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A simple question about POST and GET request

I just started to learn Django by following a sentdex tutorial. During the course, we added a User model into our database and we created a function in our views.py file:
def register(request):
if request.method == "POST":
form = UserCreationForm(request.POST)
if form.is_valid():#si les champs sont OK :
user = form.save()
login(request, user)
return redirect("main:homepage")
else:
for msg in form.error_messages:
print(form.error_messages[msg])
But in this piece of code, I don't understand how Django knows if the request.method is True or False. Is it because I created a form with a Submit button in my template ?

Its impossible to say exactly what happens in your case since we don't have your HTML but in general:
When you create an HTML form, you can specify a method as follows <form method="POST"></form> or <form method="GET"></form>. If you don't specify the default is GET.
When you submit your form, it sends the data using an http request of the specified type. This is what Django is reading.

In this case, request.method simply represents the HTTP method that was used to access your view. For example, your register function might be assigned a url configuration such as: url(r'^register/', views.register), which maps an incoming HTTP request to your view. If you have a web form with a 'Submit' button, it's likely the web application code is submitting an HTTP POST request to your web server.
Django automatically constructs the request object for you, so you can check in your view how the request was made against the web server. For more info about what other things are included in the request, check the Django docs.

Multiple Forms on 1 Page Python FLASK

So I am loading all users from a database on a single page and I'm generating a password reset form for each user on the same page rather than having an individual page for each user.
My question is how can I click submit and apply the change for that specific user since I have multiple forms and submit buttons for each user via drop-down menu?
In my case the submit button is the "Reset Password" button.
I'm trying to call the form normally using
if request.method == "POST" and form.validate():
password = request.form['password']
but I'm getting exception error
name 'form' is not defined
I've been trying to solve this for a while but i'm getting pretty confused now as I've got multiple forms (one per user) on the same page.
NOTE : I'm not using WTForms for this task
Thanks

I'm not sure if this one has been answered but here is what i just figured out:
After your standard
if request.method == 'POST':
you can test for the existence of each form item within the request.form data. So add another if statement after the first
if 'my_form_element_name' in request.form:
print ('stuff')
If you have other types of form data such as files, you can do something like:
if request.method == 'POST':
if 'file_element_name' in request.files:
return stuff
elif 'my_form_element_name' in request.form:
return stuff
else: return stuff
else: return stuff
I have four forms in one html file and this method worked for me.

Django: User Reporting Some URL on Website

So i'm trying to build something, so that users would be able to report something on site. Here's the model,
class Report(models.Model):
reporting_url = models.URLField()
message = models.TextField()
I created Form for this Model including 'message' field only because 'reporting_url' is something it needs to populate by itself depending upon the specific page from where user has clicked "Report" button.
def report(request):
url_report = ???
if request.method == 'POST':
form = ReportForm(request.POST or None)
if form.is_valid():
new_form = form.save(commit=False)
new_form.reporting_url = url_report
new_form.save()
I was wondering How can I pass the specific url to 'reporting_url' field in form depending on the Page from where user has clicked "Report" button? (Much like s we see on social Networks).
Am I doing this correctly, Or is there a better way for doing this?
Please help me with this code. Thanks in Advance!

If there is a report button on that specific page then I believe you could write custom context processor.
More info: Django: get URL of current page, including parameters, in a template
https://docs.djangoproject.com/en/1.11/ref/templates/api/
Or maybe just write it directly in the views.py in your function and set
url_report = request.get_full_path()

I think you can use the form on the same page of the URL and use:
url_report = request.get_full_path()
in the view, to get the current URL.
Else if you want to create a separate view for the reporting form. You can use
url_report = request.META.get('HTTP_REFERER')
to get the previous or refering URL which led the user to that page.
request.META.get('HTTP_REFERER') will return None if it come from a different website.

Twilio django send SMS and get answer using SMS as parameter

In the twilio example made in flask, I can send an SMS and receive an answer using text and the SMS as the search parameter in the database. I need make this but in a django project, my first option that I thought make a django view with a parameter using a url with for send the parameter, but I see that is bad idea because not is possible can use the text of SMS as parameter
This is a part of flask example
#app.route('/directory/search', methods=['POST'])
def search():
query = request.form['Body']
I need make some similar to that view in django using django restframework but how I can get the Body (I think that the body is the text send in the SMS)
for use this as parameter

Use request.POST to access the form data:
from django.shortcuts import render
def my_view(request):
if request.method == "POST":
data = request.POST
# all posted data
data['body']
# the rest of your view logic
return render(request, 'template.html', context)

How to deal with errors in large formsets?

I'm just starting with formsets and I have trouble making a user friendly error system.
So the user sees a list view that shows him all instances of a model already written into a formset. This pages is meant to show him the data and edit it as well.
Before I was using a lot of individual forms with a save button for every form. But now I want to improve it to have a formset that provides a single save button for all of the forms.
But there comes my problem: Before I used to send the user via "action" to another url (e.g. .../update/ ) which processes the request and then sends him back to the list view he saw before. That's to avoid multiple submits when hitting F5.
But now if I do this and only a single form is wrong all the information the user had entered is lost.
So instead I stopped using the extra URL and made the processing part of the list view. Now I can use form.error on every form, but also the user resubmits when hitting F5.
Is there a way to have both?
Also: I have 1 extra form. But if the user changes it, and I feed the POST data into the formset, save it and then put it back to the page I lost the extra formset, because now the former extra is showing the newly entered instance and there is no true extra field left until the page is refreshed without sending post data.
Here is my View:
class BVServerListView(View):
def get(self, request):
eigene_server = Server.objects.filter(user=request.user)
EigeneServerFormset = modelformset_factory(Server, extra=1, form=ServerForm)
eigene_server_formset = EigeneServerFormset(queryset=eigene_server)
context = {'eigene_server': eigene_server_formset,}
return render(request, 'bildverteiler/server_list.html', context)
def post(self, request):
eigene_server = Server.objects.filter(user=request.user)
EigeneServerFormset = modelformset_factory(Server, extra=1, form=ServerForm)
eigene_server_formset = EigeneServerFormset(request.POST, request.FILES)
for form in eigene_server_formset.forms:
if form.data.get('delete', False):
server = Server.objects.get(user=request.user, name=form.data['name'])
server.delete()
else:
if form.has_changed() and form.is_valid():
server = form.save(commit=False)
server.user = request.user
server.save()
context = {'eigene_server': eigene_server_formset,}
return render(request, 'bildverteiler/server_list.html', context)

There is no difference between using a single form or a formset here. The answer is the same: post to the same view, but redirect after a successful save.
The other thing that you are doing wrong here is to validate and save individual forms one by one. Don't do that, because you could end up with a situation that the first forms are valid and get saved, but subsequent ones are invalid and therefore the formset needs to be redisplayed. Instead, validate the formset as a whole:
if eigene_server_formset.is_valid():
for form in eigene_server_formset.forms:
if form.cleaned_data.get('delete'):
... delete ...
else:
form.save()
return HttpResponseRedirect('somewhere_else')
return render...