if not req :
req = request.form
req['value']

It always recommended that we need to have the ability to read the JSON file and parse an object as a request body. We are not going to parse the raw data in the request so the following method will help you to resolve it.
def POST_request():
with open("FILE PATH", "r") as data:
JSON_Body = data.read()
response = requests.post(url="URL", data=JSON_Body)
assert response.status_code == 200

Request with json as data [duplicate]

I need to POST a JSON from a client to a server. I'm using Python 2.7.1 and simplejson. The client is using Requests. The server is CherryPy. I can GET a hard-coded JSON from the server (code not shown), but when I try to POST a JSON to the server, I get "400 Bad Request".
Here is my client code:
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)
Here is the server code.
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
def POST(self):
self.content = simplejson.loads(cherrypy.request.body.read())
Any ideas?

Starting with Requests version 2.4.2, you can use the json= parameter (which takes a dictionary) instead of data= (which takes a string) in the call:
>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
'data': '{"key": "value"}',
'files': {},
'form': {},
'headers': {'Accept': '*/*',
'Accept-Encoding': 'gzip, deflate',
'Connection': 'close',
'Content-Length': '16',
'Content-Type': 'application/json',
'Host': 'httpbin.org',
'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
'X-Request-Id': 'xx-xx-xx'},
'json': {'key': 'value'},
'origin': 'x.x.x.x',
'url': 'http://httpbin.org/post'}

It turns out I was missing the header information. The following works:
import requests
url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)

From requests 2.4.2 (https://pypi.python.org/pypi/requests), the "json" parameter is supported. No need to specify "Content-Type". So the shorter version:
requests.post('http://httpbin.org/post', json={'test': 'cheers'})

Which parameter between data / json / files you need to use depends on a request header named Content-Type (you can check this through the developer tools of your browser).
When the Content-Type is application/x-www-form-urlencoded, use data=:
requests.post(url, data=json_obj)
When the Content-Type is application/json, you can either just use json= or use data= and set the Content-Type yourself:
requests.post(url, json=json_obj)
requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})
When the Content-Type is multipart/form-data, it's used to upload files, so use files=:
requests.post(url, files=xxxx)

The better way is：
url = "http://xxx.xxxx.xx"
data = {
"cardno": "6248889874650987",
"systemIdentify": "s08",
"sourceChannel": 12
}
resp = requests.post(url, json=data)

headers = {"charset": "utf-8", "Content-Type": "application/json"}
url = 'http://localhost:PORT_NUM/FILE.php'
r = requests.post(url, json=YOUR_JSON_DATA, headers=headers)
print(r.text)

Works perfectly with python 3.5+
client:
import requests
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})
server:
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
#cherrypy.tools.json_in()
#cherrypy.tools.json_out()
def POST(self):
self.content = cherrypy.request.json
return {'status': 'success', 'message': 'updated'}

With current requests you can pass in any data structure that dumps to valid JSON , with the json parameter, not just dictionaries (as falsely claimed by the answer by Zeyang Lin).
import requests
r = requests.post('http://httpbin.org/post', json=[1, 2, {"a": 3}])
this is particularly useful if you need to order elements in the response.

I solved it this way:
from flask import Flask, request
from flask_restful import Resource, Api
req = request.json
if not req :
req = request.form
req['value']

It always recommended that we need to have the ability to read the JSON file and parse an object as a request body. We are not going to parse the raw data in the request so the following method will help you to resolve it.
def POST_request():
with open("FILE PATH", "r") as data:
JSON_Body = data.read()
response = requests.post(url="URL", data=JSON_Body)
assert response.status_code == 200

Failed to curl in python but okay in bash. (ubuntu) [duplicate]

I need to POST a JSON from a client to a server. I'm using Python 2.7.1 and simplejson. The client is using Requests. The server is CherryPy. I can GET a hard-coded JSON from the server (code not shown), but when I try to POST a JSON to the server, I get "400 Bad Request".
Here is my client code:
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)
Here is the server code.
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
def POST(self):
self.content = simplejson.loads(cherrypy.request.body.read())
Any ideas?

Starting with Requests version 2.4.2, you can use the json= parameter (which takes a dictionary) instead of data= (which takes a string) in the call:
>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
'data': '{"key": "value"}',
'files': {},
'form': {},
'headers': {'Accept': '*/*',
'Accept-Encoding': 'gzip, deflate',
'Connection': 'close',
'Content-Length': '16',
'Content-Type': 'application/json',
'Host': 'httpbin.org',
'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
'X-Request-Id': 'xx-xx-xx'},
'json': {'key': 'value'},
'origin': 'x.x.x.x',
'url': 'http://httpbin.org/post'}

It turns out I was missing the header information. The following works:
import requests
url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)

From requests 2.4.2 (https://pypi.python.org/pypi/requests), the "json" parameter is supported. No need to specify "Content-Type". So the shorter version:
requests.post('http://httpbin.org/post', json={'test': 'cheers'})

Which parameter between data / json / files you need to use depends on a request header named Content-Type (you can check this through the developer tools of your browser).
When the Content-Type is application/x-www-form-urlencoded, use data=:
requests.post(url, data=json_obj)
When the Content-Type is application/json, you can either just use json= or use data= and set the Content-Type yourself:
requests.post(url, json=json_obj)
requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})
When the Content-Type is multipart/form-data, it's used to upload files, so use files=:
requests.post(url, files=xxxx)

The better way is：
url = "http://xxx.xxxx.xx"
data = {
"cardno": "6248889874650987",
"systemIdentify": "s08",
"sourceChannel": 12
}
resp = requests.post(url, json=data)

headers = {"charset": "utf-8", "Content-Type": "application/json"}
url = 'http://localhost:PORT_NUM/FILE.php'
r = requests.post(url, json=YOUR_JSON_DATA, headers=headers)
print(r.text)

Works perfectly with python 3.5+
client:
import requests
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})
server:
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
#cherrypy.tools.json_in()
#cherrypy.tools.json_out()
def POST(self):
self.content = cherrypy.request.json
return {'status': 'success', 'message': 'updated'}

With current requests you can pass in any data structure that dumps to valid JSON , with the json parameter, not just dictionaries (as falsely claimed by the answer by Zeyang Lin).
import requests
r = requests.post('http://httpbin.org/post', json=[1, 2, {"a": 3}])
this is particularly useful if you need to order elements in the response.

I solved it this way:
from flask import Flask, request
from flask_restful import Resource, Api
req = request.json
if not req :
req = request.form
req['value']

It always recommended that we need to have the ability to read the JSON file and parse an object as a request body. We are not going to parse the raw data in the request so the following method will help you to resolve it.
def POST_request():
with open("FILE PATH", "r") as data:
JSON_Body = data.read()
response = requests.post(url="URL", data=JSON_Body)
assert response.status_code == 200

Print response JSON from server with HTTP POST

How can I get respon JSON dictionaries from server with POST:
import json
import requests
url = 'http://apiurl.com'
parameters = {'code':1,
'user': 'username',
'password': 'password'
}
headers = {'content-type': 'application/json'}
response = requests.post(url, data = json.dumps(parameters),headers=headers)
print(response)
output: Response [200]

response = requests.post(url, data=json.dumps(parameters), headers=headers)
print(response)
print(response.text)

Since, you are going to receive a JSON object you can simply use request's built-in JSON decoder Simply do:
j = response.json()

How to POST JSON data with Python Requests?

I need to POST a JSON from a client to a server. I'm using Python 2.7.1 and simplejson. The client is using Requests. The server is CherryPy. I can GET a hard-coded JSON from the server (code not shown), but when I try to POST a JSON to the server, I get "400 Bad Request".
Here is my client code:
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)
Here is the server code.
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
def POST(self):
self.content = simplejson.loads(cherrypy.request.body.read())
Any ideas?

Starting with Requests version 2.4.2, you can use the json= parameter (which takes a dictionary) instead of data= (which takes a string) in the call:
>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
'data': '{"key": "value"}',
'files': {},
'form': {},
'headers': {'Accept': '*/*',
'Accept-Encoding': 'gzip, deflate',
'Connection': 'close',
'Content-Length': '16',
'Content-Type': 'application/json',
'Host': 'httpbin.org',
'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
'X-Request-Id': 'xx-xx-xx'},
'json': {'key': 'value'},
'origin': 'x.x.x.x',
'url': 'http://httpbin.org/post'}

It turns out I was missing the header information. The following works:
import requests
url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)

From requests 2.4.2 (https://pypi.python.org/pypi/requests), the "json" parameter is supported. No need to specify "Content-Type". So the shorter version:
requests.post('http://httpbin.org/post', json={'test': 'cheers'})

Which parameter between data / json / files you need to use depends on a request header named Content-Type (you can check this through the developer tools of your browser).
When the Content-Type is application/x-www-form-urlencoded, use data=:
requests.post(url, data=json_obj)
When the Content-Type is application/json, you can either just use json= or use data= and set the Content-Type yourself:
requests.post(url, json=json_obj)
requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})
When the Content-Type is multipart/form-data, it's used to upload files, so use files=:
requests.post(url, files=xxxx)

The better way is：
url = "http://xxx.xxxx.xx"
data = {
"cardno": "6248889874650987",
"systemIdentify": "s08",
"sourceChannel": 12
}
resp = requests.post(url, json=data)

headers = {"charset": "utf-8", "Content-Type": "application/json"}
url = 'http://localhost:PORT_NUM/FILE.php'
r = requests.post(url, json=YOUR_JSON_DATA, headers=headers)
print(r.text)

Works perfectly with python 3.5+
client:
import requests
data = {'sender': 'Alice',
'receiver': 'Bob',
'message': 'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})
server:
class Root(object):
def __init__(self, content):
self.content = content
print self.content # this works
exposed = True
def GET(self):
cherrypy.response.headers['Content-Type'] = 'application/json'
return simplejson.dumps(self.content)
#cherrypy.tools.json_in()
#cherrypy.tools.json_out()
def POST(self):
self.content = cherrypy.request.json
return {'status': 'success', 'message': 'updated'}

With current requests you can pass in any data structure that dumps to valid JSON , with the json parameter, not just dictionaries (as falsely claimed by the answer by Zeyang Lin).
import requests
r = requests.post('http://httpbin.org/post', json=[1, 2, {"a": 3}])
this is particularly useful if you need to order elements in the response.

I solved it this way:
from flask import Flask, request
from flask_restful import Resource, Api
req = request.json
if not req :
req = request.form
req['value']

It always recommended that we need to have the ability to read the JSON file and parse an object as a request body. We are not going to parse the raw data in the request so the following method will help you to resolve it.
def POST_request():
with open("FILE PATH", "r") as data:
JSON_Body = data.read()
response = requests.post(url="URL", data=JSON_Body)
assert response.status_code == 200